Just download this and do some specific changes in the name section and roll no section . and submit it as it is to your teacher this will surely work and help you out your class 12th board practicals exam . no worries ! ENJOY :) !

1. COMPUTER SCIENCE
Practical File
On
C++ PROGRAMS
&
MY SQL
ROLL NO . :-
Class –
Submitted By :-
C++ PROGRAMS

2. INDEX
Q1.Enter name , age and salary and display it by using outside
the class member .
Q2. Program which gives the squares of all the odd numbers
stored in an array .
Q3.Program to store numbers in an array and allow user to
enter any number which he/she wants to find in array .(Binary
Search)
Q4.Program for copy constructor .
Q5.Enter numbers in an array in any order and it will give the
output of numbers in ascending order .
Q6. Enter any number from 2 digit to 5 digit and the output
will be the sum of all the distinguish digits of the numbers .
Q7.Enter rows and columns and the output will be the sum of
the diagonals .
Q8. Enter item no. , price and quantity in a class .
Q9.Enter any line or character in a file and press * to exit the
program .
Q10. Program will read the words which starts from vowels
stored in a file .
Q11. Enter employee no , name , age , salary and store it in a
file.

3. Q12. Deleting the information of employee by entering the
employee number .
Q13. Enter any number and its power and the output will the
power of the number .
Q14. Enter 3 strings and the output will show the longest
string and the shortest string .
Q.15 Enter any number and the output will be all the prime
numbers up to that number .
Q16. Selection sort
Q17. Using loop concept the program will give the output of
numbers making a right triangle .
Q18. Program for Stacks and Queue .
Q.19Enter two arrays and the output will be the merge of two
arrays .
Q20. Sequence sort .
Q.SQL QUERIES AND OUTPUT .
Q1.Enter name , age and salary and display it by using outside
the class member .
#include<iostream.h>
#include<conio.h>
class abc

4. {
//private:
char n[20];
int a;
float sal;
public:
void getdata(void)
{
cout<<"nEnter name ";
cin>>n;
cout<<"nEnter age ";
cin>>a;
cout<<"nEnter salary ";
cin>>sal;
}
void putdata(void)
{
cout<<"nnNAME IS "<<n;
cout<<"nAGE IS "<<a;
cout<<"nSALARY IS "<<sal;
}
};
main()
{
abc p;
clrscr();
p.getdata();
p.putdata();
getch();
}

5. OUTPUT

6. Q2. Program which gives the squares of all the odd numbers
stored in an array .
#include<iostream.h>
#include<conio.h>
main()
{
int a[20],i,x;
clrscr();
cout<<"nEnter no of elements ";
cin>>x;
for(i=0;i<x;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nnArr1: ";
for(i=0;i<x;i++)
cout<<" "<<a[i];
cout<<"nnArr1: ";
for(i=0;i<x;i++)
{
if(a[i]%2==1)
a[i]=a[i]*a[i];
cout<<" "<<a[i];
}
getch();
}

7. OUTPUT

8. Q3.Program to store numbers in an array and allow user to
enter any number which he/she wants to find in array .(Binary
Search)
#include<iostream.h>
#include<conio.h>
main()
{
int a[20],n,i,no,low=0,high,mid,f=0;
clrscr();
cout<<"nEnter no of elements ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
cout<<"nEnter no to be search ";
cin>>no;
high=n-1;
while(low<=high && f==0)
{
mid=(low+high)/2;
if(a[mid]==no)
{
cout<<"nn"<<no<<" store at "<<mid+1;
f=1;
break;
}
else if(no>a[mid])
low=mid+1;
else
high=mid-1;
}
if(f==0)
cout<<"nn"<<no<<" does not exist";
getch();
}

