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# 9___Biomechanics_Torques_in_Equilibrium.pdf.pdf

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# 9___Biomechanics_Torques_in_Equilibrium.pdf.pdf

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### 9___Biomechanics_Torques_in_Equilibrium.pdf.pdf

1. 1. ©UDel Physics 1 of 8 Spring 2019 PHSY201 Lab 9 – Biomechanics of Torques and Forces in Equilibrium Instructional Goals: Goals:  Learn how to apply torques and forces to equilibrium situations.  Get a feeling for how the material we have learned so far can be applied to biomechanics.  Gain more experience comparing measured values. What You Turn In:  Pre‐Lab in the first five minutes of your lab section.  A Full Lab Report according to the instructions provided in the Lab Report Guidelines. Background Reading: Relevant background can be found in the lecture notes and Chapter 11 of Walker 4th edition. Equipment provided by the lab:  Metal poles: 1 long, 1 medium  Table clamp (or table post mount)  Wireless Force Sensor  Rotating clamp  Ring Clamps (4)  Hanging mass holder with 50g and 100 g masses  Metal chain (or inextensible string)  Meter stick and/or tape measure  Level Equipment provided by the student:  Ruler  Pen  Calculator  USB memory device for taking computerized data from the lab (or alternatively email the data to yourself
2. 2. PHYS201 Lab 9 Torques and Forces in Static Equilibrium ©UDel Physics 2 of 8 Spring 2019 Background: Torque and Rotation Consider a mass m attached to a rotation axis by a rigid but massless rod of length r as shown to the right. Suppose a force F  is applied to the mass. The only component of the applied force that can cause rotation is that which is perpendicular to both the rotation axis and the rigid, but massless, rod. Denote the magnitude of this component as F . In the plane perpendicular to the rotation axis, the setup (with only the component of force F shown) is Where from the drawing above, it is clear that sin F F    . From Newton’s second law, F ma    Multiplying both sides by the distance from the axis of rotation at which the force acts, rF mra    Since at a r   , we have for this mass, 2 rF mr I      The quantity, rF , is known as the torque caused by the applied force F  . Thus, we can define the left side of the equation as sin rF    , or in vector notation,   τ r F    , where it the magnitude is given as before. On the right‐side we have the moment of inertia, I, which is 2 I mr  . This is a quantity that depends on the distribution of mass in an object. That is the resulting rotation and changes in rotation are dependent on where each little bit of mass is located in the system relative to the axis of rotation (or pivot). Thus, Newton’s second law of motion, in a rotational sense for a point of mass is I    . We can recast Newton’s 2nd law for the case of rotation or an extended object about a pivot as net I    . Where I is the summed total of all the moments of inertia for the entire object. In practice, it is calculated using calculus methods. For now, we take it as the rotational analog of mass, just as  is the rotational analog of force and  is the rotational analog of acceleration. More on this in the next lab. At equilibrium the angular acceleration, α, is zero, so the net torque must be zero. So, if an object is not rotating at rest the net torque must be zero, 0 net i i      . That is the sum of all torques about any given pivot point must be zero. We are free to choose the pivot point as the object is not rotating. In a problem such as this, it is m r F  ϕ F  ϕ Overhead view
3. 3. PHYS201 Lab 9 Torques and Forces in Static Equilibrium ©UDel Physics 3 of 8 Spring 2019 best to pick the most convenient pivot point as possible. I.e., pick a pivot point that reduces the number of variables you need to calculate/measure. Recall here that the torque is defined as sin Fr    and we are confining ourselves to two‐dimensional motion only. Where F is the force applied, r is the distance from the pivot to the applied force and θ is the angle between the vectors F  and r  . By convention, we take the algebraic sign of the torque as positive for torques that would cause a counterclockwise (CCW) rotation in the absence of any additional torques. It is negative for torques that would cause a clockwise (CW) rotation. This is the essence of the right‐hand rule. Center of Gravity: For an extended object, such as the boom, we can think of the weight acting at one point, the center of mass, for the purposes of calculating the torque. This is the point where the extended object would balance. In this lab, you will find the center of gravity of a boom by balancing it on a meter stick’s edge and marking that place on the boom with a pencil or chalk (something erasable). Since the boom will have some attached equipment (e.g. ring hangers), its center of mass will not be at is volumetric center. Besides the angular acceleration being zero, an additional condition for equilibrium is that the linear acceleration be zero 0  a  . So, we have the additional relations for the components of the vectors (in two dimensions): 0 0 x y F and F     which we can use to analyze a system at equilibrium. We will apply these at the end of the lab to find the net force the elbow is applying. In this lab, the system we will be examining is an “arm” holding a weight. See the figure below (Figure 1). B F  A W  h W  A W  h W  B F   A h B E s Figure 1 ‐ Human Arm Analog. The horizontal beam represents the forearm with a center of mass at A. Any weight in the hand is at point h and the bicep muscle attaches at point B on the forearm (radius) and point s at the shoulder (scapula). Point E is the elbow, which experiences a force which will be calculated at the end of the lab.
