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Applications of Op-Amps



          Dr. C.SARITHA
      Lecturer in Electronics
S.S.B.N. DEGREE & PG.COLLEGE
           ANANTAPUR
OVERVIEW
   Introduction
   Definitions
   Circuit Diagrams
   Derivations
   Applications
   Conclusion
Integrator
   The circuit in which the output wave form is
    the integral of input wave form is known as
    an integrator
   Such type of circuit is obtained by using
    basic inverting amplifier configuration
    where we use a capacitor in feed back
Circuit diagram


IR          Ic




       Vs
Explanation
   Input is applied to inverting terminal of the
    op-amp.
   Non inverting terminal is grounded.
   If sin wave is applied terminal then the
    output will be cosine wave.
For an ideal op-amp Ri=infinite
                        R0=0
For an ideal op-am
                input current=output current
                IR=IC
                IR=Vi-Vs/Ri
The capacitor current Ic=c(d/dt(VS-V0)
                        Ic=-c(d/dtV0-VS)
Input current =Output current
(Vi-VS)/Ri=-C(d/dtV0-VS)
Vi/Ri-VS/Ri =-C(d/dtV0-VS)
V0=-AVS
VS=-V0/A
Substitute this Vs in the above equation
Vi/Ri+V0/ARi=-C(d/dt(V0+VS/A)
              =-C(d/dtV0)-C(d/dtVS/A)
V0/A and V0/ARi
Are very less compare to V0 and hence this
terms are neglected.
Vi/Ri=-C(d/dtV0)
Integrating on both sides b/w 0 to t
    t        t
Vi/Ridt=- o Cd/dtV0
o
1         t
Ri   0        Vidt= -CV0


V0= -1               t
         RiC    0   Vidt
The output of the integrator is the integral of
input voltage with time constant that is V0 is
directly proportional to integral of Vidt and
inversely proportional to the time constant.
 The input is sine wave the output become
  cosine wave
Input=




Output=
Similarly the input is square wave the
output become Triangle wave
Input=



Output=
Applications
   Analog computer
   A to D converters
   Many linear circuits
   Wave Shapping circuit
Differentiator
   The differentiator is the circuit whose output
    wave form is the differential input wave
    form.
   The differentiator may be constructed form
    the basic inverting amplifier
   Here we replace the input resistor by a
    capacitor.
Circuit Diagram
The capacitor current Ic=CI(d/dtVi-VS)
Current through the feed back resistor
               IR=(VS-V0)/RF
     Input current=Output Current
                IC=IR
     C(d/dt(Vi-VS)=(VS-V0)/RF
   CiRF(d/dt(Vi-VS)=VS-V0
                  V0=-CiRF(d/dt(Vi-VS)+VS
Gain A=-V0/VS
                  VS=-V0/A
Substitute VS in the above equation
 -CiRFd/dt(Vi-VS)+VS=V0
-CiRFd/dt(Vi-VS)-VO/A=V0
V0/A is very small and hence neglected
                  VO=-CiRFd/dt(Vi)
The input is cosine wave the output become
sine wave
Input=




Output=
Similarly the input is Triangle wave the
output become Square wave
Input=



Output=
Active Filters
   Filter is a circuit which gives the DC from
    the given input AC.
   The filter which constructed by using an op-
    amp is known as the active filter. (Because
    the op-amp is an active component)
Types of filters
 High pass filter:
       It allows the high frequency signals and
  filter them (convert them into DC).
 Low pass filter:

       It allows the low frequency signals and
  filter them (convert them into DC).
Low pass filters




R
     C
Working
   A first order filter consists of a single RC
    network connected non inverting terminal of
    the op-amp
   At low frequency the capacitor appears
    open and the circuit acts like an inverting
    amplifier with a voltage a gain of (1+R2/R1)
…Continues
   As the frequency increases the capacitive
    reactance the capacitive reactance
    decreases causing a decrease in the
    voltage at the non inverting input and hence
    at the output.
Frequency Response
   Here fcutoff the value of input signal frequency
    at which the output decrease to 0.707 times
    its low frequency value
High pass filters
Working
   A first order active high pass RC filter also
    consist of a RC network connected to the
    non inverting terminal of the op-amp in
    case low pass.
   Here R and C are inter changed.
…Continues
   In this case at low frequencies the
    reactance of the capacitor is infinite and it
    blocks the input signal. Hence the output is
    zero.
   As we increase the frequency, capacitive
    reactance decreases, and out put increase
Frequency Response
   Here fcutoff the value of input signal frequency
    at which the output increase to 0.707 times
    its low frequency value
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Applications of op amps

