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STOICHIOMETRY LET’S ROCK WITH STOICHIOMETRY!!!
Let’s rock it!!! http://www.youtube.com/watch?v=rWCv-ymhpfY
[object Object],[object Object],[object Object]
FUN with STOICHIOMETRY!!! Balancing chemical equations Ratio and Proportion Limiting Reagent All You Know About Stoichiometry
[object Object],[object Object]
Which one would you pick??? ( yellow /  red ) Zn + HCl ---> ZnCl 2  + H 2 Zn + 2HCl ---> ZnCl 2  + H 2 (keep your choice in your mind…you might want to change your choice later  )
More fun…fun…fun… http://funbasedlearning.com/chemistry/chemBalancer/default.htm
Arrange the atoms in the box to form the respective products (Drag and drop the atoms) ,[object Object],H Na O H H CI Na O H CI
Arrange the atoms to form the respective products ,[object Object],H H S Na O O O O O H H Na O H H H H O O O O O O Na Na S
Arrange the atoms to form the reactants and the products ,[object Object],REACTANTS Mg Mg O O PRODUCTS Mg Mg O O
[object Object],[object Object],[object Object]
C 2 H 4  + O 2  CO 2  + H 2 O  C H O LEFT RIGHT 2 4 2 3 2 1 F I R S T
 
[object Object],[object Object],[object Object],[object Object],[object Object],S E C O N D
C 2 H 4  + 3O 2   2CO 2  + 2H 2 O  C H O LEFT RIGHT 2 4 6 6 4 2 F I N A L L Y
Coefficient and subscript ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
How many Aluminium and Chlorine atoms are present in 2 Aluminium chloride molecules? ,[object Object],[object Object],[object Object],6 2
SUBSCRIPT AND COEFFICIENT ,[object Object],[object Object],[object Object],3 2 6 2
[object Object],AI H CI H CI H CI H CI H CI H CI AI AI CI CI CI AI CI CI CI H H H H H H Are  the number of each atom present on the left (reactant) and the right (product) the same?
SHARPEN YOUR SKILLS!!! HOME http://funbasedlearning.com/chemistry/chemBalancer/default.htm
RATIOS & PROPORTION!!!
Mary was home alone…. She was craving for pancakes … She  remembered  that her mum always kept a stock of pancake mixture in the kitchen … She grabbed the box... And started reading the  instructions…
This is what the instruction said… 4 cups of mixture 2 cups of water 4 eggs Mix all, Beat well!!! Note : Each pack makes 12 large pancakes
But 12 is too many!!! She wanted only 3… Hmm…can you help her with the pancake mixture?
4 cups of mixture 2 cups of water 4 eggs 12 pancakes  ?eggs 3 pancakes  ? cups of mixture ? cups of water Can you help her with the correct measurements to make just 3 pancakes???
[object Object],[object Object],[object Object],4 cups of mixture 12 pancakes 3 pancakes ? cups of mixture 12/4 ? Can you decide how many cups of mixture will be needed?
[object Object],[object Object],[object Object]
4 cups of mixture 2 cups of water 4 eggs 12 pancakes  ?eggs 3 pancakes  ? cups of mixture ? cups of water 1 egg 3 pancakes  1 cup of mixture ½ cup of water ÷4 ÷4 ÷4 ÷4
The pancakes turned out so well for a first timer…Mary loved it !!! THANK YOU!
Can you apply the same idea here??? 1 mole of hydrochloric acid react with 1 mole of Sodium hydroxide solution to form 1 mole of sodium chloride and 1 mole of water. Can you figure out how many moles of water will be produced if 0.5 mole of acid is used???
How many moles of water produced??? ,[object Object],1 1 1 1 Can you determine how many mole of water will be produced if 0.5 mole of acid is used???
Now… consider this equation! ,[object Object],How many moles of sodium sulphate by proportion will be produced if 1 mole of sodium hydroxide is used? 1.0 0.5 2.0 0.25
Now let’s get into the lab and do some ‘real’ stuffs!!! ,[object Object],http://www.chemcollective.org/vlab/vlab.php
One final task before getting started!!! Explore  the reagents and the apparatus provided in the virtual lab… Explore your virtual lab!!! Get familiarized with it…
Get your task sheet and get going with your virtual lab… You are suppose to complete the task given using your virtual lab tools Get the word document  ‘ FUN WITH VIRTUAL LAB’ http://www.scribd.com/doc/66347972
Now more exciting activities… Beginner Intermediate Advance
For BEGINNERS….
[object Object],[object Object],[object Object],[object Object],[object Object],6 8 3 4
[object Object],[object Object],[object Object],[object Object],[object Object],20 eggs and 3kg of flour 15 eggs and 2.5kg of flour 15 eggs and 3kg of flour 10 eggs and 2.5kg of flour
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],HCI + NaOH  NaCI +  H 2 O 0.8 mol 1.0 mol 0.6 mol 0.5 mol
[object Object],[object Object],[object Object],H 2 SO 4  + 2NaOH    NA 2 SO 4  + 2H 2 O 0.5 mol 1.5 mol 1.0 mol 0.3 mol
 
