This document provides an overview of the normal distribution and how to calculate probabilities and areas under the standard normal curve. It discusses the key properties of the normal distribution including that it is symmetric and bell-shaped. It also presents the process for finding areas in different regions of the standard normal distribution, including tails, between values with the same sign, between values with opposite signs, and cumulative areas. Examples are provided for calculating areas in each of these four cases. The document is intended as a lecture presentation for a Grade 11 statistics and probability class to teach students how to work with the normal distribution and standard normal curve.
4. The Normal Distribution
The Normal Distribution
The NORMAL DISTRIBUTION is a
continuous, symmetric, bell-shaped
distribution of a random variable. The
graph of this distribution is called a
NORMAL CURVE.
a normal curve
CABT Statistics & Probability – Grade 11 Lecture Presentation
5. The Normal Distribution
The Normal Distribution
The equation of the theoretical normal
distribution is given by the formula
2
2
2
1
2
x
f x e
where is the mean of the distribution, is
the standard deviation, and e and are
irrational constants (e = 2.718… and =
3.1415….)
CABT Statistics & Probability – Grade 11 Lecture Presentation
6. The Normal Distribution
Properties of the Normal
Distribution
1. The distribution curve is
bell-shaped.
2. The curve is symmetric
about its center, the mean.
3. The mean, the median,
and the mode coincide at
the center.
4. The width of the curve is
determined by the
standard deviation of the
distribution.CABT Statistics & Probability – Grade 11 Lecture Presentation
7. The Normal Distribution
Properties of the Normal
Distribution
5. The tails of the curve flatten
out indefinitely along the
horizontal axis, always
approaching the axis but
never touching it. That is,
the curve is asymptotic to
the base line.
6. The area under the curve is
1. Thus, it represents the
probability or proportion or
the percentage associated
with specific sets of
asymptotic to the x-axis
8. The Normal Distribution
The Distribution of Area
Under the Normal Curve
- a.k.a. the empirical rule or the
“68% - 95% - 99.7%” rule
The area under the part of a normal curve that
lies:
• within 1 standard deviation of the mean is
approximately 0.68, or 68%;
• within 2 standard deviations, about 0.95, or
95%
within 3 standard deviations, about 0.997,
CABT Statistics & Probability – Grade 11 Lecture Presentation
9. The Normal Distribution
The Distribution of Area
Under the Normal Curve
CABT Statistics & Probability – Grade 11 Lecture Presentation
10. The Normal Distribution
The Standard Normal
Distribution
The STANDARD NORMAL
DISTRIBUTION of a random variable
is a normal distribution with mean =
0 and standard deviation = 1.
The letter Z is used to denote the
standard normal random variable. The
specific value z of the r.v. Z is called
the z-score.
CABT Statistics & Probability – Grade 11 Lecture Presentation
11. The Normal Distribution
The Standard Normal
Distribution
The probability function of a random
variable Z with a standard normal
distribution by is given by
2
2
1
2
z
y p z e
CABT Statistics & Probability – Grade 11 Lecture Presentation
12. The Normal Distribution
The Standard Normal
Distribution
The graph of the standard normal
distribution
is shown below:
13. The Normal Distribution
Areas Under the Standard
Normal Curve
The Table of Areas under the Normal Curve
is also known as the z-Table.
The z-score is a measure of relative standing.
It is calculated by subtracting the mean from
the measurement X and then dividing the
result by the standard deviation.
The final result, the z-score, represents the
distance between a given measurement X and
the mean, expressed in standard deviations.
14. The Normal Distribution
The standard normal distribution table to be
used in this course gives areas under the
standard normal curve for the variable Z
ranging from 0 to a positive number z.
Areas Under the Standard
Normal Curve
15. The Normal Distribution
In the table, the area A
gives the
PROBABILITY that
the value of Z lies
between 0 and a
constant z0; i.e.
CABT Statistics & Probability – Grade 11 Lecture Presentation
00A P Z z
Areas Under the Standard
Normal Curve
16. The Normal Distribution
Four-Step Process in Finding the Areas Under
the Normal Curve Given a z-Value
Step 1. Express the given z-value into a three-digit
form.
Step 2. Using the z-Table, find the first two digits on
the left column.
Step 3. Match the third digit with the appropriate
column on the right.
Step 4. Read the area (or probability) at the
intersection of the row and the column. This is
CABT Statistics & Probability – Grade 11 Lecture Presentation
Areas Under the Standard
Normal Curve
17. The Normal Distribution
Find the area that corresponds to
z = 1.
The area is A = 0.3413
CABT Statistics & Probability – Grade 11 Lecture Presentation
Areas Under the Standard
Normal Curve
18. The Normal Distribution
Find the area that corresponds to
z = 2.58.
The area is A = 0.4951
CABT Statistics & Probability – Grade 11 Lecture Presentation
Areas Under the Standard
Normal Curve
19. The Normal Distribution
FACT: The area between 0 and a positive
value z is the same as the area between z
and 0.
