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Chapter 11
   Chemical Bonds: The Formation
     of Compounds from Atoms
The atoms in vitamin C
(ascorbic acid) bond together
in a very specific orientation to
form the shape of the
molecule. The molecules
collect together into a crystal,
which has been photographed
here in a polarized micrograph
(magnified 200 times).

                 Introduction to General, Organic, and Biochemistry 10e
                                 John Wiley & Sons, Inc
                      Morris Hein, Scott Pattison, and Susan Arena
Chapter Outline

11.1 Periodic Trends in Atomic 11.6 Electronegativity
     Properties                11.7 Lewis Structures of
11.2 Lewis Structures of Atoms      Compounds
11.3 The Ionic Bond: Transfer            11.8 Complex Lewis Structures
     of Electrons from One               11.9 Compounds Containing
     Atom to Another                          Polyatomic Ions
11.4 Predicting Formulas of              11.10 Molecular Shape
     Ionic Compounds
                                         11.11 The Valence Shell
11.5 The Covalent Bond:                        Electron Pair Repulsion
     Sharing Electrons                         (VSEPR) Model
                    Copyright 2012 John Wiley & Sons, Inc
Periodic Trends in Atomic Properties

Metallic character increases from right to left and top to
 bottom on the periodic table.




                    Copyright 2012 John Wiley & Sons, Inc
Atomic Radii    Review
                                       Question 8:
                                        Compare

What 2 factors effect the
size of atoms?
• Increase in number of
   energy levels.
• Within an energy level,
   increase inQuestion 1 & charge.
Helps with Review
                  nuclear 10
Ionization Energy

The amount of energy required to remove an electron
  from a gaseous atom.
              Na + 496 kJ/mol Na+ + e-
             1s22s22p63s1                1s22s22p6
                                                            He

Ionization energy in Group A elements increases from
  the bottom to the top on the periodic table.
Ionization energy increases from left to right across a
  period.

                    Copyright 2012 John Wiley & Sons, Inc
Ionization Energy
Review Question 4: Explain what happen
to the ionization energy as you go down
         the Alkali metal family.




                                   Review Question 5: Explain what happen
                                   to the ionization energy as you go down
                                             the Noble Gas family.



         Copyright 2012 John Wiley & Sons, Inc
Ionization Energy

  More energy is needed to remove an electron from an
   element or ion with a noble gas electron configuration.




                                                              Review
Review                                                       Question 7
Question
   3




                     Copyright 2012 John Wiley & Sons, Inc
Nonmetals

•   Have relatively high ionization energies.
•   Gain electrons to be stable.
•   Form anions (negatively charged ions).
•   The most active nonmetals are found
    in the upper right corner of the table.




                     Copyright 2012 John Wiley & Sons, Inc
Your Turn!

    Explain why more Ionization Energy is required to
      remove the first electron from neon then from
      sodium?
    a. Neon has two principal energy levels, sodium has
        three
       – Outmost e- is farther away in sodium
       – More e- shielding in sodium
    b. Neon has a perfect octet, Sodium does not


Review Question 2     Copyright 2012 John Wiley & Sons, Inc
Your Turn!

Metals generally form ions by
a. Gaining electrons, forming positive ions
b. Losing electrons, forming positive ions
c. Gaining electrons, forming negative ions
d. Losing electrons, forming negative ions




                  Copyright 2012 John Wiley & Sons, Inc
Lewis Structures of Atoms
Review Question 11 & 22: Why are only valence electrons were presented in a Lewis structure?

    Lewis structures use dots to represent the valence electrons
      of an atom. Those are the electrons involving bonding.
    The symbol of the element represents the nucleus and the
      electrons in filled inner shells.
    Boron has the electron configuration: [He]2s22p1




                                 Copyright 2012 John Wiley & Sons, Inc
Lewis Structures of Atoms




Review Question 22
    Figure 11.4 Lewis structures of the first 20 elements. Dots
    represent electrons in the outermost s and p energy levels only.

                           Copyright 2012 John Wiley & Sons, Inc
The Noble Gases

The representative elements tend to gain, lose or share
  enough electrons to have the same number of electrons
  as the very stable noble gases.




*Each noble gas has eight valence electrons (except He).
                   Copyright 2012 John Wiley & Sons, Inc
Your Turn!

How many valence electrons are present in an atom of
  bromine in the ground state and how many does
  bromine need to gain to have the same electron
  configuration as a noble gas?
a. 1, 7
b. 2, 6
c. 3, 5
d. 7, 1


                  Copyright 2012 John Wiley & Sons, Inc
Your Turn!