9. OUTPUT

10. Q4.Program for copy constructor .
#include<iostream.h>
#include<conio.h>
#include<string.h>
class data
{
char n[20];
int age;
float sal;
public:
data(){}
data(char x[],int a,float k)
{
strcpy(n,x);
age=a;
sal=k;
}
data(data &p)
{
strcpy(n,p.n);
age=p.age;//+20;
sal=p.sal;//+1000;
}
display()
{
cout<<"nnNAME : "<<n;
cout<<"nnAGE : "<<age;
cout<<"nnSalary: "<<sal;
}
};
main()
{
clrscr();
data d("ajay",44,5000); //implicit caling
data d1(d);
data d2=d;
data d3;
d3=d2;
d.display();
d1.display();
d2.display();

11. d3.display();
getch();
}
OUTPUT
Q5.Enter numbers in an array in any order and it will give the
output of numbers in ascending order .(Bubble Sort)

12. #include<iostream.h>
#include<conio.h>
void main()
{
int a[20],n,i,j,t;
clrscr();
cout<<"nEnter no of elements in A ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
for(i=0;i<n;i++)
for(j=0;j<n-i-1;j++)
if(a[j]>a[j+1])
{
t=a[j];
a[j]=a[j+1];
a[j+1]=t;
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
getch();
}
OUTPUT

13. Q6. Enter any number from 2 digit to 5 digit and the output
will be the sum of all the distinguish digits of the numbers .
#include<iostream.h>
#include<conio.h>

14. main()
{
int a=0,b=0,c;
clrscr();
cout<<"nEnter value for A ";
cin>>a;
while(a>0) // for(;a>0;) or for(i=a;i>0;i=i/10)
{
c=a%10;
b=b+c;
a=a/10;
}
cout<<"nSum of digits "<<b;
getch();
}
OUTPUT
Q7.Enter rows and columns and the output will be the sum of
the diagonals .
#include<iostream.h>
#include<conio.h>
main()
{

15. int a[10][10],i,j,r,c;
clrscr();
cout<<"nEnter no of rows ";
cin>>r;
cout<<"nEnter no of Col ";
cin>>c;
for(i=0;i<r;i++)
for(j=0;j<c;j++)
{
cout<<"nEnter no ";
cin>>a[i][j];
}
int sum=0,sum1=0;
for(i=0;i<r;i++)
{
cout<<"n";
for(j=0;j<c;j++)
{
cout<<" "<<a[i][j];
/// if(i==j) //&& a[i][j]>0)
// cout<<a[i][j];
// else
// cout<<" ";
//sum=sum+a[i][j];
/* if(i+j==r-1)// && a[i][j]>0)
cout<<a[i][j];
else
cout<<" "; */
if(i==j)
sum1=sum1+a[i][j];
}
}
for(i=0;i<r;i++)
{
cout<<"n";
for(j=0;j<c;j++)
{
// cout<<" "<<a[i][j];
/* if(i==j) //&& a[i][j]>0)
cout<<a[i][j];
else
cout<<" ";*/
//sum=sum+a[i][j];
if(i+j==r-1)// && a[i][j]>0)

16. // cout<<a[i][j];
// else
// cout<<" ";
sum=sum+a[i][j];
}
}
cout<<"nnFirst diagonal sum "<<sum1;
cout<<"nnSecond diagonal sum "<<sum;
getch();
}
OUTPUT
Q8. Enter item no. , price and quantity in a class .
#include<iostream.h>
#include<conio.h>
class dd
{

17. char item[20];
int pr,qty;
public:
void getdata();
void putdata();
};
void dd::getdata()
{
cout<<"nEnter item name ";
cin>>item;
cout<<"nEnter price ";
cin>>pr;
cout<<"nEnter quantity ";
cin>>qty;
}
void dd::putdata()
{
cout<<"nnItem name:"<<item;
cout<<"nnPrice: "<<pr;
cout<<"nnQty:"<<qty;
}
main()
{
dd a1,o1,k1;
clrscr();
a1.getdata();
o1.getdata();
k1.getdata();
a1.putdata();
o1.putdata();
k1.putdata();
getch();
}
OUTPUT