To find the area between z and 0, use the
value in the table corresponding to positive z.
Both regions have the same
area.CABT Statistics & Probability – Grade 11 Lecture Presentation
Areas Under the Standard
Normal Curve
20. The Normal Distribution
The area that corresponds to
z = 2.58 is the same as the area
that corresponds to z = 2.58,
which is
A = 0.4951.
The area is A = 0.4951
CABT Statistics & Probability – Grade 11 Lecture Presentation
Areas Under the Standard
Normal Curve
21. The Normal Distribution
Probabilities and Areas Under
the Standard Normal Curve
Find the area that corresponds to
z = 1.15.
The area is A = 0.3749
CABT Statistics & Probability – Grade 11 Lecture Presentation
22. The Normal Distribution
What is the probability that the value
of a standard normal random variable
Z lies between
a. 0 and 1.28?
b. 2.07 and 0?
0 1.28
A = 0.3997
02.0
7A = 0.4808
CABT Statistics & Probability – Grade 11 Lecture Presentation
Areas Under the Standard
Normal Curve
24. The Normal Distribution
Finding areas of other regions
CABT Statistics & Probability – Grade 11 Lecture Presentation
tails - right of a positive z
or left of a negative z
between two z values
with the same sign
between two z values
with opposite signs
cumulative - left of a positive z
or right of a negative z
Areas Under the Standard
Normal Curve
25. The Normal Distribution
Finding areas of other regions
CASE REGION INVOLVED ILLUSTRATION
1
tails - right of a positive z
or left of a negative z
2
between two z values with
the same sign
3
between two z values with
opposite signs
4
cumulative - left of a
positive z or right of a
negative z
Areas Under the Standard
Normal Curve
26. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
To find the area at any
tail:
• Look up the z score to
get the area.
• Subtract the area from
0.5.
CASE 1: Finding areas of region in the TAILS
CABT Statistics & Probability – Grade 11 Lecture Presentation
27. The Normal Distribution
CASE 1: Finding areas of region in the TAILS
Probabilities and Areas Under the
Standard Normal Curve
To the RIGHT of or GREATER THAN +z:
00.5A P Z z A
To the LEFT of or LESS THAN z:
0.5 A P Z z P Z z
00.5A P Z z A
Let A0 be the area between 0 and +z (value in
table)
CABT Statistics & Probability – Grade 11 Lecture Presentation
28. The Normal Distribution
Find the area under the standard
normal curve for z greater than 2.
2
Look for the value in the
table corresponding to z =
2:
0 0.4772A
Subtract the table value from
0.5 to find the area.
0.5 0.4772 0.0228A
CABT Statistics & Probability – Grade 11 Lecture Presentation
Areas Under the Standard
Normal Curve
29. The Normal Distribution
2
NOTE: The area under the standard
normal curve for z greater than 2 (or to the
right of 2) is the same as the area for z
less than 2 (or to the left of 2).
The table value at z = 2 is
0 0.4772A
The area corresponding to z < 2 is
0.5 0.4772 0.0228A
Areas Under the Standard
Normal Curve
30. The Normal Distribution
Find the area to the left of z = 1.5.
Probabilities and Areas Under the
Standard Normal Curve
1.5
Look for the value in the table
corresponding to z = 1.5:
0 0.4332A
Subtract the table value from
0.5 to find the area.
0.5 0.4332A 0.0668
CABT Statistics & Probability – Grade 11 Lecture Presentation
31. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
Between two z scores on
the same side of the mean
(or with the SAME SIGN):
• Look up both z scores to
get the areas.
• Subtract the smaller
area from the larger
area.
CASE 2: Finding areas between two values
of z with the SAME SIGN
CABT Statistics & Probability – Grade 11 Lecture Presentation
32. The Normal Distribution
CASE 2: Finding areas between two values
of z with the SAME SIGN
Probabilities and Areas Under the
Standard Normal Curve
Let z1 = number nearer zero
z2 = number farther from zero
If A1 = area corresponding to z1
A2 = area corresponding to z2
2 1A A A
The area of the region between z1 and
z2 is
CABT Statistics & Probability – Grade 11 Lecture Presentation
33. The Normal Distribution
Find the area of the region
between
z = 1.23 and z = 2.57Let z1 = 1.23 and z2 =
2.57.
1.23 2.57
From the table:
For z1 : A1 = 0.3907
For z2 : A2 = 0.4911
The area of the region is
2 1A A A 0.4911 0.3907
0.1104
Areas Under the Standard
Normal Curve
34. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
Note: The area of the region between
z = 1.23 and z = 2.57 is EQUAL to the
area between z = 2.57 and z = 1.23.
