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114 Handy Formulae for Quantitative Aptitude Problems
                                                    Author: Sagar Sonker

                               Table of Contents
     ℵ Numbers
     ℵ H.C.F & L.C.M of Numbers
     ℵ Surds & Indices
     ℵ Percentage
     ℵ Profit & Loss
     ℵ Ratio & Proportion
     ℵ Partnership
     ℵ Chain Rule
     ℵ Time & Work
     ℵ Pipes & Cisterns
     ℵ Time And Distance
     ℵ Trains
     ℵ Boats & Streams
     ℵ Alligation or Mixture
     ℵ Simple Interest
     ℵ Compound Interest
     ℵ Logarithms
     ℵ Area
     ℵ Volume & Surface Area
     ℵ Stocks & Shares
     ℵ True Discount
     ℵ Banker’s Discount
     ℵ Copyright Notice




                                                              Page 1 of 12
                                          Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                              Author: Sagar Sonker

                                                   Numbers

  1. A number is divisible by 2, if its unit’s place digit is 0, 2, 4, or 8

  2. A number is divisible by 3, if the sum of its digits is divisible by 3

  3. A number is divisible by 4, if the number formed by its last two digits is divisible by 4

  4. A number is divisible by 8, if the number formed by its last three digits is divisible by 8

  5. A number is divisible by 9, if the sum of its digits is divisible by 9

  6. A number is divisible by 11, if, starting from the RHS,
     (Sum of its digits at the odd place) – (Sum of its digits at even place) is equal to 0 or 11x

  7. (a + b)2            = a2 + 2ab + b2

  8. (a - b)2            = a2 - 2ab + b2

  9. (a + b)2 - (a - b)2= 4ab

  10. (a + b)2 + (a - b)2 = 2(a2 + b2)

  11. (a2 – b2)          = (a + b)(a - b)

  12. (a3 + b3)          = (a + b)(a2 - ab + b2)

  13. (a3 – b3)          = (a - b)(a2 + ab + b2)

  14. Results on Division:

                Dividend = Quotient × Divisor + Remainder

  15. An Arithmetic Progression (A. P.) with first term ‘a’ and Common Difference ‘d’ is given
        by:
              [a], [(a + d)], [(a + 2d)], … … …, [a + (n - 1)d]

                nth term, Tn              = a + (n - 1)d
                Sum of first ‘n’ terms, Sn
                                          = n/2 (First Term + Last Term)

  16. A Geometric Progression (G. P.) with first term ‘a’ and Common Ratio ‘r’ is given by:
            a, ar, ar2, ar3, … … …, arn-1

                nth term, Tn              = arn-1
                Sum of first ‘n’ terms Sn = [a(1 - rn)] / [1 - r]

  17. (1 + 2 + 3 + … … … + n)               = [n(n + 1)] / 2

  18. (12 + 22 + 32 + … … … + n2)           = [n(n + 1)(2n + 1)] / 6

  19. (13 + 23 + 33 + … … … + n3)           = [n2(n + 1)2] / 4




                                                                                     Page 2 of 12
                                                                 Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                         Author: Sagar Sonker

                                     H.C.F & L.C.M of Numbers

  20. Product of two numbers = Their H. C. F. × Their L. C. M.

                                         Surds & Indices

  21. am × an           = a(m + n)

  22. am / an           = a(m - n)

  23. (ab)m             = a mb m

  24. (a / b)m          = an / bn

  25. a0                =1

  26.                   = a1/n

  27.                   = (a1/n)n
                        =a

  28.                   =


  29.                   =        /

  30. (    )m           =


  31.                   =

                                              Percentage

  32. To express x% as a fraction, we have x% = x / 100

  33. To express a / b as a percent, we have a / b = (a / b × 100) %

  34. If ‘A’ is R% more than ‘B’, then ‘B’ is less than ‘A’ by
                                         OR
          If the price of a commodity increases by R%, then the reduction in consumption, not
          to increase the expenditure is

                        {100R / [100 + R] } %

  35. If ‘A’ is R% less than ‘B’, then ‘B’ is more than ‘A’ by
                                          OR
          If the price of a commodity decreases by R%, then the increase in consumption, not to
          increase the expenditure is

                        {100R / [100 - R] } %

  36. If the population of a town is ‘P’ in a year, then its population after ‘N’ years is

                        P (1 + R/100)N

                                                                               Page 3 of 12
                                                           Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                            Author: Sagar Sonker


  37. If the population of a town is ‘P’ in a year, then its population ‘N’ years ago is

                         P / [(1 + R/100)N]