  • 1. Applications of Op-Amps Dr. C.SARITHA Lecturer in Electronics S.S.B.N. DEGREE & PG.COLLEGE ANANTAPUR
  • 2. OVERVIEW  Introduction  Definitions  Circuit Diagrams  Derivations  Applications  Conclusion
  • 3. Integrator  The circuit in which the output wave form is the integral of input wave form is known as an integrator  Such type of circuit is obtained by using basic inverting amplifier configuration where we use a capacitor in feed back
  • 5. Explanation  Input is applied to inverting terminal of the op-amp.  Non inverting terminal is grounded.  If sin wave is applied terminal then the output will be cosine wave.
  • 6. For an ideal op-amp Ri=infinite R0=0 For an ideal op-am input current=output current IR=IC IR=Vi-Vs/Ri The capacitor current Ic=c(d/dt(VS-V0) Ic=-c(d/dtV0-VS)
  • 7. Input current =Output current (Vi-VS)/Ri=-C(d/dtV0-VS) Vi/Ri-VS/Ri =-C(d/dtV0-VS) V0=-AVS VS=-V0/A Substitute this Vs in the above equation Vi/Ri+V0/ARi=-C(d/dt(V0+VS/A) =-C(d/dtV0)-C(d/dtVS/A)
  • 8. V0/A and V0/ARi Are very less compare to V0 and hence this terms are neglected. Vi/Ri=-C(d/dtV0) Integrating on both sides b/w 0 to t t t Vi/Ridt=- o Cd/dtV0 o
  • 9. 1 t Ri 0 Vidt= -CV0 V0= -1 t RiC 0 Vidt The output of the integrator is the integral of input voltage with time constant that is V0 is directly proportional to integral of Vidt and inversely proportional to the time constant.
  • 10.  The input is sine wave the output become cosine wave Input= Output=
  • 11. Similarly the input is square wave the output become Triangle wave Input= Output=
  • 12. Applications  Analog computer  A to D converters  Many linear circuits  Wave Shapping circuit
  • 13. Differentiator  The differentiator is the circuit whose output wave form is the differential input wave form.  The differentiator may be constructed form the basic inverting amplifier  Here we replace the input resistor by a capacitor.
  • 15. The capacitor current Ic=CI(d/dtVi-VS) Current through the feed back resistor IR=(VS-V0)/RF Input current=Output Current IC=IR C(d/dt(Vi-VS)=(VS-V0)/RF CiRF(d/dt(Vi-VS)=VS-V0 V0=-CiRF(d/dt(Vi-VS)+VS
  • 16. Gain A=-V0/VS VS=-V0/A Substitute VS in the above equation -CiRFd/dt(Vi-VS)+VS=V0 -CiRFd/dt(Vi-VS)-VO/A=V0 V0/A is very small and hence neglected VO=-CiRFd/dt(Vi)
  • 17. The input is cosine wave the output become sine wave Input= Output=
  • 18. Similarly the input is Triangle wave the output become Square wave Input= Output=
  • 19. Active Filters  Filter is a circuit which gives the DC from the given input AC.  The filter which constructed by using an op- amp is known as the active filter. (Because the op-amp is an active component)
  • 20. Types of filters  High pass filter: It allows the high frequency signals and filter them (convert them into DC).  Low pass filter: It allows the low frequency signals and filter them (convert them into DC).
  • 22. Working  A first order filter consists of a single RC network connected non inverting terminal of the op-amp  At low frequency the capacitor appears open and the circuit acts like an inverting amplifier with a voltage a gain of (1+R2/R1)
  • 23. …Continues  As the frequency increases the capacitive reactance the capacitive reactance decreases causing a decrease in the voltage at the non inverting input and hence at the output.
  • 24. Frequency Response  Here fcutoff the value of input signal frequency at which the output decrease to 0.707 times its low frequency value
  • 26. Working  A first order active high pass RC filter also consist of a RC network connected to the non inverting terminal of the op-amp in case low pass.  Here R and C are inter changed.
  • 27. …Continues  In this case at low frequencies the reactance of the capacitor is infinite and it blocks the input signal. Hence the output is zero.  As we increase the frequency, capacitive reactance decreases, and out put increase
  • 28. Frequency Response  Here fcutoff the value of input signal frequency at which the output increase to 0.707 times its low frequency value