18. Q9.Enter any line or character in a file and press * to exit the
program .

19. #include<iostream.h>
#include<fstream.h>
#include<conio.h>
main()
{
char ch;
clrscr();
ofstream f1("emp"); //implicit
//ofstream f1;
//f1.open("emp",ios::out); //explicit
cout<<"nEnter char ";
while(1) //infinity
{
ch=getche(); // to input a single charactor by keybord.
if(ch=='*')
break;
if(ch==13)
{
cout<<"n";
f1<<'n';
}
f1<<ch;
}
f1.close();
//getch();
}
OUTPUT

20. Q10. Program will read the words which starts from vowels
stored in a file .

21. #include<iostream.h>
#include<fstream.h>
#include<conio.h>
main()
{
char ch[80];
int cnt=0;
clrscr();
ifstream f1("emp");
ofstream f2("temp");
while(!f1.eof())
{
f1>>ch;
cout<<ch<<"n";
if(ch[0]=='a' || ch[0]=='e' || ch[0]=='o' || ch[0]=='i' || ch[0]=='u')
f2<<"n"<<ch;
}
f1.close();
f2.close();
cout<<"nnName start with vowels nn";
f1.open("temp",ios::in);
while(f1) //while(!f1.eof())
{
f1>>ch;
cout<<"n"<<ch;
if(f1.eof())
break;
}
f1.close();
getch();
}
OUTPUT

22. Q11. Enter employee no , name , age , salary and store it in a
file.
#include<iostream.h>

23. #include<conio.h>
#include<fstream.h>
int row=5,col=2;
class abc
{
private:
int empno;
char n[20];
int age;
float sal;
public:
void getdata()
{
char ch;
cin.get(ch); // To empty buffer
cout<<"nEnter employee no ";
cin>>empno;
cout<<"nEnter name ";
cin>>n;
cout<<"nEnter age ";
cin>>age;
cout<<"nEnter salary ";
cin>>sal;
}
void putdata()
{
// gotoxy(col,row);
cout<<"n"<<empno;
// gotoxy(col+10,row);
cout<<"t"<<n;
// gotoxy(col+25,row);
cout<<"t"<<age;
// gotoxy(col+35,row);
cout<<"t"<<sal;
// row++;
}
};
main()
{
clrscr();
abc p,p1;
fstream f1("emp5.txt",ios::in|ios::out|ios::binary);
int i;
for(i=0;i<3;i++)
{

24. p.getdata();
f1.write((char *)&p,sizeof(p));
}
cout<<"nnEMPNOtNAMEtAGEtSALARYn";
f1.seekg(0);
//f1.clear();
//clrscr();
for(i=0;i<3;i++)
{
f1.read((char*)&p1,sizeof(p1));
p1.putdata();
}
f1.close();
getch();
}
OUTPUT

26. Q12. Deleting the information of employee by entering the
employee number .
#include<iostream.h>
#include<conio.h>
#include<fstream.h>
#include<stdio.h>
class abc
{
private:
int empno;
char n[20];
int age;
float sal;
public:
void getdata()
{
cout<<"nEnter employee no ";
cin>>empno;
cout<<"nEnter name ";
cin>>n;
cout<<"nEnter age ";
cin>>age;
cout<<"nEnter salary ";
cin>>sal;
}
void putdata()
{
cout<<"nn"<<empno<<"t"<<n<<"t"<<age<<"t"<<sal;
}
int get_empno()
{
return empno;
}
};
main()
{
abc p,p1;
clrscr();
ifstream f1("emp5.txt",ios::in|ios::binary);
ofstream f2("temp",ios::out|ios::binary);
int i,emp;
cout<<"nnNAMEtAGEtSALARY";

27. f1.clear();
f1.seekg(0);
//for(i=0;i<4;i++)
while(!f1.eof())
{
f1.read((char*)&p1,sizeof(p1));
if(f1.eof())
break;
p1.putdata();
}
cout<<"nEnter employee no ";
cin>>emp;
f1.clear();
f1.seekg(0);
//while(f1)
while(!f1.eof())
{
f1.read((char*)&p1,sizeof(p1));
if(f1.eof())
break;
if(emp!=p1.get_empno())
f2.write((char*)&p1,sizeof(p1));
}
f1.close();
f2.close();
remove("emp5.txt");
rename("temp","emp5.txt");
f1.open("emp5.txt",ios::in|ios::binary);
cout<<"nnNAMEtAGEtSALARY";
f1.seekg(0);
//for(i=0;i<3;i++)
while(!f1.eof())
{
f1.read((char*)&p1,sizeof(p1));
if(f1.eof())
break;
p1.putdata();
}
f1.close();
getch();
}

