Insert a code segment in the box below to call the previous function i.docx

R

Insert a code segment in the box below to call the previous function in order to compute and display 9^2 - Squareroot 9 = 78 9 squared - squareroot of 9 = 78 Feel free to declare any local variables that you think you may need: Solution Answer: public class Simplifysquareprogram { public static void main(String[] args) { simplification(); } public static void simplification() { int number = 9; double squareroot_number = Math.sqrt(number); int square_number=number * number; double output=square_number-squareroot_number; System.out.println(\"9 squared - square root of 9 =\"+output); } } .

Insert a code segment in the box below to call the previous function in order to compute and
display 9^2 - Squareroot 9 = 78 9 squared - squareroot of 9 = 78 Feel free to declare any local
variables that you think you may need:
Solution
Answer:
public class Simplifysquareprogram
{
public static void main(String[] args)
{
simplification();
}
public static void simplification()
{
int number = 9;
double squareroot_number = Math.sqrt(number);
int square_number=number * number;
double output=square_number-squareroot_number;
System.out.println("9 squared - square root of 9 ="+output);
}
}
Insert a code segment in the box below to call the previous function i.docx

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Insert a code segment in the box below to call the previous function i.docx

  • 1. Insert a code segment in the box below to call the previous function in order to compute and display 9^2 - Squareroot 9 = 78 9 squared - squareroot of 9 = 78 Feel free to declare any local variables that you think you may need: Solution Answer: public class Simplifysquareprogram { public static void main(String[] args) { simplification(); } public static void simplification() { int number = 9; double squareroot_number = Math.sqrt(number); int square_number=number * number; double output=square_number-squareroot_number; System.out.println("9 squared - square root of 9 ="+output); } }