3. (25 points)A conducting spherical shell has inner radius A and thickness T. There is a larger, uncharged, concentic spherical conducting shell with inner radius B? and thickness T. The inner shell is given a charge a. Find the charge per unit area everywhere. (Show this in the figure above.) b. Find the electric potential difference between a point on the inside surface of the inner 2 pob shell and a point on the outside surface of the outer shell. o\'ziy c. What is the capacitance of this system? S3oit) d. If a second system of concentric spherical shells, with thickness T, and one with inner radius A2 and the second with ner radius B2 is attached to the above system by the wires shown, one going through tiny holes in the outer shells, what will be the final charges on the four shells, assuming the second system was originally neutral?
Solution
Inner radius = B 1
Thickness = T
Inner radius of inner shell = A 1 , Thickness = T
(a) Charge per unit area = Q / A
for r = A 1 + T ,
charge per unit area = Q o / 4*pi*(A 1 + T) 2
notice, i have simply used area of spherical surface formula
Similarly, for r = B 1 + T
charge per unit area = Q o / 4*pi*(B 1 + T) 2
for r = B 1
charge per unit area = - Q o / 4*pi*(B 1 ) 2
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(b) Point on inner surface of inner shell = A 1
Point on Outer surface of outer shell = B 1 + T
potential difference = kQ o (1/A 1 + T - 1/B 1 )
or, Potential difference = Q 0 / 4*pi*e o (1/A 1 + T - 1/B 1 )
where e is epsilon
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(c) C = QV
C = 4*pi*e o *B 1 (A 1 + T) / B 1 - A 1 - T
__________________________________________________________________________
(d) Not sure about this part , but may be we need to consider both charged and capacitance of whole system.
for the other system ,
C = 4*pi*e o *B 2 (A 2 + T) / B 2 - A 2 - T
.
3- (25 points)A conducting spherical shell has inner radius A and thic.docx
1. 3. (25 points)A conducting spherical shell has inner radius A and thickness T. There is a larger,
uncharged, concentic spherical conducting shell with inner radius B? and thickness T. The inner
shell is given a charge a. Find the charge per unit area everywhere. (Show this in the figure
above.) b. Find the electric potential difference between a point on the inside surface of the inner
2 pob shell and a point on the outside surface of the outer shell. o'ziy c. What is the capacitance
of this system? S3oit) d. If a second system of concentric spherical shells, with thickness T, and
one with inner radius A2 and the second with ner radius B2 is attached to the above system by
the wires shown, one going through tiny holes in the outer shells, what will be the final charges
on the four shells, assuming the second system was originally neutral?
Solution
Inner radius = B 1
Thickness = T
Inner radius of inner shell = A 1 , Thickness = T
(a) Charge per unit area = Q / A
for r = A 1 + T ,
charge per unit area = Q o / 4*pi*(A 1 + T) 2
notice, i have simply used area of spherical surface formula
Similarly, for r = B 1 + T
charge per unit area = Q o / 4*pi*(B 1 + T) 2
for r = B 1
charge per unit area = - Q o / 4*pi*(B 1 ) 2
______________________________________________________________________________
__________
2. (b) Point on inner surface of inner shell = A 1
Point on Outer surface of outer shell = B 1 + T
potential difference = kQ o (1/A 1 + T - 1/B 1 )
or, Potential difference = Q 0 / 4*pi*e o (1/A 1 + T - 1/B 1 )
where e is epsilon
______________________________________________________________________________
_______
(c) C = QV
C = 4*pi*e o *B 1 (A 1 + T) / B 1 - A 1 - T
__________________________________________________________________________
(d) Not sure about this part , but may be we need to consider both charged and capacitance of
whole system.
for the other system ,
C = 4*pi*e o *B 2 (A 2 + T) / B 2 - A 2 - T