                                               Profit & Loss

  38. If the value of a machine is ‘P’ in a year, then its value after ‘N’ years at a depreciation of
          ‘R’ p.c.p.a is

                         P (1 - R/100)N

  39. If the value of a machine is ‘P’ in a year, then its value ‘N’ years ago at a depreciation of
          ‘R’ p.c.p.a is

                         P / [(1 - R/100)N]

  40. Selling Price      = [(100 + Gain%) × Cost Price] / 100

                         = [(100 - Loss%) × Cost Price] / 100

                                          Ratio & Proportion

  41. The equality of two ratios is called a proportion. If a : b = c : d, we write a : b :: c : d and
         we say that a, b, c, d are in proportion.
      In a proportion, the first and fourth terms are known as extremes, while the second and
      third are known as means.

  42. Product of extremes          = Product of means

  43. Mean proportion between a and b is

  44. The compounded ratio of the ratios (a : b), (c : d), (e : f) is (ace : bdf)

  45. a2 : b2 is a duplicate ratio of a : b

  46.     :   is a sub-duplicate ration of a : b

  47. a3 : b3 is a triplicate ratio of a : b

  48. a1/3 : b1/3 is a sub-triplicate ratio of a : b

  49. If a / b = c / d, then, (a + b) / b = (c + d) / d, which is called the componendo.

  50. If a / b = c / d, then, (a - b) / b = (c - d) / d, which is called the dividendo.

  51. If a / b = c / d, then, (a + b) / (a - b) = (c + d) / (c - d), which is called the componendo &
         dividendo.

  52. Variation: We say that x is directly proportional to y if x = ky for some constant k and we
        write, x α y.

  53. Also, we say that x is inversely proportional to y if x = k / y for some constant k and we
        write x α 1 / y.



                                                                                   Page 4 of 12
                                                               Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                         Author: Sagar Sonker

                                            Partnership

  54. If a number of partners have invested in a business and it has a profit, then

                       Share Of Partner = (Total_Profit × Part_Share / Total_Share)

                                             Chain Rule

  55. The cost of articles is directly proportional to the number of articles.

  56. The work done is directly proportional to the number of men working at it.

  57. The time (number of days) required to complete a job is inversely proportional to the
        number of hours per day allocated to the job.

  58. Time taken to cover a distance is inversely proportional to the speed of the car.

                                            Time & Work

  59. If A can do a piece of work in n days, then A’s 1 day’s work = 1/n.

  60. If A’s 1 day’s work = 1/n, then A can finish the work in n days.

  61. If A is thrice as good a workman as B, then:
      Ratio of work done by A and B = 3 : 1,
      Ratio of times taken by A & B to finish a work = 1 : 3

                                         Pipes & Cisterns

  62. If a pipe can fill a tank in ‘x’ hours and another pipe can empty the full tank in ‘y’ hours
         (where y > x), then on opening both the pipes, the net part of the tank filled in 1 hour is

                       (1/x – 1/y)

                                        Time And Distance

  63. Suppose a man covers a distance at ‘x’ kmph and an equal distance at ‘y’ kmph, then
        average speed during his whole journey is

                       [2xy / (x + y)] kmph

                                                 Trains

  64. Lengths of trains are ‘x’ km and ‘y’ km, moving at ‘u’ kmph and ‘v’ kmph (where, u > v) in
        the same direction, then the time taken y the over-taker train to cross the slower train is

                       [(x + y) / (u - v)] hrs

  65. Time taken to cross each other is

                       [(x + y) / (u + v)] hrs

  66. If two trains start at the same time from two points A and B towards each other and after
          crossing they take a and b hours in reaching B and A respectively.


                                                                              Page 5 of 12
                                                          Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                        Author: Sagar Sonker

      Then, A’s speed : B’s speed = (      :   ).

  67. x kmph = (x × 5/18) m/sec.

  68. y metres/sec = (y × 18/5) km/hr.

                                        Boats & Streams

  69. If the speed of a boat in still water is u km/hr and the speed of the stream is v hm/hr,
          then:
                       Speed downstream = (u + v) km/hr.
                       Speed upstream = (u - v) km/hr.

  70. If the speed downstream is a km/hr and the speed upstream is b km/hr, then:

                       Speed in still water = ½ (a + b) km/hr.
                       Rate of stream = ½ (a - b) km/hr.

                                      Alligation or Mixture

  71. Alligation: It is the rule that enables us to find the ratio in which two or more ingredients at
         the given price must be mixed to produce a mixture at a given price.

