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ESTIMATION OF HEAT
DEMAND IN BUILDINGS




      PPRE, SS 10/11
      OLDENBURG        HERENA TORIO
CONTENTS
     •       INTRODUCTION
              – ENERGY SITUATION IN BUILDING SECTOR

     •       PHYSICAL PRINCIPLES
              – HEAT TRANSFER
              – MOISTURE TRANSFER

     •       ENERGY BALANCES
              – STEADY STATE BEHAVIOR
              – DYNAMIC BEHAVIOR - THERMAL INERTIA

     •       CALCULATION METHODS
              – MONTHLY METHOD
              – SIMPLIFIED METHOD




05.05.2011                      SS 10/11              2
INTRODUCTION                 PHYS. PPLES.                   ENERGY BALANCES                             CALC. METHODS


                                                         ENERGY SITUATION

    •   ENERGY CONSUMPTION IN
        GERMANY                                                                           Lighting,
                                                                       Domestic              5%
                    Energy consumption by sectors (Germany)            hot water
                                                                       demand,
                                                                         13%

             Industry, 27%




                                                                                                               Space
                                                                                                              heating,
                                                                                                                81%

                                              Households,
         Transport, 28%                          45% Source: VDEW-Materialien: Endenergieverbrauch in Deutschland, 2002




    05.05.2011                                       SS 10/11                                                             3
INTRODUCTION                PHYS. PPLES.             ENERGY BALANCES                                CALC. METHODS


                                                   ENERGY SITUATION

    •   FUELS USED IN GERMANY TO SUPPLY THE SPACE HEATING
        DEMAND

                              Electricity 4%
                                               Others 8%
                                                                                          Renewables are
                                                                                              here!
                 Distric heating 7%
                                                              Natural gas 43%
                      Carbon 2%




                           Gasoil 36%



                                                   Source: VDEW-Materialien: Endenergieverbrauch in Deutschland, 2002




    05.05.2011                                  SS 10/11                                                            4
INTRODUCTION       PHYS. PPLES.         ENERGY BALANCES      CALC. METHODS


                                      ENERGY SITUATION
    IN GERMANY EnEV - “Energie-einsparverordnung”:
          – Limits the maximal energy demand for buildings according
            to their constructive details
          – Establishes a calculation method for the energy demand of
            a building -> basis for comparison
          – Defines different building “categories” according to their
            energy consumption




    05.05.2011                     SS 10/11                          5
INTRODUCTION     PHYS. PPLES.        ENERGY BALANCES   CALC. METHODS



                                ENERGY SITUATION




    05.05.2011                  SS 10/11                       6
INTRODUCTION     PHYS. PPLES.        ENERGY BALANCES   CALC. METHODS


                                   ENERGY SITUATION

         Heat demand:
         • Typical building: 80 – 300 kWh/m2a

         • “Low Energy house” : 40 – 79 kWh/m2a

         • “Three-liters house”: 16 – 39 kWh/m2a

         • “Passive house”: max. 15 kWh/m2a

         • “Zero-Energy house”: 0 kWh/m2a


    05.05.2011                  SS 10/11                       7
INTRODUCTION        PHYS. PPLES.          ENERGY BALANCES       CALC. METHODS


                                        ENERGY SITUATION
    RENEWABLE ENERGY HEAT STANDARD
      “EEWärmegesetz”:
       – Approved July08 ->
         Jan 09
       – Application to new
         buildings




         • Biogas 30%
         • Solar: 15%, 0.03-0.04m2coll/m2living area
         • Others (biofuels, wood, geothermal or environmental heat) 50%


    05.05.2011                       SS 10/11                              8
INTRODUCTION        PHYS. PPLES.               ENERGY BALANCES               CALC. METHODS


                                      GENERAL BALANCES
    ENERGY BALANCE IN A TYPICAL BUILDING

                                                          100%

         Transmission                                     Biggest energy saving
                         Internal gains                        potential!!!
         losses                                           80%
                                    Ventilation
                                    losses                60%



                                                          40%



                                                          20%

  Solar heat                              Heat supplied
  gains                                   by heating       0%


                                          system                 Cold bridges %
                                                                 Ventilation losses %
                                                                 Transmission losses %




    05.05.2011                            SS 10/11                                       9
INTRODUCTION                 PHYS. PPLES.              ENERGY BALANCES          CALC. METHODS


                                                  GENERAL BALANCES
    • BUILDING ENVELOPE: Heat losses can amount up to 75%
      of total heat losses



                 External walls
                     20%               Roof 19%                   Moving to energy
                                                                  efficient buildings…

          Floor to crawl
           space 9%
                                                               BASIC USED
                                                               SOLUTION: Reduction
                                                               of the major heat losses
                                     Windows
                                      52%                      using better materials in
    Percentage of heat losses through different                the building envelope
        constructive parts of the envelope


    05.05.2011                                    SS 10/11                               10
INTRODUCTION             PHYS. PPLES.             ENERGY BALANCES           CALC. METHODS



                                                        HEAT TRANSFER
   • CONDUCTION
                                                          Tin
                    d layer     [m2K/W]
         Rlayer =
                    λlayerl                                                         Tout

        Rwall = ∑ Rlayer         [m2K/W]
                                                                    λmaterial [W/mK]
                  1           1                                     dmaterial [m]
      U wall =         =                [W/m2K]
                              dlayer
                 Rwall
                           ∑λ                              T
                               layer



   QT , wall = U wall ⋅ Awall ⋅ (Tin − Tout )

    05.05.2011                               SS 10/11                                  11
INTRODUCTION           PHYS. PPLES.            ENERGY BALANCES              CALC. METHODS



                                                     HEAT TRANSFER
  TRANSMISSION LOSSES: Conduction + convection

                  1           1
     U wall =         =                       [W/m2K]
                 Rwall 1      d layer 1
                           +∑        +
                        hi    λlayer he      Superficial heat transmission coefficient: [0 -
                                             100 W/m2K]
                                T




      • Floor to unheated basement          • Roof under winter conditions!
      • Roof in summer conditions

    05.05.2011                            SS 10/11                                   12
INTRODUCTION        PHYS. PPLES.            ENERGY BALANCES               CALC. METHODS



                                                  HEAT TRANSFER
   THERMAL BRIDGES
   • DEFINITION: Places on the envelope where, during the heating
     period, higher heat flows and lower inner surface temperatures
     occur.
   • CAUSES:
      Material caused thermal bridge              Geometric thermal bridge




                                                                     Source: Maas
    05.05.2011                         SS 10/11                                     13
INTRODUCTION       PHYS. PPLES.        ENERGY BALANCES               CALC. METHODS



                                             HEAT TRANSFER
   THERMAL BRIDGES
   • CHARACTERISATION:                   Ψ = Coefficient of losses through
                                         thermal bridge, [W/mK]
                                         f = (superficial) Temperature factor , [-]




                                         Θsi= surface temperature inside wall
    Source: Maas                         Θe = exterior temperature
                                         Θi = indoor temperature
                                         f=0 -> exterior temperature
                                         f=1 -> indoor air temperature
    05.05.2011                    SS 10/11                                     14
INTRODUCTION     PHYS. PPLES.        ENERGY BALANCES        CALC. METHODS