How many valence electrons are present in an atom of
  aluminum in the ground state and what charge will it
  form when it loses those electrons? Review Question 24
a. 3, +3
b. 3, -3
c. 5, +3
d. 1, +1
e. 13, +3


                   Copyright 2012 John Wiley & Sons, Inc
Ion Formation

      Sodium loses one
        valence electron.

      Chlorine gains one
        valence electron.
      Both ions have the
        perfect octet or the
        Noble Gas
        configuration

Review Question 12: Why do Metals
tend to lose electrons and nonmetalsCopyright 2012 John Wiley & Sons, Inc
                                     tend
to gain electrons ?
Ionic Bond Formation

An ionic bond is the attraction of oppositely charged
 particles.




          Na    +      Cl                            [Na]+ [ Cl ]-


                    Copyright 2012 John Wiley & Sons, Inc
NaCl Crystal




Copyright 2012 John Wiley & Sons, Inc
Atomic and Ionic Radii




*The metals lose electrons to become cations. The nonmetals gain electrons
to become anions.




                          Copyright 2012 John Wiley & Sons, Inc
Your Turn!

Which element forms an ion that is larger than its atom?
a. Lithium
b. Calcium
c. Chromium
d. Fluorine




                   Copyright 2012 John Wiley & Sons, Inc
Formation of Magnesium Chloride
Mg needs to lose 2 electrons: [Ne]3s2
Cl needs to gain 1 electron: [Ne]3s23p5
                                           2 Cl are needed!
We will need to transfer 2 electrons from Mg to Cl.




                    Copyright 2012 John Wiley & Sons, Inc
Formation of Aluminum Oxide
Al needs to lose 3 electrons: [Ne]3s2 3p1                    2 Al and 3 O
O needs to gain 2 electron: [He]2s22p4                       are needed!
We will need to transfer 6 electrons.




                     Copyright 2012 John Wiley & Sons, Inc
Your Turn!

A Cl-1 ion has an electron configuration similar to that
  of
a. Neon
b. Argon
c. Krypton
d. Xenon




                    Copyright 2012 John Wiley & Sons, Inc
Predicting Formulas of Ionic Compounds

Elements within a group behave similarly because their
   valence electron configuration is the same.
If sodium oxide is Na2O, then oxides of other Group IA
   elements will also exist in a 2:1 ratio:
   Li2O, K2O, Rb2O
If sodium oxide is Na2O, then sulfides of the Group IA
   elements will also exist in a 2:1 ratio.
   Na2S, K2S, Rb2S


                   Copyright 2012 John Wiley & Sons, Inc
Predicting Formulas of Ionic Compounds




                                        Calcium sulfate is CaSO4.

         What is the formula for barium sulfate? BaSO4


               Copyright 2012 John Wiley & Sons, Inc
Your Turn!

Calcium phosphide is Ca3P2. What is the empirical
  formula of barium nitride?
a. BaN
b. Ba3N
c. Ba2N3
d. Ba3N2




                   Copyright 2012 John Wiley & Sons, Inc
The Covalent Bond

Molecules exist as discrete units held together by
  covalent bonds.
A covalent bond consists of a pair of electrons shared
  by two atoms.




Figure 11.8 The formation of a hydrogen molecule from two
  hydrogen atoms. The two 1s orbitals overlap, forming the H2
  molecule.
                     Copyright 2012 John Wiley & Sons, Inc
The Covalent Bond- Cl2

The Cl-Cl bond is created by overlapping p orbitals.




Figure 11.9 Pairing p electrons in the formation of a
  chlorine molecule.
                   Copyright 2012 John Wiley & Sons, Inc
Other Diatomic Elements

Single bonds are formed in hydrogen and the halogens
  because each atom needs only 1 more electron to be
  stable.



A double bond is formed by oxygen because each atom
  has 6 valence electrons and needs 2 more to be stable.
A triple bond is formed by nitrogen because each atom
  has 5 valence electrons and needs 3 more to be stable.
                   Copyright 2012 John Wiley & Sons, Inc
Electronegativity

Electronegativity is a measure of the attractive force that
  one atom in a covalent bond has for the electrons of the
  bond. “How much does it want the e-?”
                              Chlorine is more
                              electronegative than H. The
                              pair of shared electrons in
                              HCl is closer to the Cl atom
                              than to the H atom, giving
                              Cl a partial negative charge ( )
                              with respect to the H atom.
                               Review Question 17: How do you determine
                               partial positive and negative charges?
Electronegativity
Review Question 21: Highest?   Lowest?