  72. Mean Price: The cost price of a quantity of the mixture is called the mean price.

  73. Rule of Alligation: If two ingredients are mixed, then:




  74. We represent the above formula as under:




  75. .: (Cheaper quantity) : (Dearer quantity) = (d - m) : (m - c)

                                         Simple Interest

  76. Let Principle = P, Rate = R% per annum and Time = T years. Then,

          a.   S.I.    = ( P × R × T ) / 100
          b.   P       = ( 100 × S.I. ) / ( R × T ),
          c.   R       = ( 100 × S.I. ) / ( P × T ),
          d.   T       = ( 100 × S.I. ) / ( P × R ).



                                                                              Page 6 of 12
                                                          Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                              Author: Sagar Sonker

                                            Compound Interest

  77. Let Principle = P, Rate = R% per annum and Time = T years. Then,

                        I.          When interest is compounded Annually,

                                    Amount = P (1 + R/100)N

                        II.         When interest is compounded Half-yearly:

                                    Amount = P (1 + R/2/100)2N

                        III.        When interest is compounded Quarterly:

                                    Amount = P (1 + R/4/100)4N

  78. When interest is compounded Annually, but the time is in fraction, say 3⅞ years.

                              Then, Amount = P (1 + R/100)3 × (1 + ⅞R/100)

  79. When Rates are different for different years, say R1%, R2%, R3% for 1st, 2nd, and 3rd year
       respectively,
                     Then, Amount = P (1 + R1/100) (1 + R2/100) (1 + R3/100)

  80. Present worth of Rs. x due n years hence is given by:

                              Present Worth = x / (1 + R/100)n

                                                   Logarithms

  81. Logarithm: If a is a positive real number, other than 1 and am = x, then we write m = loga x
        and say that the value of log x to the base a is m.

  82. Properties of Logarithms:

          a. loga (xy)                = loga x + loga y

          b. loga (x/y)               = loga x - loga y

          c.   logx x                 = 1 (i.e. Log of any number to its own base is 1)

          d. loga 1                   = 0 (i.e. Log of 1 to any base is 0)

          e. loga (xp)                = p loga x

          f.   loga x                 = 1 / logx a

          g. loga x                   = logb x / logb a
                                      = log x / log a (Change of base rule)

          h. When base is not mentioned, it is taken as 10
          i. Logarithms to the base 10 are known as common logarithms
          j. The logarithm of a number contains two parts, namely characteristic and
             mantissa. The integral part is known as characteristic and the decimal part is
             known as mantissa.


                                                                                     Page 7 of 12
                                                                 Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                            Author: Sagar Sonker

                      I.       Case 1: When the number is greater than 1.
                               In this case, the characteristic is one less than the number of digits
                               in the left of decimal point in the given number.
                      II.      Case 2: When the number is less than 1.
                               In this case, the characteristic is one more than the number of
                               zeroes between the decimal point and the first significant digit of
                               the number and it is negative.

                               e.g.
                                Number              Characteristic
                                234.56              2
                                23.456              1
                                2.34                0
                                0.234               -1
                                0.0234              -2
                                0.00234             -3

                      III.     For mantissa, we look through the log table.

                      IV.      Antilog: If log x = y, then antilog y = x.

                                                Area

  83. Rectangle:

          a. Area of a rectangle          = (length × breadth)

          b. Perimeter of a rectangle = 2 (length + breadth)

  84. Square:

          a. Area of square = (side)2

          b. Area of a square = ½ (diagonal)2

  85. Area of 4 walls of a room
                               = 2 (length + breadth) × height

  86. Triangle:

          a. Area of a triangle = ½ × base × height

          b. Area of a triangle =                             , where

                s = ½ (a + b + c), and a, b, c are the sides of the triangle

          c.    Area of an equilateral triangle =      / 4 × (side)2

          d. Radius of incircle of an equilateral triangle of side a = a / 2

          e. Radius of circumcircle of an equilateral triangle of side a = a /

  87. Parallelogram/Rhombus/Trapezium:

          a. Area of a parallelogram = Base × Height

                                                                                Page 8 of 12
                                                            Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                       Author: Sagar Sonker


          b. Area of a rhombus          = ½ × (Product of diagonals)

          c.    The halves of diagonals and a side of a rhombus form a right angled triangle with
                side as the hypotenuse.

          d. Area of trapezium          = ½ × (sum of parallel sides) × (distance between them)