                                           HEAT TRANSFER
   THERMAL BRIDGES




                                                       Source: Maas
    05.05.2011                  SS 10/11                              15
INTRODUCTION     PHYS. PPLES.        ENERGY BALANCES        CALC. METHODS



                                           HEAT TRANSFER
   THERMAL BRIDGES




                                                       Source: Maas
    05.05.2011                  SS 10/11                              16
INTRODUCTION     PHYS. PPLES.        ENERGY BALANCES   CALC. METHODS



                                           HEAT TRANSFER
   VENTILATION (CONVECTION) LOSSES




    05.05.2011                  SS 10/11                       17
INTRODUCTION            PHYS. PPLES.           ENERGY BALANCES         CALC. METHODS



                                                     HEAT TRANSFER
   VENTILATION LOSSES
                 • Definition: Energy losses due to the exchange of an air flow
                   between the building and the surroundings
                 • Characterization: measured in h-1 = represents the portion of
                   the total (heated) building volume exchanged in one hour
                 • Causes:
                     – Air leakages in the building envelope: constructive
                       problem / solution
                     – Health and Safety reasons: necessary to allow pollutants
                       leave the living space

                 According to building typology (residential, office buildings,
                  hospitals…) minimum air exchange rates have to be assured




    05.05.2011                            SS 10/11                             18
INTRODUCTION           PHYS. PPLES.               ENERGY BALANCES             CALC. METHODS



                                                        HEAT TRANSFER
   VENTILATION LOSSES

                                                               Air exchange

     Tight envelope (n50<3h-1)

     Untight envelope (n50> 5h-1)

     Regulable Ventilation units
     Window open up without cross ventilation

     Window open up with cross ventilation

     Window open without cross ventilation

     Window open with cross ventilation



                                                                              Source: Recknagel


    05.05.2011                               SS 10/11                                      19
INTRODUCTION        PHYS. PPLES.             ENERGY BALANCES                CALC. METHODS



                                                   HEAT TRANSFER
   VENTILATION LOSSES

   TYPICAL VALUES for a non efficient old building: 1,5 – 2 h-1 or even
     higher (through air leakages in envelope)

         According to EnEV (Energieeinsparverordnung) in Germany:

                    Non efficient         Efficient (proven tight)   Efficient building
                    building              building without           with mechanical
                                          mechanical ventilation     ventilation system
                                          system
   Values allowed   Air leakages: 0,7     Air leakages: 0,6          Mech.vent.: 0,4
   in EnEV, h-1                                                      Air leakages: 0,2




    05.05.2011                          SS 10/11                                     20
INTRODUCTION             PHYS. PPLES.             ENERGY BALANCES         CALC. METHODS



                                         MOISTURE TRANSFER

                                 1 - 2 liters/day person



                                                    • Transport mechanisms:
                                 2 people house:        – DIFFUSION
                                 ca. 2liters/day        – CONVECTION
                                 person
                                                          (ventilation)
                                                        – (SORPTION)
                                  4 people house:
                                  ca. 4liters/day
                                  person

          Source: Maas



    05.05.2011                               SS 10/11                             21
INTRODUCTION                                 PHYS. PPLES.           ENERGY BALANCES          CALC. METHODS


 Maximal water content in air                               MOISTURE TRANSFER


                                                                                               10°C




                                                                                                 9.4g




                                                                                      7.9g




                                                  Air temperature
Source: Maas

                                05.05.2011                     SS 10/11                                 22
INTRODUCTION     PHYS. PPLES.        ENERGY BALANCES   CALC. METHODS


CARRIER (MOLIERE) DIAGRAM




    05.05.2011                  SS 10/11                       23
INTRODUCTION               PHYS. PPLES.        ENERGY BALANCES   CALC. METHODS


CARRIER (MOLIERE) DIAGRAM
  1.- 100%RH, 20°C,14.5g/kg
  2.- 100%RH, 10°C,7.5g/kg
  3.- 70%RH, 20°C, 7g/kg
  4.- 85%RH,17°C, 7g/kg


  Air density ≈ 1.2kg/m3




       Dew point temperature




    05.05.2011                            SS 10/11                       24
INTRODUCTION                               PHYS. PPLES.                        ENERGY BALANCES           CALC. METHODS



                                                            MOISTURE TRANSFER
                                                                                                           Rel. humidity

                                Air temperature
Dew point temperature




                                                                     Dew point temperature

                                     Rel. humidity

                                                          Source: Maas                       Air temperature
                        05.05.2011                               SS 10/11                                        25
INTRODUCTION     PHYS. PPLES.               ENERGY BALANCES         CALC. METHODS



                                 MOISTURE TRANSFER
   SUPERFICIAL TEMPERATURE
   THERMAL BRIDGES
                                          Outdoor air temp. -15°C



                          Surface
                          temperatures
                          Max. relative
                          humidity

                           Indoor air temp. 20°C
                           70%RH

                          External wall - corner



    05.05.2011                        SS 10/11                              26
INTRODUCTION     PHYS. PPLES.         ENERGY BALANCES   CALC. METHODS



                                MOISTURE TRANSFER
   MOLD GROWTH




    05.05.2011                   SS 10/11                       27
INTRODUCTION                            PHYS. PPLES.             ENERGY BALANCES                            CALC. METHODS



                                                           MOISTURE TRANSFER
   MOLD GROWTH

                                        HUMIDITY                                                TEMPERATURE
            Probability of growth




                                                                       Probability of growth
                                    Relative humidity, %                                       Surf. temperature, °C

                                                                                                               Source: Maas


    05.05.2011                                              SS 10/11                                                   28
INTRODUCTION     PHYS. PPLES.         ENERGY BALANCES   CALC. METHODS



                                MOISTURE TRANSFER
   WATER CONDENSATION
                                                          Rel.
                                                          Humidity




   MOLD GROWTH




                                                          Source: Maas


    05.05.2011                   SS 10/11                         29
INTRODUCTION     PHYS. PPLES.         ENERGY BALANCES   CALC. METHODS



                                MOISTURE TRANSFER
   EXAMPLE
   Mold growth is more restrictive condition              Rel.
                                                          Humidity




                                                          Source: Maas


    05.05.2011                   SS 10/11                         30
INTRODUCTION                  PHYS. PPLES.          ENERGY BALANCES                       CALC. METHODS



                                              MOISTURE TRANSFER
   DIFFUSION




                                                                                    Source: Maas


                 Description           Unit               Description                    Unit
                  Temperature                             Partial vapor pressure

                 Heat transm. Coeff.                      Material transm. Coeff.


