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Motion GCSE Physics
Book Reference ,[object Object]
Learning Intentions ,[object Object],[object Object],[object Object],[object Object]
By definition… ,[object Object],[object Object],Eg. Distance travelled is 8 metres Displacement is 4 metres, east 2m 2m 4m N Start Finish
Questions ,[object Object],[object Object],[object Object],[object Object],[object Object],Ballymena Coleraine Ballymoney 8 miles
Displacement ,[object Object],[object Object],[object Object],25m A B Journey A – B and then B - A A B Total displacement from A to B and B back to A… zero 10m
Speed The  rate  at which an object changes the  distance  it has travelled is called its  speed . For a complete journey the  speed  of an object can be calculated by dividing the  total distance  covered by the  time taken  to complete the journey- Average Speed = Total Distance / Time Taken metres/second = metre /  second Ferrari  360 Spider speed distance time
[object Object],[object Object],[object Object],[object Object],[object Object],Size direction Lance Armstrong
Scalar versus Vector ,[object Object],[object Object]
Question Time ,[object Object],[object Object],1 mile = 1600 m
Learning Intentions ,[object Object],[object Object],[object Object]
[object Object]
Snap Shots ,[object Object],[object Object],Disp Disp.
[object Object],Acceleration =  Change in Velocity  / Time Taken Acceleration = ( Final Velocity – Initial Velocity ) / Time Taken a = (v – u) / t m/s 2 = m/s / s a t Δ v
 
Usain Bolt’s Acceleration ,[object Object],[object Object],[object Object]
Wee bit extra ,[object Object],[object Object]
Examples ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Complete the Chart showing steady acceleration ,[object Object],[object Object],[object Object],4.0 8.0 X = 2 m/s 2 Y = -2.5 m/s 2 10.0 5.0 7.5 12.5 15.0 17.5 Velocity Y 6.0 2.0 0.0 - 2.0 Velocity X 6 5 4 3 2 1 Time
Homework Questions ,[object Object]
Vectors and Scalars ,[object Object],5 m/s 16 m due North - 17 m/s 2 16 Newtons 7 N 67 m/s 12 seconds Weight 94 Joules
Learning Intentions ,[object Object],[object Object],[object Object],[object Object]
Distance – Time Graphs ,[object Object]
 
Distance- Time Graphs Distance (m) Dist. Straight line, positive correlation, both increase at the same rate
Distance- Time Graphs Distance (m) Dist. Curves up, as seconds pass, the car covers more distance than the second before
[object Object],[object Object],Graphs of motion speed speed speed Increasing speed Decreasing speed
[object Object],[object Object]
Learning Intentions ,[object Object],[object Object],[object Object],[object Object]
[object Object],1 3 2 5 4 ,[object Object]
[object Object],0 15 75 y x 1.2 4.8 y x 0 Gradient = 75 / 15 = 5 Gradient = -4.8 / 1.2 = -4 Negative gradient, slope down
The change in y is the  distance  the object has travelled The change in x is the  time  the object was travelling Speed equals distance divided by time, therefore the  gradient  of the graph is the   same   as the  speed  of the object
What is the gradient, and hence the speed of the car? Change in y = Distance travelled = 800 – 200 = 600 m Change in x = Time taken = 36 - 16 = 20 s Gradient = Speed = Distance / Time = 600 / 20 = 30 m/s
Learning Intentions ,[object Object],[object Object],[object Object],[object Object]
[object Object]
Felix is bonkers…
 
[object Object],[object Object],Graphs of motion speed speed speed Increasing speed Decreasing speed Acceleration Constant speed Slower Acceleration Stopped Deceleration v v v v v v t t t t Slower constant speed
[object Object],[object Object],[object Object],[object Object]
Learning Intentions ,[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],Time (s) Velocity (m/s) 4 10 Wee Bit Extra
Time (s) Velocity (m/s) 4 10 Velocity = Displacement / Time Area under the graph!! From the graph- Velocity = 4 m/s Time = 10 s Re-arrange the equation-  d = v x t = 4 x 10 = 40 m v d t
[object Object],Displacement
[object Object],Examples t V 15 200 t V 5 16 8 Area under line = 15 x 200 Displacement  = 3000 m Area under line = (5 x 8) + (0.5 x 8 x 5) Displacement  = 60 m
Try this one… ,[object Object],[object Object]
Momentum ,[object Object],verses
Momentum ,[object Object],[object Object],[object Object],[object Object],[object Object]
Example ,[object Object],[object Object],30 5 Velocity (m/s) 200 1000 Mass (kg) Motorcycle Car
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],30 5 Velocity (m/s) 200 1000 Mass (kg) Motorcycle Car

