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Double Angles
Double Angles
      
 sin 2  sin   
Double Angles
      
 sin 2  sin   
        sin  cos   cos  sin 
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
 cos 2  cos 2   sin 2 
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
 cos 2  cos 2   sin 2 
          cos 2   1  cos 2  
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
 cos 2  cos 2   sin 2 
          cos 2   1  cos 2  
  cos 2  2cos 2   1
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
 cos 2  cos 2   sin 2 
          cos 2   1  cos 2  
  cos 2  2cos 2   1
          2 1  sin 2    1
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
 cos 2  cos 2   sin 2 
          cos 2   1  cos 2  
  cos 2  2cos 2   1
          2 1  sin 2    1
  cos 2  1  2sin 2 
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
 cos 2  cos 2   sin 2 
          cos 2   1  cos 2  
  cos 2  2cos 2   1
          2 1  sin 2    1
  cos 2  1  2sin 2 
  tan 2  tan    
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
 cos 2  cos 2   sin 2 
          cos 2   1  cos 2  
  cos 2  2cos 2   1
          2 1  sin 2    1
  cos 2  1  2sin 2 
  tan 2  tan    
            tan   tan 
         
           1  tan  tan 
Double Angles
      
 sin 2  sin   
         sin  cos   cos  sin 
  sin 2  2sin  cos 

 cos 2  cos    
         cos  cos   sin  sin 
 cos 2  cos 2   sin 2 
          cos 2   1  cos 2  
  cos 2  2cos 2   1
          2 1  sin 2    1
  cos 2  1  2sin 2 
  tan 2  tan                              2 tan 
            tan   tan              tan 2 
                                              1  tan 2 
           1  tan  tan 
Double Angles   sin 2  2 sin  cos
Double Angles   sin 2  2 sin  cos
                cos 2  cos 2   sin 2 
Double Angles   sin 2  2 sin  cos
                cos 2  cos 2   sin 2 
                        2 cos 2   1
Double Angles   sin 2  2 sin  cos
                cos 2  cos 2   sin 2 
                                                      1
                        2 cos   1
                               2
                                              cos   1  cos 2 
                                                   2

                                                      2
Double Angles   sin 2  2 sin  cos
                cos 2  cos 2   sin 2 
                                                      1
                        2 cos   1
                               2
                                              cos   1  cos 2 
                                                   2

                                                      2

                         1 2 sin 2 
Double Angles   sin 2  2 sin  cos
                cos 2  cos 2   sin 2 
                                                      1
                        2 cos   1
                               2
                                              cos   1  cos 2 
                                                   2

                                                      2
                                                      1
                         1 2 sin 2         sin   1  cos 2 
                                                  2

                                                      2
Double Angles   sin 2  2 sin  cos
                cos 2  cos 2   sin 2 
                                                      1
                        2 cos   1
                               2
                                              cos   1  cos 2 
                                                   2

                                                      2
                                                      1
                        1 2 sin 2          sin   1  cos 2 
                                                  2

                                                      2
                           2 tan 
                tan 2 
                         1  tan 2 
Double Angles        sin 2  2 sin  cos
                     cos 2  cos 2   sin 2 
                                                           1
                              2 cos   1
                                    2
                                                   cos   1  cos 2 
                                                        2

                                                           2
                                                           1
                              1 2 sin 2         sin   1  cos 2 
                                                       2

                                                           2
                                 2 tan 
                      tan 2 
                               1  tan 2 
                     2
e.g.  i  If cos   , find tan 2
                     3
Double Angles        sin 2  2 sin  cos
                     cos 2  cos 2   sin 2 
                                                           1
                              2 cos   1
                                    2
                                                   cos   1  cos 2 
                                                        2

                                                           2
                                                           1
                              1 2 sin 2         sin   1  cos 2 
                                                       2

                                                           2
                                 2 tan 
                      tan 2 
                               1  tan 2 
                     2
e.g.  i  If cos   , find tan 2
                     3                                         3
                                                                        5
                                                              
                                                                   2
Double Angles         sin 2  2 sin  cos
                      cos 2  cos 2   sin 2 
                                                            1
                                2 cos   1
                                       2
                                                    cos   1  cos 2 
                                                         2

                                                            2
                                                            1
                                 1 2 sin 2       sin   1  cos 2 
                                                        2

                                                            2
                                    2 tan 
                         tan 2 
                                  1  tan 2 
                        2
e.g.  i  If cos   , find tan 2
                        3                                       3
                                                                         5
                 2 tan 
   tan 2                                                     
               1  tan 2                                           2
Double Angles         sin 2  2 sin  cos
                      cos 2  cos 2   sin 2 
                                                               1
                               2 cos   1
                                      2
                                                       cos   1  cos 2 
                                                                2

