NEED STEPS ON HOW TO SOLVE PROBLEMS IN NUMBER TWO! For each of the numbers t in the above problem, find a number s in [0, 2pi] such that W(s) = W(t). Part a is done for you. For each of the following values of t, find two other values, one positive and one negative, that have value. Solution 2) W(9pi/2)=W(4pi+pi/2)=W(pi/2) 3)W(-15pi)=W(-16pi+pi)=W(pi) 4)W(-13pi/3)=W(-4pi-pi/3)=W(pi/3) 5)W(-8pi/6)=W(-4pi/3)=W(-2pi+2pi/3)=W(2pi/3) 6)W(-21pi/4)=W(-6pi+3pi/4)=W(3pi/4) 7)W(3pi)=W(2pi+pi)=W(pi) 8)W(-17pi/3)=W(-6pi+pi/3)=W(pi/3) Steps to solve these questions are Write given value of angle as multiple of 2Pi and add some angle between 0 and 2pi.That angle between zero and 2pi will be the value at which function has same value because 2pi is time period of function after which value of function repeats.