Let z1 = 1.23 and z2 = 2.57. From the table:
-1.23-2.57
For z1 : A1 = 0.3907
For z2 : A2 = 0.4911
The area of the region is
2 1A A A 0.1104
CABT Statistics & Probability – Grade 11 Lecture Presentation
35. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
Find the area of the region
between
z = 0.96 and z = 0.36.Let z1 = 0.36 and z2 = 0.96. From the table:
1.23 2.57
For z1 (use z = 0.36): A1 =
0.1406
For z2 (use z = 0.96): A2 =
0.3395
The area of the region is
2 1A A A 0.3395 0.1406
0.1909
36. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
Between two z scores on
DIFFERENT sideS of the
mean (or with DIFFERENT
SIGNS):
• Look up both z scores to
get the areas.
• Add the two areas.
CASE 3: Finding areas between two values
of z with DIFFERENT SIGNS
CABT Statistics & Probability – Grade 11 Lecture Presentation
37. The Normal Distribution
CASE 3: Finding areas between two values
of z with DIFFERENT SIGNS
CABT Statistics & Probability – Grade 11 Lecture Presentation
Let z1 = negative z value
z2 = positive z value
If A1 = area corresponding to z1
A2 = area corresponding to z2
1 2A A A
The area of the region between z1 and
z2 is
Areas Under the Standard
Normal Curve
38. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
Find the area of the region
between
z = 2.46 and z = 1.55.Let z1 = 2.46 and z2 = 1.55. From the table:
-2.46 1.55
For z1 (use z = 2.46): A1 =
0.4931
For z2 (use z = 1.55): A2 =
0.4394
The area of the region is
1 2A A A 0.4931 0.4394
0.9325CABT Statistics & Probability – Grade 11 Lecture Presentation
39. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
To find the area to the left of
any positive z score or to
the right of a negative z
score:
CASE 4: Finding areas of regions to the
LEFT of a positive z or to the RIGHT of a
negative z
CABT Statistics & Probability – Grade 11 Lecture Presentation
• Look up the z score to get
the area.
• Add 0.5 to the area.
40. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
Find the area of the region to the
left of z = 2.37.
From the table, the area corresponding to z =
2.37 is
The area of the region is
00.5A A
0.5 0.4911 0.9911
0 0.4911A
2.37
CABT Statistics & Probability – Grade 11 Lecture Presentation
41. The Normal Distribution
Find the area of the region to the
right of z = 2.37.
From the table, the area corresponding to z =
2.37 is the same for z = 2.37:
The area of the region is
00.5A A
0.5 0.4911
0.9911
0 0.4911A
2.37
CABT Statistics & Probability – Grade 11 Lecture Presentation
Areas Under the Standard
Normal Curve
42. Check your
understanding
The Normal Distribution
CABT Statistics & Probability – Grade 11 Lecture Presentation
Determine the area of the indicated
region under the standard normal
curve.1. to the left of z = 1.31
2. to the right of z = 1.92
3. to the left of z = 2
4. between z = 1.23 and z = 1.9
5. between z = 1.98 and z = 1.46
6. between z = 3 and z = 1.5
0.9049
0.9726
0.0228
0.0806
0.0482
0.9319
43. The Normal Distribution
Probabilities and Areas Under the
Standard Normal Curve
Recall that the area under the graph of a
continuous probability function corresponds to
the value of a probability in an interval.
CABT Statistics & Probability – Grade 11 Lecture Presentation
PROBABILITY CORRESPONDING AREA
P(Z > a) to the right of a
P(Z < a) to the left of a
P( a < Z < b) between a and b
NOTE: The area won’t change even if “>” and
“<” are replaced by “” and “”, respectively.
44. The Normal Distribution
If Z is a standard normal random
variable, what is the probability
that
Probabilities and Areas Under the
Standard Normal Curve
a. 0 < Z < 0.33?
b. Z > 2?
c. Z < 1.67?
d. 1.03 < Z < 0.99?
Direct table value
Case 1
Case 4
Case 2
Case 3
CABT Statistics & Probability – Grade 11 Lecture Presentation
45. The Normal Distribution
If Z is a standard normal random
variable, what is the probability
that
a. 0 < Z < 0.33?
b. Z > 2?
c. Z < 1.67?
d. 1.03 < Z < 0.99?
Probabilities and Areas Under the
Standard Normal Curve
A = 0.1293
A = 0. 5 –
0.4772
=
0.0228A = 0. 5 +
0.4525
=
0.9525A = 0. 3485 – 0.3389=
0.0096A = 0. 4986 + 0.0793=
0.5779
CABT Statistics & Probability – Grade 11 Lecture Presentation
46. Check your
understanding
The Normal Distribution
CABT Statistics & Probability – Grade 11 Lecture Presentation
Given the random variable Z with a
standard normal distribution,
determine the following probabilities:
1. P(– 0.75 < Z < 0)
2. P(Z > 1.92)
3. P(Z < 1.11)
4. P(0.33 < Z < 0.99)
5. P(Z > 0.2)
0.2734
0.5 + 0.4726 = 0.9726
0.5 + 0.3665 = 0.8665
0.3389 0.1293 = 0.2096
0.5 0.0793 = 0.4207