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a bolt is p cents, then x thosand bolts must be sold in a certain hardware store, where p=9-x/22.
How many bolts must be sold to maximize revenue?
Solution
The price of a bolt in terms of thousands of bolts sold x is p = 9 - x/22. The revenue earned when
1000 bolts are sold is R = x*(9 - x/22)
R = x*(9 - x/22)
=> R = x*9 - x^2/22
The expression R has to be maximized by changing x. Solve [(dR)/(dx) = 0]
=> 9 - 2x/22 = 0
=> x/11 = 9
=> x = 99
TO maximize revenue 99000 bolts should be sold.

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a bolt is p cents, then x thosand bolts must be sold in a certain ha.pdf

  • 1. a bolt is p cents, then x thosand bolts must be sold in a certain hardware store, where p=9-x/22. How many bolts must be sold to maximize revenue? Solution The price of a bolt in terms of thousands of bolts sold x is p = 9 - x/22. The revenue earned when 1000 bolts are sold is R = x*(9 - x/22) R = x*(9 - x/22) => R = x*9 - x^2/22 The expression R has to be maximized by changing x. Solve [(dR)/(dx) = 0] => 9 - 2x/22 = 0 => x/11 = 9 => x = 99 TO maximize revenue 99000 bolts should be sold.