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9011031155

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recordings.

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9011031155

Electromagnetic Induction
Multiple Choice questions
1. In an A.C. circuit E = 100 sin(500t) volt and

I = 1000

. The power dissipated in

the circuit is
(a) 10W

(b) 100W

(c) 50W

(d) 25W

2. An L-C-R series circuit is joined to a source of
alternating e.m.f. If R=9Ω, XL=28Ω, XC=16Ω, then
the impendence of the circuit will be
(a) 10Ω

(b) 15Ω

(c) 20Ω

(d) 30Ω

3. A current I=3 sin ωt ampere flows through a bulb.
The P.D. across the bulb is given by V=4cosωt
volt. The power dissipated in the bulb is
2
9011041155 /
9011031155

(a) 12W

(b) 6W

(c) Zero W

4. An inductance of

(d) 3W

henry and a resistance of

30Ω are joined in series. If an alternating e.m.f. of
200V, 50Hz is applied to their combination, then
the impedance of the circuit will be
(a) 50 Ω

(b) 40 Ω

(c) 100 Ω

(d) 10 Ω

5. In an A.C. circuit, a resistance R=40Ω and an
inductance L are connected in series. If the phase
angle between voltage and current is 45º, then
the value of the inductive reactance will be
(a) 20 Ω

(b) 40 Ω

(c) 10 Ω

(d) 50 Ω

3
9011041155 /
9011031155

Solutions
1.
(d) 25W

2.
(b) 15Ω

4
9011041155 /
9011031155

3.
(c) Zero W

∴ The phase difference between I and V is

∴ Power consumed in the circuit is zero

4. (a) 50 Ω
When L and R are joined in series, the

5
9011041155 /
9011031155

5. (b) 40 Ω

Form the impedance triangle,
For an L-R circuit,

6
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9011031155

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For inquiry and registration, call 9011041155 /
9011031155.

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12th Physics - Electromagnetic Induction MCQ's with Solution

  • 1. 9011041155 / 9011031155 • Live Webinars (online lectures) with recordings. • Online Query Solving • Online MCQ tests with detailed solutions • Online Notes and Solved Exercises • Career Counseling 1
  • 2. 9011041155 / 9011031155 Electromagnetic Induction Multiple Choice questions 1. In an A.C. circuit E = 100 sin(500t) volt and I = 1000 . The power dissipated in the circuit is (a) 10W (b) 100W (c) 50W (d) 25W 2. An L-C-R series circuit is joined to a source of alternating e.m.f. If R=9Ω, XL=28Ω, XC=16Ω, then the impendence of the circuit will be (a) 10Ω (b) 15Ω (c) 20Ω (d) 30Ω 3. A current I=3 sin ωt ampere flows through a bulb. The P.D. across the bulb is given by V=4cosωt volt. The power dissipated in the bulb is 2
  • 3. 9011041155 / 9011031155 (a) 12W (b) 6W (c) Zero W 4. An inductance of (d) 3W henry and a resistance of 30Ω are joined in series. If an alternating e.m.f. of 200V, 50Hz is applied to their combination, then the impedance of the circuit will be (a) 50 Ω (b) 40 Ω (c) 100 Ω (d) 10 Ω 5. In an A.C. circuit, a resistance R=40Ω and an inductance L are connected in series. If the phase angle between voltage and current is 45º, then the value of the inductive reactance will be (a) 20 Ω (b) 40 Ω (c) 10 Ω (d) 50 Ω 3
  • 5. 9011041155 / 9011031155 3. (c) Zero W ∴ The phase difference between I and V is ∴ Power consumed in the circuit is zero 4. (a) 50 Ω When L and R are joined in series, the 5
  • 6. 9011041155 / 9011031155 5. (b) 40 Ω Form the impedance triangle, For an L-R circuit, 6
  • 7. 9011041155 / 9011031155 • Ask Your Doubts • For inquiry and registration, call 9011041155 / 9011031155. 7