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PPSMI ASSESMENT 2006     Panel Pakar Runding GC MMMT
                                    MATHEMATICS 1449/2
                                          FORM 4

No                                     Marking Scheme                           Marks

1.   a)   ∈
                                   Q                                            P1
               P




     b. ∈ P                                                                     P2
               Q                   R




                                                                                3


2.   1 x 15 x 15 x 21                                                           K1
     3

     22 x 7 x 7 x 9                                                             K1
     7    2 2

     1 x 15 x 15 x 21 + 22 x 7 x 7 x 9                                          K1
     3                  7    2 2

     1228.5                                                                     N1
                                                                                4


3.   4m + 2n = 6          @ 6m + 3n = 9                                         K1

              5n = -5     @     10m = 20                                        K1

               n = -1 ,    m = 2                                                N1 N1
                                                                                4




                          https://panelmathsaddmathswordpress.com/                      1
PPSMI ASSESMENT 2006      Panel Pakar Runding GC MMMT
                                  MATHEMATICS 1449/2
                                         FORM 4
No                                  Marking Scheme                             Marks

4.   a) 270o x 2 x 22 x 21 @ 90o x 2 x 22 x 14                                 K1
        360o       7         360 o     7

       270o x 2 x 22 x 21 + 90o x 2 x 22 x 14 + 7 +        7                   K1
        360o      7         360 o     7

       135                                                                     N1


     b) 270o x 22 x 21 x 21 @ 60o x 22 x 14 x 14                               K1
        360o   7              360 o 7

        270o x 22 x 21 x 21  60o x 22 x 14 x 14                               K1
        360o   7              360 o 7

        936.8                                                                  N1
                                                                               6

5.   2x2  5x + 3 = 0                                                          K1

     ( x - 1 ) ( 2x - 3 )= 0                                                   K1

                   x    = 1, 3                                                 N1 N1
                             2
                                                                               4


6.       a) Statement                                                          P1

         b) If 4k < 20, then k < 5
            If k < 5, then 4k < 20                                             P2

         c) n + 1 is not an even number                                        P2

                                                                               5




                         https://panelmathsaddmathswordpress.com/                      2
PPSMI ASSESMENT 2006      Panel Pakar Runding GC MMMT
                                  MATHEMATICS 1449/2
                                         FORM 4
No                                  Marking Scheme                             Marks

7.   a) y = 4                                                                  P1

     b) Identify mRS = 3                                                       P1
         y − 20                                                                K1
                = 3 or equivalent
         x − 13
         y = 3x − 19 or equivalent                                             N1

     c) 0 = 3x − 19
             19      1                                                         K1
         x=     or 6                                                           N1
              3      3

8.   < AGD                                                                     P1

     Tan θo = 6                                                                K2
              5

        θo = 50.19 o @ 50° 11’                                                 N1


                                                                               4


9.   a) 6                                                                      P2
        11

     b) 1 = 12                                                                 K2
        3   x

        x = 36                                                                 N1
                                                                               5




                         https://panelmathsaddmathswordpress.com/                      3
PPSMI ASSESMENT 2006       Panel Pakar Runding GC MMMT
                                   MATHEMATICS 1449/2
                                          FORM 4
No                                   Marking Scheme                              Marks
10.   a) mRQ = 5                                                                 P1
               3

      b) 10 = 5 ( 3) + c                                                         K1
              3
         c = 5                                                                   K1

        y = 5 x+5                                                                N1
            3

      c) 0 = 5 x + 5                                                             K1
             3
         x = -3                                                                  N1

                                                                                 6

11.      a) i. >                                                                 P1

             ii. <                                                               P1

         b) PQRST is a pentagon                                                  P2

         c) 3n2 where n = 0, 1, 2, 3, …                                          P2

                                                                                 6




                           https://panelmathsaddmathswordpress.com/                      4
PPSMI ASSESMENT 2006      Panel Pakar Runding GC MMMT
                                 MATHEMATICS 1449/2
                                        FORM 4
No                                 Marking Scheme                             Marks

