Proponga una o ms hiptesis para cada uno de los siguientes.pdf

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Proponga una o ms hiptesis para cada uno de los siguientes pares de variables, especificando cul es la variable independiente y cul es la variable dependiente. Luego, desarrolle la hiptesis bsica para incluir al menos una variable moderadora o una variable interviniente. a) El ndice de Confianza del Consumidor y el ciclo econmico b) Nivel de rendimiento de los trabajadores y cercana de la supervisin de los trabajadores. c) Nivel de hurto de empleados y presencia de cmara de videovigilancia a) El ndice de Confianza del Consumidor y el ciclo econmico b) Nivel de rendimiento de los trabajadores y cercana de la supervisin de los trabajadores. c) Nivel de hurto de empleados y presencia de cmara de videovigilancia.

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public class Monster { protected String clanAffiliation; protected int ferocity; protected int defense; protected int magic; protected int treasure; protected int health; public Monster(String clanAffiliation, int ferocity, int defense, int magic) { this.clanAffiliation = clanAffiliation; this.ferocity = ferocity; this.defense = defense; this.magic = magic; this.treasure = 0; this.health = 100; } public String getClanAffiliation() { return clanAffiliation; } public int getFerocity() { return ferocity; } public int getDefense() { return defense; } public int getMagic() { return magic; } public int getTreasure() { return treasure; } public int getHealth() { return health; } public void addTreasure(int treasure) { if (health > 0) { this.treasure += treasure; } } public void subtractTreasure(int treasure) { if (health > 0) { this.treasure -= treasure; if (this.treasure < 0) { this.treasure = 0; } } } public void addHealth(int amount) { if (health > 0) { health += amount; } } public void subtractHealth(int amount) { if (health > 0) { health -= amount; if (health < 0) { health = 0; } } } public boolean isAlive() { return health > 0; } public double getBattleScore() { if (health <= 0) { return 0; } return (ferocity + defense + magic) / 3.0; } public abstract void attack(Monster opponent); public abstract void defend(double opponentBattleScore); @Override public String toString() { return "Monster{" + "clanAffiliation='" + clanAffiliation + ''' + ", ferocity=" + ferocity + ", defense=" + defense + ", magic=" + magic + ", treasure=" + treasure + ", health=" + health + '}'; } } public class Orc extends Monster { private OrcCommander commander; public Orc(String clan, int ferocity, int defense, int magic, int treasure, int health) { super(clan, ferocity, defense, magic, treasure, health); } public void setCommander(OrcCommander commander) { this.commander = commander; } public OrcCommander getCommander() { return commander; } public int getLeadership() { if (this instanceof Warlord) { Warlord warlord = (Warlord) this; return warlord.getLeadership(); } return 0; } public int getInfantryCount() { if (this instanceof Warlord) { Warlord warlord = (Warlord) this; return warlord.getInfantryCount(); } return 0; } public void setInfantry(Warlord warlord) { if (this instanceof Infantry) { Infantry infantry = (Infantry) this; infantry.setCommander(warlord); } } @Override public void attack(Monster opponent) { int attackScore = calculateAttackScore(); int defenseScore = opponent.calculateDefenseScore(); int damage = Math.max(attackScore - defenseScore, 0); opponent.takeDamage(damage); } } public class Warlord extends Orc { private int leadershipRating; private Infantry[] infantry; public Warlord(String name, int ferocity, int defense, int magic, int leadershipRating) { super(name, ferocity, defense, magic); this.leadershipRating = leadershipRating; this.infantry = new Infantry[5]; } public int getLeadershipRating() { return leadershipRating; } public void setLeade.

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Provide three evidences with scholar reference that support that euthanasia violates the religious belief three evidences with scholar references support that the legislation of euthanasia can easily be abused by doctors, and relative . Three evidences with scholar references that support that the legislation of euthanasia will weaken a patient will to fight with diseases Provide references for your answer.

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Provincial Government The name of the representative of the Queen for my province is The representative of the Queen in my province, the Lieutenant Governor, is The Head of Government (the Premier) is The name of the provincial party in power is The names of the provincial opposition parties and leaders are My provincial representative is Territorial Government The name of the Commissioner, who represents the federal government in my territory, is The name of the Premier is The name of my territorial representative is Municipal Government The name of the municipality where I live is The name of the head of the municipal government (mayor or reeve) is.

