on the average, there are 5 messages sent per hour to a computer bulletin board. On a period of three hours, find the probability that more than 6 messages will be sent. please use poisson distribution. Solution X is the number of messages sent in an hour X ~ Po(5*3) i.e. X ~ Po(15) P(X > 6) = 1 - P(X <= 6) = 1 - possioncdf(15,6) = 1 - 0.0076319 = 0.9923681 = 0.992 (3sf).