12.   a) i. m OA = 4                                                          P1

          ii. c = -18                                                         K1

               y = 4x – 18                                                    N1

         iii. mAB = 2                                                         K1
                    5

              c = 18                                                          N1
                   5

      b) i. Identify ∠ NLJ                                                    P1
             JL = 12 2 + 12 2 or 16 ⋅ 97                                      K1
             tan θo =      5                                                  K1
                        16.97

                 θo = 16.42o or 16o 25’                                       N1
         ii. Identify ∠NMJ                                                    P1
              tan θo = 5                                                      K1
                       13

                  θo = 22⋅62o or 22o 37’                                      N1

                                                                              12




                        https://panelmathsaddmathswordpress.com/                      5
PPSMI ASSESMENT 2006   Panel Pakar Runding GC MMMT
                                         MATHEMATICS 1449/2
                                                FORM 4
No                                         Marking Scheme                          Marks

13.        a)     i. { 2, 3, 5, 6, 8, 9, 11, 12 }                                  P1
                  ii. { 2, 6, 8, 12 }                                              P1
                       4          1
                 iii.       @                                                      P2
                       8          2
                       6          3
                  iv.       @
                      10          5
                                                                                   P2
      b)        i. 60o x 2 x 22 x 28
                   360o      7
                                                                                   K1
                 60o x 2 x 22 x 28 + 28 + 14 + 14 + 14 +14
                  360o     7
                                                                                   K1
                 113 1
                     3
                                                                                   N1
            ii. 60o x 22 x 28 x 28 @ 150o x 22 x 14 x 14
                360o 7               360o   7
                                                                                   K1
                60o x 22 x 28 x 28 + 14 x 14 - 150o x 22 x 14 x 14
                360o   7                      360o    7
                                                                                   K1
                 350
                                                                                   N1




                                                                                   12




                             https://panelmathsaddmathswordpress.com/                      6
PPSMI ASSESMENT 2006              Panel Pakar Runding GC MMMT
                                      MATHEMATICS 1449/2
                                             FORM 4
No                                      Marking Scheme                                     Marks

14.         a) 3n2 – 11n – 4 = 0                                                           K1
                ( n – 4 ) ( 3n + 1 ) = 0                                                   K1
                                 n = 4, - 1                                                N1, N1
                                          3
                  2
            b) x – 2x + 24 = 0                                                             K1
               ( x – 6 ) ( x + 4 )= 0                                                      K1
                               x = 6, - 4                                                  N1, N1

            c) 1 x 22 x 7 x 7 x 10                                                         K1
               2 7

               1 x 1 x 22 x 7 x 7 x 5                                                      K1
               2   3 7

               1 x 22 x 7 x 7 x 10 +          1 x 1 x 22 x 7 x 7 x 5                       K1
               2 7                            2   3 7

               898 1                                                                       N1
                   3




15.   a).
                   Age           Frequency          Mid point    Upper boundary
                                    (I)               ( II )         ( III )
                    1-5              1                  3              5.5
                   6-10              4                  8             10.5
                   11-15             9                 13             15.5
                   16-20             9                 18             20.5
                   21-25             5                 23             25.5
                   26-30             2                 28             30.5

             All values in column ( I ) correct                                            P2
             All values in column ( II ) correct                                           P1
             All values in column ( III ) correct                                          P1


            b) Mean= 1(3) + 4(8) + 9(13) + 9(18) + 5(23) + 2(28) or 485                    K2
                                 30                                 30

                     = 16.17                                                               N1




                           https://panelmathsaddmathswordpress.com/                                7
PPSMI ASSESMENT 2006          Panel Pakar Runding GC MMMT
                               MATHEMATICS 1449/2
                                      FORM 4
No                               Marking Scheme                                 Marks
     c) Histogram

        Using the uniform scales for 0.5 ≤ x ≤ 30.5 and 0 ≤ y ≤ 9               K1

        6 bars* drawn correctly.                                                K2
        Note: 5 or 4 bars* drawn correctly.                                K1

         The 6 bars with correct frequencies are drawn.                         N1

     d) 16 x 100 = 53.33%
        30                                                                      P1

     * referring to candidates frequencies                                      12




                    https://panelmathsaddmathswordpress.com/                            8
PPSMI ASSESMENT 2006                Panel Pakar Runding GC MMMT
                                     MATHEMATICS 1449/2
                                            FORM 4
No                                     Marking Scheme                                       Marks