                               Copyright 2012 John Wiley & Sons, Inc
The Bonding Continuum

Bonding is determined by differences in electronegativities
If the difference in electronegativity between 2 atoms is
• greater than 2, the bonding is ionic.
• equal to 0, the bonding is covalent (equal sharing).
• in between 0 and 2, the bonding is polar covalent
   (unequal sharing).




                     Copyright 2012 John Wiley & Sons, Inc
Nonpolar Covalent Bonds
Review Question 14: Are all molecules that contain polar bonds polar molecules ?

    Nonpolar covalent bonds have very small or no
      differences in electronegativity between the two
      atoms of the bond.
    The electrons are shared equally.

    C-S electronegativity difference = 2.5 – 2.5 = 0
    N-Cl electronegativity difference = 3.0 – 3.0 = 0



                                  Copyright 2012 John Wiley & Sons, Inc
Polar Covalent Bonds

Polar covalent bonds are found when the two different
  atoms are sharing the electrons unequally.
Look for differences in electronegativity less than 2.

P- O electronegativity difference = 3.5 – 2.1 = 1.4
                         P               O
N-C   electronegativity difference = 3.0 – 2.5 = 0.5
                         N                C


                   Copyright 2012 John Wiley & Sons, Inc
Polar or Ionic

• If the electronegativity difference between two
  bonded atoms is greater than 1.7-1.9, the bond will
  be more ionic than covalent.
   P- F electronegativity difference = 4.0 – 2.1 = 1.9
• If the electronegativity difference is greater than 2,
  the bond is strongly ionic.
   Si- F electronegativity difference = 4.0 – 1.8 = 2.2
• If the electronegativity difference is less than 1.5,
  the bond is strongly covalent.

                    Copyright 2012 John Wiley & Sons, Inc
Your Turn!

A bond that is principally ionic will form between
a. Magnesium and chlorine
b. Silicon and phosphorus
c. Selenium and oxygen
d. Oxygen and nitrogen




                   Copyright 2012 John Wiley & Sons, Inc
Your Turn!

A polar covalent bond will form between which two
  atoms?
a. Beryllium and fluorine
b. Hydrogen and chlorine
c. Sodium and oxygen
d. Fluorine and fluorine




                  Copyright 2012 John Wiley & Sons, Inc
Molecular Shape and Polarity

Molecules with polar bonds may or may not be polar
  depending on their geometry.
Symmetric arrangements of polar bonds result in
  nonpolar molecules.
                      O=C=O
Asymmetric arrangements of polar
                                                          N
  bonds result in polar molecules. H                              H
                                                              H


                  Copyright 2012 John Wiley & Sons, Inc
Lewis Structures of Compounds
   Review Question 16

1. Sum number of valence electrons
2. Draw the skeletal structure and bond atoms with a
   single bond (2 electrons). Note that H can have only
   one bond so cannot be a central atom.
3. Subtract electrons used from the sum
4. Distribute pairs of electrons on remaining atoms to
   complete their octet (except H)
5. Form double/triple bonds if necessary to complete
   octet.

                        Copyright 2012 John Wiley & Sons, Inc
Lewis Structure: NF3

Sum the valence electrons: N +3F = 5 + 3(7) = 26
Arrange skeletal structure and bond atoms.
                     ..           .. ..              Review Question 18: difference
                    :F            N .. :
                                     F               between dots and dashes
                     ..
                                :F :
                                 ..
Subtract bonding electrons from sum: 26-3(2) = 20
Distribute the 20 electrons in pairs to complete the octet
  of each atom.


                    Copyright 2012 John Wiley & Sons, Inc
Lewis Structure: CH2O

Sum the valence electrons: C+2H+O = 4 + 2(1) +6 = 12
Arrange skeletal structure and bond atoms.
                                      ..     ..


                         H          C .. :
                                      O
                                   H
Subtract bonding electrons from sum: 12-3(2) = 6
Distribute the 6 electrons in pairs to complete the octet
  of each atom.
Form double/triple bonds if necessary to complete octet.
                   Copyright 2012 John Wiley & Sons, Inc
Lewis Structure: CO

Sum the valence electrons: C+O = 4 + 6 = 10
Arrange skeletal structure and bond atoms.

                          :C
                           ..          O:
                                       O:
                                       ..
Subtract bonding electrons from sum: 10-1(2) = 8
Distribute the 8 electrons in pairs to complete the octet
  of each atom.
Form double/triple bonds if necessary to complete octet.


                   Copyright 2012 John Wiley & Sons, Inc
Complex Lewis Structures: NO2-

Sum the valence electrons: N+2O+1(e-) = 5+2(6)+1 =18
  Note the extra electron from the -1 charge.
Arrange skeletal structure and bond atoms.