                  Heat conductivity                       Vapor diffusivity


                  Thermal resistance                      Resistance to vapor
                                                          diffusion

                  Heat flow                               Vapor diffussion flow
    05.05.2011                                 SS 10/11                                            31
INTRODUCTION     PHYS. PPLES.         ENERGY BALANCES                                CALC. METHODS



                                MOISTURE TRANSFER
   DIFFUSION


                      Air                              Bitumen




                                                       Metal
                  Insulation

                                                         d air
                     Concrete
                                        Z air            δ air            δ air
                                 μ=                =                =
                                      Z material       d material       δ material
                                [-]                    δmaterial
                                                            dmaterial=dair             Source: Maas

    05.05.2011                   SS 10/11                                                      32
INTRODUCTION              PHYS. PPLES.         ENERGY BALANCES              CALC. METHODS



                                         MOISTURE TRANSFER
                                                                 g
   DIFFUSION - EXAMPLE
  Material               μ

  Concrete               70-150
                                                                     1086

  Insulation                             g = 0.421 g/m2h
          Kork           5-10
          PU foams       30-100
  Alu-foil               Tight
                                                                     472
                         (100000000)                                          281

  Wood                   40 (50/400)




                                                                            Source: Maas

                 [m h Pa / kg]
    05.05.2011                            SS 10/11                                     33
INTRODUCTION     PHYS. PPLES.         ENERGY BALANCES        CALC. METHODS



                                MOISTURE TRANSFER
   CONVECTION - EXAMPLE




                                                        Source: Maas
    05.05.2011                   SS 10/11                              34
INTRODUCTION          PHYS. PPLES.                ENERGY BALANCES            CALC. METHODS



                                        MOISTURE TRANSFER
   CONVECTION - EXAMPLE
      Vh,buil=50m3 ; n=0.8 h-1               Ps = 1170 Pa
      Vvent=40m3/h (=Vh,buil*n)              R = 462 J/kgK
      Ti=20°C, RH=50%                        Ps = 139 Pa
      Te=-10°C, RH=80%




                                                 and


                                     -10°C      and                            1.15

                                                               263.15
                                                        1.15              304.3
                                                                        Source: Maas
    05.05.2011                               SS 10/11                                  35
INTRODUCTION     PHYS. PPLES.             ENERGY BALANCES        CALC. METHODS



                                 MOISTURE TRANSFER
   COMPARISON
   CONVECTION - DIFFUSION

                                                                  g




                           Aint,walls=22.5 m2               g = 0.421 g/m2h
                           n = 0.8 h-1
                           Outside: 80% RH, -10°C
     304.3 g/h                                              9.47 g/h
                           Inside: 50% RH, 20°C
                                                            Source: Maas
    05.05.2011                       SS 10/11                              36
INTRODUCTION     PHYS. PPLES.                          ENERGY BALANCES        CALC. METHODS



                                              MOISTURE TRANSFER
   CONVECTION:
   Air exchange


                   Required air exchange   Rel. humidity




                                              Humidity production

                                                                         Source: Maas
    05.05.2011                                    SS 10/11                              37
INTRODUCTION          PHYS. PPLES.               ENERGY BALANCES            CALC. METHODS


                                             ENERGY BALANCES
  STEADY STATE

         Transmission      Internal gains
         losses
                                      Ventilation
                 QT                   losses



                                        Qv

  Solar heat                                                            In order to keep
  gains                                     Heat supplied
                                            by heating            the room temperature
                                            system
                                                         at a constant acceptable value
                             Energy Supplied = Heat Losses - Energy Gains

                              “Active gains”                         “Passive gains”
    05.05.2011                              SS 10/11                                   38
INTRODUCTION           PHYS. PPLES.               ENERGY BALANCES               CALC. METHODS


                                                   THERMAL LOSSES
   TRANSMISSION LOSSES                                      env,i = walls, floor, roof,
                                                                    windows
   QT ,env = ΣU env,i ⋅ Aenv,i ⋅ (Tin − Tout )     [W]
                                                            (separately for each of them)

         – INCLUDING THERMAL BRIDGES

     H T ,building = ΣU env ,i ⋅ Aenv ,i + ΔU tb ⋅ Aenvelope      [W/K]


         – TOTAL TRANSMISSION LOSSES

           QT ,buil = (ΣU env,i ⋅ Aenv,i + ΔU tb ⋅ Aenv ) ⋅ (Tin − Tout )       [W]




    05.05.2011                               SS 10/11                                     39
INTRODUCTION         PHYS. PPLES.              ENERGY BALANCES                CALC. METHODS


                                                THERMAL LOSSES
  VENTILATION LOSSES

                                                     n = air exchange rate [h-1]
    H V = Vh,buil ⋅ 0.34 ⋅ n          [W/K]



           HEATED          Heat
           volume of the   capacity of
                           air [Wh/m3K]
           building [m3]
                                                          QV = H V ⋅ (Tin − Tout )
        According to the German regulation EnEV, can
        be simplified:
        Vh ,buil = Vbrutto ⋅ 0.76


    05.05.2011                            SS 10/11                                    40
INTRODUCTION            PHYS. PPLES.                ENERGY BALANCES               CALC. METHODS


                                                    THERMAL LOSSES
  TOTAL LOSSES (TRANSMISSION+VENTILATION)
       – Transmission Losses
          QT ,buil = (ΣU env,i ⋅ Aenv,i + ΔU tb ⋅ Aenv ) ⋅ (Tin − Tout ) =HT ⋅ (Tin − Tout )    [W]


       – Ventilation Losses
          QV = H V ⋅ (Tin − Tout )      [W]

       – Total Losses

          Qlosses = ( H T + H V ) ⋅ (Tin − Tout )   [W]




    05.05.2011                                SS 10/11                                         41
INTRODUCTION            PHYS. PPLES.           ENERGY BALANCES   CALC. METHODS


                             THERMAL LOSSES + GAINS
   WINDOWS
         – Upane = 3 – 0.6 [W/m2K]
                 -> great influence on heat
                   demand


         – SHGC, g = 0.5 – 0.8 [-]
                 -> great influence on
                   cooling demand


         – ε = 0.84
         – εlow = 0.2 !!!




    05.05.2011                            SS 10/11                       42
INTRODUCTION          PHYS. PPLES.               ENERGY BALANCES   CALC. METHODS


                                              ENERGY - DYNAMIC
    ENERGY BALANCE - DYNAMIC BEHAVIOR
         Transmission      Internal gains
         losses
                                      Ventilation
                 QT                   losses



                                        Qv

  Solar heat
  gains                                     Heat supplied
                                            by heating
                                            system


         Energy Supplied = Heat Losses - Energy Gains +- Energy Stored


    05.05.2011                              SS 10/11                       43
INTRODUCTION                                 PHYS. PPLES.                                                          ENERGY BALANCES                                                 CALC. METHODS

            5000

            4000
                                    Specific heat capacity                                             ENERGY - DYNAMIC
                                                                                                                                                                    THERMAL MASS
c [J/kgK]




            3000

            2000

            1000

               0




                                                                                                       Aluminium
                                                      Foam glass
                            Glass




                                                                                        Brick
                    Wood




                                                                   Sand




                                                                                                                           Concrete



                                                                                                                                               Water
                                      insulation
                                        Mineral




                                                                                 3000
                                                                                                                                                                density
                                                                                 2500

                                                                                 2000
                                                                   rho [kg/m3]




               Csto = ci ⋅ ρ i ⋅ Ai ⋅ d i                                        1500

                                                                                 1000

                                                                                  500

                                                                                    0




                                                                                                                                                                                   Aluminium
                                                                                                                   Glass




                                                                                                                                                                           Brick
                                                                                                                                                                    Sand




                                                                                                                                                                                               Concrete
                                                                                                                                                       Foam glass
                                                                                                Wood




                                                                                                                                                                                                               Water
                                                                                                                                  insulation
                                                                                                                                    Mineral




                                                   Source: Wikipedia
               05.05.2011                                                                          SS 10/11                                                                                               44
lambda [W/mK]




                                                                                  0
                                                                                      1
                                                                                            2
                                                                                                   3
                                                                                                           4
                                                                                                                  5
                                                                           Wood


                                                                            Glass




05.05.2011
                                                                                                                                                     INTRODUCTION




              Source: Wikipedia
                                                                          Mineral
                                                                        insulation


                                                                  Foam glass
                                                                                                                                      THERMAL MASS




                                                                             Sand


                                                                             Brick
                                                                                                                                                     PHYS. PPLES.