                                                               2
                                                               1
                                 1 2 sin 2          sin   1  cos 2 
                                                           2

                                                               2
                                    2 tan 
                         tan 2 
                                  1  tan 2 
                        2
e.g.  i  If cos   , find tan 2                   5
                        3                       2                 3
                                    tan 2  
                                                      2                    5
                 2 tan 
   tan 2                                        
                                                            2       
               1  tan 2                              5
                                               1                     2
                                                     2 
Double Angles         sin 2  2 sin  cos
                      cos 2  cos 2   sin 2 
                                                              1
                               2 cos   1
                                       2
                                                      cos   1  cos 2 
                                                             2

                                                              2
                                                              1
                                 1 2 sin 2         sin   1  cos 2 
                                                          2

                                                              2
                                    2 tan 
                         tan 2 
                                  1  tan 2 
                        2
e.g.  i  If cos   , find tan 2                5
                        3                        2              3
                 2 tan             tan 2        2                     5
   tan 2                                          5
                                                         2       
               1  tan 2                      1                   2
                                                    2 
                                                  5
                                              
                                                  1
                                                
                                                  4
                                               4 5
5   5
 ii  Find the exact value of sin cos
                                  12   12
5   5
 ii  Find the exact value of sin cos
                                  12   12
                    5   5 1     5  5 
                 sin cos   =  2sin cos 
                    12   12 2     12  12 
5   5
 ii  Find the exact value of sin cos
                                  12   12
                    5   5 1     5  5 
                 sin cos   =  2sin cos 
                    12   12 2     12  12 
                                 1  5 
                                = sin  2  
                                 2  12 
5   5
 ii  Find the exact value of sin cos
                                  12   12
                    5   5 1     5  5 
                 sin cos   =  2sin cos 
                    12   12 2     12  12 
                                 1  5 
                                = sin  2  
                                 2  12 
                                 1 5
                                = sin
                                 2    6
5   5
 ii  Find the exact value of sin cos
                                  12   12
                    5   5 1     5  5 
                 sin cos   =  2sin cos 
                    12   12 2     12  12 
                                 1  5 
                                = sin  2  
                                 2  12 
                                 1 5
                                = sin
                                 2    6
                                 1 1
                                = 
                                 2 2
                                  1
                                =
                                  4
2                              
 iii  If cos  , find the exact value of sin
                 3                              2
2                              
 iii  If cos  , find the exact value of sin
                 3                              2
                                       1
                           sin 2       1  cos 2 
                                       2
2                              
 iii  If cos  , find the exact value of sin
                 3                              2
                                1
                                  1  cos 2 
                           sin 2  
                                2
                             2 1
                         sin  1  cos  
                              2 2
2                              
 iii  If cos  , find the exact value of sin
                 3                              2
                                 1
                                   1  cos 2 
                           sin 2  
                                 2
                             2  1
                         sin  1  cos  
                              2 2
                                 1 2
                                 1  
                                 2 3
2                              
 iii  If cos  , find the exact value of sin
                 3                              2
                                  1
                           sin 2  1  cos 2 
                                  2
                             2   1
                         sin  1  cos  
                              2 2
                                  1 2
                                 1  
                                  2 3
                                  1
                                
                                  6
2                              
 iii  If cos  , find the exact value of sin
                 3                              2
                                    1
                           sin 2    1  cos 2 
                                    2
                              2    1
                         sin  1  cos  
                               2 2
                                    1 2
                                   1  
                                    2 3
                                    1
                                  
                                    6
                                       1
                            sin  
                                2        6
1  cos 2 x
 iv  Prove                tan x
               1  cos 2 x
1  cos 2 x
 iv  Prove                tan x
               1  cos 2 x

               1  cos 2 x       1  1  2sin 2 x 
                             
               1  cos 2 x       1   2cos 2 x  1
1  cos 2 x
 iv  Prove                tan x
               1  cos 2 x

               1  cos 2 x       1  1  2sin 2 x 
                             
               1  cos 2 x       1   2cos 2 x  1

                               2sin 2 x
                             
                               2cos 2 x
1  cos 2 x
 iv  Prove                tan x
               1  cos 2 x

               1  cos 2 x       1  1  2sin 2 x 
                             
               1  cos 2 x       1   2cos 2 x  1

                               2sin 2 x
                             
                               2cos 2 x

                               sin 2 x
                             
                               cos 2 x
1  cos 2 x
 iv  Prove                tan x
               1  cos 2 x

               1  cos 2 x       1  1  2sin 2 x 
                             
               1  cos 2 x       1   2cos 2 x  1

                               2sin 2 x
                             
                               2cos 2 x

                               sin 2 x
                             
                               cos 2 x
                              tan 2 x
1  cos 2 x
 iv  Prove                tan x
               1  cos 2 x