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Prpugh shicti the bloset fides. 1 rightventikiele+3 Fxetcise 22.2 Creot Vesseh of the Heart 2. The uff common carsot anery hit the Eistsecandterdi braoth of the aortic arch. 2 Fxerdses 22.2-22. Systemik Circule 3. Label the diagram mets the appopoiane artery sumet. 3 -(1) A 15 (t) 1 17 2 3 4. b. 6. 20 21 ? 22 b.- Daxnen cinle forsa buids. where the podratie trustape is cuted ter Laerdes 22 int Filose brise Was Structue known as the Lunat Pictemaledeinas Ceercise 22.11. Fiastic Artery-The Aorta a curtave an internai esintr lamion . h. contais migipie layers of smooth minde c. furich meda contains numersua elasitic fitees 1. 7ypifa dianesers e 12.5an in dameter: t. very thin with no smooth muscle cess 7t. The ibilty of an einsic artiy to eyand as it recelees blood from the ventricles is due to (icilagenciatic fors. 24 7. Larpe arterias sach as the aorta are nourtshed by ling blocd versels calles. Fercise 2212 : Muscidar Artery D. The amount of smosth musde in the turics medis of a miakidar alery is. igreatenlesi than that of elaste ateits. 2 . 14. Elase arterits are trpicaly located clonest ts the heart where presures are (Dighest lowest 24 Exercise 22.13: Acteriole 15. Constriction of atestales. ( (Secreasestho eases) blood fiow ines capiling beds. A) Exertise 22.14z Vein 16. Weins are convldered - Dighlisw pr issure versels. 29 12. A venous valve a formed dy an inlalding of the turica firitisinediblextring Exroise 22.15: Capilaries to. Rank the following types of capilaries trom inoost to toast permeable. 2 . is costinutis b. fenestrated c. sinusaidalIncreacaldecremet in puhe site. 68 Finrole 2217. Riaod Pressare and Pulte Using e Standard Dlood Pressure Cuft 21. When medturing tiobd preskur ising a blobd preskes ouft the tiat Kor olkeff saund cocresponds to . (datalichysitgila pressure. wheites the second Korotabli sound comespones to 22. The tidod pressure chanpes that ogcur during the cardaci oyde are detected by meauiring the puits in the (internai jugutar vinhradial antery. Exercise 22.18- A10pac Lossan 16 : Blood Pressure 29. Mean ameilat presuare (Maty b chases in value io a sibitcts. (diastalichystolig biode presiour. 34 24. Wharous extetae - (decoeatesintreases) 5yteric tiood brane. 33 Can You Apply What You've Lnamed? 25. Explain why large blood vesseis hre Bhel owin biocd vessels fiasa vionuary li the funica extema. The phyician will then guide the catheter along the venous system untili it reaches the right atrlum tist, in ordec, the xelos through which the central Inte pesses as it trovels trom the basilic vein to the right atrum of the beat. Basilic vein 28. Ater the centrat ine was placed fquestion 27 , it phiched etf and failed to work when the patient heid a heavy inight in her hand and the inferior mevement of her clavicle campressed the central line within the subdevian vein. The plysian decided to remove the central line focti the basilic vein and place anether center line Into the intemal jugular vein (DV). The INV provid.

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Provide SQL that creates two database tables: Employee and Department, as follows: (Please choose appropriate data types and their lengths for all the attributes) a) The attributes of Employee table are empNumber, firstName, lastName, middleName, DOB, SSN, and deptNumber. b) The attributes of Department table are deptNumber, and deptName. c) Make empNumber and deptNumber primary keys in their respective tables. d) Make deptNumber in Employee table, a foreign key. e) Make all attributes NOT NULL in both tables except middleName and deptNumber in Employee table..

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Program 02 Based on the previous problem, you should implement this second problem in the same file a05.c. Find the places in the code marked with the ToDo label and complete the work. You should not change any other part of the code. This includes do not add any global variables or any other function. For this problem, we are reusing the same struct from problem 1, but adding a pointer to the struct to be able to create a linked list. In this problem, you must use linked list to create a user playlist (play_list). The struct is holding the information of a song: ID, Name, Singer, Genre, Year, and the pointer Next (the pointer to the struct). There should be the following functions. In the similar way we have done in previous assignments, complete the following functions: Add a song to the play_list - always inserted at the end of the list. Search song by name - given the name of the song, return the struct with the data of the song. Edit a song - given the name of the song, find it in the play_list and modify any of the fields of the song (ID cannot be edited, and all fields should have a valid value). Return -1 if the song was not found. Delete a song - given the name of the song, find it, delete the song from the play_list (i.e., disconnect the node from the list). Return -1 if the song was not found, 1 if it was deleted. // Problem 2 // struct to hold information about a song struct Song { int id; char name[MAX_SONG_NAME_LENGTH]; char singer[MAX_SINGER_NAME_LENGTH]; genreType genre; int year; struct Song *next; }; // Function declarations struct Song *createSong(int id, char *name, char *singer, char *genre, int year); void printPlaylist(struct Song *playlist); void add_song(struct Song **playlist, struct Song *newSong); struct Song *search_song(struct Song *playlist, char *name); int edit_song(struct Song *playlist, char *name, char *singer, char *genre, int year); int delete_song(struct Song *playlist, char *name); // function to create a new song struct Song *createSong(int id, char *name, char *singer, char *genre, int year) { struct Song *newSong = (struct Song *)malloc(sizeof(struct Song)); newSong->id = id; strcpy(newSong->name, name); strcpy(newSong->singer, singer); if (strcmp(genre, "Pop") == 0) newSong->genre = 1; else if (strcmp(genre, "Rock") == 0) newSong->genre = 2; else if (strcmp(genre, "Reggae") == 0) newSong->genre = 3; else if (strcmp(genre, "Country") == 0) newSong->genre = 4; else if (strcmp(genre, "Blues") == 0) newSong->genre = 5; else if (strcmp(genre, "Balad") == 0) newSong->genre = 6; else newSong->genre = 0; newSong->year = year; newSong->next = NULL; return newSong; } // function to print the playlist void printPlaylist(struct Song *playlist) { struct Song *current = playlist; while (current != NULL) { printf("%dt%st%st%dt%dn", current->id, current->name, current->singer, current->genre, current->year); current = current->next; } } // function to add a song to the end of the playlist void add_song(struct Song .

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