1. The vertical end of a trough is trapezoidal in shape, with dimensions provided. The area is calculated to be 1.89 square meters. 2. A square ABCD has a side of length x. An equilateral triangle BEC is inscribed inside the square, with BC equal to x. To calculate the angle AED: a sketch is made, with altitude EF drawn and shown to bisect BC at the midpoint; GE is then calculated to be {(2 - √3)x}/2; and tan(AED) = GE/EF to find the angle.

1. NEED THE COMPLETE SOLUTION WITH ILLUSTRATION PLEASE! THANKS:)
1. the vertical end of a trough, which is in the form of a trapezoid, has the following dimensions:
width at the top is 1.65m, width at the bottom is 1.15m and depth is 1.35m. find the area of this
section of the trough.
2,a square section ABCD has one of its sides equal to x . point E is inside the square forming an
equilateral triangle BEC with one side equal in length to the side of the square. find angle AED.
Solution
1)A = (1/2)h(b1 + b2) = (1/2)(1.35 m)(1.65m + 1.15 m) = (1/2)(1.35 m)(2.8 cm) = 1.89 m^2
2)i) Kindly make a sketch for the description. BEC is an equilateral triangle inscribed in the
square whose side equal to measure of BC.
ii) So, BC = BE = EC = x units.
iii) Draw an altitude through the vertex E and perpendicular to BC;
let it meet BC at F and AD at G.
iv) Since in an equilateral triangle, the altitude bisects the base, F is mid point of BC; as well G
is the midpoint of AD.
EF being altitude of the equilateral triangle, EF = (?3)x/2 units
So, GE = x - (?3)x/2 = {(2 - ?3)x}/2
v) So from the above, tan(