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4.
A sample of 49 observations is taken from a normal population with a standard deviation of 10. The sample mean is 55.
Determine the 99 percent confidence interval for the population mean. (Round your answers to 3 decimal places.)
Confidence interval for the population mean is and .
5.
Forty-nine items are randomly selected from a population of 500 items. The sample mean is 40 and the sample standard deviation 9.
Develop a 99 percent confidence interval for the population mean? (Round your answers to 3 decimal places.)
The confidence interval is between and
The following information applies to questions 7- 11 displayed below.]
The following information is available.
H0: μ ≤ 17
H1: μ > 17
The sample mean is 18 for a sample of 38. The population standard deviation is 3.
Use the .01 significance level.
7.
Is this a one- or two-tailed test?
One-tailed test
Two-tailed test
8.
What is the decision rule?
Fail to reject H0 when z > 2.33
Fail to reject H0 when z ≤ 2.33
9.
What is the value of the test statistic? (Round your answer to 2 decimal places.)
Value of the test statistic
check my workreferences
10.
What is your decision regarding H0?
Fail to reject H0
Reject H0
11.
What is the p-value? (Round your answer to 4 decimal places.)
p-value
12. According to a study by the American Pet Food Dealers Association, 61 percent of U.S. households own pets. A report is being prepared for an editorial in the San Francisco Chronicle. As a part of the editorial a random sample of 260 households showed 170 own pets. Does this data disagree with the Pet Food Dealers Association data? Use a 0.05 level of significance.
(a)
State the null hypothesis and the alternate hypothesis. (Round your answers to 2 decimal places.)
H0: π =
H1: π ≠
(b)
State the decision rule for 0.05 significance level. (Round your answers to 2 decimal places.)
H0 is rejected if z is not between and .
(c)
Compute the value of the test statistic. (Round your answer to 2 decimal places.)
Value of the test statistic
(d)
Does this data disagree with the Pet Food Dealers Association data? Use a 0.05 level of significance.
H0 is . There is evidence to show the proportion has changed.
13.
The following null and alternate hypotheses are given.
H0 : μ ≤ 50
H1 : μ > 50
Suppose the population standard deviation is 10. The probability of a Type I error is set at .01 and the probability of a Type II error at .30.
Assume that the population mean shifts from 50 to 55. How large a sample is necessary to meet these requirements? (Round your answer to the nearest whole number.)
Sample
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QUIZ #2
During a national debate on changes to health care, a cable news service performs an opinion poll of 500 small-business owners. It shows that 65 percent of small-business owners do not approve of the changes.
(a)
Develop a 95 percent con.
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1. I CAN CHECK THESE ANSWERS ONCE YOU ARE
COMPLETE
4.
A sample of 49 observations is taken from a normal population
with a standard deviation of 10. The sample mean is 55.
Determine the 99 percent confidence interval for the population
mean. (Round your answers to 3 decimal places.)
Confidence interval for the population mean is and .
5.
Forty-nine items are randomly selected from a population of
500 items. The sample mean is 40 and the sample standard
deviation 9.
Develop a 99 percent confidence interval for the population
mean? (Round your answers to 3 decimal places.)
The confidence interval is between and
The following information applies to questions 7- 11 displayed
below.]
The following information is available.
H0: μ ≤ 17
H1: μ > 17
The sample mean is 18 for a sample of 38. The population
standard deviation is 3.
Use the .01 significance level.
2. 7.
Is this a one- or two-tailed test?
One-tailed test
Two-tailed test
8.
What is the decision rule?
Fail to reject H0 when z > 2.33
Fail to reject H0 when z ≤ 2.33
9.
What is the value of the test statistic? (Round your answer to 2
decimal places.)
Value of the test statistic
check my workreferences
10.
What is your decision regarding H0?
Fail to reject H0
Reject H0
3. 11.
What is the p-value? (Round your answer to 4 decimal places.)
p-value
12. According to a study by the American Pet Food Dealers
Association, 61 percent of U.S. households own pets. A report
is being prepared for an editorial in the San Francisco
Chronicle. As a part of the editorial a random sample of 260
households showed 170 own pets. Does this data disagree with
the Pet Food Dealers Association data? Use a 0.05 level of
significance.
(a)
State the null hypothesis and the alternate hypothesis. (Round
your answers to 2 decimal places.)
H0: π =
H1: π ≠
(b)
State the decision rule for 0.05 significance level. (Round your
answers to 2 decimal places.)
