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Exercise 1:
The resistivity measurement system that used was based on the four point
probe Schlumberger configuration and it is shown in figure 1




                    Figure 1 :The Measurement System

The circuit diagram of a constant current source is shown in figure 2.If we
apply input voltage Vin ,this circuit produces the same output current
irrespective the changes in load resistor Rload .Since the output current Io
equals the current through R on the resistor R,hence the the circuit shown
here has a nearly infinite load resistance. For Vin=0.6V      and     R=3000
ohms                         ……{given}
current Io can be calculated as follows
 Io= Vin/R
 Io= 0.6/3000 = 0.0002A               or   0.2 mA
Actually by changing the load resistance Rload the opamp output changes its
voltage to keep the current Io remain constant.


      Vin = 0.6V

                                            Vload




         R=3KOhm




Figure 2 : Constant current generator
Below is the table showing the values of Vload for different values of Rload for
the resistivity measurement system used i.e,Vin=0.6 V.


                   Rload(Ohms) V load (Volts)         Io load(A)
                       1000             0.2             0.0002
                       2000             0.4             0.0002
                       3000             0.6             0.0002
                       4000             0.8             0.0002
                       5000              1              0.0002
                       6000             1.2             0.0002
                        Table showing results of Vload at Different Rload

Plotting graph between Vload and Rload we have got


                                                Vload Vs Rload

                              1.4
                              1.2       y = 0.0002x
                               1
              Vload (Vlots)




                              0.8                                 Series1
                              0.6                                 Linear (Series1)
                              0.4
                              0.2
                               0
                                    0          5000       10000
                                           Rload (ohms)


                                    Graph between Vload Vs Rload

From the above graph between Vload and Rload the equation of line is given
by
Y=0.0002x
Where Gradient=Vload/Rload=Io
Therefore
Io=0.0002 A

Results:
From the graph we can see that the gradient remains the same for all values
of Rload.
Hence we can say that in this constant current source the output current Io is
independent of the changes in Rload and therefore the circuit has nearly
infinite load resistance within the compliance range.
.

Exercise 2:Measurement Strategies




       Figure 1:Resistivity Measurement strategy used in archaeology site

The measuring system used in a archaeology site (as shown by figure 1) for
measuring electrical resistivity or conductivity of any material was based on
the four point probe method.This is a simple and low cost method which is
first proposed by Thomson in 1861 and first used by Schlumberger in 1920 to
measure the resistivity of Earth.

Principle
The basic principle of four point probe method is illustrated in the figure below




                                   Ground


                           Four Point Probe Method
“By applying constant current to the outer electrodes ,Potential Difference can
be measured by the inner electrodes at different positions on the surface of
the material .The current remains constant in the circuit irrespective to the
changes in resistances and the output voltage is totally dependent on the
resistance changes.”

The four point method offers advantages over Direct or two probes method
which offer very poor performance due to polarization and electrode contact
issues. By using constant current source the current flowing through the
material will largely independent to the probe/contact impedances as current
remains constant as resistance changes.For verification below is the
experimental results showing that the current remains same for different
values of load resistances and only the output voltage will be changed with
resistance.this experiment was performed with 1 mA current source with
different values of resistances.and the output voltage of 15 V as opamp
maximum i/p was 15 V and the opamp saturated at 13 volts approximately.



                    R         Vout          I
                    ohms      (volts)       (amperes)
                       1000           1.02     0.00102
                       2000              2        0.001
                       3000           3.05    0.001017
                       4000           4.07    0.001018
                       5000           5.08    0.001016
                       6000            6.1    0.001017
                       7000           7.12    0.001017
                       8000           8.15    0.001019
                       9000         9.165     0.001018
                     10000          10.18     0.001018
                     11000          11.18     0.001016
                     12000          12.19     0.001016
                     13000          13.21     0.001016
Results from Laborator experiment for verification of constant current source

The graph between different Voltage and resistances values is shown below .
V vs R(Linear Range)

           14
                    y = 0.0010x - 0.0050
           12
           10
           8
  Vo (V)




                                                      Linear
           6                                          Linear (Linear)

           4
           2
           0
                0       5000    10000      15000
                           R(ohm)




Also to ensure that virtually no current will flow through the voltage measuring
electrodes an instrumentational amplifier is used as shown in the figure.
In designing the voltage measuring electrodes should be as near to resistance
as possible to minimize contact resistance and loading effects.