  88. Circle/Arc/Sector, where R is the radius of the circle:

          a. Area of a circle           = πR2

          b. Circumference of a circle = 2πR

          c.    Length of an arc        = Ө/360 × 2πR

          d. Area of a sector           = ½ (arc × R)

                                        = Ө/360 × πR2

                                     Volume & Surface Area

  89. Cuboid:

          Let length = l, breadth = b & height = h units Then,

          a. Volume             = (l × b × h) cu units

          b. Surface Area       = 2 (lb + bh + hl) sq. units

          c.    Diagonal        =               units

  90. Cube:

          Let each edge of a cube be of length a. Then,

          a. Volume             = a3 cu units

          b. Surface Area       = 6a2 sq. units

          c.    Diagonal        =(    × a) units

  91. Cylinder:

          Let radius of base = r & height (or length) = h. Then,

          a. Volume             = (πr2h) cu. units

          b. Curved Surface Area = (2πrh) sq. units

          c.    Total Surface Area = 2πr(r + h) sq. units

  92. Cone:

          Let radius of base = r & height = h. Then,


                                                                                Page 9 of 12
                                                            Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                      Author: Sagar Sonker


          a. Slant height, l    =         units

          b. Volume             = (⅓ πr2h) cu. units

          c.    Curved Surface Area = (πrl) sq. units

          d. Total Surface Area = πr(r + l) sq. units

  93. Sphere:

          Let the radius of the sphere be r. Then,

          a. Volume             = (4/3 πr3) cu. units

          b. Surface Area       = (4πr2) sq. units

  94. Hemi-sphere:

          Let the radius of the sphere be r. Then,

          a. Volume             = (2/3 πr3) cu. units

          b. Curved Surface Area = (2πr2) sq. units

          c.    Total Surface Area = (3πr2) sq. units

                                        Stocks & Shares

  95. Brokerage: The broker’s charge is called brokerage.

  96. When stock is purchased, brokerage is added to the cost price.

  97. When the stock is sold, brokerage is subtracted from the selling price.

  98. The selling price of a Rs. 100 stock is said to be:

          a. at par, if S.P. is Rs. 100 exactly;
          b. above par (or at premium), if S.P. is more than Rs. 100;
          c. below par (or at discount), if S.P. is less than Rs. 100.

  99. By ‘a Rs. 800, 9% stock at 95’, we mean a stock whose face value is Rs. 800, annual
        interest is 9% of the face value and the market price of a Rs. 100 stock is Rs. 95.

                                         True Discount

  100. Suppose a man has to pay Rs. 156 after 4 years and the rate of interest is 14% per
       annum. Clearly, Rs. 100 at 14% will amount to Rs. 156 in 4 years. So, the payment of
       Rs. 100 now will clear off the debt of Rs. 156 due 4 years hence. We say that:

                Sum due         = Rs. 156 due 4 years hence;
                Present Worth (P.W.) = Rs. 100;
                True Discount (T.D.) = Rs. (156 - 100)
                                = (Sum due) – (P.W.)



                                                                               Page 10 of 12
                                                            Copyright © 2006 www.sonker.com
114 Handy Formulae for Quantitative Aptitude Problems
                                                                      Author: Sagar Sonker

  101. T.D.           = Interest on P.W.

  102. Amount         = (P.W.) + (T.D.)

  103. Interest is reckoned on R.W. and true discount is reckoned on the amount

  104. Let rate = R% per annum & time = T years. Then,

          a. P.W.     = (100 × Amount) / (100 + [R × T])
                      = (100 × T.D.) / (R × T)

          b. T.D.     = (P.W.) × R × T / 100
                      = ([Amount] × R × T) / (100 + [R × T])

          c.   Sum    = ([S.I.] × [T.D.]) / ([S.I.] – [T.D.])

          d. (S.I.) – (T.D.) = S.I. on T.D.

          e. When the sum is put at compound interest, then

                      P.W. = Amount / (1 + R/100)T

                                       Banker’s Discount

  105. Banker’s Discount (B.D.) is the S.I. on the face value for the period from the date on
       which the bill was discounted and the legally due date.

