This document discusses using integration by parts to solve an integral involving an exponential term, which results in the standard exponential distribution. The integral is defined as I/v (t- E[t])^2 f(t) dt = I/v^2. A link is provided to the Wikipedia page on exponential distributions for further information.

1. tv e- vt d t = I/v (t- E[t])2 f(t) d t = I/v2
Solution
Use integration by parts in the first question, you'll get the answer easily. It is
nothing but the standard exponential distribution.
http://en.wikipedia.org/wiki/Exponential_distribution