               1  cos 2 x       1  1  2sin 2 x 
                             
               1  cos 2 x       1   2cos 2 x  1

                               2sin 2 x
                             
                               2cos 2 x

                               sin 2 x
                             
                               cos 2 x
                              tan 2 x
                              tan x
sin 3 cos3
(v) Prove that             2   1996 Extension 1 HSC Q4a)
                sin   cos
sin 3 cos3
(v) Prove that             2         1996 Extension 1 HSC Q4a)
                sin   cos

              sin 3 cos3     sin 3 cos   cos3 sin 
                            
               sin    cos            sin  cos 
sin 3 cos3
(v) Prove that             2          1996 Extension 1 HSC Q4a)
                sin   cos

              sin 3 cos3     sin 3 cos   cos3 sin 
                            
               sin    cos            sin  cos 
                                2 sin 3   
                              
                                2 sin  cos
sin 3 cos3
(v) Prove that             2           1996 Extension 1 HSC Q4a)
                sin   cos

              sin 3 cos3     sin 3 cos   cos3 sin 
                            
               sin    cos            sin  cos 
                                2 sin 3   
                              
                                2 sin  cos
                                  2 sin 2
                              
                                   sin 2
sin 3 cos3
(v) Prove that             2           1996 Extension 1 HSC Q4a)
                sin   cos

              sin 3 cos3     sin 3 cos   cos3 sin 
                            
               sin    cos            sin  cos 
                                2 sin 3   
                              
                                2 sin  cos
                                  2 sin 2
                              
                                   sin 2
                              2
(vi) Prove the following identity;   1994 Extension 1 HSC Q2a)
           2 tan A
                     sin 2 A
          1  tan A
                 2
(vi) Prove the following identity;          1994 Extension 1 HSC Q2a)
           2 tan A
                     sin 2 A
          1  tan A
                 2

                                  2sin A
                      2 tan A
                                 cos A
                    1  tan 2 A     sin 2 A
                                 1
                                    cos 2 A
(vi) Prove the following identity;           1994 Extension 1 HSC Q2a)
           2 tan A
                     sin 2 A
          1  tan A
                 2

                                   2sin A
                      2 tan A
                                 cos A
                    1  tan 2 A      sin 2 A
                                  1
                                     cos 2 A
                                   2 sin A cos A
                                
                                  cos 2 A  sin 2 A
(vi) Prove the following identity;           1994 Extension 1 HSC Q2a)
           2 tan A
                     sin 2 A
          1  tan A
                 2

                                   2sin A
                      2 tan A
                                 cos A
                    1  tan 2 A      sin 2 A
                                  1
                                     cos 2 A
                                   2 sin A cos A
                                
                                  cos 2 A  sin 2 A
                                  sin 2 A
                              
                                     1
(vi) Prove the following identity;           1994 Extension 1 HSC Q2a)
           2 tan A
                     sin 2 A
          1  tan A
                 2

                                   2sin A
                      2 tan A
                                 cos A
                    1  tan 2 A      sin 2 A
                                  1
                                     cos 2 A
                                   2 sin A cos A
                                
                                  cos 2 A  sin 2 A
                                  sin 2 A
                              
                                     1
                               sin 2 A
(vi) Prove the following identity;           1994 Extension 1 HSC Q2a)
           2 tan A
                     sin 2 A
          1  tan A
                 2

                                   2sin A
                      2 tan A
                                 cos A
                    1  tan 2 A      sin 2 A
                                  1
                                     cos 2 A
                                   2 sin A cos A
                                