  106. Banker’s Gain (B.G.) = (B.D.) – (T.D.) for the unexpired time

  107. When the date of the bill is not given, grace days are not to be added

  108. B.D.           = S.I. on bill for unexpired time

  109. B.G.           = (B.D.) – (T.D.)
                      = S.I. on T.D.
                      = (T.D.)2 / P.W.

  110. T.D.           =

  111. B.D.           = (Amount × Rate × Time) / 100

  112. T.D.           = (Amount × Rate × Time) / (100 + [Rate × Time])

  113. Amount         = (B.D. × T.D.) / (B.D. – T.D.)

  114. T.D.           = (B.G. × 100) / (Rate × Time)


  Copyright Notice:
  Feel free to share, print, copy, distribute this document for free. Make sure to preserve this
  copyright notice alongwith the header and footer with the copyright note of www.sonker.com.

  Be sure to read the copyright information and terms of use of the documents at
  http://www.sonker.com/sagar/Copyright.htm before you share, print, copy, distribute this
  document.


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                                                               Author: Sagar Sonker


  Illegal reproduction of this document without the prior permission of the author and/or
  removal of this copyright notice and/or the header/footer gives www.sonker.com the full
  authority to take a legal action.

  Do you have any more information to add to this document? Write to me at
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Important formulaeforquantitativeaptitude

