For any truth table, there are 2n number of rows, where n = the number of variables (i.e. for a pq
truth table has 22 = 4 rows) P(AxB) = P(BxA)
Solution
Let A have n elements and B have n elements
Then I element in A can be mapped into any of the n elements in B.
Similarly II III IV etc
Thus each of m elements in A have n choices in B.
Hence no of elements in set AxB = m x n = mn.
Thus power set of (AxB) = 2mn
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Consider BXA
Each element in B has m choices in B.
That is each of n element there can be m elements in B.
Hence n(BXA) = nm = mn ( as commutative)
Power set has 2mn elements
Or P(AxB) = P(BxA)