2. Objectives
• General Introduction to smart materials
and structures
• Recognize the nature of piezoelectric
material
• Understand the use of passive shunt
circuits
• Dynamics of structures with shunt
piezoelectric materials
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8. What is Piezoelectric Material?
• Piezoelectric Material is one that
possesses the property of converting
mechanical energy into electrical energy
and vice versa.
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9. Piezoelectric Materials
• Mechanical Stresses Electrical
Potential Field : Sensor (Direct Effect)
• Electric Field Mechanical Strain :
Actuator (Converse Effect)
Clark, Sounders, Gibbs, 1998
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11. Piezoelectric Sensor
• When mechanical stresses are applied on
the surface, electric charges are
generated (sensor, direct effect).
• If those charges are collected on a
conductor that is connected to a circuit,
current is generated
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12. Piezoelectric Actuator
• When electric potential (voltage) is applied
to the surface of the piezoelectric material,
mechanical strain is generated (actuator).
• If the piezoelectric material is bonded to a
surface of a structure, it forces the
structure to move with it.
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13. Other types of Piezo!
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14. 1-3 Piezocomposites
T 3 =c
E
33
S 3 +e 33 E 3
D 3 =e 33 S 3 + ε
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S
33
E3
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15. Active Fiber Composites (AFC)
c
eff
11
=c
E
11
+
v p e2
31
(v
C
e
eff
31
p
ε 33+ v ε
=
p
v ε 33 +v ε
ε
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33
=
33
)
ε 33 e 31
C
eff
S
ε 33 ε
(v
C
S
S
33
33
p
ε 33 + v ε
S
33
)
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16. Applications of Piezoelectric
Materials in Vibration Control
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25. Shunted Piezoelectric Material
(Physical)
•Mechanical energy is
converted to electrical
energy through
piezoelectric effect
•Electric charge is driven
by potential difference
through the circuit
•Energy is dissipated in
the resistance
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28. Mechanical Impedance /
Viscoelastic Analogy
Resistor Shunt
RES
Z 11 =1−
R-L Shunt
2
k 31
1+iρ3
2
δ
RSP
2
Z 11 =1−k 31 2 2
γ +δ rγ+ δ 2
r =RC ωn (dissipation tuning parameter )
s
γ= ( complex non-dimensional frequency )
ωn
ω
δ= e (resonant shunted piezoelectric frequency tuning parameter )
ωn
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29. Viscoelastic analogy
• The model of the shunted piezoelectric
patches, in many researches, is reduced
to an equivalent of a viscoelastic patch.
• But Piezoelectric patches are elements
that respond to the total strain rather than
the local strain!
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30. The Problem With Viscoelastic
Analogy!
Base structure
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32. Constitutive Relations
• The piezoelectric
effect appears in the
stress strain relations
of the piezoelectric
material in the form of
an extra electric term
• Similarly, the
mechanical effect
appears in the electric
relations
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S=s 11 T +d 31 E
D=d 31 T 1 +¿33 E
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33. Constitutive Relations
•
•
•
•
‘S’ (capital s) is the strain
‘T’ is the stress (N/m2)
‘E’ is the electric field (Volt/m)
‘s’ (small s) is the compliance; 1/stiffness
(m2/N)
• ‘D’ is the electric displacement, charge per
unit area (Coulomb/m)
• ¿ Electric permittivity (Farade/m)
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34. The Electromechanical Coupling
• d31 is called the electromechanical
coupling factor (m/Volt)
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35. Manipulating the Equations
• The electric displacement is
the charge per unit area:
• The rate of change of the
charge is the current:
• The electric field is the
electric potential per unit
length:
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Q
D=
A
1
I
D= ∫ Idt=
A
As
V
E=
t
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36. Using those relations:
• Using the
relations:
• Introducing the
capacitance:
• Or the electrical
admittance:
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S =s 11 T +
d 31
t
I = Ad 31 sT 1 +
V
A ∈33 s
t
V
I = Ad 31 sT 1 +CsV
I = Ad 31 sT 1 +YV
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37. For open circuit (I=0)
• We get:
• Using that into the
strain relation:
• Using the
expression for the
electric admittance:
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V =−
Ad 31 s
S =s 11 T −
(
S =s 11 1−
Y
T1
2
Asd 31
tY
d2
31
¿33 s 11
T1
)
T1
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38. The electromechanical coupling
factor
• Introducing the factor ‘k’:
(
2
S =s 11 1−k 31
)T 1
• ‘k’ is called the electromechanical coupling
factor (coefficient)
• ‘k’ presents the ratio between the mechanical
energy and the electrical energy stored in the
piezoelectric material.
