From Engineer MAIRAJ

1. IN THE NAME OF
ALLAH, WHO IS
MOSTMERCIFUL

2. DEPARTMENT:-
THE BENAZIR BHUTTO SHAHEED
UNIVERSTY OF TECHNOLOGY & SKILL DEVELOPMENT
KHAIRPUR MIRS
CIVILENGINEERING

3. SOILMECHANICS
PRESENTATION OF
TOPIC
SIEVE ANALYSIS

4. PRESENTED TO
ENGR.IMTIAZ ALI
RESPECTED SIR..

5. GROUPMEMBERS
PRESENTED BY
 HYDER ALI  AQIB ALI HYDER LUND  MAIRAJ SHAR  M. Naseem

6. Content
PURPOSE Of Sieve analysis
GRAIN SIZE DISTRIBUTION
SIZE OF SIEVE
 SIEVE ANALYSIS
SIEVING PROCEDURE
DATA ANALYSES
EXAMPLES

7. PURPOSE:-
 This test is performed to determine
the percentage of different grain sizes
contained within a soil.
 Sieve analysis is performed to
determine the distribution of the
coarser, larger-sized particles, and the
hydrometer method is used to
determine the distribution of the finer
particles.

8. SIGNIFICANCE:-
 The distribution of different grain sizes
affects the engineering properties of
soil.
 Grain size analysis provides the grain
size distribution, and it is required in
classifying the soil.

9. GRAIN SIZE
DISTRIBUTION
 Determination of GSD:
 In coarse grain soils ... By sieve analysis
 In fine grain soils …... By hydrometer
analysis

10. GRAIN SIZE
DISTRIBUTION
 In fine grain soils …... By hydrometer
analysis
hydrometer
soil/water
suspension
sieve shaker
Sieve Analysis
of sieves stack
HydrometerAnalysis

11. SIEVEANALYSIS
 The (BS) British stadium, (IS) Indian standard
& ASTM standard the sieve size are given in
term of the no. of opening per inch

12. SIEVEANALYSIS
 The Complete Sieve Analysis divided into two
parts.
1. The Fine Analysis
2. The Coarser Analysis

13. SIEVE SIZE
For Coarser Particle
1. 100mm
2. 63mm
3. 20mm
4. 10mm
5. 4.75mm

14. SIEVE SIZE
For Fine Particle
1. 2mm
2. 1mm
3. 600 microns
4. 425 microns
5. 300 micron
6. 212 micron
7. 150 micron
8. 75 micron

15. SIEVEANALYSIS
 In oven dry sample is separated into two fraction
by sieving through 4.75mm returned as coarse
gravel and kept for coarse analysis .
 While (-4.75) is subjected to fine sieve analysis

16. SIEVE
ANALYSES

17. SIEVE
ANALYSES

18. SIEVE
DESIGNATION -
LARGE
 Sieves larger than the #4 sieve are
designated by the size of the openings in
the sieve

19. SIEVE
DESIGNATION -
SMALLER
 Smaller Sieves are numbered according
to the number of openings per inch
#10 Sieves

20. SIEVING
PROCEDURE
1. Write down the weight of each sieve as well as the
bottom pan to be used in the analysis.
2. Record the weight of the given dry soil sample.
3. Make sure that all the sieves are clean, and
assemble them in the ascending order of sieve
numbers (# 4 sieve at top and #200 sieve at
bottom ). Place the pan below #200 sieve.
Carefully pour the soil sample into the top sieve
and place the cap over it.
4. Place sieve stack in the mechanical shaker and
shake for 10 minutes.
5. the bottom pan with its retained fine soil Remove
the stack from the shaker and carefully weigh and
record the weight of each sieve with its retained
soil. In addition, remember to weight and record
the weight of the bottom pan with its retained fine
soil.

21. SIEVE
ANALYSES

22. SIEVE
ANALYSES

23. DATA
ANALYSES
1. Obtain the mass of soil retained on each sieve by
subtracting the weight of empty sieve from the
mass of the sieve +retained soil and record this
mass as the weight retained on the sheet. The
sun of these retained mass should be
approximately equals in the initial mass of the
soil sample. A loss of more than two percent is
unsatisfactory
2. Calculate the percent retained on each sieve by
dividing the weight retained on each sieve by
original sample mass
3. Calculate the percent passing ( or percent finer
by starting with 100 percent and subtracting the
percent retained on each sieve as a cumulative
procedure

24. FOR
EXAMPLE
 For example:Total mass = 500 g,
 Mass retained on No. 4 sieve = 9.7 g
 For the No.4 sieve:
 Quantity passing = Total mass – Mass Retained
 = 500 - 9.7 = 490.3 g
 The percent retained is calculated as:
 retained = Mass retained/Total mass
 = (9.7/500) X 100 = 1.9 %
 From this, the % passing = 100 - 1.9 = 98.1%

25. DATA

26. SOIL
 For example:Total mass = 500 g,
 Mass retained on No. 4 sieve = 9.7 g
 For the No.4 sieve:
 Quantity passing = Total mass – Mass Retained
 = 500 - 9.7 = 490.3 g
 The percent retained is calculated as:
 retained = Mass retained/Total mass
 = (9.7/500) X 100 = 1.9 %
 From this, the % passing = 100 - 1.9 = 98.1%

27. THEENDS!
THANKS!