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KALKULUS 1
TEKNIK INFORMATIKA
UNIVERSITAS INDRAPRASTA PGRI
DEDY YUSUF ADITYA
PERTEMUAN 2
PERSAMAAN MATEMATIKA
• PENGERTIAN PERSAMAAN DALAM BENTUK MATEMATIKA
• PENYELESAIAN MASALAH TENTANG PERSAMAAN LINIER SATU VARIABEL
• PENYELESAIAN MASALAH TENTANG PERSAMAAN KUADARAT
PENGERTIAN PERSAMAAN DALAM BENTUK
MATEMATIKA
KESAMAAN : SUATU KALIMAT MATEMATIKA YANG TIDAK MEMILIKI VARIABLE DENGAN TANDA
HUBUNG “=”.
MISAL: 2+3 = 5
PERSAMAAN: SUATU KALIMAT MATEMATIKA YANG MEMILIKI VARIABLE DENGAN TANDA “=”,
SEHINGGA MEMERLUKAN PENYELESAIAN KHUSUS UNTUK MENCARI NILAI VARIABEL TSB.
MISAL: 2X -5 = 9
A. Persamaan Linear
1. PENGERTIAN PERSAMAAN LINEAR
PERSAMAN ADALAH KALIMAT TERBUKA YANG MENGANDUNG HUBUNGAN (RELASI) SAMA DENGAN. SEDANGKAN PERSAMAAN LINEAR ADALAH
SUATU PERSAMAAN YANG PANGKAT TERTINGGI DARI VARIABELNYA ADALAH SATU ATAU BERDERAJAT SATU.
2. PERSAMAAN LINEAR SATU VARIABEL
A = KOEFISIEN DARI X
X = VARIABEL
B = KONSTANTA
CONTOH:
4X + 8 = 0
68 -18 = 0
SIFAT-SIFAT PERSAMAAN LINEAR
A. NILAI PERSAMN TIDAK BERUBAH, JIKA :
1) KEDUA RUAS DITAMBAH ATAU DIKURANGI BILANGAN YANG SAMA.
2) KEDUA RUAS DIKALIKAN ATAU DIBAGI BILANGAN YANG SAMA.
B. SUATU PERSAMAAN JIKA DIPINDAHKAN RUAS, MAKA :
1) PENJUMLAHAN BERUBAH MENJADI PENGURANGAN DAN SEBALIKNYA.
2) PERKALIAN BERUBAH MENJADI PEMBAGIAN DAN SEBALIKNYA.
CONTOH 1
CONTOH 2
PERSAMAAN KUADRAT
PENTYELESAIAN PERSAMAAN KUADRAT
1. MEMFAKTORKAN
2. MELENGKAPKAN KUADRAT SEMPURNA
3. MENGGUNAKAN RUMUS ABC
1) SELESAIKAN X2 – 5X + 6 = 0 !
JAWAB:
X2 – 5X + 6 = 0
 (X – 3)(X – 2)= 0
 X – 3 = 0 ATAU X -2 = 0
X = 3 ATAU X = 2
JADI HP = {3, 2}
MEMFAKTORKAN
MELENGKAPKAN KUADRAT SEMPURNA
RUMUS ABC
3. SIFAT-SIFAT AKAR PERSAMAAN KUADRAT
SIFAT-SIFAT AKAR PERSAMAAN KUADRAT YANG
MENYANGKUT BANYAKNYA AKAR PERSAMAAN
KUADRAT, DITENTUKAN OLEH NILAI
YAITU D = B2 – 4AC.
