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SPECIAL METHODS
THOMAS METHOD  This method emerges as a simplification of an LU factorization of a tridiagonal matrix.   We know that a positive definite matrixA has a unique symmetric square root F such that : 𝑭 ² = 𝑭𝑭′ = 𝑨 Now if we do not insist on symmetry, there is a very large set of (non symmetric) matrices G such that : 𝑮𝑮′ = 𝑨 and which may also be regarded as "square roots" of A. The positive definite matrix A is then said to be factored into the "square" of its square root.  
One of these factorizations is of particular interest, both from theoretical and practical standpoints: Cholesky Decomposition, which is expressed as follows. THOMAS METHOD
Based on the matrix product shown above gives the following expressions: THOMAS METHOD
As far as making the sweep from k = 2 to n leads to the following: THOMAS METHOD
If Lux and Ux = r = d then Ld = r, therefore: THOMAS METHOD
Finally we solve Ux = d from a backward place:  THOMAS METHOD
EXAMPLE  Solve the following system using the method of Thomas: Vectors are identified a, b, c and r as follows:
We obtain the following equalities: EXAMPLE
Now once known L and U, Ld = r is solved by a progressive replacement: EXAMPLE
Finally Ux = d is solved by replacing regressive: EXAMPLE
So the solution vector is: EXAMPLE
If A is only positive semi-definite, the diagonal elements of L can only be said to be non negative. The Cholesky factorization can be symbolically represented by :   CHOLESKY METHODS  LT L A =LLT A
The Cholesky factorization is the prefered numerical method for calculating : The inverse, and the determinant of a positive definite matrix (in particular of a covariance matrix), as well as for the simulation of a random multivariate normalvariable. CHOLESKY METHODS
From the product of the n-th row of L by the n-th column of LT we have: CHOLESKY METHODS
Making the sweep from k = 1 to n we have: CHOLESKY METHODS
On the other hand if we multiply the n-th row of L by the column (n-1) LT we have: CHOLESKY METHODS
By scanning for k = 1 to n we have: CHOLESKY METHODS
EXAMPLE  Apply Cholesky for symmetric matrix decomposed as follows: For k = 1:
EXAMPLE  For k = 2:  For k = 3:
EXAMPLE  Finally, as a result of decomposition was found that:
BIBLIOGRAPHY http://www.google.com.co/imgres?imgurl=http://userweb.cs.utexas.edu/~plapack/icpp98/img38.gif&imgrefurl=http://www.cs.utexas.edu/~plapack/icpp98/node2.html&usg=__lcX8ioMpUm91zLexBn6t8JE72_Q=&h=823&w=751&sz=20&hl=es&start=3&um=1&itbs=1&tbnid=cWGkKDGz2Os9EM:&tbnh=144&tbnw=131&prev=/images%3Fq%3Dcholesky%26um%3D1%26hl%3Des%26ndsp%3D20%26tbs%3Disch:1

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