                           : :
                           : :
                                     :
                                     :
                                               :
                                               : :
                      [ :O            N         O : ]-
Subtract bonding electrons from sum: 18-2(2) = 14
Distribute the 14 electrons in pairs to complete the octet
  of each atom.
Form double/triple bonds if necessary to complete octet.

                    Copyright 2012 John Wiley & Sons, Inc
Complex Lewis Structures: NO2-

A molecule or ion that has multiple correct Lewis
  structures show resonance.
The nitrite ion has 2 resonance structures:
         : :
               :
                   :




                                                   :
                                                           :
                                                               : :
      [ :O     N   O: ]- or                   [ :O         N   O : ]-




                   Copyright 2012 John Wiley & Sons, Inc
Compounds Containing Polyatomic Ions

Ionic compounds containing polyatomic ions have both
  ionic bonds and covalent bonds.
NaNO2 is a food preservative. It has an ionic bond
  between the Na+ and the NO2-, but the bonding within
  the polyatomic ion is covalent.
                             : :
                                       :
                                                 :
                Na+     [ :O            N         O : ]-




                  Copyright 2012 John Wiley & Sons, Inc
Molecular Shape
Figure 11.12 Geometric shapes of common molecules. Each molecule is
   shown as a ball and stick model (showing the bonds) and as a spacefilling
   model (showing the shape).




                           Copyright 2012 John Wiley & Sons, Inc
VSEPR

Valence Shell Electron Pair Repulsion modeling is the
  method used for visualizing the effects of the
  repulsion that exists between bonding and
  nonbonding electrons around the central atom.
Arranging the electron pairs as far apart as possible
  minimizes the electron pair repulsions and determines
  the molecular geometry.




                   Copyright 2012 John Wiley & Sons, Inc
VSEPR

Linear structures result when two
  pairs of electrons surround the
  central atom.
                             BeCl2

Trigonal Planar structures when
  three pairs of electrons surround
  the central atom.
                               BF3



                   Copyright 2012 John Wiley & Sons, Inc
VSEPR

Tetrahedral structures when four pairs of electrons
  surround the central atom.
Methane (CH4) is shown 3 different ways.




                   Copyright 2012 John Wiley & Sons, Inc
Molecular Shape and Lone Pairs

The 4 electron pairs in NH3 are arranged in a              ..
  tetrahedral structure.                      H            N H
The arrangement of the three bonds is                      H
  pyramidal.




                   Copyright 2012 John Wiley & Sons, Inc
Molecular Shape and Lone Pairs

The 4 electron pairs in H2O are arranged in a              ..
  tetrahedral structure.                      H            O H
                                                           ..
The arrangement of the two bonds is bent.




                   Copyright 2012 John Wiley & Sons, Inc
VSEPR




Copyright 2012 John Wiley & Sons, Inc
Determining Molecular Shape
               Using VSEPR
1.   Draw the Lewis structure for the molecule.
2.   Count the electron pairs and arrange them to
     minimize repulsions.
3.   Determine the positions of the atoms.
4.   Name the molecular structure from the position of
     the atoms.




                   Copyright 2012 John Wiley & Sons, Inc
Your Turn!

What is the molecular geometry for CH2O?
a. linear
                                                          ..

b. trigonal planar           H C .. : O
c. tetrahedral
                                  H
d. trigonal pyramidal
e. bent




                  Copyright 2012 John Wiley & Sons, Inc
Your Turn!

What is the molecular geometry for NF3?
a. linear
b. trigonal planar           .. .. ..
                           : F N .. : F
c. tetrahedral               ..
d. trigonal pyramidal            :F :
                                   ..
e. bent




                 Copyright 2012 John Wiley & Sons, Inc
Your Turn!

Is the molecule NF3 polar or nonpolar?
a. Polar, because it has polar bonds arranged
    symmetrically around the N.
b. Polar, because it has polar bonds arranged
    asymmetrically around the N.
c. Nonpolar, because it has polar bonds arranged
    symmetrically around the N.




                  Copyright 2012 John Wiley & Sons, Inc
Your Turn!

What is the molecular geometry for CF4?
a. linear
b. trigonal planar
c. tetrahedral
d. trigonal pyramidal
e. bent




                  Copyright 2012 John Wiley & Sons, Inc
Your Turn!

Is the molecule CF4 polar or nonpolar?
a. Polar, because it has polar bonds arranged
    symmetrically around the C.
b. Polar, because it has polar bonds arranged
    asymmetrically around the C.
c. Nonpolar, because it has polar bonds arranged
    symmetrically around the C.