  • 1. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker Table of Contents ℵ Numbers ℵ H.C.F & L.C.M of Numbers ℵ Surds & Indices ℵ Percentage ℵ Profit & Loss ℵ Ratio & Proportion ℵ Partnership ℵ Chain Rule ℵ Time & Work ℵ Pipes & Cisterns ℵ Time And Distance ℵ Trains ℵ Boats & Streams ℵ Alligation or Mixture ℵ Simple Interest ℵ Compound Interest ℵ Logarithms ℵ Area ℵ Volume & Surface Area ℵ Stocks & Shares ℵ True Discount ℵ Banker’s Discount ℵ Copyright Notice Page 1 of 12 Copyright © 2006 www.sonker.com
  • 2. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker Numbers 1. A number is divisible by 2, if its unit’s place digit is 0, 2, 4, or 8 2. A number is divisible by 3, if the sum of its digits is divisible by 3 3. A number is divisible by 4, if the number formed by its last two digits is divisible by 4 4. A number is divisible by 8, if the number formed by its last three digits is divisible by 8 5. A number is divisible by 9, if the sum of its digits is divisible by 9 6. A number is divisible by 11, if, starting from the RHS, (Sum of its digits at the odd place) – (Sum of its digits at even place) is equal to 0 or 11x 7. (a + b)2 = a2 + 2ab + b2 8. (a - b)2 = a2 - 2ab + b2 9. (a + b)2 - (a - b)2= 4ab 10. (a + b)2 + (a - b)2 = 2(a2 + b2) 11. (a2 – b2) = (a + b)(a - b) 12. (a3 + b3) = (a + b)(a2 - ab + b2) 13. (a3 – b3) = (a - b)(a2 + ab + b2) 14. Results on Division: Dividend = Quotient × Divisor + Remainder 15. An Arithmetic Progression (A. P.) with first term ‘a’ and Common Difference ‘d’ is given by: [a], [(a + d)], [(a + 2d)], … … …, [a + (n - 1)d] nth term, Tn = a + (n - 1)d Sum of first ‘n’ terms, Sn = n/2 (First Term + Last Term) 16. A Geometric Progression (G. P.) with first term ‘a’ and Common Ratio ‘r’ is given by: a, ar, ar2, ar3, … … …, arn-1 nth term, Tn = arn-1 Sum of first ‘n’ terms Sn = [a(1 - rn)] / [1 - r] 17. (1 + 2 + 3 + … … … + n) = [n(n + 1)] / 2 18. (12 + 22 + 32 + … … … + n2) = [n(n + 1)(2n + 1)] / 6 19. (13 + 23 + 33 + … … … + n3) = [n2(n + 1)2] / 4 Page 2 of 12 Copyright © 2006 www.sonker.com
  • 3. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker H.C.F & L.C.M of Numbers 20. Product of two numbers = Their H. C. F. × Their L. C. M. Surds & Indices 21. am × an = a(m + n) 22. am / an = a(m - n) 23. (ab)m = a mb m 24. (a / b)m = an / bn 25. a0 =1 26. = a1/n 27. = (a1/n)n =a 28. = 29. = / 30. ( )m = 31. = Percentage 32. To express x% as a fraction, we have x% = x / 100 33. To express a / b as a percent, we have a / b = (a / b × 100) % 34. If ‘A’ is R% more than ‘B’, then ‘B’ is less than ‘A’ by OR If the price of a commodity increases by R%, then the reduction in consumption, not to increase the expenditure is {100R / [100 + R] } % 35. If ‘A’ is R% less than ‘B’, then ‘B’ is more than ‘A’ by OR If the price of a commodity decreases by R%, then the increase in consumption, not to increase the expenditure is {100R / [100 - R] } % 36. If the population of a town is ‘P’ in a year, then its population after ‘N’ years is P (1 + R/100)N Page 3 of 12 Copyright © 2006 www.sonker.com
  • 4. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker 37. If the population of a town is ‘P’ in a year, then its population ‘N’ years ago is P / [(1 + R/100)N] Profit & Loss 38. If the value of a machine is ‘P’ in a year, then its value after ‘N’ years at a depreciation of ‘R’ p.c.p.a is P (1 - R/100)N 39. If the value of a machine is ‘P’ in a year, then its value ‘N’ years ago at a depreciation of ‘R’ p.c.p.a is P / [(1 - R/100)N] 40. Selling Price = [(100 + Gain%) × Cost Price] / 100 = [(100 - Loss%) × Cost Price] / 100 Ratio & Proportion 41. The equality of two ratios is called a proportion. If a : b = c : d, we write a : b :: c : d and we say that a, b, c, d are in proportion. In a proportion, the first and fourth terms are known as extremes, while the second and third are known as means. 42. Product of extremes = Product of means 43. Mean proportion between a and b is 44. The compounded ratio of the ratios (a : b), (c : d), (e : f) is (ace : bdf) 45. a2 : b2 is a duplicate ratio of a : b 46. : is a sub-duplicate ration of a : b 47. a3 : b3 is a triplicate ratio of a : b 48. a1/3 : b1/3 is a sub-triplicate ratio of a : b 49. If a / b = c / d, then, (a + b) / b = (c + d) / d, which is called the componendo. 50. If a / b = c / d, then, (a - b) / b = (c - d) / d, which is called the dividendo. 51. If a / b = c / d, then, (a + b) / (a - b) = (c + d) / (c - d), which is called the componendo & dividendo. 52. Variation: We say that x is directly proportional to y if x = ky for some constant k and we write, x α y. 53. Also, we say that x is inversely proportional to y if x = k / y for some constant k and we write x α 1 / y. Page 4 of 12 Copyright © 2006 www.sonker.com