• For the k13, the best conditions will give a value
of 0.4
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39. Different Conditions
• With open circuit conditions, the stiffness
of the piezoelectric material appears to be
higher (less compliance)
(
2
S =s 11 1−k 31
) T 1 == s
D
T1
• While for short circuit conditions, the
stiffness appears to be lower (more
compliance) S =s T =s E T
11
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40. Different Conditions
• Similar results could be obtained for the
electric properties; electric properties are
affected by the mechanical boundary
conditions.
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41. Damping of Structural Vibration
with Piezoelectric Materials and
Passive Electrical Networks
N. W. HAGOOD AND A. VON
FLOTOW
Journal of Sound and Vibration (1991)
146(2), 243-268
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42. The Constitutive Relations for
Piezoelectric Materials
• The constitutive relation is:
• Where:
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43. Constitutive relation (cont’d)
• The electric permiativity:
• Electromechanical
coupling:
• Mechanical
compliance:
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44. Electrical relation
• Into constitutive
relations:
• Where the
capacitance is:
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45. The Electric admittance
• Introducing the electric admittance:
• Generally; with a shunt circuit:
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47. Remember
• The electric admittance is
the reciprocal of the electric
impedance.
1
Z = EL
Y
EL
• Also, you may have up to
three circuits:
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48. From Constitutive Relations
• The voltage may be written as:
• Into the strain equation
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49. The Electromechanical Compliance
• The Electromechanical
Compliance
• Or
• Where
• Generally:
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50. The Mi matrices
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51. Uniaxial Loading Cases
• The compliance:
• Introducing the
electromechanical
coupling coefficient:
• The compliance
becomes:
• For open circuit
conditions
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52. Uniaxial Loading Cases
• For open circuit, the
compliance becomes:
• A similar expressions for
capacitance in case of
zero stress is:
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53. Uniaxial Loading Cases
• Introducing the
mechanical impedance:
(Which is the reciprocal
of the compliance)
• We may write the nondimensional mechanical
impedance:
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54. The Complex Modulus
• Now, let’s reintroduce the complex
modulus of the viscoelastic material:
• Where:
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55. Resistive Shunt Example
• For the case or resistive shunting, the
resistance and the capacitance are in
parallel 1
1
1
1 RCs+1
Z
EL
=
Z
D
+
Z
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SU
=Cs+
R
=
R
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56. Resistive Shunt Example
• Recall:
• Using the previous
results:
• Simplifying:
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ME
2
1−k ij
RES
Z jj =Z jj =
1−k 2
ij
(
RCs
1+ RCs
)
2
RES
Z jj =1−
k ij
1+( 1−k 2 ) RCs
ij
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57. Resistive Shunt Example
• Substituting s=iω and
• Introducing the non-dimensional
parameter ρ=RCω, we get:
Z RES =1−
jj
k2
ij
1+(
• Finally:
2
1−k ij
) ρi
(
RES
Z jj =
=1−
1−
2
k ij
1+(
2 2
1−k ij
)
ρ
ρ
)(
2
k ij
1+ (
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+
2 2
1−k ij
)
2
2
2
2
k ij ( 1−k ij ) ρi
2 2
1−k ij
1+ (
1+
)
2
k ij
1+ (
ρ2
ρ
1−k 2
ij
)ρ
2
i
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59. Homework #11
1. Derive the equations for the RL shunt
circuit.
