Solve for x the module equation |2x+16|=24? Solution We recall the property of absolute value: |x| = a>0 We\'ll have to discuss 2 cases: 1) 2x+16 = 24, if 2x+16>=0 => x belongs to [8;+infinite) We\'ll subtract 16 both sides: 2x = 24-16 2x = 8 We\'ll divide by 2: x = 4 2) 2x+16 = -24, if 2x+16<0 => x belongs to (-infinite,8) We\'ll subtract 16 both sides, to isolate x to the left side: 2x = -16 - 24 2x = -40 We\'ll divide by 2: x = -20 Since both values are in theadmissibleintervals, they both become thesolutions of theequation: {- 20 ; 4}..