Maxwell's Equations Explained for Electromagnetic Fields and Waves
1. EEEC6430310 ELECTROMAGNETIC FIELDS AND WAVES
Maxwell’s Equation
FACULTY OF ENGINEERING AND COMPUTER TECHNOLOGY
BENG (HONS) IN ELECTRICALAND ELECTRONIC ENGINEERING
Ravandran Muttiah BEng (Hons) MSc MIET
2. Maxwell’s Equation
I. Maxwell’s Equation For Linear Media
𝛻 × 𝑬 = −𝜇
𝜕𝑯
𝜕𝑡
Faraday′
s Law
𝛻 × 𝑯 = 𝑱 + 𝜀
𝜕𝑬
𝜕𝑡
Ampere′
s Law
𝛻 ∙ 𝑬 =
𝜌f
𝜀
Gauss′
s Law
𝛻 ∙ 𝑯 = 0 Gauss′
s Law
where, 𝛻 = vector differential (del) operator
𝑬 = electric field intensity
𝑯 = magnetic field intensity
𝑱 = electric current density
𝜌f = free electric charge density
1
4. 3
V
𝛻 ∙ 𝑬 × 𝑯 d𝑉 =
S
𝑬 × 𝑯 ∙ d𝑺
S
𝑬 × 𝑯 ∙ d𝒂 +
d
d𝑡 V
1
2
𝜀 𝑬 2
+
1
2
𝜇 𝑯 2
d𝑉 = −
𝑉
𝑬 ∙ 𝑱 d𝑉
𝑺 = 𝑬 × 𝑯 Poynting Vector
Watt
m2
𝑊 = V
1
2
𝜀 𝑬 2
+
1
2
𝜇 𝑯 2
d𝑉 Electromagnetic Stored Energy
𝑃d = V
𝑬 ∙ 𝑱 d𝑉 Power dissipated if 𝐽 ∙ 𝑬 > 0
e.g., 𝑱 = 𝜎𝑬 ⇒ 𝐽 ∙ 𝑬 = 𝜎 𝑬 𝟐
Power source if 𝐽 ∙ 𝑬 < 0
𝑃out =
S
𝑬 × 𝑯 ∙ d𝒂 =
S
𝑺 ∙ d𝒂
𝑃out +
d𝑊
d𝑡
= −𝑃d
𝑤e =
1
2
𝜀 𝑬 2
Electric energy density in
Joules
m3
𝑤m =
1
2
𝜇 𝑯 2
Magnetic energy density in
Joules
m3
5. 4
Figure 1: The circuit power into an N terminal network 𝑘=1
𝑁
𝑉𝑘𝐼𝑘 equals the
electromagnetic power flow into the surface surrounding the network, − s
𝑬 × 𝑯 · d𝑺
B. Power In Electric Circuits
E
H
𝑆 = 𝐸 × 𝐻
𝑉1
𝑉2
𝑉3
𝑉𝑁−1
𝑉𝑁
𝐼1
𝐼2
𝐼3
𝐼𝑁−1
𝐼𝑁
𝑆
6. 5
Outside circuit elements
C
𝑬 ∙ d𝒍 ≈ 0, 𝛻 × 𝑬 = 0 ⇒ 𝑬 = −𝛻Ф (Kirchoff’s Voltage Law 𝑘 𝑣𝑘 = 0)
𝛻 × 𝑯 = 𝑱 ⇒ 𝛻 ∙ 𝑱 = 0, S
𝑱 ∙ d𝑺 = 0 (Kirchoff’s Current Law 𝑘 𝑖𝑘 = 0)
𝑃in = −
S
𝑬 × 𝑯 ∙ d𝑺
= −
V
𝛻 ∙ 𝑬 × 𝑯 d𝑉
𝛻 ∙ 𝑬 × 𝑯 = 𝑯 ∙ 𝛻 × 𝑬 − 𝑬 ∙ 𝛻 × 𝑯 = −𝑬 ∙ 𝑱 = 𝛻Ф ∙ 𝑱
𝛻 ∙ 𝑱Ф = Ф𝛻 ∙ 𝑱 + 𝑱 ∙ 𝛻Ф
𝛻 ∙ 𝑬 × 𝑯 = 𝑱 ∙ 𝛻Ф = 𝛻 ∙ Ф𝑱
𝑃in = −
V
𝛻 ∙ 𝑬 × 𝑯 d𝑉 = −
V
𝛻 ∙ 𝑱Ф d𝑉 = −
S
𝑱Ф ∙ d𝑺
On 𝑆, Ф = voltages on each wire, 𝑱 is non-zero only on wires.
