ceptual Connection 17-1 -Enhanced - with Feedback Part A Which solutio.docx

•Download as DOCX, PDF•

0 likes•2 views

ceptual Connection 17.1 -Enhanced - with Feedback Part A Which solution is a buffer? O a solution that is 0.200 M in HCHO2 and 0.200 M in NaNO3 e a solution that is 0 200 M in HCHO2 and 0 200 M in NaCHO2 e a solution that is 0.200 M in HBr and 0.200 M in NaBr O a solution that is 0.200 M in HCHO2 and 0.200 M in HBr Submit Request Answer rovide Feedback Solution The answer is b.( a solution that is 0.200 M HCHO2 and 0.200 M in NaCHO2.because HCHO2 is a weak acid and its conjugate base is CH2O^-. Buffer is a solution that can resist change in pH.it is made by weak acid and its conjugate base. In option 1: it can\'t be a buffer HCHO2 is a weak acid but there is mo conjugate base. In option 3 : It can\'t be a buffer as HBr is a strong acid. In option 4: it can\'t be a buffer as there is no conjugate base. .

Education

More from rtodd544

Calculating Internal Growth [LO3] The most recent financial statements for Live Co. are shown here: Assets and costs are proportional to sales. Debt and equity are not. The company maintains a constant 30 percent dividend payout ratio. No external equity financing is possible. What is the internal growth rate? Solution Answer - Internal Growth rate = (ROA * Retenstion Rate) / (1 - ROA * Retention Rate) ROA = Net income / total assets = 3420 / 39150 = 0.087 Retention rate = 1 - dividend payout ratio = 1 - 0.3 = 0.70 put values in internal growth rate formula = IGR = (0.087 * 0.70) / ( 1 - 0.087 * 0.70 ) = 0.061 / 0.938 IGR = 0.065 or 6.50 % .

Calculating Internal Growth -LO3- The most recent financial statements.docx

rtodd544

Ch 12 LT Liabilities and Present Value of MoneySolutionRequirement 1-.docx

rtodd544

CCES Corporation acquires a controlling interest in Schmaling, Inc. CCES may utilize three methods to internally account for this investment. Class, what are these methods? Could you discuss their advantages and disadvantages? Solution There are typically three types of accounting for investment made internally. 1) Cost or equity method: It is used when investor acquires < 20% of investee\'s voting stock (insignificant influence). 2) Equity method: Investor acquires 20% â€“ 50% of investee\'s voting stock (significant influence). 3) Consolidation Method Investor acquires > 50% of investee\'s voting stock (legal control). .

CCES Corporation acquires a controlling interest in Schmaling- Inc- CC.docx

rtodd544

Case 2-2 The Theoretical Foundation of Accounting Principles During the past several years, the FASB has attempted to strengthen the theoretical foundation for the development of accounting principles. Two of the most important results of this attempt are the Conceptual Framework Project and the Emerging Issues Task Force. During this same period, the FASB has been criticized for imposing too many standards on the financial reporting process, the so-called standards overload problem. Required: Solution 1. 1. The objective of the conceptual framework project is to develop an improved conceptual framework that provides a sound foundation for developing future accounting standards. Such a framework is essential to fulfilling the Board .

Case 2-2 The Theoretical Foundation of Accounting Principles During th.docx

rtodd544

Cap and dividend (adapted from Boyce and Riddle) Aggregate US demand for carbon emissions (or the marginal benefit of carbon emissions) is approximately: Q = 1,500,000,000 Solution 3. If the total cost is $ 400 then Q is: = 1,500,000,000 - 500,000 ($400) = 1,300,000,000 4. The corbon permits should give by the government is : = 1,300,000,000/ $200= 6,500,000 5. If the government collects taxes, it can be utilize for the welfare or development of the citizens of US 6. the amount is going to be distribute equal to all to the people of US 7. The tax impose on rich should be high with proportinate of their emit of carbon gases, and if the government distribute on the basis of equal per capita income the rich will be the beneficiaries and poor will be the sufferers. .

Cap and dividend (adapted from Boyce and Riddle) Aggregate US demand f.docx

rtodd544

Can you tell from the darkness of the color which foods have the most starch? List first four (4) (banana, potato, cereal and bread) in order to decreasing amount of starch. Solution The dark color appears on the reaction of iodine (titrator) with the food, the formation of dark blue color confirms the presence of starch in the food which can be formed due to the reaction of I2 and starch present in the food The starch content is highest in Banana, followed by Cereals, Bread and Potato Potato has starch content of 18-22% Bread has starch content of 40-44% Ceral has starch content of 60-80% Banana has starch content of 76-80% .

Can you tell from the darkness of the color which foods have the most.docx

rtodd544

Can the US government really stop advanced encryption techniques from failing into the hands of criminals. Solution So many hackers trying to daily enter government organization to steal data. Strong encryption consists giving good security to data. But hackers also some times decrypt data .so no one county have fully stop advanced encryption techniques from failing into the hands of criminals. US government has strong exporting rules on encryption productions .because US has some ability stop advanced encryption techniques from failing into the hands of criminals.. Encryption items specifically designed, developed, configured, adapted or modified for military applications (including command, control and intelligence applications) are controlled by the Department of State on the United States Munitions List. .