                  Copyright 2012 John Wiley & Sons, Inc
Your Turn!

What is the molecular geometry for CO2?
a. linear
b. trigonal planar
c. tetrahedral
d. trigonal pyramidal
e. bent




                  Copyright 2012 John Wiley & Sons, Inc
Questions

Review Questions
  – Did in class
Paired Questions (pg 244)
  – Do 1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45
  – Practice later every other even (2, 6, etc)




                    Copyright 2012 John Wiley & Sons, Inc   1-60

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NWTC General Chemistry Ch 11

  • 1. Chapter 11 Chemical Bonds: The Formation of Compounds from Atoms The atoms in vitamin C (ascorbic acid) bond together in a very specific orientation to form the shape of the molecule. The molecules collect together into a crystal, which has been photographed here in a polarized micrograph (magnified 200 times). Introduction to General, Organic, and Biochemistry 10e John Wiley & Sons, Inc Morris Hein, Scott Pattison, and Susan Arena
  • 2. Chapter Outline 11.1 Periodic Trends in Atomic 11.6 Electronegativity Properties 11.7 Lewis Structures of 11.2 Lewis Structures of Atoms Compounds 11.3 The Ionic Bond: Transfer 11.8 Complex Lewis Structures of Electrons from One 11.9 Compounds Containing Atom to Another Polyatomic Ions 11.4 Predicting Formulas of 11.10 Molecular Shape Ionic Compounds 11.11 The Valence Shell 11.5 The Covalent Bond: Electron Pair Repulsion Sharing Electrons (VSEPR) Model Copyright 2012 John Wiley & Sons, Inc
  • 3. Periodic Trends in Atomic Properties Metallic character increases from right to left and top to bottom on the periodic table. Copyright 2012 John Wiley & Sons, Inc
  • 4. Atomic Radii Review Question 8: Compare What 2 factors effect the size of atoms? • Increase in number of energy levels. • Within an energy level, increase inQuestion 1 & charge. Helps with Review nuclear 10
  • 5. Ionization Energy The amount of energy required to remove an electron from a gaseous atom. Na + 496 kJ/mol Na+ + e- 1s22s22p63s1  1s22s22p6 He Ionization energy in Group A elements increases from the bottom to the top on the periodic table. Ionization energy increases from left to right across a period. Copyright 2012 John Wiley & Sons, Inc
  • 6. Ionization Energy Review Question 4: Explain what happen to the ionization energy as you go down the Alkali metal family. Review Question 5: Explain what happen to the ionization energy as you go down the Noble Gas family. Copyright 2012 John Wiley & Sons, Inc
  • 7. Ionization Energy More energy is needed to remove an electron from an element or ion with a noble gas electron configuration. Review Review Question 7 Question 3 Copyright 2012 John Wiley & Sons, Inc
  • 8. Nonmetals • Have relatively high ionization energies. • Gain electrons to be stable. • Form anions (negatively charged ions). • The most active nonmetals are found in the upper right corner of the table. Copyright 2012 John Wiley & Sons, Inc
  • 9. Your Turn! Explain why more Ionization Energy is required to remove the first electron from neon then from sodium? a. Neon has two principal energy levels, sodium has three – Outmost e- is farther away in sodium – More e- shielding in sodium b. Neon has a perfect octet, Sodium does not Review Question 2 Copyright 2012 John Wiley & Sons, Inc
  • 10. Your Turn! Metals generally form ions by a. Gaining electrons, forming positive ions b. Losing electrons, forming positive ions c. Gaining electrons, forming negative ions d. Losing electrons, forming negative ions Copyright 2012 John Wiley & Sons, Inc
  • 11. Lewis Structures of Atoms Review Question 11 & 22: Why are only valence electrons were presented in a Lewis structure? Lewis structures use dots to represent the valence electrons of an atom. Those are the electrons involving bonding. The symbol of the element represents the nucleus and the electrons in filled inner shells. Boron has the electron configuration: [He]2s22p1 Copyright 2012 John Wiley & Sons, Inc
  • 12. Lewis Structures of Atoms Review Question 22 Figure 11.4 Lewis structures of the first 20 elements. Dots represent electrons in the outermost s and p energy levels only. Copyright 2012 John Wiley & Sons, Inc