For INTERMEDIATES…
[object Object],[object Object],[object Object],[object Object],H 2 SO 4    +   Mg                2MgSO 4    +   H 2 H 2 SO 4    +   Mg                MgSO 4    +   H 2 H 2 SO 4    +   2Mg                Mg 2 SO 4    +   H 2 2H 2 SO 4    +   Mg                2MgSO 4    +   H 2
    H 2 SO 4   +  Mg  MgSO 4  + H 2 ,[object Object],[object Object],[object Object],[object Object],[object Object],2 moles 0.5 mole 1 mole 3 moles
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],2 moles 0.5 mole 1 mole 3 moles
 
For ADVANCE…
2AI + 6HCI  2AICI 3  + 3H 2 ,[object Object],[object Object],[object Object],[object Object],[object Object],60cm 3 0.06cm 3 72dm 3 72cm 3
C 2 H 4  + 3O 2   2CO 2  + 2H 2 O ,[object Object],[object Object],[object Object],[object Object],0.9 dm 3 22 dm 3 21.6 dm 3 0.3 dm 3
Al + 3Cu(NO 3 ) 2    2Al(NO 3 )  3 +3Cu ,[object Object],[object Object],[object Object],[object Object],20.1g 28.8g 16.9g 10.3g
HOME
 
More + Less = LESS http://www.youtube.com/watch?v=RO1kErdVqqw
Can you answer these questions??? ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
OBJECTIVE ,[object Object],[object Object],[object Object]
LET’S BUILD STOOLS ,[object Object]
LET’S BUILD STOOLS ,[object Object]
THE TOP
[object Object]
[object Object]
What is a limiting reactant? ,[object Object],[object Object]
[object Object],5 carbon atoms 10 oxygen molecules 5 carbon dioxide molecules
[object Object],[object Object],[object Object],Carbon atoms Oxygen molecules Carbon atoms
 
Let’s do this together… ,[object Object],[object Object],[object Object],[object Object],[object Object]
HCI + NaOH  NaCI +H 2 O V= 50cm 3  M=1.0mol/   dm 3  V= 25cm 3  M=1.0mol/   dm 3  Mass=?  How would you determine what is the maximum mass of sodium chloride that can be produced ?
 
Inspect the equation to check if it was balance Calculate the number of mole of the reactants given to you Determine the limiting reagent Calculate the maximum mass of sodium  chloride that can be obtained
Now more exciting activities… Beginner Intermediate Advance
For BEGINNERS….
[object Object],[object Object],[object Object],[object Object],[object Object],85 95 90 80
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],magnesium Sulphuric acid hydrogen Magnesium sulphate
[object Object],[object Object],[object Object],[object Object],Volume of hydrogen No of mole of hydrogen No of mole of magnesium No of mole of sulphuric acid
 
For INTERMEDIATES…
[object Object],[object Object],[object Object],[object Object],2CuCI 2  + NaNO 3  2NaCI  + CuNO 3 CuCI 2  + 2NaNO 3  2NaCI + Cu(NO 3 ) 2 2CuCI 2  + NaNO 3  NaCI  + 2CuNO 3 CuCI 2  + 2NaNO 3  NaCI  + Cu(NO 3 ) 2
[object Object],[object Object],[object Object],[object Object],11g 13g 10g 12g
[object Object],[object Object],Copper chloride Copper  Sodium nitrate Sodium chloride
 
For the ADVANCED…
[object Object],[object Object],[object Object],[object Object],[object Object],0.2g of oxygen 6.4g of oxygen 1.207g of oxygen 0.083g of oxygen
[object Object],[object Object],[object Object],[object Object],[object Object],48.9g 50.9g 49.9g 51.9g
[object Object],[object Object],[object Object],[object Object],[object Object],265.5 g of aluminium sulphide 493 g of aluminium sulphide 265.5 g of water 227.5 g of water
HOME
 
