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Note lowercase v is a vectorSolutionfor kernel, l(0) T for v.pdf
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Not sure how to go about solving this equation. Please help..Thanks .pdf
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Not sure how to go about solving this equation. Please help..Thanks If A = [x y 2 -2], determine the values of x and y for which A2 = A. x = , y = . Solution A^2 =A thus x 2 * x 2 y -2 y -2 = x^2 + 2y 2x-4 xy-2y 2y+4 = A thus 2x-4 = 2 2x = 6 x = 3 2y+4 = -2 2y = -2-4 = -6 y = -3 thus ans.
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Not sure how to go about solving this equation. Please help..Thanks .pdf
- Not sure how to go about solving this equation. Please help..Thanks If A = [x y 2 -2], determine the values of x and y for which A2 = A. x = , y = . Solution A^2 =A thus x 2 * x 2 y -2 y -2 = x^2 + 2y 2x-4 xy-2y 2y+4 = A thus 2x-4 = 2 2x = 6 x = 3 2y+4 = -2 2y = -2-4 = -6 y = -3 thus ans