                                  cos 2 A  sin 2 A
                                  sin 2 A
                              
                                     1
                               sin 2 A

                              Book2
   Exercise 2A; 2ade, 3bde, 5adej, 7, 8adg, 10ab, 11, 13ck, 16, 19*

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  • 2. Double Angles   sin 2  sin   
  • 3. Double Angles   sin 2  sin     sin  cos   cos  sin 
  • 4. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos 
  • 5. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos    
  • 6. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin 
  • 7. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin  cos 2  cos 2   sin 2 
  • 8. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin  cos 2  cos 2   sin 2   cos 2   1  cos 2  
  • 9. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin  cos 2  cos 2   sin 2   cos 2   1  cos 2   cos 2  2cos 2   1
  • 10. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin  cos 2  cos 2   sin 2   cos 2   1  cos 2   cos 2  2cos 2   1  2 1  sin 2    1
  • 11. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin  cos 2  cos 2   sin 2   cos 2   1  cos 2   cos 2  2cos 2   1  2 1  sin 2    1 cos 2  1  2sin 2 
  • 12. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin  cos 2  cos 2   sin 2   cos 2   1  cos 2   cos 2  2cos 2   1  2 1  sin 2    1 cos 2  1  2sin 2  tan 2  tan    
  • 13. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin  cos 2  cos 2   sin 2   cos 2   1  cos 2   cos 2  2cos 2   1  2 1  sin 2    1 cos 2  1  2sin 2  tan 2  tan     tan   tan   1  tan  tan 
  • 14. Double Angles   sin 2  sin     sin  cos   cos  sin  sin 2  2sin  cos  cos 2  cos      cos  cos   sin  sin  cos 2  cos 2   sin 2   cos 2   1  cos 2   cos 2  2cos 2   1  2 1  sin 2    1 cos 2  1  2sin 2  tan 2  tan     2 tan  tan   tan  tan 2   1  tan 2  1  tan  tan 
  • 15. Double Angles sin 2  2 sin  cos
  • 16. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2 
  • 17. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2   2 cos 2   1
  • 18. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2
  • 19. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2  1 2 sin 2 
  • 20. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2 1  1 2 sin 2   sin   1  cos 2  2 2
  • 21. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2 1  1 2 sin 2   sin   1  cos 2  2 2 2 tan  tan 2  1  tan 2 
  • 22. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2 1  1 2 sin 2   sin   1  cos 2  2 2 2 tan  tan 2  1  tan 2  2 e.g.  i  If cos   , find tan 2 3
  • 23. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2 1  1 2 sin 2   sin   1  cos 2  2 2 2 tan  tan 2  1  tan 2  2 e.g.  i  If cos   , find tan 2 3 3 5  2
  • 24. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2 1  1 2 sin 2   sin   1  cos 2  2 2 2 tan  tan 2  1  tan 2  2 e.g.  i  If cos   , find tan 2 3 3 5 2 tan  tan 2   1  tan 2  2
  • 25. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2 1  1 2 sin 2   sin   1  cos 2  2 2 2 tan  tan 2  1  tan 2  2 e.g.  i  If cos   , find tan 2  5 3 2  3 tan 2   2  5 2 tan  tan 2   2  1  tan 2  5 1   2  2 
  • 26. Double Angles sin 2  2 sin  cos cos 2  cos 2   sin 2  1  2 cos   1 2  cos   1  cos 2  2 2 1  1 2 sin 2   sin   1  cos 2  2 2 2 tan  tan 2  1  tan 2  2 e.g.  i  If cos   , find tan 2  5 3 2  3 2 tan  tan 2   2  5 tan 2   5 2  1  tan 2  1   2  2  5  1  4  4 5
  • 27. 5 5  ii  Find the exact value of sin cos 12 12
  • 28. 5 5  ii  Find the exact value of sin cos 12 12 5 5 1  5 5  sin cos =  2sin cos  12 12 2  12 12 