  • 13. The Noble Gases The representative elements tend to gain, lose or share enough electrons to have the same number of electrons as the very stable noble gases. *Each noble gas has eight valence electrons (except He). Copyright 2012 John Wiley & Sons, Inc
  • 14. Your Turn! How many valence electrons are present in an atom of bromine in the ground state and how many does bromine need to gain to have the same electron configuration as a noble gas? a. 1, 7 b. 2, 6 c. 3, 5 d. 7, 1 Copyright 2012 John Wiley & Sons, Inc
  • 15. Your Turn! How many valence electrons are present in an atom of aluminum in the ground state and what charge will it form when it loses those electrons? Review Question 24 a. 3, +3 b. 3, -3 c. 5, +3 d. 1, +1 e. 13, +3 Copyright 2012 John Wiley & Sons, Inc
  • 16. Ion Formation Sodium loses one valence electron. Chlorine gains one valence electron. Both ions have the perfect octet or the Noble Gas configuration Review Question 12: Why do Metals tend to lose electrons and nonmetalsCopyright 2012 John Wiley & Sons, Inc tend to gain electrons ?
  • 17. Ionic Bond Formation An ionic bond is the attraction of oppositely charged particles. Na + Cl [Na]+ [ Cl ]- Copyright 2012 John Wiley & Sons, Inc
  • 18. NaCl Crystal Copyright 2012 John Wiley & Sons, Inc
  • 19. Atomic and Ionic Radii *The metals lose electrons to become cations. The nonmetals gain electrons to become anions. Copyright 2012 John Wiley & Sons, Inc
  • 20. Your Turn! Which element forms an ion that is larger than its atom? a. Lithium b. Calcium c. Chromium d. Fluorine Copyright 2012 John Wiley & Sons, Inc
  • 21. Formation of Magnesium Chloride Mg needs to lose 2 electrons: [Ne]3s2 Cl needs to gain 1 electron: [Ne]3s23p5 2 Cl are needed! We will need to transfer 2 electrons from Mg to Cl. Copyright 2012 John Wiley & Sons, Inc
  • 22. Formation of Aluminum Oxide Al needs to lose 3 electrons: [Ne]3s2 3p1 2 Al and 3 O O needs to gain 2 electron: [He]2s22p4 are needed! We will need to transfer 6 electrons. Copyright 2012 John Wiley & Sons, Inc
  • 23. Your Turn! A Cl-1 ion has an electron configuration similar to that of a. Neon b. Argon c. Krypton d. Xenon Copyright 2012 John Wiley & Sons, Inc
  • 24. Predicting Formulas of Ionic Compounds Elements within a group behave similarly because their valence electron configuration is the same. If sodium oxide is Na2O, then oxides of other Group IA elements will also exist in a 2:1 ratio: Li2O, K2O, Rb2O If sodium oxide is Na2O, then sulfides of the Group IA elements will also exist in a 2:1 ratio. Na2S, K2S, Rb2S Copyright 2012 John Wiley & Sons, Inc
  • 25. Predicting Formulas of Ionic Compounds Calcium sulfate is CaSO4. What is the formula for barium sulfate? BaSO4 Copyright 2012 John Wiley & Sons, Inc
  • 26. Your Turn! Calcium phosphide is Ca3P2. What is the empirical formula of barium nitride? a. BaN b. Ba3N c. Ba2N3 d. Ba3N2 Copyright 2012 John Wiley & Sons, Inc
  • 27. The Covalent Bond Molecules exist as discrete units held together by covalent bonds. A covalent bond consists of a pair of electrons shared by two atoms. Figure 11.8 The formation of a hydrogen molecule from two hydrogen atoms. The two 1s orbitals overlap, forming the H2 molecule. Copyright 2012 John Wiley & Sons, Inc
  • 28. The Covalent Bond- Cl2 The Cl-Cl bond is created by overlapping p orbitals. Figure 11.9 Pairing p electrons in the formation of a chlorine molecule. Copyright 2012 John Wiley & Sons, Inc
  • 29. Other Diatomic Elements Single bonds are formed in hydrogen and the halogens because each atom needs only 1 more electron to be stable. A double bond is formed by oxygen because each atom has 6 valence electrons and needs 2 more to be stable. A triple bond is formed by nitrogen because each atom has 5 valence electrons and needs 3 more to be stable. Copyright 2012 John Wiley & Sons, Inc
  • 30. Electronegativity Electronegativity is a measure of the attractive force that one atom in a covalent bond has for the electrons of the bond. “How much does it want the e-?” Chlorine is more electronegative than H. The pair of shared electrons in HCl is closer to the Cl atom than to the H atom, giving Cl a partial negative charge ( ) with respect to the H atom. Review Question 17: How do you determine partial positive and negative charges?
