1. Intelligent Urban Traffic Control System
(KKKA 6424)
Assignment no .1
Traffic Light Setting
Supervisor
Prof. Dr. Riza Atiq Abdullah OK Rehmat
Prepared by: Rasha salah ahmed P64799
Sarah hazim P65407

2. Fig (1) (The Study area)
Location of intersections

4. First Intersection
Phase Traffic volume Actual
flow
(pcu/hr)
saturation
flowper
lane
(pcu/hr)
saturation
flow
(pcu/hr)
Y=
flow/sat
uration
flow
Green
time split
Y / ∑y
(Y / ∑y)
*Geleft straight right
1 111 88 199 1800 3600 0.1 0.33 8
2 95 201 296 1800 3600 0.1 0.33 8
3 85 100 185 1800 3600 0.1 0.33 8
∑y=0.3 ∑=24

5. 1. L(losttime)=3×(3+2)=15sec
2. Co=
(1.5 𝐿 +5
1−∑𝑌
=
1.5 15 +5
1−0.3
=39.28 takeCo=40sec
3. Effectivegreentime(Ge)=Co-L=40-15=25sec
(Multiplythisvalueingreentimesplit to getthefinalcolumn).
4. Totalgreentime=24sec
5. Cycletime=greentime+losttime
=24+15=39sec

6. Secondintersection
Phase Trafficvolume Actual
flow
(pcu/hr)
saturation
flowper
lane
(pcu/hr)
saturation
flow
(pcu/hr)
Y=
flow/sat
uration
flow
Green
timesplit
Y/∑y
(Y/∑y)
*Geleft straight right
1 80 328 184 592 1800 3600 0.16 0.31 16
2 84 140 98 322 1800 3600 0.1 0.19 10
3 148 252 160 560 1800 3600 0.16 0.31 16
4 64 92 120 276 1800 3600 0.1 0.19 10
∑y=0.52 ∑=52

7. 1. L (lost time) =4× (3+2) =20 sec
2. Co=
(1.5 𝐿 +5
1−∑𝑌
=
1.5 20 +5
1−0.52
=72.9 take Co=73 sec
3. Effective green time (Ge) =Co-L =73-20=53 sec
(Multiply this value in green time split to get the final column).
4. Total green time=52 sec
5. Cycle time =green time + lost time
=52+20=72 sec

8. Thirdintersection
Phase Trafficvolume Actual
flow
(pcu/hr)
saturation
flowper
lane
(pcu/hr)
saturation
flow
(pcu/hr)
Y=
flow/sat
uration
flow
Green
time
split
Y/∑y
(Y/
∑y)
*Ge
left straight right
1 151 215 99 465 1800 3600 0.13 0.217 15
2 90 198 75 363 1800 3600 0.1 0.167 11
3 88 119 90 297 1800 3600 0.1 0.167 11
4 356 501 113 970 1800 3600 0.27 0.45 31
∑y=0.6 ∑=68

9. 1. L (lost time) =4× (3+2) =20 sec
2. Co=
(1.5 𝐿 +5
1−∑𝑌
=
1.5 20 +5
1−0.6
=87.5 take Co=88 sec
3. Effective green time (Ge) =Co-L =88-20=68 sec
(Multiply this value in green time split to get the final column).
4. Total green time=68 sec
5. Cycle time =green time + lost time
=68+20=88 sec.
 To determine (offset time) T ideal from inter1 to 2:
T ideal=
𝐿
𝑆
− 𝑄 × ℎ + 𝑙𝑜𝑠𝑠 𝑡𝑖𝑚𝑒 Where:
L=450m
S=10m/sec
Q=14 cars
h=2sec
Loss time=2 sec. T ideal=15 sec.
 To determine (offset time) T ideal from inter 2 to 3:
L=650m
S=10m/sec
Q=12 cars
h=2 sec
Loss time=2 sec T ideal=39 sec

11. We choosethe maximum value ofC₀ = 88 and make recalculation for the greentime, and
the new results inthe table below:
Co=88 Ge=Co-L=88-20=68 sec
phase Intersection 1 Intersection 2 Intersection 3
GreenTime = (Y/∑
Y)*Ge
GreenTime = (Y/∑
Y)*Ge
GreenTime = (Y/∑
Y)*Ge
Q1 23 21 15
Q2 23 13 11
Q3 22 21 11
Q4 13 31
∑=68 ∑=68 ∑=68
So the new diagramwill be like the following:

13. Pictures from the study area

17. THANK YOU