16.    a)

       Age           Frequency      Cumulative             Upper
       (years)                      frequency              boundary
                                           (I)                 ( II )
       10 – 14             0                0                  14.5             Row I
       15 - 19            10                10                 19.5
       20 – 24            20                30                 24.5
       25 – 29            50                80                 29.5
       30 – 34            60               140                 34.5
       35 - 39            36               176                 39.5
       40 - 44            18               194                 44.5
       45 - 49             6               200                 49.5

      All values in Row I correct.                                                          P1
      All values in Column ( I ) correct excluding Row I correct.                           P2
      All values in Column ( II ) correct excluding Row I correct.                          P1

      b) Mean = 10(19.5) + 20(24.5) + 50(29.5) + 60(34.5) +36(39.5) + 18(44.5) +6(49.5)
                                         200
             Or 6750
                    200                                                                     K2

                 33.75                                                                      N1

      c) x-axis is drawn with the right direction and uniform scaled from                   P1
         14.5 ≤ x ≤ 49.5

        y-axis is drawn with the right direction and uniform scaled from                    P1
        0 ≤ y ≤ 200

        All eight points* plotted correctly.                                                P2
        Note : Seven or six points* plotted correctly.                                P1

        All the right eight points plotted correctly and ogive is drawn smoothly passing    N1
        through all the points.

      * referring to candidates frequencies




                         https://panelmathsaddmathswordpress.com/                                   9

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Maths Answer Ppsmi2006 F4 P2