                                                                                                                             237




                                                                        Aluminium

                                                                                                                      c [J/kgK]
                                                                        Concrete
                                                                                                           0
                                                                                                               1000
                                                                                                                      2000
                                                                                                                               3000
                                                                                                                                            4000
                                                                                                                                                     5000




                                              rho [kg/m3]

                                                                           Water




                                  0
                                      500
                                            1000
                                                   1500
                                                          2000
                                                                 2500
                                                                           3000




                                                                                                  Wood




SS 10/11
             Wood
                                                                                                   Glass

             Glass
                                                                                                Mineral
                                                                                              insulation
     Mineral
   insulation
                                                                                            Foam glass
                                                                                                                                                     ENERGY BALANCES




Foam glass

                                                                                                   Sand
             Sand

                                                                                                   Brick
             Brick


                                                                                              Aluminium
 Aluminium


     Concrete                                                                                   Concrete
45
                                                                                                                               THERMAL MASS




             Water                                                                                Water
                                                                                                                                                     CALC. METHODS
INTRODUCTION         PHYS. PPLES.                   ENERGY BALANCES           CALC. METHODS



                 Specific heat capacity          ENERGY - DYNAMIC
                                                                 THERMAL MASS
                                               Concrete         Insulation




                                 Temperature




                                                                                    Temperature
                                                                  Thickness

    05.05.2011                                 SS 10/11                                 46
                                                                                Source: Maas
INTRODUCTION                        PHYS. PPLES.                         ENERGY BALANCES            CALC. METHODS



                                Specific heat capacity        ENERGY - DYNAMIC
                                    U-Value     Mass                                  THERMAL MASS
                                    [W/m2K]     [kg/m2]
 6cm




                                                                Outdoor Temperature
40cm




                                                                 Energy flow
43.5cm




                                                                Solar radiation
 26cm



                                                                                      Time of day
   Outdoor Temperature




                                                radiation
                                                Solar




                   05.05.2011                               SS 10/11                                          47
                                                                                                      Source: Maas
INTRODUCTION             PHYS. PPLES.                  ENERGY BALANCES                 CALC. METHODS




  TOTAL LOSSES (TRANSMISSION+VENTILATION)
       – Transmission Losses
             QT ,buil = (ΣU env,i ⋅ Aenv,i + ΔU tb ⋅ Aenv ) ⋅ (Tin − Tout ) =H T ⋅ (Tin − Tout )    [W]


       – Ventilation Losses
            QV = H V ⋅ (Tin − Tout )        [W]                    For which time-step
                                                                     Depends on the
                                                                   data we have for the
                                                                     do we apply this
                                                                        equation?
                                                                         outdoor
       – Total Losses                                                 temperature…

            Qlosses = ( H T + H V ) ⋅ (Tin − Tout )          [W]

            Tin is the indoor desired temperature: regarded as a CONSTANT value,
            typically set between 19 and 21°C for the heating period.


    05.05.2011                                    SS 10/11                                         48
INTRODUCTION             PHYS. PPLES.            ENERGY BALANCES              CALC. METHODS


                                               MONTHLY METHOD
   TOTAL LOSSES




                     Q losses = Σ ( H T + H V ) ⋅ (Tin − Tout ) ⋅ t M ⋅ 24       [Wh/a]
                               months



                 • Tout represents MONTHLY mean values
                 • tM represents the number of days of the month considered




    05.05.2011                              SS 10/11                                  49
INTRODUCTION             PHYS. PPLES.               ENERGY BALANCES    CALC. METHODS


                                                  MONTHLY METHOD
   SOLAR HEAT GAINS


    QSolar , windows = Σ Awindows ⋅ g i ⋅ FF ⋅ Fs ⋅ Gwindow   [Wh/a]
                      months


                 • gi represents the energy
                       transmissivity of the window glass;
                       typically is around 0.6
                 • FF represents the % of glass against frame in the window
                   area; typically is around 0.7
                 • Fs represents the % of shadowing over the glass
                 • Gwindow represents the incident solar radiation onto the
                   window, in Wh/m2



    05.05.2011                                 SS 10/11                        50
INTRODUCTION            PHYS. PPLES.            ENERGY BALANCES            CALC. METHODS


                                 THERMAL LOSSES + GAINS

  WINDOWS, 52% of total losses:
                                 Does not require
        1. Avoid heat losses -> Better insulation materials:
                            much more planning
           - Uw= 3 - 0.6 W/m2K
                                       Three pane window
                 Single or two
                                 effort.
                                       filled with Ar/Kr
                 pane window
                                 Typ. In efficient houses
        2. Increase solar heat gains -> Orientation
            - Highest solar irradiation on the south façade,
           Requires integral planning of
              high potential for solar heat gains -> maximize
              glazed surface facing south
           the building integrated into
            - North façade receives very few solar
           its environment for solar gains and
              irradiation, low potential
              high heat losses through windows -> minimize
           Typ. Approach passive houses
              glazed surfaces                                     Yearly variation of solar
                                                                  path in the sky


    05.05.2011                             SS 10/11                                   51
INTRODUCTION             PHYS. PPLES.              ENERGY BALANCES           CALC. METHODS


                                                MONTHLY METHOD
   INTERNAL HEAT GAINS




                 • Internal heat gains depend on the use pattern of the building:
                   office, hospital, residential…
                 • For residential buildings: constant hourly value of 5 W/m2, per m2
                   useful area in the building

                           Qint_ gains = Σ 5 ⋅ AN ⋅ 24 ⋅ tM        [Wh/a]
                                          months



    05.05.2011                               SS 10/11                                   52
INTRODUCTION             PHYS. PPLES.              ENERGY BALANCES             CALC. METHODS


                                                 MONTHLY METHOD
   ENERGY DEMAND

          – Simplification:
           Qh = Qlosses − QSolar , windows − Qint_ gains    [Wh/a]


          – Actually, not all energy gains can be “used”:
           Qh = Qlosses − η (QSolar , windows + Qint_ gains )        [Wh/a]

