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Not sure how to go about solving this equation. Please help..Thanks If A = [x y 2 -2], determine
the values of x and y for which A2 = A. x = , y = .
Solution
A^2 =A
thus
x 2 * x 2
y -2 y -2
= x^2 + 2y 2x-4
xy-2y 2y+4
= A
thus
2x-4 = 2
2x = 6
x = 3
2y+4 = -2
2y = -2-4 = -6
y = -3
thus ans

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Not sure how to go about solving this equation. Please help..Thanks .pdf

  • 1. Not sure how to go about solving this equation. Please help..Thanks If A = [x y 2 -2], determine the values of x and y for which A2 = A. x = , y = . Solution A^2 =A thus x 2 * x 2 y -2 y -2 = x^2 + 2y 2x-4 xy-2y 2y+4 = A thus 2x-4 = 2 2x = 6 x = 3 2y+4 = -2 2y = -2-4 = -6 y = -3 thus ans