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Motion

  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7. Speed The rate at which an object changes the distance it has travelled is called its speed . For a complete journey the speed of an object can be calculated by dividing the total distance covered by the time taken to complete the journey- Average Speed = Total Distance / Time Taken metres/second = metre / second Ferrari 360 Spider speed distance time
  • 8.
  • 9.
  • 10.
  • 11.
  • 12.
  • 13.
  • 14.
  • 15.  
  • 16.
  • 17.
  • 18.
  • 19.
  • 20.
  • 21.
  • 22.
  • 23.
  • 24.  
  • 25. Distance- Time Graphs Distance (m) Dist. Straight line, positive correlation, both increase at the same rate
  • 26. Distance- Time Graphs Distance (m) Dist. Curves up, as seconds pass, the car covers more distance than the second before
  • 27.
  • 28.
  • 29.
  • 30.
  • 31.
  • 32. The change in y is the distance the object has travelled The change in x is the time the object was travelling Speed equals distance divided by time, therefore the gradient of the graph is the same as the speed of the object
  • 33. What is the gradient, and hence the speed of the car? Change in y = Distance travelled = 800 – 200 = 600 m Change in x = Time taken = 36 - 16 = 20 s Gradient = Speed = Distance / Time = 600 / 20 = 30 m/s
  • 34.
  • 35.
  • 37.  
  • 38.
  • 39.
  • 40.
  • 41.
  • 42. Time (s) Velocity (m/s) 4 10 Velocity = Displacement / Time Area under the graph!! From the graph- Velocity = 4 m/s Time = 10 s Re-arrange the equation- d = v x t = 4 x 10 = 40 m v d t
  • 43.
  • 44.
  • 45.
  • 46.
  • 47.
  • 48.
  • 49.

Notes de l'éditeur

  1. What other quantities must be accompanied by a direction as well as its size?
  2. What physical quantities do we need to be able to work out the acceleration of something? Mark Cavendish – video clip of tour de France, final stage (21, coming into Paris at the Arc de Triomphe). During the last 200 m Cav is known as a legend for accelerating up to 48 mph to snatch a win (world record for someone from the UK, winning 6 stages at only 24 years-old)
  3. Michael Johnston left speechless! http://news.bbc.co.uk/sport1/hi/athletics/8204766.stm First 30 m, t = 3.78 s, u = 0 m/s, v = 11.11 m/s, a = 2.94 m/s^2 Last 20 m, t = 9.58 - 7.92 = 1.66 s , u = 12.20 m/s, v = 12.05 m/s, a = -0.09 m/s^2
  4. Shallow slope up Steep slope up Slope down Negative Positive low Positive high Continually changing Steep to shallow Shallow to steep
  5. Wind-up racer’s motion
  6. Red Bull Stratos – Felix Baungartner and Joe Kittinger As this piece of historic motion is yet to be done we unfortunately don’t have any speeds to work with but we were luck enough to catch up with Felix on a stretch of road through the country side where he allowed us to film. So here we go, pens at the ready, take down the distance at 5 second intervals and then we’ll replay the high-octane action for speed.
  7. Video clip of v-t, results table time 0 – 30, take results every second (vertically down) Time axis – every box 2 seconds Velocity axis – every box 5 m/s
  8. Talk through the ‘journey’ Label acceleration, deceleration, speeding up, slowing down, steady speed, zero speed and low & high speed Calculate acceleration during 1 st five seconds – 12 m/s^2 From 5 s to 8 s (6-60)/3 = -18 m/s^2
  9. Which is more impressive, Neo dealing with being shot at or Hancock saving someone’s life? How could we judge who is the most awesome? Vid clips, Neo with the bullet-stopping and Hancock with the train-stopping What did Neo do at the start of the clip and what physical factor was it that he so impressively controlled? Extremely fast speed (or velocity). Hancock did something similar but it was a different physical factor that made his ability so impressive, what was it? Both superheroes are controlling the ‘momentum’ of the objects, and in these examples each object has a great deal of momentum! In Science momentum is ‘ mass in motion ’ Momentum of a football team, they’re hard to stop – they’ve built up a lot of pace