                 • η depends on the heat storage capacity of the building structure
                   and its materials, which is a function of ρ [kg/m3], c [Wh/kgK], d [m],
                   A [m2] of the material:

                         Csto = ci ⋅ ρ i ⋅ Ai ⋅ d i      [W/K]


    05.05.2011                                SS 10/11                                   53
INTRODUCTION           PHYS. PPLES.               ENERGY BALANCES               CALC. METHODS


                                                MONTHLY METHOD
   ENERGY DEMAND

          – Types of building constructions according to its heat
            capacity
                 • LIGHT
                    – Csto/A < 50 Wh/m2K

                 • HEAVY
                    – Csto/A > 130 Wh/m2K
                           Qh = Qlosses − η (QSolar , windows + Qint_ gains )   [Wh/a]

          – η = 0.9 for light buildings  [-]
          – η = 0.95 for heavy buildings [-]

    05.05.2011                               SS 10/11                                    54
INTRODUCTION             PHYS. PPLES.                ENERGY BALANCES                 CALC. METHODS


                                                     MONTHLY METHOD
   ENERGY DEMAND
          – BUILDING WITH ZONES AT DIFFERENT
            TEMPERATURES:
                 • German Norm: gives correction factors, Fx, that have to be applied
                   to obtain the HT corrected of the building
                                                 Building part                          Fx [-]
                                                 Outside wall, window, roof, floor      1
    H T = ΣU wall ⋅ Awall + ΔU tb ⋅ Aenvelope    Walls and roofs to unheated rooms      0.5
                                                 -   Floor to ground                   0.6
                                                 -   Walls and floor to unheated crawl
                                                     space

    H T = ΣU wall ⋅ Awall ⋅ Fx + ΔU tb ⋅ Aenvelope


    05.05.2011                                  SS 10/11                                         55
INTRODUCTION              PHYS. PPLES.             ENERGY BALANCES            CALC. METHODS


                                       DEGREE-DAYS METHOD
   TOTAL HEATING DEMAND
   DEGREE-DAYS


                      z
                                         [Kd/a]
         Gt 20 /15 = ∑ (Tin − Tout )
                      1                  [°Cd/a]




                 • Tout represents mean DAILY values
                 • Sets up a “heating limit” (15°C), above which no space heating is
                   required. For this conditions (Tin-Tout)=0
                 • Below the “heating limit”, (Tin-Tout) is calculated and added up to
                   give a value of the “degrees-day”
    05.05.2011                                SS 10/11                                   56
INTRODUCTION               PHYS. PPLES.                 ENERGY BALANCES                       CALC. METHODS


                                         DEGREE-DAYS METHOD
  TOTAL HEATING DEMAND



   [Wh/a]        Qlosses = Σ ( H T + H V ) ⋅ Gt               Q losses = Σ ( H T + H V ) ⋅ (Tin − Tout ) ⋅ t M
                                                                       months
                            days



   [Wh/a] QSolar , windows = orientation Awindows ⋅ g i ⋅ FF ⋅ Fs ⋅ Gwindow
                                 Σ
                                                    QSolar , windows = Σ Awindows ⋅ g i ⋅ FF ⋅ Fs ⋅ Gwindow
                                                                        months

  [kWh/a]        Qint_ gains = 22 ⋅ AN
                                                       Qint_ gains = Σ 5 ⋅ AN ⋅ 24 ⋅ tM
                                                                          months

  [Wh/a]         Qlosses = Qh − η (Qsolar − Qint ernal ) Qh = Qlosses − η (Qsolar , windows − Qint ernal )

    05.05.2011                                     SS 10/11                                               57
INTRODUCTION            PHYS. PPLES.          ENERGY BALANCES         CALC. METHODS


                                                    DYNAMIC TOOLS

         – The equations for steady state conditions are not valid
           here!!!-> Energy stored in the building structure plays a
           role

         – FREEware available (Hourly simulations):DOE2, eQUEST,
           ePLUS (http://www.doe2.com/ )

                   Much more accurate results

                 × Require the description of the HVAC system as INPUT
                 × Time demanding to learn how to work with them: weather
                  data for Stüdl Hütte, etc… may not be in database

    05.05.2011                           SS 10/11                             58
INTRODUCTION            PHYS. PPLES.                ENERGY BALANCES   CALC. METHODS


                                       STATIONARY METHODS

    • STATIC (simplified) METHODS & SOFTWARE:
          – Based on the steady-state simple equation -> quite simple
            calculations

                  Depends only on (rough) CLIMATIC data and the
                  BUILDING ENVELOPE -> Does not require the description
                  of the HVAC system as INPUT

                 × Much more rough results

          – Examples: “DEGREE-DAY Method” and Monthly
            simplified method in EnEV http://www.uni-
             kassel.de/fb6/bpy/de/index.html


    05.05.2011                                 SS 10/11                       59
THANK YOU FOR YOUR
             THANKS FOR YOUR
                  ATTENTION!!!
               ATTENTION!!!!!!




05.05.2011            SS 10/11     60
EXAMPLE                                     3.0m

• AN = 147m2 ; Vbrutto = 580 m3                                   3.0m
                                                     10m
• Awalls = 209.34 m2; Afloor = 88.2 m2; Aroof = 88.2
     m2                                                        7.35m

• Awindows: S 15 m2; E/W 10m2; N 5.5 m2
• Uwalls = 0.45 W/m2K (walls); • G19/10 = 2750 °Cd/a (Hamburg)
     Ufloor-roof = 0.3 W/m2K (floor and roof);
                                         Orientation
                                                           Solar
                                                         radiation
     Uwindows = 1.4 W/m   2K (windows)        [j]        [kWh/m²]
                                            Nord           136
• Utb = 0.1 W/m        2K
                                            Süd            349

• n =0.6 h-1                                 Ost           220
                                            West           220
• Windows: Ff= 0.7; Fs=0.9;g=0.58;
• Heavy building
05.05.2011                   SS 10/11                          61

     T 19°C

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Building heat demand_and_moisture

