A rigid tank contains .5 kmol of argon gas (Ar) and 2 kmol of nitrogen gas (N2) at 250 kPa and 280 K. The mixture is then heated to 400 K. Assume ideal gas behavior. Determine the following: 1. The tank volume (m^3) 2. The final pressure (kPa) of the mixture Solution P1 = initial pressure = 250 k pa T1 = 280 k T2 = 400k n = total mole of gas = 0.5 + 2 = 2.5 k mole v = volume of tank :: R = gas constant = 8.31 using gas law :: P1*V = nRT1 V = nRT1/P1 = 23.26 m^3 then using : P1/T1 = P2/T2 P2 = T2* P1/T1 = 357.14 k pa .