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# A solution containing 29-60 mg of an unknown protein per 27-0 mL solut.docx

tjames442
3 Feb 2023
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### A solution containing 29-60 mg of an unknown protein per 27-0 mL solut.docx

1. A solution containing 29.60 mg of an unknown protein per 27.0 mL solution was found to have an osmotic pressure of 3.65 torr at 35 ?C. What is the molar mass of the protein? Solution by definition osmotic pressure = C x R x T given osmotic pressure = 3.65 torr x ( 1 atm / 760 torr) = 0.0048 atm R= gas constant = 0.0821 L atm / mol K T = temperature = 35 C = 35 + 273 K = 308 K plug in the values 0.0048 atm = C x 0.0821 (L-atm / mol K) x 308 K C = 0.00019 mol/L so concentration of protein = 0.00019 mol / L volume of solution = 27 ml = 0.027 L now moles of protein = 0.027 L x 0.00019 mol / L = 5.128 x 10-6 mol now
2. molar mass of protein = 29.60 x 10-3 g / (5.128 x 10-6 mol) molar mass of protein = 5772 g/mol so molar mass of the protein is 5772 g/mol
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