  • 5. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker Partnership 54. If a number of partners have invested in a business and it has a profit, then Share Of Partner = (Total_Profit × Part_Share / Total_Share) Chain Rule 55. The cost of articles is directly proportional to the number of articles. 56. The work done is directly proportional to the number of men working at it. 57. The time (number of days) required to complete a job is inversely proportional to the number of hours per day allocated to the job. 58. Time taken to cover a distance is inversely proportional to the speed of the car. Time & Work 59. If A can do a piece of work in n days, then A’s 1 day’s work = 1/n. 60. If A’s 1 day’s work = 1/n, then A can finish the work in n days. 61. If A is thrice as good a workman as B, then: Ratio of work done by A and B = 3 : 1, Ratio of times taken by A & B to finish a work = 1 : 3 Pipes & Cisterns 62. If a pipe can fill a tank in ‘x’ hours and another pipe can empty the full tank in ‘y’ hours (where y > x), then on opening both the pipes, the net part of the tank filled in 1 hour is (1/x – 1/y) Time And Distance 63. Suppose a man covers a distance at ‘x’ kmph and an equal distance at ‘y’ kmph, then average speed during his whole journey is [2xy / (x + y)] kmph Trains 64. Lengths of trains are ‘x’ km and ‘y’ km, moving at ‘u’ kmph and ‘v’ kmph (where, u > v) in the same direction, then the time taken y the over-taker train to cross the slower train is [(x + y) / (u - v)] hrs 65. Time taken to cross each other is [(x + y) / (u + v)] hrs 66. If two trains start at the same time from two points A and B towards each other and after crossing they take a and b hours in reaching B and A respectively. Page 5 of 12 Copyright © 2006 www.sonker.com
  • 6. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker Then, A’s speed : B’s speed = ( : ). 67. x kmph = (x × 5/18) m/sec. 68. y metres/sec = (y × 18/5) km/hr. Boats & Streams 69. If the speed of a boat in still water is u km/hr and the speed of the stream is v hm/hr, then: Speed downstream = (u + v) km/hr. Speed upstream = (u - v) km/hr. 70. If the speed downstream is a km/hr and the speed upstream is b km/hr, then: Speed in still water = ½ (a + b) km/hr. Rate of stream = ½ (a - b) km/hr. Alligation or Mixture 71. Alligation: It is the rule that enables us to find the ratio in which two or more ingredients at the given price must be mixed to produce a mixture at a given price. 72. Mean Price: The cost price of a quantity of the mixture is called the mean price. 73. Rule of Alligation: If two ingredients are mixed, then: 74. We represent the above formula as under: 75. .: (Cheaper quantity) : (Dearer quantity) = (d - m) : (m - c) Simple Interest 76. Let Principle = P, Rate = R% per annum and Time = T years. Then, a. S.I. = ( P × R × T ) / 100 b. P = ( 100 × S.I. ) / ( R × T ), c. R = ( 100 × S.I. ) / ( P × T ), d. T = ( 100 × S.I. ) / ( P × R ). Page 6 of 12 Copyright © 2006 www.sonker.com
  • 7. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker Compound Interest 77. Let Principle = P, Rate = R% per annum and Time = T years. Then, I. When interest is compounded Annually, Amount = P (1 + R/100)N II. When interest is compounded Half-yearly: Amount = P (1 + R/2/100)2N III. When interest is compounded Quarterly: Amount = P (1 + R/4/100)4N 78. When interest is compounded Annually, but the time is in fraction, say 3⅞ years. Then, Amount = P (1 + R/100)3 × (1 + ⅞R/100) 79. When Rates are different for different years, say R1%, R2%, R3% for 1st, 2nd, and 3rd year respectively, Then, Amount = P (1 + R1/100) (1 + R2/100) (1 + R3/100) 80. Present worth of Rs. x due n years hence is given by: Present Worth = x / (1 + R/100)n Logarithms 81. Logarithm: If a is a positive real number, other than 1 and am = x, then we write m = loga x and say that the value of log x to the base a is m. 82. Properties of Logarithms: a. loga (xy) = loga x + loga y b. loga (x/y) = loga x - loga y c. logx x = 1 (i.e. Log of any number to its own base is 1) d. loga 1 = 0 (i.e. Log of 1 to any base is 0) e. loga (xp) = p loga x f. loga x = 1 / logx a g. loga x = logb x / logb a = log x / log a (Change of base rule) h. When base is not mentioned, it is taken as 10 i. Logarithms to the base 10 are known as common logarithms j. The logarithm of a number contains two parts, namely characteristic and mantissa. The integral part is known as characteristic and the decimal part is known as mantissa. Page 7 of 12 Copyright © 2006 www.sonker.com
  • 8. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker I. Case 1: When the number is greater than 1. In this case, the characteristic is one less than the number of digits in the left of decimal point in the given number. II. Case 2: When the number is less than 1. In this case, the characteristic is one more than the number of zeroes between the decimal point and the first significant digit of the number and it is negative. e.g. Number Characteristic 234.56 2 23.456 1 2.34 0 0.234 -1 0.0234 -2 0.00234 -3 III. For mantissa, we look through the log table. IV. Antilog: If log x = y, then antilog y = x. Area 83. Rectangle: a. Area of a rectangle = (length × breadth) b. Perimeter of a rectangle = 2 (length + breadth) 84. Square: a. Area of square = (side)2 b. Area of a square = ½ (diagonal)2 85. Area of 4 walls of a room = 2 (length + breadth) × height 86. Triangle: a. Area of a triangle = ½ × base × height b. Area of a triangle = , where s = ½ (a + b + c), and a, b, c are the sides of the triangle c. Area of an equilateral triangle = / 4 × (side)2 d. Radius of incircle of an equilateral triangle of side a = a / 2 e. Radius of circumcircle of an equilateral triangle of side a = a / 87. Parallelogram/Rhombus/Trapezium: a. Area of a parallelogram = Base × Height Page 8 of 12 Copyright © 2006 www.sonker.com