  • 1. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks 1. a) ∈ Q P1 P b. ∈ P P2 Q R 3 2. 1 x 15 x 15 x 21 K1 3 22 x 7 x 7 x 9 K1 7 2 2 1 x 15 x 15 x 21 + 22 x 7 x 7 x 9 K1 3 7 2 2 1228.5 N1 4 3. 4m + 2n = 6 @ 6m + 3n = 9 K1 5n = -5 @ 10m = 20 K1 n = -1 , m = 2 N1 N1 4 https://panelmathsaddmathswordpress.com/ 1
  • 2. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks 4. a) 270o x 2 x 22 x 21 @ 90o x 2 x 22 x 14 K1 360o 7 360 o 7 270o x 2 x 22 x 21 + 90o x 2 x 22 x 14 + 7 + 7 K1 360o 7 360 o 7 135 N1 b) 270o x 22 x 21 x 21 @ 60o x 22 x 14 x 14 K1 360o 7 360 o 7 270o x 22 x 21 x 21  60o x 22 x 14 x 14 K1 360o 7 360 o 7 936.8 N1 6 5. 2x2  5x + 3 = 0 K1 ( x - 1 ) ( 2x - 3 )= 0 K1 x = 1, 3 N1 N1 2 4 6. a) Statement P1 b) If 4k < 20, then k < 5 If k < 5, then 4k < 20 P2 c) n + 1 is not an even number P2 5 https://panelmathsaddmathswordpress.com/ 2
  • 3. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks 7. a) y = 4 P1 b) Identify mRS = 3 P1 y − 20 K1 = 3 or equivalent x − 13 y = 3x − 19 or equivalent N1 c) 0 = 3x − 19 19 1 K1 x= or 6 N1 3 3 8. < AGD P1 Tan θo = 6 K2 5 θo = 50.19 o @ 50° 11’ N1 4 9. a) 6 P2 11 b) 1 = 12 K2 3 x x = 36 N1 5 https://panelmathsaddmathswordpress.com/ 3
  • 4. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks 10. a) mRQ = 5 P1 3 b) 10 = 5 ( 3) + c K1 3 c = 5 K1 y = 5 x+5 N1 3 c) 0 = 5 x + 5 K1 3 x = -3 N1 6 11. a) i. > P1 ii. < P1 b) PQRST is a pentagon P2 c) 3n2 where n = 0, 1, 2, 3, … P2 6 https://panelmathsaddmathswordpress.com/ 4
  • 5. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks 12. a) i. m OA = 4 P1 ii. c = -18 K1 y = 4x – 18 N1 iii. mAB = 2 K1 5 c = 18 N1 5 b) i. Identify ∠ NLJ P1 JL = 12 2 + 12 2 or 16 ⋅ 97 K1 tan θo = 5 K1 16.97 θo = 16.42o or 16o 25’ N1 ii. Identify ∠NMJ P1 tan θo = 5 K1 13 θo = 22⋅62o or 22o 37’ N1 12 https://panelmathsaddmathswordpress.com/ 5
  • 6. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks 13. a) i. { 2, 3, 5, 6, 8, 9, 11, 12 } P1 ii. { 2, 6, 8, 12 } P1 4 1 iii. @ P2 8 2 6 3 iv. @ 10 5 P2 b) i. 60o x 2 x 22 x 28 360o 7 K1 60o x 2 x 22 x 28 + 28 + 14 + 14 + 14 +14 360o 7 K1 113 1 3 N1 ii. 60o x 22 x 28 x 28 @ 150o x 22 x 14 x 14 360o 7 360o 7 K1 60o x 22 x 28 x 28 + 14 x 14 - 150o x 22 x 14 x 14 360o 7 360o 7 K1 350 N1 12 https://panelmathsaddmathswordpress.com/ 6
  • 7. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks 14. a) 3n2 – 11n – 4 = 0 K1 ( n – 4 ) ( 3n + 1 ) = 0 K1 n = 4, - 1 N1, N1 3 2 b) x – 2x + 24 = 0 K1 ( x – 6 ) ( x + 4 )= 0 K1 x = 6, - 4 N1, N1 c) 1 x 22 x 7 x 7 x 10 K1 2 7 1 x 1 x 22 x 7 x 7 x 5 K1 2 3 7 1 x 22 x 7 x 7 x 10 + 1 x 1 x 22 x 7 x 7 x 5 K1 2 7 2 3 7 898 1 N1 3 15. a). Age Frequency Mid point Upper boundary (I) ( II ) ( III ) 1-5 1 3 5.5 6-10 4 8 10.5 11-15 9 13 15.5 16-20 9 18 20.5 21-25 5 23 25.5 26-30 2 28 30.5 All values in column ( I ) correct P2 All values in column ( II ) correct P1 All values in column ( III ) correct P1 b) Mean= 1(3) + 4(8) + 9(13) + 9(18) + 5(23) + 2(28) or 485 K2 30 30 = 16.17 N1 https://panelmathsaddmathswordpress.com/ 7
  • 8. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks c) Histogram Using the uniform scales for 0.5 ≤ x ≤ 30.5 and 0 ≤ y ≤ 9 K1 6 bars* drawn correctly. K2 Note: 5 or 4 bars* drawn correctly. K1 The 6 bars with correct frequencies are drawn. N1 d) 16 x 100 = 53.33% 30 P1 * referring to candidates frequencies 12 https://panelmathsaddmathswordpress.com/ 8
  • 9. PPSMI ASSESMENT 2006 Panel Pakar Runding GC MMMT MATHEMATICS 1449/2 FORM 4 No Marking Scheme Marks 16. a) Age Frequency Cumulative Upper (years) frequency boundary (I) ( II ) 10 – 14 0 0 14.5 Row I 15 - 19 10 10 19.5 20 – 24 20 30 24.5 25 – 29 50 80 29.5 30 – 34 60 140 34.5 35 - 39 36 176 39.5 40 - 44 18 194 44.5 45 - 49 6 200 49.5 All values in Row I correct. P1 All values in Column ( I ) correct excluding Row I correct. P2 All values in Column ( II ) correct excluding Row I correct. P1 b) Mean = 10(19.5) + 20(24.5) + 50(29.5) + 60(34.5) +36(39.5) + 18(44.5) +6(49.5) 200 Or 6750 200 K2 33.75 N1 c) x-axis is drawn with the right direction and uniform scaled from P1 14.5 ≤ x ≤ 49.5 y-axis is drawn with the right direction and uniform scaled from P1 0 ≤ y ≤ 200 All eight points* plotted correctly. P2 Note : Seven or six points* plotted correctly. P1 All the right eight points plotted correctly and ogive is drawn smoothly passing N1 through all the points. * referring to candidates frequencies https://panelmathsaddmathswordpress.com/ 9