2. Plot the frequency response of
piezoelectric bar with a shunt circuit (R &
RL)
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60. RL Shunt Example
• For the case or RL shunting, the resistance and
the inductance are in series and are in parallel
with the capacitance
2
1
1
1
1
LCs + RCs+1
= D + SU =Cs+
=
EL
Ls+ R
Ls+ R
Z
Z
Z
LCs 2 + RCs
Z EL =
LCs 2 + RCs+1
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61. RL Shunt Example
• Recall:
• Using the previous
results:
• Simplifying:
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2
ME
1−k ij
RSP
Z jj =Z jj =
2
1−k ij
Z RSP =
jj
(
LCs 2 + RCs
LCs 2 + RCs+1
1−k 2 ) ( LCs 2 + RCs+1 )
( ij
2
2
1+( 1−k ij ) ( LCs + RCs )
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62. RL Shunt Example
• Ignoring (1-k2) in the denominator:
ω2
e
Z RSP =1−k 2
jj
ij
ω2
n
2
2
2
ωe
ωe
s
s
+ 2 RC ω n
+ 2
2
ωn ω n
ωn ωn
Z RSP =1−k 2 2
jj
ij
δ
2
2
γ +δ rγ+δ
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63. RL Shunt Example
• Using the full
term:
(
( 1−k 2 )
ij
Z RSP =
jj
ω2
e
ω2
e
2
Z RSP =
jj
ωn
ω2
e
s
+ 2 RC
s+ 2
2
ωn
ωn ω n
ωn
(
2
+ ( 1−k ij )
ω2
n
(
( 1−k 2 )
ij
2
ωn
s 2 ωe
+ 2 RC
s
2
ωn
ω n ωn
)
)
Z RSP =
jj
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ωn
s2
+ RC
s +1
2
ωn
ωe
(
1+( 1−k 2 )
ij
ωn
s2
+ RC
s
2
ωn
ωe
)
)
1−k 2 ) ( γ 2 + δ 2 rγ + δ 2 )
( ij
2
2
2
2
δ + (1−k ij ) ( γ + δ rγ )
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64. RL Shunt Example: Hagood results
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66. Modulus of Elasticity
• Recall that:
• And:
• Where:
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67. Modulus of Elasticity
• Substituting:
• Getting the
stiffness:
• Simplifying:
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SU
s jj =
SU
E jj =
SU
Z jj
Lj s
Aj
SU
E jj =
=
D
s jj
SU
Z jj
Lj s
D ME
Z jj Z jj L j s
ME
Z jj
Aj
Aj
ME
=
Z jj
s E (1−k 2 )
jj
ij
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68. Finite Element Model
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69. Recall
• Recall the constitutive
relations of
Piezoelectric materials:
S 1 =s11 T 1 +d 31 E 3
D3 =d 31 T 1 +¿ 33 E 3
1
T 1 = D S 1 −h31 D3
• Rearranging the terms:
s
11
1
E 3 =−h 31 S 1 + S D 3
¿ 33
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70. Where:
h 31=
d 31
(
2
s11 ∈33 1−k 31
s
¿33=¿ 33 1−k 2
31
D
2
s11=s 11 1−k 31
(
(
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)
)
)
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71. Potential Energy
• Writing the expression for the potential
energy of the shunted piezoelectric
material:
l
l
1
1
U = ∫ S 1 T 1 Adx+ ∫ D3 E 3 Adx
20
20
l
(
S1
)
l
(
)
D3
1
1
U = ∫ S 1 D −h 31 D 3 Adx+ ∫ D3 −h31 D 3 + S Adx
20
2 0
s11
¿ 33
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72. The interpolation functions
( ) ()
( ) (
) () ⌊
( )
( )
( ) ()
x
x
u ( x )= 1− u1 +
u 2 = ⌊ N ( x ) ⌋ {u e }
l
l
x
x
e
d x = 1− d 1 +
d 2= N ( x ) ⌋ {d }
l
l
du x
1
1
S1 x =
= − u 1+
u2 = ⌊ N x ( x ) ⌋ {ue }
dx
l
l
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73. The Stiffness Matrices
l
1
k e = D ∫ { N x }⌊ N x ⌋ Adx
s 11 0
l
k eD =−h31∫ { N x } ⌊ N ⌋ Adx
l
0
1
k D= S ∫ { N } ⌊ N ⌋ Adx
¿33 0
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74. Kinetic Energy
l
1
2
T = ∫ ρ u Adx
˙
20
l
me = ρA ∫ { N } ⌊ N ⌋ dx
0
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75. External Work
l
l
l
˙
¨
˙
W =∫ VDbdx=∫ ( L I + RI ) Dbdx=∫ ( L Q+R Q ) Dbdx
0
0
0
l
¨
˙
¿∫ A ( L D+ R D ) Dbdx
0
l
m D= AbL∫ { N } ⌊ N ⌋ dx
0
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l
c D= AbR∫ { N } ⌊ N ⌋ dx
0
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76. Element Equation
[
me
0
0
mD
]{ } [ ]{ } [
ue
¨
0
+
¨
De 0
0
cD
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ue
ke
˙
+
˙
De
k De
k eD
kD
]{ } { }
ue
f
=
0
De
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