𝑃in = −
S
𝑱Ф ∙ d𝑺 = −
𝑘=1
𝑁
𝑣𝑘
S
𝑱 ∙ d𝑺 =
𝑘=1
𝑁
𝑣𝑘𝑖𝑘
0
0
−𝑖𝑘
7. C. Complex Poynting’s Theorem (Sinusoidal Steady State, ej𝜔𝑡
)
6
𝑬 𝒓, 𝑡 = Re 𝑬 𝒓 ej𝜔𝑡
=
1
2
𝑬∗
𝒓 ej𝜔𝑡
+ 𝑬∗
𝒓 e−j𝜔𝑡
𝑯 𝒓, 𝑡 = Re 𝑯 𝒓 ej𝜔𝑡
=
1
2
𝑯∗
𝒓 ej𝜔𝑡
+ 𝑯∗
𝒓 e−j𝜔𝑡
The real part of a complex number is
one-half of the sum of the number
and its complex conjugate
11. III. Transverse Electromagnetic Waves (𝑱 = 0, 𝜌f = 0)
10
The great success of Maxwell’s equations lies partly in the simple prediction of
electromagnetic waves and their simple characterization of materials in terms of
conductivity 𝜎, permittivity 𝜀, and permeability 𝜇. In vacuum we find 𝜎 = 0, 𝜀 = 𝜀o
and 𝜇 = 𝜇o. Therefore, 𝑱 = 𝜎𝑬 = 0 and 𝜌f = 0.
A. Wave Equation
𝛻 × 𝑬 = −𝜇
𝜕𝑯
𝜕𝑡
𝛻 × 𝑯 = 𝜀
𝜕𝑬
𝜕𝑡
𝛻 ∙ 𝑬 = 0
𝛻 ∙ 𝑯 = 0
In contrast the nano-structure of media can be quite complex and requires quantum
mechanics and for its full explanation. Fortunately, simple classical approximations
to atoms and molecules suffice to understand the origin of 𝜎, 𝜀 and 𝜇.
18. 17
C. Normal Incidence Onto A Perfect Conductor
Incident Fields: 𝑬i 𝑧, 𝑡 = Re 𝑬iej 𝜔𝑡−𝑘𝑧
𝒊𝑥
𝑯i 𝑧, 𝑡 = Re
𝑬i
𝜂
ej 𝜔𝑡−𝑘𝑧
𝒊𝑦
Reflected Fields: 𝑬r 𝑧, 𝑡 = Re 𝑬rej 𝜔𝑡+𝑘𝑧
𝒊𝑥
𝑯r 𝑧, 𝑡 = Re −
𝑬r
𝜂
ej 𝜔𝑡+𝑘𝑧
𝒊𝑦
𝑘 = 𝜔 𝜀𝜇, 𝜂 =
𝜇
𝜀
The boundary conditions require that,
𝐸𝑥 𝑧 = 0, 𝑡 = 𝐸𝑥, i 𝑧 = 0, 𝑡 + 𝐸𝑥, r 𝑧 = 0, 𝑡 = 0
𝑬i + 𝑬r = 0 ⇒ 𝑬r = −𝑬i
19. 18
Figure 2: Time varying electromagnetic phenomena differ only in the scaling of time
(frequency) and size (wavelength). In linear dielectric media the frequency and
wavelength are related as 𝑓λ = 𝑐 (𝜔 = 𝑘𝑐), where 𝑐 =
1
𝜀𝜇
is the velocity of light in the
medium.
sin 𝑘z
𝜆 =
2π
𝑘
𝑇 =
2π
𝜔
2π
𝑘
2π
𝜔
𝑧
𝑡
π
𝜔
π
𝑘
−1
−1
1
1 sin 𝜔𝑡
0 102
104 106
108 1010
1012
1014 1016 1018
1020
Circuit Theory Microwaves
f (Hz)
Visible Light Ultraviolet X-Rays Gamma Rays
Power Infrared (Heat)
Radio and Television
AM FM
3 × 106
λ meters 3 × 104 3 × 102 3 3 × 10−2
3 × 10−4
3 × 10−6 3 × 10−8
3 × 10−10 3 × 10−12
20. 19
For 𝑬i = 𝐸i real we have:
𝐸𝑥 𝑧, 𝑡 = 𝐸𝑥, i 𝑧, 𝑡 + 𝐸𝑥, r 𝑧, 𝑡 = Re 𝑬i e−j𝑘𝑧
− ej𝑘𝑧
ej𝜔𝑡
= 2𝐸i sin 𝑘𝑧 sin 𝜔𝑡
𝐻𝑦 𝑧, 𝑡 = 𝐻𝑦, i 𝑧, 𝑡 + 𝐻𝑦, r 𝑧, 𝑡 = Re
𝑬i
𝜂
e−j𝑘𝑧
− ej𝑘𝑧
ej𝜔𝑡
=
2𝐸i
𝜂
cos 𝑘𝑧 cos 𝜔𝑡
𝐾𝑧 𝑧 = 0, 𝑡 = 𝐻𝑦 𝑧 = 0, 𝑡 =
2𝐸i
𝜂
cos 𝜔𝑡
Radiation pressure in free space 𝜇 = 𝜇o, 𝜀 = 𝜀o
Force𝑧
Area 𝑧=0
=
1
2
𝑲 × 𝜇o𝑯 =
1
2
𝜇o𝐾𝑥𝐻𝑦
𝑧=0
𝒊𝑧 =
1
2
𝜇o𝐻𝑦
2
𝑧 = 0 𝒊𝑧
=
2𝜇o𝐸i
2
𝜂o
2 cos2
𝜔𝑡 𝒊𝑧
=
2𝜇o
𝜂o
𝜀o
𝐸i
2
cos2
𝜔𝑡 𝒊𝑧
= 2𝜀o 𝐸i
2
cos2
𝜔𝑡 𝒊𝑧
21. 20
Figure 3: A uniform plane wave normally incident upon a perfect conductor has zero
electric field at the conducting surface thus requiring a reflected wave. The source of this
reflected wave is the surface current at 𝑧 = 0, which equals the magnetic field there. The
total electric and magnetic fields are 90° out of phase in time and space.
