1. Two forces are applied on a 10-kg box on a horizontal frictionless floor as shown in the
following diagram. The acceleration of the box is 3N 5N a. zero b. 0.2 m/s to the right c. 0.8
m/s2 to the right d. 0.8 m/s to the left e. 0.2 m/s2 to the left
Solution
Given
mass of the box is m = 10 kg
the forces acting on it are
F1x = 5 N , F2x = -3 N
the net force acting on the box is by vector sum of the forces
F = F1x -F2x = 5 - 2 = 2 N
from Newton's second law the force acting on the mass mass due to which can accelerates
is
F = m*a
a = F/m
a = 2/10 m/s2
a = 0.2 m/s2
so the box can accelerates in the+x direction with an acceleration of 0.2 m/s2
finally
the answer is 0.2 m/s2 to the right option b <<<-------- answer