28. OUTPUT
Q13. Enter any number and its power and the output will the
power of the number .
#include<iostream.h>

29. #include<conio.h>
#include<math.h>
#define CUBE(a,b) pow(a,b)
//a>b?a:b
main()
{
int x,y,z;
clrscr();
cout<<"nEnter base value ";
cin>>x;
cout<<"nEnter power ";
cin>>y;
z=CUBE(x,y);
cout<<"n"<<z;
getch();
}
OUTPUT
Q14. Enter 3 strings and the output will show the longest
string and the shortest string .
#include<iostream.h>
#include<conio.h>
#include<string.h>

30. main()
{
char n[20],n1[20],n2[20];
int l1,l2,l3;
clrscr();
cout<<"nEnter String1 ";
cin>>n;
cout<<"nEnter String2 ";
cin>>n1;
cout<<"nEnter String3 ";
cin>>n2;
l1=strlen(n);
l2=strlen(n1);
l3=strlen(n2);
(l1>l2 && l1>l3) ?cout<<"nLong: "<<n:(l2>l1 && l2>l3) ? cout<<"nLong: "<<n1
:cout<<"nLong: "<<n2;
(l1<l2 && l1<l3)?cout<<"nshort:"<<n:(l2<l1 && l2<l3)?
cout<<"nshort:"<<n1:cout<<"nshort:"<<n2;
getch();
}
OUTPUT

31. Q.15 Enter any number and the output will be all the prime
numbers up to that number .
#include<iostream.h>
#include<conio.h>

32. main()
{
int n,i,j,p;
clrscr();
cout<<"nEnter no of N ";
cin>>n;
for(i=1;i<=n;i++)
{
p=0;
for(j=2;j<=i/2;j++)
if(i%j==0)
p=1;
if(p==0)
cout<<" "<<i;
}
getch();
}
OUTPUT
Q16. Selection sort
#include<iostream.h>
#include<conio.h>
void main()
{

33. int a[20],n,i,j,t,min,p;
clrscr();
cout<<"nEnter no of elements in A ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
for(i=0;i<n;i++)
{
min=a[i];
p=i;
for(j=i;j<n;j++)
{
if(a[j]<min)
{
min=a[j];
p=j;
}
}
t=a[i];
a[i]=a[p];
a[p]=t;
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
getch();
}
OUTPUT

34. Q17. Using loop concept the program will give the output of
numbers making a right triangle .
#include<iostream.h>
#include<conio.h>

35. main()
{
int i,j;
clrscr();
for(i=1;i<=4;i++)
{
cout<<"nn";
for(j=1;j<=i;j++)
cout<<" "<<i;
}
getch();
}
OUTPUT
Q18. Program for Stacks and Queue .
#include<iostream.h>
#include<conio.h>
#include<stdlib.h>
struct queue

36. {
int x;
queue *next;
}*front=NULL,*rear;
void insert(int);
void delnode();
void display();
void main()
{
int a,ch;
clrscr();
do
{
cout<<"nEnter 1 for Insert";
cout<<"nEnter 2 for Delete";
cout<<"nEnter 3 for display";
cout<<"nEnter 4 for exit";
cout<<"nnEnter your choice ";
cin>>ch;
switch(ch)
{
case 1: cout<<"nEnter no for insert ";
cin>>a;
insert(a);
break;
case 2: delnode();
break;
case 3: display();
break;
case 4: exit(0);
}
}
while(1);
getch();
}
void insert(int no) // char str[]
{
queue *ptr;
ptr=new queue; // strcpy(ptr->n,str)
// ptr=(struct queue*)malloc(sizeof(struct queue));
ptr->x=no;
ptr->next=NULL;
if(front==NULL)
{

