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on of a complex ion such as -Cu(NH)l (aq) 1 categorized as a(n) reacti.docx

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on of a complex ion such as [Cu(NH)l (aq) 1 categorized as a(n) reaction. \" __ (A) Arrhenius acid-base (B) Bronsted-Lowry acid-base (C) Lewis acid-base (D) oxidation-reduction 15. when balancing this half-reaction in basic solution,-- electrons are added to the side of the equation. MnO4 (aq) ? MnO2(aa) (A) 3. product (B) 3, reactant (C) 5, product (D) 5, reactant Which reaction has Standard Reduction Potentials, V the highest potential under standard 16. Pb\"(aq) + 2e ? Pb(s) -0.13 Sn\"(aq) + 2e-? Sn2-(aq) +0.15 Br(aq) + 2e-2Br(aq) +1 09 conditions? (A) Sn (aq)+ Pb(s) products (B) Br (ag)+ Sn (aq) products (C) Pb(s) + Br(aq) ? products (D) Pb (ag) Sn (aq)-products
Solution
The answer for the 14th question is as follows:
A lewis acid is one that is an electron acceptor in a reaction. Also Cu +2 in the reaction is positively charged and would readily accept electrons. So thinking of where does the electron that Cu +2 gains come from?
The electrons come from the lone pair on NH 3 .
Thus, we have a electron donor and an electron acceptor. Also, you can call Cu +2 and electrophile(lacking or deficient in electrons).
Thus we see that the copper ion is the lewis acid in the reaction as it accepts the lone pair of electrons from NH 3 Thus ammonia acts as the lewis base as it donates it\'s electrons. Thus, this reaction is an example of a lewis acid-base reaction.
Hence, option C is correct.
.

on of a complex ion such as [Cu(NH)l (aq) 1 categorized as a(n) reaction. \" __ (A) Arrhenius acid-base (B) Bronsted-Lowry acid-base (C) Lewis acid-base (D) oxidation-reduction 15. when balancing this half-reaction in basic solution,-- electrons are added to the side of the equation. MnO4 (aq) ? MnO2(aa) (A) 3. product (B) 3, reactant (C) 5, product (D) 5, reactant Which reaction has Standard Reduction Potentials, V the highest potential under standard 16. Pb\"(aq) + 2e ? Pb(s) -0.13 Sn\"(aq) + 2e-? Sn2-(aq) +0.15 Br(aq) + 2e-2Br(aq) +1 09 conditions? (A) Sn (aq)+ Pb(s) products (B) Br (ag)+ Sn (aq) products (C) Pb(s) + Br(aq) ? products (D) Pb (ag) Sn (aq)-products
Solution
The answer for the 14th question is as follows:
A lewis acid is one that is an electron acceptor in a reaction. Also Cu +2 in the reaction is positively charged and would readily accept electrons. So thinking of where does the electron that Cu +2 gains come from?
The electrons come from the lone pair on NH 3 .
Thus, we have a electron donor and an electron acceptor. Also, you can call Cu +2 and electrophile(lacking or deficient in electrons).
Thus we see that the copper ion is the lewis acid in the reaction as it accepts the lone pair of electrons from NH 3 Thus ammonia acts as the lewis base as it donates it\'s electrons. Thus, this reaction is an example of a lewis acid-base reaction.
Hence, option C is correct.
.

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on of a complex ion such as -Cu(NH)l (aq) 1 categorized as a(n) reacti.docx

  1. 1. on of a complex ion such as [Cu(NH)l (aq) 1 categorized as a(n) reaction. " __ (A) Arrhenius acid-base (B) Bronsted-Lowry acid-base (C) Lewis acid-base (D) oxidation-reduction 15. when balancing this half-reaction in basic solution,-- electrons are added to the side of the equation. MnO4 (aq) ? MnO2(aa) (A) 3. product (B) 3, reactant (C) 5, product (D) 5, reactant Which reaction has Standard Reduction Potentials, V the highest potential under standard 16. Pb"(aq) + 2e ? Pb(s) -0.13 Sn"(aq) + 2e-? Sn2-(aq) +0.15 Br(aq) + 2e-2Br(aq) +1 09 conditions? (A) Sn (aq)+ Pb(s) products (B) Br (ag)+ Sn (aq) products (C) Pb(s) + Br(aq) ? products (D) Pb (ag) Sn (aq)-products Solution The answer for the 14th question is as follows: A lewis acid is one that is an electron acceptor in a reaction. Also Cu +2 in the reaction is positively charged and would readily accept electrons. So thinking of where does the electron that Cu +2 gains come from? The electrons come from the lone pair on NH 3 . Thus, we have a electron donor and an electron acceptor. Also, you can call Cu +2 and electrophile(lacking or deficient in electrons). Thus we see that the copper ion is the lewis acid in the reaction as it accepts the lone pair of electrons from NH 3 Thus ammonia acts as the lewis base as it donates it's electrons. Thus, this reaction is an example of a lewis acid-base reaction. Hence, option C is correct.

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