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EXTRACTION
presented by:
CECILLE ABOAGYE DINAH ADOMAKO EMMANUEL BERKO
INTRODUCTION
• Method of removal of a soluble fraction in the form of
a solution from an insoluble medium with the help of
a suitable solvent.
• Process by which a solute is transferred from one
phase to a new phase.
• Removal of soluble constituents from a phase with the
means of suitable solvent.
• Separation can be due to gravitational force or
TYPES OF EXTRACTION
• Liquid-Liquid (Solvent extraction)
• Solid-Liquid (Leaching)
• Gas-Liquid (Absorption)
LIQUID-LIQUID
• Involves using a liquid solvent to remove a liquid
component from a liquid mixture.
• The component dissolves preferably in the solvent.
(Lewis, 2007)
APPLICATION OF LIQUID-LIQUID
EXTRACTION
• Removal of vitamins from aqueous solutions
• Aromatic compounds from crude oil fractions
SOLID-LIQUID
• Allows soluble components to be removed from solids
using a solvent.
• Soluble material is dissolved into the solvent and
solvent is evaporated to recover the solute(s) in
powder or crystalline form.
(Lewis, 2007)
APPLICATION OF SOLID-LIQUID
EXTRACTION
• Drinkable coffee (solvent with dissolved flavors).
• Obtaining oil from oil seeds
• Leaching of metal salts from ore
GAS-LIQUID
• This involves the use of a densified gas (solvent) to
extract a medium from a liquid mixture.
• Heavy volatile compounds often require this process.
• Principle behind extraction is Change in Pressure
and/or Temperature.
APPLICATION OF GAS-LIQUID
EXTRACTION
• Solvent used mostly is Carbon dioxide (CO2) and
Extracts are usually Esters, Alcohols etc.
extra
ct
CONSIDERING SELECTION OF A
SOLVENT
• Solvent must form a separate phase from the feed
solution.
• Able to extract the solute from the feed solution.
• Chemical reactivity and stability
• Flammability and Toxicity
• Cost analysis of process.
FACTORS THAT AFFECT RATE OF
EXTRACTION
Holding time – (depending on the solvent and solute of
interest)
• The longer the holding time, the more solutes are
extracted.
• Takes a shorter time if the solute is easily soluble in
the solvent.
Temperature
• the higher the temperature the faster the rate of
FACTORS contd.
Surface area of the solids exposed to the solvent
• the larger the surface area, the faster the rate of
extraction.
• implies reduction of size for solids.
Viscosity of the solvent
• the thicker the solvent, the slower and more difficult
the rate of extraction.
• the solvent would not be able to penetrate into the
EQUIPMENT USED
(EXTRACTOR)
SINGLE STEP MIXER – (SEPARATOR)
•It is the simplest form of extraction
•Uses the principle of gravitational force.
•Has a High efficiency rate of extraction per
step.
•Requires large amounts of solvent.
• Hence expensive.
Solvent
MIXER-SETTLER-CASCADE
• This involves a multiple stage separation of liquid
mixtures.
There are two designs:
• Box type – mixing and settling zones are separated by
plates
• Tower type – the single steps are one above the other
so that less ground area is used.
CENTRIFUGAL EXTRACTORS
• Heavier phase is transported to the periphery and the
lighter phase to the center.
• Centrifugal force is responsible for the counter current
flow of the phases.
• There’s high throughput, low amounts of solvent
needed.
• High cost of operations.
APPLICATION TO COFFEE
EXTRACTION
PRINCIPLES
CONCEPT
• Coffee extraction is a solid-liquid type of extraction.
• Solvent used is water.
• Extract of interest are soluble flavors.
• Generally involves the transfer of solutes from a solid
(coffee grains) to a fluid (water).
FACTORS CONSIDERED
• Quantity of coffee grains/water used (mass/weight).
• Grind precision (size particles).
• Correct degree of extraction (efficiency).
• Controlled by correct Temperature and Time.
SCHEMATIC DIAGRAM OF THE COFFEE
GRAIN
• Øh – volume fraction of
intergranular pore
• (1– Øh) – volume fraction of
grains
• Øc – soluble volume fraction
• Øs,i – insoluble volume
fraction
SETUP FOR THE EXTRACTION
INTERACTION OF WATER & COFFEE
GRAINS
Terms Used
Total Dissolved Solids (TDS)
• TDS is expressed in parts per million (ppm).
Strength
• Also known as "solubles concentration", measured by
Total Dissolved Solids – how concentrated or watery
the coffee is.
