1. The document contains SQL exercises and their solutions for working with employee and customer tables. 2. It includes queries using aggregates, joins, unions, intersections and other SQL clauses. 3. It also covers SQL data manipulation statements like INSERT, DELETE, UPDATE.

1. ESCUELA SUPERIOR POLITECNICA DEL LITORAL FACULTAD DE INGENIERIA EN ELECTRICIDAD Y COMPUTACION SISTEMAS DE BASES DE DATOS I TRABAJO EN CLASE EJERCICIOS SQL ALUMNO. GUZMAN CONTRERAS MAURICIO PROFESOR. ING. FABRICIO ECHEVERRIA PARALELO. 01 GUAYAQUIL, JULIO 22 DE 2009 Ejercicios 1. 1. select emp_id, emp_fname, emp_lname, salary from employee where salary<(select avg(salary) from employee) 2. select emp_id, emp_fname, emp_lname from employee where dept_id in(select dept_id from department where dept_name='R & D') 3. select emp_id, emp_fname, emp_lname, salary from employee where salary>some(select salary from employee where city='Milton') 4. select emp_id, emp_fname, emp_lname, salary from employee where salary>all(select salary from employee where city='Milton') 5. select prod.name, prod.quantity, clte.fname, clte.lname from product prod, customer clte, sales_order salo, sales_order_items sali where clte.id=salo.cust_id and salo.id=sali.id and sali.prod_id=prod.id 6. SELECT dep1.dept_name, sum(emp1.salary) as total FROM employee emp1, department dep1 where emp1.dept_id = dep1.dept_id group by dep1.dept_name Ejercicios 2. 1. Para la clausula some, la clausula equivalente es between. 2. Para la clausula all, la clausula equivalente es max. 3. SELECT emp1.emp_fname, emp1.emp_lname FROM employee emp1, department dep1 where exists (select * from employee where employee.salary > '80000' and employee.city = 'Milton') 4. SELECT emp1.emp_fname, cus.fname FROM employee emp1, customer cus SELECT employee.emp_fname from employee union all select customer.fname from customer 5. SELECT employee.city from employee intersect all select customer.city from customer 6. SELECT employee.city from employee except all select contact.city from contact 1. insert into contact_copy select * from contact 2. insert into contact_copy(id, last_name, first_name, title, street, city, state, zip, phone, fax) values (12,'Hildebrand','Jane','ma','280 Washington St.','Kanata','CA','94608','5105551309','5105554209') 3. delete from contact_copy 4. delete from contact_copy where city like'm%' or city like'l%' or city like'k%' 5. insert into employee_copy select * from employee 6. insert into employee_copy(emp_id, manager_id, emp_fname, emp_lname, dept_id, street, city, state, zip_code, phone, status, ss_number, salary, start_date, termination_date, birth_date, bene_health_ins, bene_life_ins, bene_day_care, sex) values(310,702,'mauricio','guzman','521','urdesanorte','guay','guaya',012457128,042156789,'z',0124578,400000,'1984-09-12',null,'1972-02-12','d','j','f','m') 7. delete from employee_copy where salary<(select 0.5*avg(salary) from employee_copy) 8. update employee_copy set salary= salary+salary*0.2 9. update employee_copy set salary= salary+salary*0.1 where sex= 'f' 10. update employee_copy set salary= salary-1000 where salary>(select avg(salary) from employee_copy) 11. select distinct empy.emp_id, empy.emp_fname from employee empy, employee mana where empy.emp_id= mana.manager_id