H0 is rejected if z is not between and .
(c)
Compute the value of the test statistic. (Round your answer to 2
decimal places.)
4. Value of the test statistic
(d)
Does this data disagree with the Pet Food Dealers Association
data? Use a 0.05 level of significance.
H0 is . There is evidence to show the proportion has changed.
13.
The following null and alternate hypotheses are given.
H0 : μ ≤ 50
H1 : μ > 50
Suppose the population standard deviation is 10. The
probability of a Type I error is set at .01 and the probability of
a Type II error at .30.
Assume that the population mean shifts from 50 to 55. How
large a sample is necessary to meet these requirements? (Round
your answer to the nearest whole number.)
Sample
I AM UNABLE TO CHECK THE ANSWERS FOR THE QUIZ
QUIZ #2
During a national debate on changes to health care, a cable
news service performs an opinion poll of 500 small-business
owners. It shows that 65 percent of small-business owners do
not approve of the changes.
(a)
Develop a 95 percent confidence interval for the proportion
5. opposing health care changes. (Round your answers to 4
decimal places.)
Confidence interval for the proportion and .
(b)
Do majority approve?
QUIZ #4
Warren County Telephone Company claims in its annual report
that "the typical customer spends $62 per month on local and
long-distance service." A sample of 12 subscribers revealed the
following amounts spent last month.
$65
$67
$64
$67
$60
$64
$68
$64
$64
$57
$54
$67
(a)
What is the point estimate of the population mean? (Round your
answer to 3 decimal places. Omit the "$" sign in your
response.)
6. Estimated population mean
$
(b)
Develop a 95 percent confidence interval for the population
mean. (Round your answers to 3 decimal places. Omit the "$"
sign in your response.)
Confidence interval for the population mean
$ and $
(c)
Is the company's claim that the "typical customer" spends $62
per month reasonable?
QUIZ #5
A sample of 45 observations is selected from a normal
population. The sample mean is 27, and the population standard
deviation is 6. Conduct the following test of hypothesis using
the .05 significance level.
H0 : μ ≤ 26
H1 : μ > 26
(a)
Is this a one- or two-tailed test?
(b)
7. What is the decision rule? (Round your answer to 2 decimal
places.)
H0 and H1 when z >
(c)
What is the value of the test statistic? (Round your answer to 2
decimal places.)
Value of the test statistic
(d)
What is your decision regarding H0?
There is evidence to conclude that the population mean is
greater than 26.
(e)
What is the p-value? (Round your answer to 4 decimal places.)
QUIZ #6
Tina Dennis is the comptroller for Meek Industries. She
believes that the current cash flow problem at Meek is due to
the slow collection of accounts receivable. She believes that
more than 60 percent of the accounts are in arrears more than
three months. A random sample of 200 accounts showed that
140 were more than three months old. At the .01 significance
8. level, can she conclude that more than 60 percent of the
accounts are in arrears for more than three months?
(a)
State the null hypothesis and the alternate hypothesis. (Round
your answers to 2 decimal places.)
H0: π ≤
H1: π >
(b)
State the decision rule for .01 significance level. (Round your
answer to 2 decimal places.)
Reject H0 if z is >
(c)
Compute the value of the test statistic. (Round your answer to 2
decimal places.)
z value is
(d)
At the .01 significance level, can she conclude that more than
60 percent of the accounts are in arrears for more than three
months?
H0. Ms. Dennis is in concluding that more than 60 percent
of the accounts are in arrears for more than three months.
9. [The following information applies to the questions 10 – 14
displayed below.]
The waiting time for customers at MacBurger Restaurants
follows a normal distribution with a mean of 3 minutes and a
standard deviation of 1 minute. At the Warren Road MacBurger,
the quality-assurance department sampled 50 customers and
found that the mean waiting time was 2.75 minutes. At the .05
significance level, can we conclude that the mean waiting time
is less than 3 minutes?
QUIZ #10.
State the null hypothesis and the alternate hypothesis.
H0: μ ≥
H1: μ <
QUIZ #11.
State whether the decision rule is true or false: Reject H0 if z <
– 1.65
True
False
QUIZ #12.
Compute the value of the test statistic. (Negative amount should
be indicated by a minus sign. Round your answer to 2 decimal
10. places.)
Test statistic is
QUIZ #13.
What is your decision regarding H0?
Do not reject H0
Reject H0
#14
What is the p-value? (Round your answer to 4 decimal places.)
p-value is
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