4. 4. PHYS201 Lab 9 Torques and Forces in Static Equilibrium ©UDel Physics 4 of 8 Spring 2019 Please note the following from Figure 1:  The forearm (radius/ulna) in our mock up is a horizontal boom from E (elbow) to hand (h).  The bicep muscle is a chain, with a force meter attached running from s (shoulder) to B (forearm).  The elbow is a joint between the vertical metal rod and the horizontal boom. The point where the joint swivels is E in the diagrams above. Note that in our mock up, the rod does not end at E but extends past this point. You need to make sure you are measuring from the correct point when getting distances.  We have excluded other muscles (e.g. triceps, etc.) which cause other torques on the “bones” in our system and the attachment points of the biceps are approximated. However, it is quite accurate for our needs. In order to calculate our torques, we must set a point about which we would rotate. In this system, we’ll use the natural choice of the elbow, E. We choose this point because we cannot directly measure the forces applied here and since sin Fr    , any force applied at a distance of r = 0, provides no torque. We will calculate the components and net force on the elbow after we have satisfied that the system is not rotating. We need to define some distance measurements. We define them according to Figure 2. Every distance measured from our defined pivot point to any point on the horizontal boom is given as r with the appropriate subscript. For example, the distance from the elbow (E) to the center of mass of the horizontal boom (A) is A r . The distance from the elbow (E) to the shoulder (s) is s  and the distance from the shoulder (s) to the horizontal boom through the chain (i.e. muscle) at point (B) is B  . To keep our calculations simple, we will make the forearm horizontal such that gravity always pulls down at a right angle to the boom. If the upper arm is vertical, we have a right triangle SEB such that, 2 2 2 B B s r     and 2 2 sin s s b b s r         Table 1: Determination of Uncertainties for Measured Values Every measurement you will make will have an uncertainty associated with it. We will determine the uncertainties of the measurements in the same ways as before (see Table 1). We will take these values and find the propagated uncertainty for the forces and torques. You will use the measured values to calculate the force of the muscle and compare it to the value given by the force meter. Measurement Uncertainty Mass ±1 in the last digit of the scale or the amount of fluctuation. Distance ±1 in the smallest increment of the ruler/meter stick or estimate of how well you can judge the size due to rounded edges. Force meter Student Determined Figure 2 ‐ Defined distances used in this manual. A W  h W  B F   A h B E s
5. 5. PHYS201 Lab 9 Torques and Forces in Static Equilibrium ©UDel Physics 5 of 8 Spring 2019 The practical application of this being that if we show that we can accurately calculate the force needed to hold up the forearm, we need not slice open an actual person’s forearm and replace the bicep muscle with a force meter to determine the usual force the muscle can provide. If you then know how much force the muscle should provide, you can then determine a course of physical therapy or determine how much can be lifted in a hand or many, many other possibilities. Experimental Procedure: A. Setup Capstone to read the force meter. 1. In “Hardware Setup” add the Wireless Force Sensor. 2. Drag the “Digits” display to the screen and set it to Force (N). You should have at least two points after the decimal place. B. Finding the center of mass of the boom. 1. Remove the boom from the rotating clamp and remove the mass hanger. Balance the boom arm on a straight edge (e.g. a meter stick) to find the center of mass and mark it on the boom (e.g. with chalk or pencil). Please note, you should balance the boom without the attachment hardware, but leave the slip rings. If at any point you move the slip rings, you will change the location of the center of mass and must start the experiment again from Part B1. 2. Mass the boom on the digital scale or triple beam balance. Remember, do not move the slip rings, they are part of the forearm! C. Assemble the Arm Analog and measure the distances and forces: 1. Attach the boom to the vertical support and allow it to swing freely up and down. Do not tighten the rotating portion of the elbow clamp, it must swing freely. If it were not, additional torques and forces would be applied. This would be akin to a person having an arthritic elbow. 2. Record the distance from the pivot (E) to the center of mass (A), A r . Measure and record the distance from pivot (E) to the chain attachment (B), B r . Measure and record the distance from pivot (E) to the hanger (h), h r . If you remove the horizontal boom or adjust the elbow clamp in any way you must start from (B.2), again. 3. Calculate and record the value of A W . This value should not change through the experiment. 4. Attach the inextensible chain with the Force meter at the shoulder point (s) to the forearm at (B). Initially do not attach the mass hanger and attachment hardware to the bar at (h). In later trials, you will attach these items and use the scale to determine the actual mass of the hanger, attachment hardware, and added masses.