x
z
y
𝐸i = Re 𝑬iej 𝜔𝑡−𝑘𝑧
𝒊𝑥
𝐻i = Re
𝑬i
𝑍o
ej 𝜔𝑡−𝑘𝑧
𝒊𝑦
𝑘 =
𝜔
𝑐
𝒊𝑧
𝐻r = Re −
𝑬r
𝑍o
ej 𝜔𝑡+𝑘𝑧
𝒊𝑦
𝐸r = Re 𝑬rej 𝜔𝑡+𝑘𝑧
𝒊𝑥
𝑘r = −
𝜔
c1
𝒊𝑧
𝜀o, 𝜇o 𝜂o = 𝑍o=
𝜇o
𝜀o
𝐻𝑦 𝑠, 𝑡 =
2𝑬i
𝑍o
cos 𝑘𝑠 cos 𝜔𝑡
𝐸𝑥 𝑠, 𝑡 = 2𝑬isin 𝑘𝑠 sin 𝜔𝑡
𝜎 → ∞
22. 21
Figure 4: A uniform plane wave normally incident upon a dielectric interface separating
two different materials has part of its power reflected and part transmitted.
IV. Normal Incidence Onto A Dielectric
x
z
y
𝜀1, 𝜇1 𝜂1 = 𝑍1 =
𝜇1
𝜀1
, 𝑐1 =
1
𝜀1𝜇1
𝜀2, 𝜇2 𝑍2 =
𝜇2
𝜀2
, 𝑐2 =
1
𝜀2𝜇2
𝐸i = Re 𝑬iej 𝜔𝑡−𝑘1𝑧
𝒊𝑥
𝐸t = Re 𝑬tej 𝜔𝑡−𝑘2𝑧
𝒊𝑥
𝐻t = Re
𝑬t
𝑍2
ej 𝜔𝑡−𝑘2𝑧
𝒊𝑦
𝐻r = Re −
𝑬r
𝑍1
ej 𝜔𝑡+𝑘1𝑧
𝒊𝑦
𝐻i = Re
𝑬i
𝑍1
ej 𝜔𝑡−𝑘1𝑧
𝒊𝑦
𝐸r = Re 𝑬rej 𝜔𝑡+𝑘1𝑧
𝒊𝑥
𝑘i = 𝑘1𝒊𝑧 =
𝜔
𝑐1
𝒊𝑧
𝑘r = −𝑘1𝒊𝑧 =
−𝜔
𝑐1
𝒊𝑧
𝑘t = 𝑘2𝒊𝑧 =
𝜔
𝑐2
𝒊𝑧
23. 22
𝑬i 𝑧, 𝑡 = Re 𝑬iej 𝜔𝑡−𝑘1𝑧
𝑖𝑥 , 𝑘1 = 𝜔 𝜀1𝜇1
𝑯i 𝑧, 𝑡 = Re
𝑯i
𝜂1
ej 𝜔𝑡−𝑘1𝑧
𝑖𝑦 , 𝜂1 = 𝜔
𝜇1
𝜀1
𝑬r 𝑧, 𝑡 = Re 𝑬rej 𝜔𝑡+𝑘1𝑧
𝑖𝑥
𝑯r 𝑧, 𝑡 = Re −
𝑬r
𝜂1
ej 𝜔𝑡+𝑘1𝑧
𝑖𝑦
𝑬t 𝑧, 𝑡 = Re 𝑬tej 𝜔𝑡−𝑘2𝑧
𝑖𝑥 , 𝑘2 = 𝜔 𝜀2𝜇2
𝑯t 𝑧, 𝑡 = Re
𝑬t
𝜂2
ej 𝜔𝑡−𝑘2𝑧
𝑖𝑦 , 𝜂2 = 𝜔
𝜇2
𝜀2