Brew ratio
• The ratio of coffee grounds (mass) to water (volume)
• how much coffee is used for a given quantity of water.
EQUATION INVOLVED
Extraction yield (%)
• The percentage by mass of coffee grounds that ends
up dissolved in the brewed coffee.
Extraction yield % =
Brewed Coffee[g] x TDS[%]
Coffee Grounds[g]
NB: TDS (mg/L) = 𝑤𝑒𝑖𝑔ℎ𝑡 𝑜𝑓 𝑟𝑒𝑠𝑖𝑑𝑢𝑒(𝑚𝑔) ×1000
𝑚𝑙 𝑜𝑓 𝑠𝑎𝑚𝑝𝑙𝑒
EXAMPLE
• 18 grams of coffee was placed in an espresso and this
brewed 36 grams of coffee from it. It is observed that 10%
of solids are dissolved from the grounds. Calculate the
extraction yield of this coffee grounds.
Assumption: 1 milliliter (ml) of water = 1 gram of water
• 𝐸𝑥𝑡𝑟𝑎𝑐𝑡𝑖𝑜𝑛 𝑦𝑖𝑒𝑙𝑑 = 36𝑔 𝑏𝑟𝑒𝑤𝑒𝑑 𝑐𝑜𝑓𝑓𝑒𝑒 × 10% 𝑇𝐷𝑆
18𝑔 (𝑐𝑜𝑓𝑓𝑒𝑒 𝑔𝑟𝑜𝑢𝑛𝑑𝑠)
= 20%
CONCLUSION
• Substance distribution between two liquids determines
its potential to be extracted.
• Extraction generally involves separation of elements.
• Solutes can be obtained by concentrating impurities.
• Solutes can form part of the solvent as a desired
solution.
REFERENCES
• Lewis, R. J. (2007). Liquid-Liquid Extraction. PreLab,
73–92.
https://doi.org/10.1002/9780470114735.hawley098
99
• Gamse, T. (n.d). Extraction. Department of chemical
engineering and environmental technology, Graz
university of technology.
• http://www.cst.ur.ac.rw/library/Food%20Science%20b
ooks/batch1/Food%20Processing%20Technology%20Pr
Thank
you

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Extraction Methods in Processing Industry

  • 1. EXTRACTION presented by: CECILLE ABOAGYE DINAH ADOMAKO EMMANUEL BERKO
  • 2. INTRODUCTION • Method of removal of a soluble fraction in the form of a solution from an insoluble medium with the help of a suitable solvent. • Process by which a solute is transferred from one phase to a new phase. • Removal of soluble constituents from a phase with the means of suitable solvent. • Separation can be due to gravitational force or
  • 3. TYPES OF EXTRACTION • Liquid-Liquid (Solvent extraction) • Solid-Liquid (Leaching) • Gas-Liquid (Absorption)
  • 4. LIQUID-LIQUID • Involves using a liquid solvent to remove a liquid component from a liquid mixture. • The component dissolves preferably in the solvent. (Lewis, 2007)
  • 5. APPLICATION OF LIQUID-LIQUID EXTRACTION • Removal of vitamins from aqueous solutions • Aromatic compounds from crude oil fractions
  • 6. SOLID-LIQUID • Allows soluble components to be removed from solids using a solvent. • Soluble material is dissolved into the solvent and solvent is evaporated to recover the solute(s) in powder or crystalline form. (Lewis, 2007)
  • 7. APPLICATION OF SOLID-LIQUID EXTRACTION • Drinkable coffee (solvent with dissolved flavors). • Obtaining oil from oil seeds • Leaching of metal salts from ore
  • 8. GAS-LIQUID • This involves the use of a densified gas (solvent) to extract a medium from a liquid mixture. • Heavy volatile compounds often require this process. • Principle behind extraction is Change in Pressure and/or Temperature.
  • 9. APPLICATION OF GAS-LIQUID EXTRACTION • Solvent used mostly is Carbon dioxide (CO2) and Extracts are usually Esters, Alcohols etc. extra ct
  • 10. CONSIDERING SELECTION OF A SOLVENT • Solvent must form a separate phase from the feed solution. • Able to extract the solute from the feed solution. • Chemical reactivity and stability • Flammability and Toxicity • Cost analysis of process.
