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LAWS OF INDICES
Worked Examples
Example 1
Determine the value of
 32 × 34
Recall: 𝒂𝒎 × 𝒂𝒏 = 𝒂𝒎+𝒏
32 × 34
= 32+4
= 36
= 3 × 3 × 3 × 3 × 3 × 3
= 729
 36 × 3−5 × 3−1
36 × 3−5 × 3−1
= 36−5−1
= 30
Recall: 𝒂𝟎
= 𝟏
Therefore,
36
× 3−5
× 3−1
= 30
= 1
Example 2
Determine the value of
 56 ÷ 54
Recall: 𝒂𝒎 ÷ 𝒂𝒏 = 𝒂𝒎−𝒏
56 ÷ 54
= 56−4
= 52
= 5 × 5
= 25

27
24
27
24
= 27−4
= 23
= 2 × 2 × 2
= 8
Example 3
Determine the value of
 52 3
Recall: 𝒂𝒎 𝒏 = 𝒂𝒎×𝒏
52 3
= 52×3
= 56
= 5 × 5 × 5 × 5 × 5 × 5
= 15625
 42 −2
= 42×−2
= 4−4
Recall: 𝒂−𝒎
=
𝟏
𝒂𝒎
Therefore:
𝟒𝟐 −𝟐
= 𝟒−𝟒 =
𝟏
𝟒𝟒
=
𝟏
𝟒 × 𝟒 × 𝟒 × 𝟒
=
𝟏
𝟐𝟓𝟔
Example 4
Determine the value of
 27
1
3 × 32
1
5
Recall: 𝑎
1
𝑛 = 𝑛
𝑎
27
1
3 × 32
1
5
=
3
27 ×
5
32
= 3 × 2
= 6
 125
2
3 × 81
3
4
Recall: 𝑎
𝑚
𝑛 =
𝑛
𝑎𝑚
125
2
3 × 81
3
4
=
3
1252 ×
4
813
= 25 × 27
= 675

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Laws of indices examples

  • 2. Example 1 Determine the value of  32 × 34 Recall: 𝒂𝒎 × 𝒂𝒏 = 𝒂𝒎+𝒏 32 × 34 = 32+4 = 36 = 3 × 3 × 3 × 3 × 3 × 3 = 729  36 × 3−5 × 3−1 36 × 3−5 × 3−1 = 36−5−1 = 30 Recall: 𝒂𝟎 = 𝟏 Therefore, 36 × 3−5 × 3−1 = 30 = 1
  • 3. Example 2 Determine the value of  56 ÷ 54 Recall: 𝒂𝒎 ÷ 𝒂𝒏 = 𝒂𝒎−𝒏 56 ÷ 54 = 56−4 = 52 = 5 × 5 = 25  27 24 27 24 = 27−4 = 23 = 2 × 2 × 2 = 8
  • 4. Example 3 Determine the value of  52 3 Recall: 𝒂𝒎 𝒏 = 𝒂𝒎×𝒏 52 3 = 52×3 = 56 = 5 × 5 × 5 × 5 × 5 × 5 = 15625  42 −2 = 42×−2 = 4−4 Recall: 𝒂−𝒎 = 𝟏 𝒂𝒎 Therefore: 𝟒𝟐 −𝟐 = 𝟒−𝟒 = 𝟏 𝟒𝟒 = 𝟏 𝟒 × 𝟒 × 𝟒 × 𝟒 = 𝟏 𝟐𝟓𝟔
  • 5. Example 4 Determine the value of  27 1 3 × 32 1 5 Recall: 𝑎 1 𝑛 = 𝑛 𝑎 27 1 3 × 32 1 5 = 3 27 × 5 32 = 3 × 2 = 6  125 2 3 × 81 3 4 Recall: 𝑎 𝑚 𝑛 = 𝑛 𝑎𝑚 125 2 3 × 81 3 4 = 3 1252 × 4 813 = 25 × 27 = 675