Question 1 0/1 pts What does the following code print? for ( unsigned 1=5;1 se e; 1 ) f cout ee 1 ee is * Compilation error, won't fun. It painta but it loops forcyer Every object has access to its own address through a pointer called Which line contains the error? You can assume that Account is defined, and contains a method named setBalance which takes a double as an argument..

1. Question 1 0/1 pts What does the following code print? for ( unsigned 1=5;1 se e; 1 ) f cout ee 1
ee is * Compilation error, won't fun. It painta but it loops forcyer
Every object has access to its own address through a pointer called
Which line contains the error? You can assume that Account is defined, and contains a method
named setBalance which takes a double as an argument.