  • 11. FACTORS THAT AFFECT RATE OF EXTRACTION Holding time – (depending on the solvent and solute of interest) • The longer the holding time, the more solutes are extracted. • Takes a shorter time if the solute is easily soluble in the solvent. Temperature • the higher the temperature the faster the rate of
  • 12. FACTORS contd. Surface area of the solids exposed to the solvent • the larger the surface area, the faster the rate of extraction. • implies reduction of size for solids. Viscosity of the solvent • the thicker the solvent, the slower and more difficult the rate of extraction. • the solvent would not be able to penetrate into the
  • 14. SINGLE STEP MIXER – (SEPARATOR) •It is the simplest form of extraction •Uses the principle of gravitational force. •Has a High efficiency rate of extraction per step. •Requires large amounts of solvent. • Hence expensive.
  • 16. MIXER-SETTLER-CASCADE • This involves a multiple stage separation of liquid mixtures. There are two designs: • Box type – mixing and settling zones are separated by plates • Tower type – the single steps are one above the other so that less ground area is used.
  • 17.
  • 18. CENTRIFUGAL EXTRACTORS • Heavier phase is transported to the periphery and the lighter phase to the center. • Centrifugal force is responsible for the counter current flow of the phases. • There’s high throughput, low amounts of solvent needed. • High cost of operations.
  • 19.
  • 21. CONCEPT • Coffee extraction is a solid-liquid type of extraction. • Solvent used is water. • Extract of interest are soluble flavors. • Generally involves the transfer of solutes from a solid (coffee grains) to a fluid (water).
  • 22. FACTORS CONSIDERED • Quantity of coffee grains/water used (mass/weight). • Grind precision (size particles). • Correct degree of extraction (efficiency). • Controlled by correct Temperature and Time.
  • 23. SCHEMATIC DIAGRAM OF THE COFFEE GRAIN • Øh – volume fraction of intergranular pore • (1– Øh) – volume fraction of grains • Øc – soluble volume fraction • Øs,i – insoluble volume fraction
  • 24. SETUP FOR THE EXTRACTION
  • 25. INTERACTION OF WATER & COFFEE GRAINS
  • 26. Terms Used Total Dissolved Solids (TDS) • TDS is expressed in parts per million (ppm). Strength • Also known as "solubles concentration", measured by Total Dissolved Solids – how concentrated or watery the coffee is. Brew ratio • The ratio of coffee grounds (mass) to water (volume) • how much coffee is used for a given quantity of water.
  • 27. EQUATION INVOLVED Extraction yield (%) • The percentage by mass of coffee grounds that ends up dissolved in the brewed coffee. Extraction yield % = Brewed Coffee[g] x TDS[%] Coffee Grounds[g] NB: TDS (mg/L) = 𝑤𝑒𝑖𝑔ℎ𝑡 𝑜𝑓 𝑟𝑒𝑠𝑖𝑑𝑢𝑒(𝑚𝑔) ×1000 𝑚𝑙 𝑜𝑓 𝑠𝑎𝑚𝑝𝑙𝑒
  • 28. EXAMPLE • 18 grams of coffee was placed in an espresso and this brewed 36 grams of coffee from it. It is observed that 10% of solids are dissolved from the grounds. Calculate the extraction yield of this coffee grounds. Assumption: 1 milliliter (ml) of water = 1 gram of water • 𝐸𝑥𝑡𝑟𝑎𝑐𝑡𝑖𝑜𝑛 𝑦𝑖𝑒𝑙𝑑 = 36𝑔 𝑏𝑟𝑒𝑤𝑒𝑑 𝑐𝑜𝑓𝑓𝑒𝑒 × 10% 𝑇𝐷𝑆 18𝑔 (𝑐𝑜𝑓𝑓𝑒𝑒 𝑔𝑟𝑜𝑢𝑛𝑑𝑠) = 20%
  • 29. CONCLUSION • Substance distribution between two liquids determines its potential to be extracted. • Extraction generally involves separation of elements. • Solutes can be obtained by concentrating impurities. • Solutes can form part of the solvent as a desired solution.
  • 30. REFERENCES • Lewis, R. J. (2007). Liquid-Liquid Extraction. PreLab, 73–92. https://doi.org/10.1002/9780470114735.hawley098 99 • Gamse, T. (n.d). Extraction. Department of chemical engineering and environmental technology, Graz university of technology. • http://www.cst.ur.ac.rw/library/Food%20Science%20b ooks/batch1/Food%20Processing%20Technology%20Pr

Notes de l'éditeur

  1. Solids are reduced in sized to allow for larger surface area during extraction process.
  2. Compare experimental to total of solution to obtain %age
  3. Temperature range of coffee is 91–94 °C Ideal yield is widely agreed to be 20%±2% (18%–22%).