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# A stream containing 60- octane and 40- hexadecane (mole basis) at 5-0.docx

tjames442
3 Feb 2023
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ENGINEERING CHEMICAL - Give Complete Written Solution with Picture (2).docx
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### A stream containing 60- octane and 40- hexadecane (mole basis) at 5-0.docx

1. A stream containing 60% octane and 40% hexadecane (mole basis) at 5.0 bar and 500 K is separated into vapour and liked streams at 4.0 bar and 500 K. At 500 K the vapour pressures are: The feed, while a single stream. Is a mixture of 13.54% vapour and 86.46% liquid. The product split is 32.02% in the vapour stream. 67.98% in the liquid stream. The heats of vaporization at 25 degree C are: Using Watsons equation, which uses critical temperature, normal boiling temperature, and the 25 degree C heat of vaporization, the heats of vaporization can be estimated at T = 500 K: Solution A similar problem : Example Type I Problem. Flash Vaporization for a Benzene + Toluene Stream Problem: A stream containing 35.0 mol % benzene and 65.0 mol % toluene is flowing at 100.0 mol/s, 100.0 o C, and 10 atm. It is flashed across a valve and into a flash drum held at 100.0 o C and 1.00 atm. What are the compositions and flow rates of the product streams, and what is the duty for this flash unit? Prepare solutions by a) hand calculations assuming Raoult
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