37. front=ptr;
rear=ptr;
}
else
{
rear->next=ptr;
rear=ptr;
}
}
void delnode()
{
int p;
queue *ptr;
if(front==NULL)
{
cout<<"nnQueue is Empty";
return;
}
p=front->x; //strcpy(p,front->n)
ptr=front;
front=front->next;
delete ptr;
cout<<"nndeleted element "<<p<<"n";
}
void display()
{
queue *ptr;
cout<<"nQueue now:- n";
for(ptr=front;ptr!=NULL;ptr=ptr->next)
cout<<" "<<ptr->x;
}
OUTPUT

39. Q.19Enter two arrays and the output will be the merge of two
arrays .

40. # include <iostream.h>
# include <conio.h>
main()
{
int arr1[100],arr2[100],arr3[100],c,i=0,j=0,k=0,size1,size2;
clrscr();
cout<<"n enter no of element of arr1 ";
cin>>size1;
for (i=0;i<size1;i++)
{
cout<<"n enter no. ";
cin>>arr1[i];
}
cout<<"n enter no of element of arr2 ";
cin>>size2;
for (i=0;i<size2;i++)
{
cout<<"n enter no. ";
cin>>arr2[i];
}
cout<<"n arr1 ";
for (i=0;i<size1;i++)
cout<<" "<<arr1[i];
cout<<"n arr2 ";
for (i=0;i<size2;i++)
cout<<" "<<arr2[i];
i=0;j=0;k=0;
while (i<size1 && j<size2)
{
if (arr1[i]<arr2[j])
arr3[k++]=arr1[i++];
else if (arr2[j]<arr1[i])
arr3[k++]=arr2[j++];
else
i++;
}
while (i<size1)
arr3[k++]=arr1[i++];
while (j<size2)
arr3[k++]=arr2[j++];

41. cout<<"n arr3 ";
for (i=0;i<k;i++)
cout<<" "<<arr3[i];
getch();
}
OUTPUT
Q20.Sequence Sort (Insertion Sort)
#include<iostream.h>
#include<conio.h>
void main()

42. {
int a[20],n,i,j,t;
clrscr();
cout<<"nEnter no of elements in A ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"nEnter no ";
cin>>a[i];
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
for(i=0;i<n;i++)
for(j=i+1;j<n;j++)
if(a[i]>a[j])
{
t=a[i];
a[i]=a[j];
a[j]=t;
}
cout<<"nn";
for(i=0;i<n;i++)
cout<<" "<<a[i];
getch();
}
OUTPUT

43. My SQL

44. School homework
QUERIES
Ques 1. mysql> select ename ,sal,dept_no from empl
where commission is null ;

45. Ques 2. mysql> select ename ,sal,dept_no from empl where
commission is not null;
Ques 3. mysql> select * from empl where sal between
1000 and 2500;

46. Ques 4. mysql> select ename from empl where ename like
‘a%’ ;
Ques 5 . mysql> select concat (ename,dept_no)as “name
dept” from empl;

47. Ques 6 . mysql> select lower(ename) “empl name” from
empl;
Ques 7 . mysql> select upper(ename) “empl name” from
empl;

48. Ques 8 . mysql> select substr(job,1,5) from empl where
empno=8888 or empno=8900;
Ques 9 . mysql> select job,instr (job,’le’)as “le in ename”
from empl;

49. Ques 10 . mysql> select ename, length (ename)as “name
length” from empl where empno <=8888 ;

50. OUTPUT QUESTIONS
Ques 1 . mysql> select left(‘Informatices practices’,5) ;
Ques 2 . mysql> select right (‘Informatices practices’,5);
Ques 3 . mysql> select mid(‘Informatices practices’,6,9);

51. Ques 4 . mysql> select ltrim(‘ akshit’);
Ques 5 . mysql> select rtrim(‘akshit ‘);