rectangle problemThe length of a rectangle is 3 in. more than twic.pdf

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The length of a rectangle is 3 inches more than twice its width. The perimeter is given as 18 inches. Setting up two equations for the length, width, and perimeter and solving the system of equations reveals that the width of the rectangle is 2 inches.

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rectangle problem
The length of a rectangle is 3 in. more than twice its width. If the perimeter of the rectangle is 18
in., what are the width of the rectangle?
Solution
First, we set up two equations based on the information you have given.
L = 2w + 3
2L + 2W = 18
Now, we use the value for L in the first equation and substitute it into the second equation.
2 (2W + 3) + 2W = 18
4W + 6 + 2W = 18
6W = 12
W = 2
Now we use this value for W to determine L.
L = 2*2 + 3
L = 4 + 3
L = 7
So, the length is 7 inches and the width is 2 inches.

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