  • 1. ESTIMATION OF HEAT DEMAND IN BUILDINGS PPRE, SS 10/11 OLDENBURG HERENA TORIO
  • 2. CONTENTS • INTRODUCTION – ENERGY SITUATION IN BUILDING SECTOR • PHYSICAL PRINCIPLES – HEAT TRANSFER – MOISTURE TRANSFER • ENERGY BALANCES – STEADY STATE BEHAVIOR – DYNAMIC BEHAVIOR - THERMAL INERTIA • CALCULATION METHODS – MONTHLY METHOD – SIMPLIFIED METHOD 05.05.2011 SS 10/11 2
  • 3. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS ENERGY SITUATION • ENERGY CONSUMPTION IN GERMANY Lighting, Domestic 5% Energy consumption by sectors (Germany) hot water demand, 13% Industry, 27% Space heating, 81% Households, Transport, 28% 45% Source: VDEW-Materialien: Endenergieverbrauch in Deutschland, 2002 05.05.2011 SS 10/11 3
  • 4. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS ENERGY SITUATION • FUELS USED IN GERMANY TO SUPPLY THE SPACE HEATING DEMAND Electricity 4% Others 8% Renewables are here! Distric heating 7% Natural gas 43% Carbon 2% Gasoil 36% Source: VDEW-Materialien: Endenergieverbrauch in Deutschland, 2002 05.05.2011 SS 10/11 4
  • 5. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS ENERGY SITUATION IN GERMANY EnEV - “Energie-einsparverordnung”: – Limits the maximal energy demand for buildings according to their constructive details – Establishes a calculation method for the energy demand of a building -> basis for comparison – Defines different building “categories” according to their energy consumption 05.05.2011 SS 10/11 5
  • 6. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS ENERGY SITUATION 05.05.2011 SS 10/11 6
  • 7. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS ENERGY SITUATION Heat demand: • Typical building: 80 – 300 kWh/m2a • “Low Energy house” : 40 – 79 kWh/m2a • “Three-liters house”: 16 – 39 kWh/m2a • “Passive house”: max. 15 kWh/m2a • “Zero-Energy house”: 0 kWh/m2a 05.05.2011 SS 10/11 7
  • 8. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS ENERGY SITUATION RENEWABLE ENERGY HEAT STANDARD “EEWärmegesetz”: – Approved July08 -> Jan 09 – Application to new buildings • Biogas 30% • Solar: 15%, 0.03-0.04m2coll/m2living area • Others (biofuels, wood, geothermal or environmental heat) 50% 05.05.2011 SS 10/11 8
  • 9. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS GENERAL BALANCES ENERGY BALANCE IN A TYPICAL BUILDING 100% Transmission Biggest energy saving Internal gains potential!!! losses 80% Ventilation losses 60% 40% 20% Solar heat Heat supplied gains by heating 0% system Cold bridges % Ventilation losses % Transmission losses % 05.05.2011 SS 10/11 9
  • 10. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS GENERAL BALANCES • BUILDING ENVELOPE: Heat losses can amount up to 75% of total heat losses External walls 20% Roof 19% Moving to energy efficient buildings… Floor to crawl space 9% BASIC USED SOLUTION: Reduction of the major heat losses Windows 52% using better materials in Percentage of heat losses through different the building envelope constructive parts of the envelope 05.05.2011 SS 10/11 10
  • 11. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER • CONDUCTION Tin d layer [m2K/W] Rlayer = λlayerl Tout Rwall = ∑ Rlayer [m2K/W] λmaterial [W/mK] 1 1 dmaterial [m] U wall = = [W/m2K] dlayer Rwall ∑λ T layer QT , wall = U wall ⋅ Awall ⋅ (Tin − Tout ) 05.05.2011 SS 10/11 11
  • 12. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER TRANSMISSION LOSSES: Conduction + convection 1 1 U wall = = [W/m2K] Rwall 1 d layer 1 +∑ + hi λlayer he Superficial heat transmission coefficient: [0 - 100 W/m2K] T • Floor to unheated basement • Roof under winter conditions! • Roof in summer conditions 05.05.2011 SS 10/11 12
  • 13. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER THERMAL BRIDGES • DEFINITION: Places on the envelope where, during the heating period, higher heat flows and lower inner surface temperatures occur. • CAUSES: Material caused thermal bridge Geometric thermal bridge Source: Maas 05.05.2011 SS 10/11 13
  • 14. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER THERMAL BRIDGES • CHARACTERISATION: Ψ = Coefficient of losses through thermal bridge, [W/mK] f = (superficial) Temperature factor , [-] Θsi= surface temperature inside wall Source: Maas Θe = exterior temperature Θi = indoor temperature f=0 -> exterior temperature f=1 -> indoor air temperature 05.05.2011 SS 10/11 14
  • 15. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER THERMAL BRIDGES Source: Maas 05.05.2011 SS 10/11 15
  • 16. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER THERMAL BRIDGES Source: Maas 05.05.2011 SS 10/11 16
  • 17. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER VENTILATION (CONVECTION) LOSSES 05.05.2011 SS 10/11 17
  • 18. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER VENTILATION LOSSES • Definition: Energy losses due to the exchange of an air flow between the building and the surroundings • Characterization: measured in h-1 = represents the portion of the total (heated) building volume exchanged in one hour • Causes: – Air leakages in the building envelope: constructive problem / solution – Health and Safety reasons: necessary to allow pollutants leave the living space According to building typology (residential, office buildings, hospitals…) minimum air exchange rates have to be assured 05.05.2011 SS 10/11 18
  • 19. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER VENTILATION LOSSES Air exchange Tight envelope (n50<3h-1) Untight envelope (n50> 5h-1) Regulable Ventilation units Window open up without cross ventilation Window open up with cross ventilation Window open without cross ventilation Window open with cross ventilation Source: Recknagel 05.05.2011 SS 10/11 19
  • 20. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS HEAT TRANSFER VENTILATION LOSSES TYPICAL VALUES for a non efficient old building: 1,5 – 2 h-1 or even higher (through air leakages in envelope) According to EnEV (Energieeinsparverordnung) in Germany: Non efficient Efficient (proven tight) Efficient building building building without with mechanical mechanical ventilation ventilation system system Values allowed Air leakages: 0,7 Air leakages: 0,6 Mech.vent.: 0,4 in EnEV, h-1 Air leakages: 0,2 05.05.2011 SS 10/11 20
  • 21. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER 1 - 2 liters/day person • Transport mechanisms: 2 people house: – DIFFUSION ca. 2liters/day – CONVECTION person (ventilation) – (SORPTION) 4 people house: ca. 4liters/day person Source: Maas 05.05.2011 SS 10/11 21
