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Fgrsdg
1.
2.
The amount of
coconuts after on monkey has finished will equal b = (6/7)*(x-1) where b is the number of coconuts.
3.
Use the same
equation for the remaining monkeys
4.
5.
b = (6/7)*(x-1)
= amount after 1 monkey,
6.
c = (6/7)*(b-1)
= amount after 2 monkeys,
7.
d = (6/7)*(c-1)
= amount after 3 monkeys,
8.
e = (6/7)*(d-1)
= amount after 4 monkeys,
9.
f = (6/7)*(e-1)
= amount after 5 monkeys,
10.
g = (6/7)*(f-1)
= amount after 6 monkeys,
11.
h = (6/7)*(g-1)
= amount after 7 monkeys,
12.
i = (1/7)*(h-1)
= amount each got at the end.
13.
This works as
the original number of coconuts must be able to be subtracted from 6/7 when one is subtracted from the original number and form an integer
14.
15.
b = (6/7)*(x-1)
Multiply each side by 7
16.
7B=6*(x-1) Distribute out
the 6
17.
7B=6x-6 Put
the six on one side of the equation and the variables on the other
18.
6=7B+6x
19.
Repeat this process
with the remaining equations; you get
20.
6a - 7b
= 6,
21.
6b - 7c
= 6,
22.
6c - 7d
= 6,
23.
6d - 7e
= 6,
24.
6e - 7f
= 6,
25.
6f - 7g
= 6,
26.
6g - 7h
= 6,
27.
h - 7i
= 1
28.
29.
6^1x - 7^1b
= 6*(7^1 - 6^1)
30.
6^2x - 7^2c
= 6*(7^2 - 6^2)
31.
6^3x - 7^3d
= 6*(7^3 - 6^3)
32.
6^4x - 7^4e
= 6*(7^4 - 6^4)
33.
6^5x - 7^5f
= 6*(7^5 - 6^5)
34.
6^6x - 7^6g
= 6*(7^6 - 6^6)
35.
6^7x - 7^7h
= 6*(7^7 - 6^7)
36.
6^7x - 7^8i
= 7^8 – 6^8
37.
38.
In the last
problem;I is going to equal -1(again match the -7^8i on the left to the 7^8 on the right)
39.
40.
X=-6 + 7^8*T
41.
And
42.
I=-1 + 6^7*T
43.
T is any
integer
44.
45.
X=-6+7^8(1)
46.
X=5,764,795
47.
I=-1+6^7(1)
48.
I=279,935
49.
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