  • 31. Electronegativity Review Question 21: Highest? Lowest? Copyright 2012 John Wiley & Sons, Inc
  • 32. The Bonding Continuum Bonding is determined by differences in electronegativities If the difference in electronegativity between 2 atoms is • greater than 2, the bonding is ionic. • equal to 0, the bonding is covalent (equal sharing). • in between 0 and 2, the bonding is polar covalent (unequal sharing). Copyright 2012 John Wiley & Sons, Inc
  • 33. Nonpolar Covalent Bonds Review Question 14: Are all molecules that contain polar bonds polar molecules ? Nonpolar covalent bonds have very small or no differences in electronegativity between the two atoms of the bond. The electrons are shared equally. C-S electronegativity difference = 2.5 – 2.5 = 0 N-Cl electronegativity difference = 3.0 – 3.0 = 0 Copyright 2012 John Wiley & Sons, Inc
  • 34. Polar Covalent Bonds Polar covalent bonds are found when the two different atoms are sharing the electrons unequally. Look for differences in electronegativity less than 2. P- O electronegativity difference = 3.5 – 2.1 = 1.4 P O N-C electronegativity difference = 3.0 – 2.5 = 0.5 N C Copyright 2012 John Wiley & Sons, Inc
  • 35. Polar or Ionic • If the electronegativity difference between two bonded atoms is greater than 1.7-1.9, the bond will be more ionic than covalent. P- F electronegativity difference = 4.0 – 2.1 = 1.9 • If the electronegativity difference is greater than 2, the bond is strongly ionic. Si- F electronegativity difference = 4.0 – 1.8 = 2.2 • If the electronegativity difference is less than 1.5, the bond is strongly covalent. Copyright 2012 John Wiley & Sons, Inc
  • 36. Your Turn! A bond that is principally ionic will form between a. Magnesium and chlorine b. Silicon and phosphorus c. Selenium and oxygen d. Oxygen and nitrogen Copyright 2012 John Wiley & Sons, Inc
  • 37. Your Turn! A polar covalent bond will form between which two atoms? a. Beryllium and fluorine b. Hydrogen and chlorine c. Sodium and oxygen d. Fluorine and fluorine Copyright 2012 John Wiley & Sons, Inc
  • 38. Molecular Shape and Polarity Molecules with polar bonds may or may not be polar depending on their geometry. Symmetric arrangements of polar bonds result in nonpolar molecules. O=C=O Asymmetric arrangements of polar N bonds result in polar molecules. H H H Copyright 2012 John Wiley & Sons, Inc
  • 39. Lewis Structures of Compounds Review Question 16 1. Sum number of valence electrons 2. Draw the skeletal structure and bond atoms with a single bond (2 electrons). Note that H can have only one bond so cannot be a central atom. 3. Subtract electrons used from the sum 4. Distribute pairs of electrons on remaining atoms to complete their octet (except H) 5. Form double/triple bonds if necessary to complete octet. Copyright 2012 John Wiley & Sons, Inc
  • 40. Lewis Structure: NF3 Sum the valence electrons: N +3F = 5 + 3(7) = 26 Arrange skeletal structure and bond atoms. .. .. .. Review Question 18: difference :F N .. : F between dots and dashes .. :F : .. Subtract bonding electrons from sum: 26-3(2) = 20 Distribute the 20 electrons in pairs to complete the octet of each atom. Copyright 2012 John Wiley & Sons, Inc
  • 41. Lewis Structure: CH2O Sum the valence electrons: C+2H+O = 4 + 2(1) +6 = 12 Arrange skeletal structure and bond atoms. .. .. H C .. : O H Subtract bonding electrons from sum: 12-3(2) = 6 Distribute the 6 electrons in pairs to complete the octet of each atom. Form double/triple bonds if necessary to complete octet. Copyright 2012 John Wiley & Sons, Inc
  • 42. Lewis Structure: CO Sum the valence electrons: C+O = 4 + 6 = 10 Arrange skeletal structure and bond atoms. :C .. O: O: .. Subtract bonding electrons from sum: 10-1(2) = 8 Distribute the 8 electrons in pairs to complete the octet of each atom. Form double/triple bonds if necessary to complete octet. Copyright 2012 John Wiley & Sons, Inc
  • 43. Complex Lewis Structures: NO2- Sum the valence electrons: N+2O+1(e-) = 5+2(6)+1 =18 Note the extra electron from the -1 charge. Arrange skeletal structure and bond atoms. : : : : : : : : : [ :O N O : ]- Subtract bonding electrons from sum: 18-2(2) = 14 Distribute the 14 electrons in pairs to complete the octet of each atom. Form double/triple bonds if necessary to complete octet. Copyright 2012 John Wiley & Sons, Inc