OBJECTIVE ,[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object]
Interpret the question to form a chemical equation Recognize unbalanced and balanced reaction equations  Balance the unbalanced equation Explain excess and limiting reagent Calculate the mass of the yield
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Let us look at some solved examples…
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Interpret the question to form a chemical equation 25g of sodium chloride reacts with 50cm 3  of silver nitrate solution with the  concentration of 1.0 mol dm -3 . What is  the maximum amount of silver chloride  produced? Which one is the limiting  reagent? NaCI +  AgNO 3   AgCI +  NaNO 3
Recognize unbalanced and balanced reaction equations  NaCI +  AgNO 3   AgCI +  NaNO 3 Na Cl Ag 1 1 1 1 1 1 NO 3 1 1 BALANCED
[object Object],[object Object],[object Object],[object Object],Balance the unbalanced equation
Explain excess and limiting reagent ,[object Object],n NaCI   = Mass/ RMM = 25/(23 + 35.5) = 0.42 mol n AgNO3   = Mass/ RMM   =  50/[108+14+3(16)]   = 0.29 mol The limiting reagent in this experiment is Silver nitrate as the number of moles of it used is fewer than the number of moles of sodium chloride used
[object Object],[object Object],[object Object],Calculate the mass of the yield n= mass/RMM So, mass = n X RMM
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Interpret the question to form a chemical equation In a metal displacement reaction,65g of  aluminium reacted with 150g of Iron (ii) Oxide. What will be the excess reagent  at the end of the experiment? What needs to be added to maximize the production of Iron? Al +  Fe 2 O 3   Al 2 O 3   +  Fe
Recognize unbalanced and balanced reaction equations  Al +  Fe 2 O 3   Al 2 O 3   +  Fe Al Fe O 1 2 3 3 1 2 UNBALANCED
Balance the unbalanced equation Al +  Fe 2 O 3   Al 2 O 3  + Fe Al Fe O 1 2 3 3 1 1 BALANCED! X 2 X 2 2Al +  Fe 2 O 3   Al 2 O 3  + 2Fe
Explain excess and limiting reagent ,[object Object],n Al   = Mass/ RMM = 65/27 = 2.41 mol n  =Mass/ RMM = 150/[2(56) + 3(16)]   = 0.94mol The Excess reagent in this experiment is Aluminium as the number of moles of it used is more than the number of moles of Iron (II) Oxide used Fe 2 O 3
Calculate the mass of the yield No calculation for the amount of yield for this question, but it requires you to decide which reactant needs to be added to maximize the mass of yield Increase the mass of Iron(II) Oxide as it is the limiting reagent in this experiment!
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Interpret the question to form a chemical equation 50cm 3  of Sodium Hydroxide with the  concentration of 0.2mol/dm 3  was used to  neutralize 35cm 3  of sulphuric acid with  the same concentration. What will be the  maximum mass of water produced?  Which one is the limiting reagent in the  above reaction? NaOH + H 2 SO 4   Na 2 SO 4 +H 2 O
Recognize unbalanced and balanced reaction equation  NaOH + H 2 SO 4   Na 2 SO 4 +H 2 O Na O H 1 5 3 2 5 2 S 1 1 UNBALANCED
Balance the unbalanced equation NaOH + H 2 SO 4   Na 2 SO 4 +H 2 O 2NaOH + H 2 SO 4   Na 2 SO 4 + 2H 2 O Balancing the number of Sodium atoms, oxygen and hydrogen atoms will balance out the other elements…You don’t really have to balance each and everyone of them… BALANCED!
Explain excess and limiting reagent ,[object Object],n NaOH   = MV/1000 = (50 X 0.2)/1000 = 0.01 mol n  =MV/ 1000 = (35 X 0.2)/1000   = 0.007mol The limiting reagent in this experiment is sulphuric acid as the number of moles of it used is fewer than the number of mol of sodium hydroxide solution used H 2 SO 4 H 2 SO 4
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Calculate the mass of the yield n= mass/RMM So, mass = n X RMM
More and more fun activities… Please try to solve them before looking at the solutions!!! ,[object Object],[object Object],[object Object],[object Object]
HOME
[object Object],[object Object],HCI + NaOH  NaCI +H 2 O BACK
n = MV n HCI  = MV = [(1.0 mol/dm 3 ) (50 cm 3  )]÷1000 = 0.05 mol n NaOH  = MV = [(1.0 mol/dm 3 ) (25 cm 3  )]÷1000 = 0.025 mol BACK
n HCI  = 0.05 mol n NaOH  = 0.025 mol NaOH will be the limiting reagent as it is the limited one here. Only  0.025 mol of it is present. BACK
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
n HCI  =  n NaCI    =  0.025  mol Mass  = No. of mol x Relative molecular mass = 0.025mol x (23 + 35.5) = 0.025mol x 58.5 g/mol = 1.46g BACK
CORRECT!!!
WRONG!!! TRY AGAIN… 
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
WRONG!!! TRY AGAIN… 
CORRECT!!!
WRONG!!! TRY AGAIN… 
WRONG!!! TRY AGAIN… 

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