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TRIGONOMETRIC
RATIOS

Consider a right triangle with  as one of its acute
angles. The trigonometric ratios are defined as follows .
opposite
sin  =
hypotenuse


adjacent

opposite

adjacent
cos  =
hypotenuse

hypotenuse
sec  =
adjacent

opposite
tan  =
adjacent

hypotenuse

hypotenuse
csc  =
opposite

adjacent
cot  =
opposite

Note: The symbols we used for these ratios are abbreviations
for their full names: sine, cosine, tangent, cosecant, secant
and cotangent.
RECIPROCAL
FUNCTIONS
The following gives the reciprocal relation of
the six trigonometric functions.
sin  =

1
csc 

cos  =

1
sec 

1
tan  =
cot

csc  =

1
sin

sec  =

1
cos

1
cot  =
tan
THE PYTHAGOREAN
THEOREM
The Pythagorean Theorem states that the square of the
hypotenuse is equal to the sum of the squares of the
other two sides. In symbol, using the ABC as shown,

B
a
C

c2  a2  b2

c

b

A
FUNCTIONS OF COMPLIMENTARY
ANGLES
a
sin A =
c

a
cos B =
c

b
cos A =
c

b
sin B =
c

a
tan A =
b

a
cot B =
b

b
cot A =
a

b
tan B =
a

b
sec A =
c

b
csc B =
c

c
csc A =
a

c
sec B =
a

B
a

C

c
b

A

Comparing these formulas
for the acute angles A and
B, and making use of the
fact that A and B are
complementary angles
(A+B=900), then
FUNCTIONS OF COMPLIMENTARY
ANGLES
sin B = sin (900  A) = cos

cos B = cos (900  A) = sin A
tan B = tan (90 0  A) = cot A
cot B = cot (90 0  A) = tan A

sec B = sec (90 0  A) = csc A
csc B = csc (90 0  A) = sec A
The relations may then be expressed by a
single statement: Any function of the
complement of an angle is equal to the co-function
of the angle.
To find the functions of 450, construct a diagonal
in a square of side 1. By Pythagorean Theorem
this diagonal has length of 2 .
1
sin
= 
2
0=1 
cos 45
2

450

1

450

2

1

450

tan 450 = 1

2
2
2
2

csc 450 = 2
sec 450 = 2
cot 450 = 1
To find the functions of 300 and 600, take an
equilateral triangle of side 2 and draw the
bisector of one of the angles. This bisector
divides the equilateral triangle into two
congruent right triangles whose angles are 300
and 600. By Pythagorean Theorem the length of
the altitude is 3 .
300

2

3

600
1
sin

300

1
=
2

cos

300

3
=
2

tan

300

1
3
= 
3
3

cot 300 = 3
sec

300

2 2 3
= 
3
3

csc 300 = 2

cos

600

1
=
2

sin

600

3
=
2

cot

600

1
3
= 
3
3

tan 600 = 3
csc

600

2 2 3
= 
3
3

sec 600 = 2
1.

Draw the right triangle whose sides have the following
values, and find the six trigonometric functions of the
acute angle A:

a) a=5 , b=12 , c=13
b) a=1 , b= 3 , c=2
2. The point (7, 12) is the endpoint of the
terminal side of an angle in standard position.
Determine the exact value of the six
trigonometric functions of the angle.
3. Without the aid of the calculator, evaluate the
following:

a) 3 tan2 600 + 2 sin2 300 – cos2 450
b) 5 cot2 450 + 5 tan 450 + sin 300
c) cos2 600 – csc2 300 – sec 300

d) tan 600 + 2 cot 300 – sin 600
e) tan5 450 + cot2 450 – sin4 600










http://www.slideshare.net/gayathrigaya10/in
troduction-to-trigonometry
http://www.slideshare.net/rcruz091462/trigratios
http://www.slideshare.net/cosmocog/trigright-triangle-trig
http://www.slideshare.net/dylanxclusive/ma
th12-lesson6
http://www.slideshare.net/bigkelt12/larson43-15368029

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trigonomery of right triangles

  • 1.
  • 2. TRIGONOMETRIC RATIOS Consider a right triangle with  as one of its acute angles. The trigonometric ratios are defined as follows . opposite sin  = hypotenuse  adjacent opposite adjacent cos  = hypotenuse hypotenuse sec  = adjacent opposite tan  = adjacent hypotenuse hypotenuse csc  = opposite adjacent cot  = opposite Note: The symbols we used for these ratios are abbreviations for their full names: sine, cosine, tangent, cosecant, secant and cotangent.
  • 3. RECIPROCAL FUNCTIONS The following gives the reciprocal relation of the six trigonometric functions. sin  = 1 csc  cos  = 1 sec  1 tan  = cot csc  = 1 sin sec  = 1 cos 1 cot  = tan
  • 4. THE PYTHAGOREAN THEOREM The Pythagorean Theorem states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. In symbol, using the ABC as shown, B a C c2  a2  b2 c b A
  • 5. FUNCTIONS OF COMPLIMENTARY ANGLES a sin A = c a cos B = c b cos A = c b sin B = c a tan A = b a cot B = b b cot A = a b tan B = a b sec A = c b csc B = c c csc A = a c sec B = a B a C c b A Comparing these formulas for the acute angles A and B, and making use of the fact that A and B are complementary angles (A+B=900), then
  • 6. FUNCTIONS OF COMPLIMENTARY ANGLES sin B = sin (900  A) = cos cos B = cos (900  A) = sin A tan B = tan (90 0  A) = cot A cot B = cot (90 0  A) = tan A sec B = sec (90 0  A) = csc A csc B = csc (90 0  A) = sec A The relations may then be expressed by a single statement: Any function of the complement of an angle is equal to the co-function of the angle.
  • 7. To find the functions of 450, construct a diagonal in a square of side 1. By Pythagorean Theorem this diagonal has length of 2 . 1 sin =  2 0=1  cos 45 2 450 1 450 2 1 450 tan 450 = 1 2 2 2 2 csc 450 = 2 sec 450 = 2 cot 450 = 1
  • 8. To find the functions of 300 and 600, take an equilateral triangle of side 2 and draw the bisector of one of the angles. This bisector divides the equilateral triangle into two congruent right triangles whose angles are 300 and 600. By Pythagorean Theorem the length of the altitude is 3 . 300 2 3 600 1
  • 9. sin 300 1 = 2 cos 300 3 = 2 tan 300 1 3 =  3 3 cot 300 = 3 sec 300 2 2 3 =  3 3 csc 300 = 2 cos 600 1 = 2 sin 600 3 = 2 cot 600 1 3 =  3 3 tan 600 = 3 csc 600 2 2 3 =  3 3 sec 600 = 2
  • 10. 1. Draw the right triangle whose sides have the following values, and find the six trigonometric functions of the acute angle A: a) a=5 , b=12 , c=13 b) a=1 , b= 3 , c=2 2. The point (7, 12) is the endpoint of the terminal side of an angle in standard position. Determine the exact value of the six trigonometric functions of the angle.
  • 11. 3. Without the aid of the calculator, evaluate the following: a) 3 tan2 600 + 2 sin2 300 – cos2 450 b) 5 cot2 450 + 5 tan 450 + sin 300 c) cos2 600 – csc2 300 – sec 300 d) tan 600 + 2 cot 300 – sin 600 e) tan5 450 + cot2 450 – sin4 600