  • 44. Complex Lewis Structures: NO2- A molecule or ion that has multiple correct Lewis structures show resonance. The nitrite ion has 2 resonance structures: : : : : : : : : [ :O N O: ]- or [ :O N O : ]- Copyright 2012 John Wiley & Sons, Inc
  • 45. Compounds Containing Polyatomic Ions Ionic compounds containing polyatomic ions have both ionic bonds and covalent bonds. NaNO2 is a food preservative. It has an ionic bond between the Na+ and the NO2-, but the bonding within the polyatomic ion is covalent. : : : : Na+ [ :O N O : ]- Copyright 2012 John Wiley & Sons, Inc
  • 46. Molecular Shape Figure 11.12 Geometric shapes of common molecules. Each molecule is shown as a ball and stick model (showing the bonds) and as a spacefilling model (showing the shape). Copyright 2012 John Wiley & Sons, Inc
  • 47. VSEPR Valence Shell Electron Pair Repulsion modeling is the method used for visualizing the effects of the repulsion that exists between bonding and nonbonding electrons around the central atom. Arranging the electron pairs as far apart as possible minimizes the electron pair repulsions and determines the molecular geometry. Copyright 2012 John Wiley & Sons, Inc
  • 48. VSEPR Linear structures result when two pairs of electrons surround the central atom. BeCl2 Trigonal Planar structures when three pairs of electrons surround the central atom. BF3 Copyright 2012 John Wiley & Sons, Inc
  • 49. VSEPR Tetrahedral structures when four pairs of electrons surround the central atom. Methane (CH4) is shown 3 different ways. Copyright 2012 John Wiley & Sons, Inc
  • 50. Molecular Shape and Lone Pairs The 4 electron pairs in NH3 are arranged in a .. tetrahedral structure. H N H The arrangement of the three bonds is H pyramidal. Copyright 2012 John Wiley & Sons, Inc
  • 51. Molecular Shape and Lone Pairs The 4 electron pairs in H2O are arranged in a .. tetrahedral structure. H O H .. The arrangement of the two bonds is bent. Copyright 2012 John Wiley & Sons, Inc
  • 52. VSEPR Copyright 2012 John Wiley & Sons, Inc
  • 53. Determining Molecular Shape Using VSEPR 1. Draw the Lewis structure for the molecule. 2. Count the electron pairs and arrange them to minimize repulsions. 3. Determine the positions of the atoms. 4. Name the molecular structure from the position of the atoms. Copyright 2012 John Wiley & Sons, Inc
  • 54. Your Turn! What is the molecular geometry for CH2O? a. linear .. b. trigonal planar H C .. : O c. tetrahedral H d. trigonal pyramidal e. bent Copyright 2012 John Wiley & Sons, Inc
  • 55. Your Turn! What is the molecular geometry for NF3? a. linear b. trigonal planar .. .. .. : F N .. : F c. tetrahedral .. d. trigonal pyramidal :F : .. e. bent Copyright 2012 John Wiley & Sons, Inc
  • 56. Your Turn! Is the molecule NF3 polar or nonpolar? a. Polar, because it has polar bonds arranged symmetrically around the N. b. Polar, because it has polar bonds arranged asymmetrically around the N. c. Nonpolar, because it has polar bonds arranged symmetrically around the N. Copyright 2012 John Wiley & Sons, Inc
  • 57. Your Turn! What is the molecular geometry for CF4? a. linear b. trigonal planar c. tetrahedral d. trigonal pyramidal e. bent Copyright 2012 John Wiley & Sons, Inc
  • 58. Your Turn! Is the molecule CF4 polar or nonpolar? a. Polar, because it has polar bonds arranged symmetrically around the C. b. Polar, because it has polar bonds arranged asymmetrically around the C. c. Nonpolar, because it has polar bonds arranged symmetrically around the C. Copyright 2012 John Wiley & Sons, Inc
  • 59. Your Turn! What is the molecular geometry for CO2? a. linear b. trigonal planar c. tetrahedral d. trigonal pyramidal e. bent Copyright 2012 John Wiley & Sons, Inc
  • 60. Questions Review Questions – Did in class Paired Questions (pg 244) – Do 1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45 – Practice later every other even (2, 6, etc) Copyright 2012 John Wiley & Sons, Inc 1-60

Notes de l'éditeur

  1. Figure 11.3 Periodic relationship of the first ionization energy for representative elements in the first four periods.
  2. Figure 11.4 Lewis structures of the first 20 elements. Dots represent electrons in the outermost s and p energy levels only.