Can the US government really stop advanced encryption techniques from.docx

rtodd544

can you help me solve this and show the work so I can correct my mistake please 3) The decomposition of SO2Cl2 is first-order in SO2Clh and it has a half-life of 4.1 hours. If you begin with 1.6 x 10-3 mol of SO Cl2, how many hours elapse before the quantity of SO2Cl2 has decreased to 2.00 x 10-4 mol? (Chapter 14) Solution t1/2 = 4.1hours K = 0.693/t1/2 = 0.693/4.1 = 0.169hour^-1 [A0] = 1.6*10^-3 mol = 0.0016mol [A] = 2*10^-4 mol = 0.0002mol K = 2.303/t log[A0]/[A] t = 2.303/K log[A0]/[A] = 2.303/0.169 log0.0016/0.0002 = 13.627*0.903 = 12.3hours .

can you help me solve this and show the work so I can correct my mista.docx

rtodd544

Can someone show me the steps and also two examples on how to find which compound among four or five of them has the highest percentage of ionic character Solution The % of ionic character depends on the electronegativity difference between the two element which have been joined to form the compound Generally ionic character is highest for compounds between alkaline metals (electronegativity very low) and halogen (high value of electronegativity) The electronegativity trends increases from left to right in a period and decreases the down Hence the most ionic compound will be CsF (Flourie has the highest electronegativity on pauling scale equal to 4) The bonds of same element have zero ionic character i.e. F2,Cl2 etc .

Can someone show me the steps and also two examples on how to find whi.docx

rtodd544

Can someone suggest a hypothetical situation or scenario to exemplify Kosslyn Image Theory? Solution Imagination is cricial step in psychological theory It is a arguable pont that the imaginary is not just the ole form of internal representation, as an imagecannot present an object or scene without some interpretative function that picks out the salient features. In this hypothesis we can assume the five properties of imaginery: 1. Depcits info about brightness contrast etc 2. As the distance from center increase the activation degree decreases 3. The image surfacuce resoultion is limited to some context 4. The image is somewhat eliptical in shape 5. Images are more difficult to maintainm and store .

Can someone suggest a hypothetical situation or scenario to exemplify.docx

rtodd544

Can someone explain the more dilute the solution is (acid solution) the greater the degree of ionization? Can someone explain the more dilute the solution is (acid solution) the greater the degree of ionization? Solution Degree of Ionisation means no. Of ions increase. And degree of Ionisation is directly proportional to the degree of disassociation more will be the dissociation of solution more will be its no. Of ions . On dilution the degree of disassociation increase because water provides energy for dissociation of acid and thus degree of ionisation increase with dilution . .

Can someone explain the more dilute the solution is (acid solution) th.docx

rtodd544

can multilayers point to the same feature class Solution No , multiple layers cannot point to the same feature class, when you are publishing a map service with WFS capabilities it is not true. WFS service : If we use the WFS service to support transactions for editing (WFS-T), the source data for all the layers in the map must come from the same enterprise geodatabase; otherwise, the map cannot contain layers from multiple sources. Let us consider two or more layers in the map cannot reference the same feature class or have the same name. If they do, you will receive the error Workspace item or name is a duplicate . The name of the layer is the type name returned from WFS. .

can multilayers point to the same feature classSolutionNo- multiple la.docx

rtodd544

Calculate the pH of the resulting solution if 22.0 mL of 0.220 M HCl(aq) is added to (a) 32.0 mL of 0.220 M NaOH(aq). (b) 12.0 mL of 0.320 M NaOH(aq). Solution number of moles of HCl = 22*0.22 = 0.00484 mol number of moles of NaOH = 32*0.22 = 0.00704 mol number of moles excess = 0.00704 - 0.00484 = 0.0022 pOH = -log([OH-]) pOH = -log(0.0022*1000/(22+32)) pOH = 1.39 pH = 14 - 1.39 = 12.61 number of moles of NaOH = 12*0.32 = 0.00384 mol number of moles excess = 0.00484 - 0.00384 = 0.001 mol pH = -log([H+]) pH = -log(0.001*1000/(12+22)) pH = 1.531 .

Calculate the pH of the resulting solution if 22-0 mL of 0-220 M HCl(a.docx

rtodd544

Calculate the radius of a palladium atom, given that Pd has an FCC crystal structure, a density of 12.0 g/cm 3 , and an atomic weight of 106.4 g/mol. Solution Lets assume the radius to be r. In FCC, a*sqrt(2) = 4r Thus, a = 2sqrt(2)*r Volume of cell = a^3 = 16sqrt(2)r^3 = 22.627*r^3 Number of atoms in 1 cell = 4 mass of one cell = 4 * 106.4 / (6.02 * 10^23) = 7.069 * 10^-22 g Now, mass = vol * density Thus, 7.069 * 10^-22 = 22.627*r^3 * 12 r^3 = (7.069 * 10^-22) / (22.627 * 12) = 2.603 * 10^-24 cm^3 Thus, r = 1.37 * 10^-8 cm .

Calculate the radius of a palladium atom- given that Pd has an FCC cry.docx

rtodd544

More from rtodd544 (14)