  • 29. 5 5  ii  Find the exact value of sin cos 12 12 5 5 1  5 5  sin cos =  2sin cos  12 12 2  12 12  1  5  = sin  2   2  12 
  • 30. 5 5  ii  Find the exact value of sin cos 12 12 5 5 1  5 5  sin cos =  2sin cos  12 12 2  12 12  1  5  = sin  2   2  12  1 5 = sin 2 6
  • 31. 5 5  ii  Find the exact value of sin cos 12 12 5 5 1  5 5  sin cos =  2sin cos  12 12 2  12 12  1  5  = sin  2   2  12  1 5 = sin 2 6 1 1 =  2 2 1 = 4
  • 32. 2   iii  If cos  , find the exact value of sin 3 2
  • 33. 2   iii  If cos  , find the exact value of sin 3 2 1 sin 2   1  cos 2  2
  • 34. 2   iii  If cos  , find the exact value of sin 3 2 1 1  cos 2  sin 2   2 2 1  sin  1  cos   2 2
  • 35. 2   iii  If cos  , find the exact value of sin 3 2 1 1  cos 2  sin 2   2 2 1  sin  1  cos   2 2 1 2  1   2 3
  • 36. 2   iii  If cos  , find the exact value of sin 3 2 1 sin 2  1  cos 2  2 2 1  sin  1  cos   2 2 1 2  1   2 3 1  6
  • 37. 2   iii  If cos  , find the exact value of sin 3 2 1 sin 2   1  cos 2  2 2 1  sin  1  cos   2 2 1 2  1   2 3 1  6  1 sin   2 6
  • 38. 1  cos 2 x  iv  Prove  tan x 1  cos 2 x
  • 39. 1  cos 2 x  iv  Prove  tan x 1  cos 2 x 1  cos 2 x 1  1  2sin 2 x   1  cos 2 x 1   2cos 2 x  1
  • 40. 1  cos 2 x  iv  Prove  tan x 1  cos 2 x 1  cos 2 x 1  1  2sin 2 x   1  cos 2 x 1   2cos 2 x  1 2sin 2 x  2cos 2 x
  • 41. 1  cos 2 x  iv  Prove  tan x 1  cos 2 x 1  cos 2 x 1  1  2sin 2 x   1  cos 2 x 1   2cos 2 x  1 2sin 2 x  2cos 2 x sin 2 x  cos 2 x
  • 42. 1  cos 2 x  iv  Prove  tan x 1  cos 2 x 1  cos 2 x 1  1  2sin 2 x   1  cos 2 x 1   2cos 2 x  1 2sin 2 x  2cos 2 x sin 2 x  cos 2 x  tan 2 x
  • 43. 1  cos 2 x  iv  Prove  tan x 1  cos 2 x 1  cos 2 x 1  1  2sin 2 x   1  cos 2 x 1   2cos 2 x  1 2sin 2 x  2cos 2 x sin 2 x  cos 2 x  tan 2 x  tan x
  • 44. sin 3 cos3 (v) Prove that  2 1996 Extension 1 HSC Q4a) sin cos
  • 45. sin 3 cos3 (v) Prove that  2 1996 Extension 1 HSC Q4a) sin cos sin 3 cos3 sin 3 cos   cos3 sin    sin  cos  sin  cos 
  • 46. sin 3 cos3 (v) Prove that  2 1996 Extension 1 HSC Q4a) sin cos sin 3 cos3 sin 3 cos   cos3 sin    sin  cos  sin  cos  2 sin 3     2 sin  cos
  • 47. sin 3 cos3 (v) Prove that  2 1996 Extension 1 HSC Q4a) sin cos sin 3 cos3 sin 3 cos   cos3 sin    sin  cos  sin  cos  2 sin 3     2 sin  cos 2 sin 2  sin 2
  • 48. sin 3 cos3 (v) Prove that  2 1996 Extension 1 HSC Q4a) sin cos sin 3 cos3 sin 3 cos   cos3 sin    sin  cos  sin  cos  2 sin 3     2 sin  cos 2 sin 2  sin 2 2
  • 49. (vi) Prove the following identity; 1994 Extension 1 HSC Q2a) 2 tan A  sin 2 A 1  tan A 2
  • 50. (vi) Prove the following identity; 1994 Extension 1 HSC Q2a) 2 tan A  sin 2 A 1  tan A 2 2sin A 2 tan A  cos A 1  tan 2 A sin 2 A 1 cos 2 A
  • 51. (vi) Prove the following identity; 1994 Extension 1 HSC Q2a) 2 tan A  sin 2 A 1  tan A 2 2sin A 2 tan A  cos A 1  tan 2 A sin 2 A 1 cos 2 A 2 sin A cos A  cos 2 A  sin 2 A
  • 52. (vi) Prove the following identity; 1994 Extension 1 HSC Q2a) 2 tan A  sin 2 A 1  tan A 2 2sin A 2 tan A  cos A 1  tan 2 A sin 2 A 1 cos 2 A 2 sin A cos A  cos 2 A  sin 2 A sin 2 A  1
  • 53. (vi) Prove the following identity; 1994 Extension 1 HSC Q2a) 2 tan A  sin 2 A 1  tan A 2 2sin A 2 tan A  cos A 1  tan 2 A sin 2 A 1 cos 2 A 2 sin A cos A  cos 2 A  sin 2 A sin 2 A  1  sin 2 A
  • 54. (vi) Prove the following identity; 1994 Extension 1 HSC Q2a) 2 tan A  sin 2 A 1  tan A 2 2sin A 2 tan A  cos A 1  tan 2 A sin 2 A 1 cos 2 A 2 sin A cos A  cos 2 A  sin 2 A sin 2 A  1  sin 2 A Book2 Exercise 2A; 2ade, 3bde, 5adej, 7, 8adg, 10ab, 11, 13ck, 16, 19*