  • 22. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS Maximal water content in air MOISTURE TRANSFER 10°C 9.4g 7.9g Air temperature Source: Maas 05.05.2011 SS 10/11 22
  • 23. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS CARRIER (MOLIERE) DIAGRAM 05.05.2011 SS 10/11 23
  • 24. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS CARRIER (MOLIERE) DIAGRAM 1.- 100%RH, 20°C,14.5g/kg 2.- 100%RH, 10°C,7.5g/kg 3.- 70%RH, 20°C, 7g/kg 4.- 85%RH,17°C, 7g/kg Air density ≈ 1.2kg/m3 Dew point temperature 05.05.2011 SS 10/11 24
  • 25. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER Rel. humidity Air temperature Dew point temperature Dew point temperature Rel. humidity Source: Maas Air temperature 05.05.2011 SS 10/11 25
  • 26. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER SUPERFICIAL TEMPERATURE THERMAL BRIDGES Outdoor air temp. -15°C Surface temperatures Max. relative humidity Indoor air temp. 20°C 70%RH External wall - corner 05.05.2011 SS 10/11 26
  • 27. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER MOLD GROWTH 05.05.2011 SS 10/11 27
  • 28. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER MOLD GROWTH HUMIDITY TEMPERATURE Probability of growth Probability of growth Relative humidity, % Surf. temperature, °C Source: Maas 05.05.2011 SS 10/11 28
  • 29. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER WATER CONDENSATION Rel. Humidity MOLD GROWTH Source: Maas 05.05.2011 SS 10/11 29
  • 30. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER EXAMPLE Mold growth is more restrictive condition Rel. Humidity Source: Maas 05.05.2011 SS 10/11 30
  • 31. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER DIFFUSION Source: Maas Description Unit Description Unit Temperature Partial vapor pressure Heat transm. Coeff. Material transm. Coeff. Heat conductivity Vapor diffusivity Thermal resistance Resistance to vapor diffusion Heat flow Vapor diffussion flow 05.05.2011 SS 10/11 31
  • 32. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER DIFFUSION Air Bitumen Metal Insulation d air Concrete Z air δ air δ air μ= = = Z material d material δ material [-] δmaterial dmaterial=dair Source: Maas 05.05.2011 SS 10/11 32
  • 33. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER g DIFFUSION - EXAMPLE Material μ Concrete 70-150 1086 Insulation g = 0.421 g/m2h Kork 5-10 PU foams 30-100 Alu-foil Tight 472 (100000000) 281 Wood 40 (50/400) Source: Maas [m h Pa / kg] 05.05.2011 SS 10/11 33
  • 34. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER CONVECTION - EXAMPLE Source: Maas 05.05.2011 SS 10/11 34
  • 35. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER CONVECTION - EXAMPLE Vh,buil=50m3 ; n=0.8 h-1 Ps = 1170 Pa Vvent=40m3/h (=Vh,buil*n) R = 462 J/kgK Ti=20°C, RH=50% Ps = 139 Pa Te=-10°C, RH=80% and -10°C and 1.15 263.15 1.15 304.3 Source: Maas 05.05.2011 SS 10/11 35
  • 36. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER COMPARISON CONVECTION - DIFFUSION g Aint,walls=22.5 m2 g = 0.421 g/m2h n = 0.8 h-1 Outside: 80% RH, -10°C 304.3 g/h 9.47 g/h Inside: 50% RH, 20°C Source: Maas 05.05.2011 SS 10/11 36
  • 37. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MOISTURE TRANSFER CONVECTION: Air exchange Required air exchange Rel. humidity Humidity production Source: Maas 05.05.2011 SS 10/11 37
  • 38. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS ENERGY BALANCES STEADY STATE Transmission Internal gains losses Ventilation QT losses Qv Solar heat In order to keep gains Heat supplied by heating the room temperature system at a constant acceptable value Energy Supplied = Heat Losses - Energy Gains “Active gains” “Passive gains” 05.05.2011 SS 10/11 38
  • 39. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS THERMAL LOSSES TRANSMISSION LOSSES env,i = walls, floor, roof, windows QT ,env = ΣU env,i ⋅ Aenv,i ⋅ (Tin − Tout ) [W] (separately for each of them) – INCLUDING THERMAL BRIDGES H T ,building = ΣU env ,i ⋅ Aenv ,i + ΔU tb ⋅ Aenvelope [W/K] – TOTAL TRANSMISSION LOSSES QT ,buil = (ΣU env,i ⋅ Aenv,i + ΔU tb ⋅ Aenv ) ⋅ (Tin − Tout ) [W] 05.05.2011 SS 10/11 39
  • 40. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS THERMAL LOSSES VENTILATION LOSSES n = air exchange rate [h-1] H V = Vh,buil ⋅ 0.34 ⋅ n [W/K] HEATED Heat volume of the capacity of air [Wh/m3K] building [m3] QV = H V ⋅ (Tin − Tout ) According to the German regulation EnEV, can be simplified: Vh ,buil = Vbrutto ⋅ 0.76 05.05.2011 SS 10/11 40
  • 41. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS THERMAL LOSSES TOTAL LOSSES (TRANSMISSION+VENTILATION) – Transmission Losses QT ,buil = (ΣU env,i ⋅ Aenv,i + ΔU tb ⋅ Aenv ) ⋅ (Tin − Tout ) =HT ⋅ (Tin − Tout ) [W] – Ventilation Losses QV = H V ⋅ (Tin − Tout ) [W] – Total Losses Qlosses = ( H T + H V ) ⋅ (Tin − Tout ) [W] 05.05.2011 SS 10/11 41
  • 42. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS THERMAL LOSSES + GAINS WINDOWS – Upane = 3 – 0.6 [W/m2K] -> great influence on heat demand – SHGC, g = 0.5 – 0.8 [-] -> great influence on cooling demand – ε = 0.84 – εlow = 0.2 !!! 05.05.2011 SS 10/11 42
  • 43. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS ENERGY - DYNAMIC ENERGY BALANCE - DYNAMIC BEHAVIOR Transmission Internal gains losses Ventilation QT losses Qv Solar heat gains Heat supplied by heating system Energy Supplied = Heat Losses - Energy Gains +- Energy Stored 05.05.2011 SS 10/11 43
  • 44. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS 5000 4000 Specific heat capacity ENERGY - DYNAMIC THERMAL MASS c [J/kgK] 3000 2000 1000 0 Aluminium Foam glass Glass Brick Wood Sand Concrete Water insulation Mineral 3000 density 2500 2000 rho [kg/m3] Csto = ci ⋅ ρ i ⋅ Ai ⋅ d i 1500 1000 500 0 Aluminium Glass Brick Sand Concrete Foam glass Wood Water insulation Mineral Source: Wikipedia 05.05.2011 SS 10/11 44
  • 45. lambda [W/mK] 0 1 2 3 4 5 Wood Glass 05.05.2011 INTRODUCTION Source: Wikipedia Mineral insulation Foam glass THERMAL MASS Sand Brick PHYS. PPLES. 237 Aluminium c [J/kgK] Concrete 0 1000 2000 3000 4000 5000 rho [kg/m3] Water 0 500 1000 1500 2000 2500 3000 Wood SS 10/11 Wood Glass Glass Mineral insulation Mineral insulation Foam glass ENERGY BALANCES Foam glass Sand Sand Brick Brick Aluminium Aluminium Concrete Concrete 45 THERMAL MASS Water Water CALC. METHODS
  • 46. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS Specific heat capacity ENERGY - DYNAMIC THERMAL MASS Concrete Insulation Temperature Temperature Thickness 05.05.2011 SS 10/11 46 Source: Maas
  • 47. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS Specific heat capacity ENERGY - DYNAMIC U-Value Mass THERMAL MASS [W/m2K] [kg/m2] 6cm Outdoor Temperature 40cm Energy flow 43.5cm Solar radiation 26cm Time of day Outdoor Temperature radiation Solar 05.05.2011 SS 10/11 47 Source: Maas