D > 0  KEDUA AKAR REAL DAN BERBEDA
D = 0  KEDUA AKAR SAMA (KEMBAR)
D < 0  PERSAMAAN KUADRAT TIDAK MEMPUNYAI
AKAR NYATA
SOAL
SELESAIKAN DENGAN MEMFAKTORKAN
X2 + 3X + 2 = 0
2X2 + 5X + 2 = 0
X2 – 4X = 0
2X2 – 18 = 0
SELESAIKAN DENGAN MELENGKAPKAN KUADRAT SEMPURNA
X2 - 2X – 3 = 0
4X2 – 4X + 1 = 0
X2 - 9X + 9 = 0
SELESAIKAN DENGAN RUMUS ABC
6X2 + 23 X + 20 = 0
15X2 + 19X – 132 = 0
(2X + 5) (X -9) = 11 – 4X
2X2 – (X – 3 )2 = - 2

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KALKULUS SEMESTER 1 UNINDRA PERTEMUAN 2

  • 1. KALKULUS 1 TEKNIK INFORMATIKA UNIVERSITAS INDRAPRASTA PGRI DEDY YUSUF ADITYA
  • 2. PERTEMUAN 2 PERSAMAAN MATEMATIKA • PENGERTIAN PERSAMAAN DALAM BENTUK MATEMATIKA • PENYELESAIAN MASALAH TENTANG PERSAMAAN LINIER SATU VARIABEL • PENYELESAIAN MASALAH TENTANG PERSAMAAN KUADARAT
  • 3. PENGERTIAN PERSAMAAN DALAM BENTUK MATEMATIKA KESAMAAN : SUATU KALIMAT MATEMATIKA YANG TIDAK MEMILIKI VARIABLE DENGAN TANDA HUBUNG “=”. MISAL: 2+3 = 5 PERSAMAAN: SUATU KALIMAT MATEMATIKA YANG MEMILIKI VARIABLE DENGAN TANDA “=”, SEHINGGA MEMERLUKAN PENYELESAIAN KHUSUS UNTUK MENCARI NILAI VARIABEL TSB. MISAL: 2X -5 = 9
  • 4. A. Persamaan Linear 1. PENGERTIAN PERSAMAAN LINEAR PERSAMAN ADALAH KALIMAT TERBUKA YANG MENGANDUNG HUBUNGAN (RELASI) SAMA DENGAN. SEDANGKAN PERSAMAAN LINEAR ADALAH SUATU PERSAMAAN YANG PANGKAT TERTINGGI DARI VARIABELNYA ADALAH SATU ATAU BERDERAJAT SATU. 2. PERSAMAAN LINEAR SATU VARIABEL A = KOEFISIEN DARI X X = VARIABEL B = KONSTANTA CONTOH: 4X + 8 = 0 68 -18 = 0
  • 5. SIFAT-SIFAT PERSAMAAN LINEAR A. NILAI PERSAMN TIDAK BERUBAH, JIKA : 1) KEDUA RUAS DITAMBAH ATAU DIKURANGI BILANGAN YANG SAMA. 2) KEDUA RUAS DIKALIKAN ATAU DIBAGI BILANGAN YANG SAMA. B. SUATU PERSAMAAN JIKA DIPINDAHKAN RUAS, MAKA : 1) PENJUMLAHAN BERUBAH MENJADI PENGURANGAN DAN SEBALIKNYA. 2) PERKALIAN BERUBAH MENJADI PEMBAGIAN DAN SEBALIKNYA.
  • 9. PENTYELESAIAN PERSAMAAN KUADRAT 1. MEMFAKTORKAN 2. MELENGKAPKAN KUADRAT SEMPURNA 3. MENGGUNAKAN RUMUS ABC
  • 10. 1) SELESAIKAN X2 – 5X + 6 = 0 ! JAWAB: X2 – 5X + 6 = 0  (X – 3)(X – 2)= 0  X – 3 = 0 ATAU X -2 = 0 X = 3 ATAU X = 2 JADI HP = {3, 2} MEMFAKTORKAN
  • 13. 3. SIFAT-SIFAT AKAR PERSAMAAN KUADRAT SIFAT-SIFAT AKAR PERSAMAAN KUADRAT YANG MENYANGKUT BANYAKNYA AKAR PERSAMAAN KUADRAT, DITENTUKAN OLEH NILAI YAITU D = B2 – 4AC. D > 0  KEDUA AKAR REAL DAN BERBEDA D = 0  KEDUA AKAR SAMA (KEMBAR) D < 0  PERSAMAAN KUADRAT TIDAK MEMPUNYAI AKAR NYATA
  • 14. SOAL SELESAIKAN DENGAN MEMFAKTORKAN X2 + 3X + 2 = 0 2X2 + 5X + 2 = 0 X2 – 4X = 0 2X2 – 18 = 0 SELESAIKAN DENGAN MELENGKAPKAN KUADRAT SEMPURNA X2 - 2X – 3 = 0 4X2 – 4X + 1 = 0 X2 - 9X + 9 = 0 SELESAIKAN DENGAN RUMUS ABC 6X2 + 23 X + 20 = 0 15X2 + 19X – 132 = 0 (2X + 5) (X -9) = 11 – 4X 2X2 – (X – 3 )2 = - 2