  • 9. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker b. Area of a rhombus = ½ × (Product of diagonals) c. The halves of diagonals and a side of a rhombus form a right angled triangle with side as the hypotenuse. d. Area of trapezium = ½ × (sum of parallel sides) × (distance between them) 88. Circle/Arc/Sector, where R is the radius of the circle: a. Area of a circle = πR2 b. Circumference of a circle = 2πR c. Length of an arc = Ө/360 × 2πR d. Area of a sector = ½ (arc × R) = Ө/360 × πR2 Volume & Surface Area 89. Cuboid: Let length = l, breadth = b & height = h units Then, a. Volume = (l × b × h) cu units b. Surface Area = 2 (lb + bh + hl) sq. units c. Diagonal = units 90. Cube: Let each edge of a cube be of length a. Then, a. Volume = a3 cu units b. Surface Area = 6a2 sq. units c. Diagonal =( × a) units 91. Cylinder: Let radius of base = r & height (or length) = h. Then, a. Volume = (πr2h) cu. units b. Curved Surface Area = (2πrh) sq. units c. Total Surface Area = 2πr(r + h) sq. units 92. Cone: Let radius of base = r & height = h. Then, Page 9 of 12 Copyright © 2006 www.sonker.com
  • 10. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker a. Slant height, l = units b. Volume = (⅓ πr2h) cu. units c. Curved Surface Area = (πrl) sq. units d. Total Surface Area = πr(r + l) sq. units 93. Sphere: Let the radius of the sphere be r. Then, a. Volume = (4/3 πr3) cu. units b. Surface Area = (4πr2) sq. units 94. Hemi-sphere: Let the radius of the sphere be r. Then, a. Volume = (2/3 πr3) cu. units b. Curved Surface Area = (2πr2) sq. units c. Total Surface Area = (3πr2) sq. units Stocks & Shares 95. Brokerage: The broker’s charge is called brokerage. 96. When stock is purchased, brokerage is added to the cost price. 97. When the stock is sold, brokerage is subtracted from the selling price. 98. The selling price of a Rs. 100 stock is said to be: a. at par, if S.P. is Rs. 100 exactly; b. above par (or at premium), if S.P. is more than Rs. 100; c. below par (or at discount), if S.P. is less than Rs. 100. 99. By ‘a Rs. 800, 9% stock at 95’, we mean a stock whose face value is Rs. 800, annual interest is 9% of the face value and the market price of a Rs. 100 stock is Rs. 95. True Discount 100. Suppose a man has to pay Rs. 156 after 4 years and the rate of interest is 14% per annum. Clearly, Rs. 100 at 14% will amount to Rs. 156 in 4 years. So, the payment of Rs. 100 now will clear off the debt of Rs. 156 due 4 years hence. We say that: Sum due = Rs. 156 due 4 years hence; Present Worth (P.W.) = Rs. 100; True Discount (T.D.) = Rs. (156 - 100) = (Sum due) – (P.W.) Page 10 of 12 Copyright © 2006 www.sonker.com
  • 11. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker 101. T.D. = Interest on P.W. 102. Amount = (P.W.) + (T.D.) 103. Interest is reckoned on R.W. and true discount is reckoned on the amount 104. Let rate = R% per annum & time = T years. Then, a. P.W. = (100 × Amount) / (100 + [R × T]) = (100 × T.D.) / (R × T) b. T.D. = (P.W.) × R × T / 100 = ([Amount] × R × T) / (100 + [R × T]) c. Sum = ([S.I.] × [T.D.]) / ([S.I.] – [T.D.]) d. (S.I.) – (T.D.) = S.I. on T.D. e. When the sum is put at compound interest, then P.W. = Amount / (1 + R/100)T Banker’s Discount 105. Banker’s Discount (B.D.) is the S.I. on the face value for the period from the date on which the bill was discounted and the legally due date. 106. Banker’s Gain (B.G.) = (B.D.) – (T.D.) for the unexpired time 107. When the date of the bill is not given, grace days are not to be added 108. B.D. = S.I. on bill for unexpired time 109. B.G. = (B.D.) – (T.D.) = S.I. on T.D. = (T.D.)2 / P.W. 110. T.D. = 111. B.D. = (Amount × Rate × Time) / 100 112. T.D. = (Amount × Rate × Time) / (100 + [Rate × Time]) 113. Amount = (B.D. × T.D.) / (B.D. – T.D.) 114. T.D. = (B.G. × 100) / (Rate × Time) Copyright Notice: Feel free to share, print, copy, distribute this document for free. Make sure to preserve this copyright notice alongwith the header and footer with the copyright note of www.sonker.com. Be sure to read the copyright information and terms of use of the documents at http://www.sonker.com/sagar/Copyright.htm before you share, print, copy, distribute this document. Page 11 of 12 Copyright © 2006 www.sonker.com
  • 12. 114 Handy Formulae for Quantitative Aptitude Problems Author: Sagar Sonker Illegal reproduction of this document without the prior permission of the author and/or removal of this copyright notice and/or the header/footer gives www.sonker.com the full authority to take a legal action. Do you have any more information to add to this document? Write to me at sagar@sonker.com or submit your feedback at www.sonker.com/sagar. Page 12 of 12 Copyright © 2006 www.sonker.com