  • 48. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS TOTAL LOSSES (TRANSMISSION+VENTILATION) – Transmission Losses QT ,buil = (ΣU env,i ⋅ Aenv,i + ΔU tb ⋅ Aenv ) ⋅ (Tin − Tout ) =H T ⋅ (Tin − Tout ) [W] – Ventilation Losses QV = H V ⋅ (Tin − Tout ) [W] For which time-step Depends on the data we have for the do we apply this equation? outdoor – Total Losses temperature… Qlosses = ( H T + H V ) ⋅ (Tin − Tout ) [W] Tin is the indoor desired temperature: regarded as a CONSTANT value, typically set between 19 and 21°C for the heating period. 05.05.2011 SS 10/11 48
  • 49. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MONTHLY METHOD TOTAL LOSSES Q losses = Σ ( H T + H V ) ⋅ (Tin − Tout ) ⋅ t M ⋅ 24 [Wh/a] months • Tout represents MONTHLY mean values • tM represents the number of days of the month considered 05.05.2011 SS 10/11 49
  • 50. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MONTHLY METHOD SOLAR HEAT GAINS QSolar , windows = Σ Awindows ⋅ g i ⋅ FF ⋅ Fs ⋅ Gwindow [Wh/a] months • gi represents the energy transmissivity of the window glass; typically is around 0.6 • FF represents the % of glass against frame in the window area; typically is around 0.7 • Fs represents the % of shadowing over the glass • Gwindow represents the incident solar radiation onto the window, in Wh/m2 05.05.2011 SS 10/11 50
  • 51. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS THERMAL LOSSES + GAINS WINDOWS, 52% of total losses: Does not require 1. Avoid heat losses -> Better insulation materials: much more planning - Uw= 3 - 0.6 W/m2K Three pane window Single or two effort. filled with Ar/Kr pane window Typ. In efficient houses 2. Increase solar heat gains -> Orientation - Highest solar irradiation on the south façade, Requires integral planning of high potential for solar heat gains -> maximize glazed surface facing south the building integrated into - North façade receives very few solar its environment for solar gains and irradiation, low potential high heat losses through windows -> minimize Typ. Approach passive houses glazed surfaces Yearly variation of solar path in the sky 05.05.2011 SS 10/11 51
  • 52. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MONTHLY METHOD INTERNAL HEAT GAINS • Internal heat gains depend on the use pattern of the building: office, hospital, residential… • For residential buildings: constant hourly value of 5 W/m2, per m2 useful area in the building Qint_ gains = Σ 5 ⋅ AN ⋅ 24 ⋅ tM [Wh/a] months 05.05.2011 SS 10/11 52
  • 53. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MONTHLY METHOD ENERGY DEMAND – Simplification: Qh = Qlosses − QSolar , windows − Qint_ gains [Wh/a] – Actually, not all energy gains can be “used”: Qh = Qlosses − η (QSolar , windows + Qint_ gains ) [Wh/a] • η depends on the heat storage capacity of the building structure and its materials, which is a function of ρ [kg/m3], c [Wh/kgK], d [m], A [m2] of the material: Csto = ci ⋅ ρ i ⋅ Ai ⋅ d i [W/K] 05.05.2011 SS 10/11 53
  • 54. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MONTHLY METHOD ENERGY DEMAND – Types of building constructions according to its heat capacity • LIGHT – Csto/A < 50 Wh/m2K • HEAVY – Csto/A > 130 Wh/m2K Qh = Qlosses − η (QSolar , windows + Qint_ gains ) [Wh/a] – η = 0.9 for light buildings [-] – η = 0.95 for heavy buildings [-] 05.05.2011 SS 10/11 54
  • 55. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS MONTHLY METHOD ENERGY DEMAND – BUILDING WITH ZONES AT DIFFERENT TEMPERATURES: • German Norm: gives correction factors, Fx, that have to be applied to obtain the HT corrected of the building Building part Fx [-] Outside wall, window, roof, floor 1 H T = ΣU wall ⋅ Awall + ΔU tb ⋅ Aenvelope Walls and roofs to unheated rooms 0.5 - Floor to ground 0.6 - Walls and floor to unheated crawl space H T = ΣU wall ⋅ Awall ⋅ Fx + ΔU tb ⋅ Aenvelope 05.05.2011 SS 10/11 55
  • 56. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS DEGREE-DAYS METHOD TOTAL HEATING DEMAND DEGREE-DAYS z [Kd/a] Gt 20 /15 = ∑ (Tin − Tout ) 1 [°Cd/a] • Tout represents mean DAILY values • Sets up a “heating limit” (15°C), above which no space heating is required. For this conditions (Tin-Tout)=0 • Below the “heating limit”, (Tin-Tout) is calculated and added up to give a value of the “degrees-day” 05.05.2011 SS 10/11 56
  • 57. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS DEGREE-DAYS METHOD TOTAL HEATING DEMAND [Wh/a] Qlosses = Σ ( H T + H V ) ⋅ Gt Q losses = Σ ( H T + H V ) ⋅ (Tin − Tout ) ⋅ t M months days [Wh/a] QSolar , windows = orientation Awindows ⋅ g i ⋅ FF ⋅ Fs ⋅ Gwindow Σ QSolar , windows = Σ Awindows ⋅ g i ⋅ FF ⋅ Fs ⋅ Gwindow months [kWh/a] Qint_ gains = 22 ⋅ AN Qint_ gains = Σ 5 ⋅ AN ⋅ 24 ⋅ tM months [Wh/a] Qlosses = Qh − η (Qsolar − Qint ernal ) Qh = Qlosses − η (Qsolar , windows − Qint ernal ) 05.05.2011 SS 10/11 57
  • 58. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS DYNAMIC TOOLS – The equations for steady state conditions are not valid here!!!-> Energy stored in the building structure plays a role – FREEware available (Hourly simulations):DOE2, eQUEST, ePLUS (http://www.doe2.com/ ) Much more accurate results × Require the description of the HVAC system as INPUT × Time demanding to learn how to work with them: weather data for Stüdl Hütte, etc… may not be in database 05.05.2011 SS 10/11 58
  • 59. INTRODUCTION PHYS. PPLES. ENERGY BALANCES CALC. METHODS STATIONARY METHODS • STATIC (simplified) METHODS & SOFTWARE: – Based on the steady-state simple equation -> quite simple calculations Depends only on (rough) CLIMATIC data and the BUILDING ENVELOPE -> Does not require the description of the HVAC system as INPUT × Much more rough results – Examples: “DEGREE-DAY Method” and Monthly simplified method in EnEV http://www.uni- kassel.de/fb6/bpy/de/index.html 05.05.2011 SS 10/11 59
  • 60. THANK YOU FOR YOUR THANKS FOR YOUR ATTENTION!!! ATTENTION!!!!!! 05.05.2011 SS 10/11 60
  • 61. EXAMPLE 3.0m • AN = 147m2 ; Vbrutto = 580 m3 3.0m 10m • Awalls = 209.34 m2; Afloor = 88.2 m2; Aroof = 88.2 m2 7.35m • Awindows: S 15 m2; E/W 10m2; N 5.5 m2 • Uwalls = 0.45 W/m2K (walls); • G19/10 = 2750 °Cd/a (Hamburg) Ufloor-roof = 0.3 W/m2K (floor and roof); Orientation Solar radiation Uwindows = 1.4 W/m 2K (windows) [j] [kWh/m²] Nord 136 • Utb = 0.1 W/m 2K Süd 349 • n =0.6 h-1 Ost 220 West 220 • Windows: Ff= 0.7; Fs=0.9;g=0.58; • Heavy building 05.05.2011 SS 10/11 61 T 19°C