The current follows the path according to the distribution of resistivity within
the region.Thereore the potential difference between the two inner probes
contains the information about the distribution of electrical resistivity.

For measuring resistivity of the ground currents are injected into the ground
and the resulting potential differences are measured at the surface.The in situ
measurement of resistivity is impractical as it is the resistance measured
between the faces of a unit cube of material.Therefore the common method is
to measure the resistance on the surface of a material and then calculate the
apparent resistivity values using the current and voltage measurements and
the electrode configuration used

Mostly low frequency alternating sources are applied to the ground for
avoiding the polarization effect.
In practice the frequency of the alternating current required to penetrate in
the ground decreases with the increase in depth.
                                 F a.c. α 1/depth
In general a frequency of 100 Hz is required to penetrate in 10m depth
whereas 10 Hz for 100m.
The resistivity for a conducting cylinder of resistance ∆R,length ∆L and cross
sectional area ∆A is given by:

                                                   =∆R ∆A/∆L ………eq(1)
Current Flow in the ground:
Consider a homogeneous material,when current I will flow through it it will
follow the radial pattern from the electrode and create hemispherical
equipotential surfaces.
From Ohms’s Law and substituting values in eq 1 we know that


∆V/∆L =    I/∆A = -   i      …………………..eq(2)

The potential gradient ∆V/∆L is dependent on the current density I and the
resistivity of the material.
If the electrode is at distance r the surface area is 2πr² and hence current
density I is given by

i=I/2πr²

Now the potential gradient is given by




Equation (3)

Now the potential Vr at a distance r can be found by integerating above
equation (3)




The potential can be calculated at any point on or below the surface of a
homogeneous surface or ground by using above equation.
If the sink electrode is at a finite distance from the source as illustrated in the
figure below
The potential at any point is the sum of the potential contributions from each
current conducting electrode.
Absolute potential are difficult to measure hence normally the potential
difference ∆V between any two voltage sensing electrodes is measured and is
given by




By using the above equation the electric resistivity can be calculated for any
electrode configuration . The resistivity should be independent of the both
electrode spacing and geometery and same for a uniform material but if the
material is non uniform the electric resistivity will vary with the electrode
position.

Actually the apparent resistivity does not represent the average resistivity of
the material and hence negative values can be possible. It does however
provide a
means of scanning a region for resistivity variations and hence offers the
possibility of tomographic imaging. The depth of penetration of the current
increases as the separation of the current electrodes is increased and hence
it is possible to probe the material to different depths.

In general the depth of penetration is limited to about half the electrode
separation with features close to the surface having a greater influence on the
current path (MC Phillipson et. All)

Lock in Amplifier:
By using the lock-in amplifier the effects of noise can be subsequently
reduced and therefore it improves the signal to noise ratio. The main
advantages are that it responds to the frequency of interest, and the reference
frequency can be chosen to minimize the effect of 1/f and to avoid strong
interfering noise signals.Actually, the lock-in amplifier is a phase sensitive
detector which performs the following additional functions:

o Phase shifting of input signal with respect to reference signal
o Amplification and filtering of input signal.
o Narrow bandwidth detection
Exercise 3:
To calculate the apparent resistivity and by plotting the graph between
resistivity and position find out if there is any archaeological objects hidden
inside the ground.

Solution:
It is given that
Array (current injection probes) separation 2L =6.5 m
Voltage probes separation 2l=0.2 m
Injected current =0.0002 A


The provided data are illustrated in columns 1,2 of the following table.
                              Position of
                             mid point of
                               potential
                              electrodes
                             from LHS of
                                 site.      DVmeasured
                                 (m)          (V)
                                  0.5        0.14
                                  1.0        0.14
                                  1.5        0.10
                                  2.0        0.22
                                  2.5        0.60
                                  3.0        0.20
                                  3.5        0.16
                                  4.0        0.10
                                  4.5        0.11
                                  5.0        0.16
                                  5.5        0.30
                                  6.0        1.10

Since the distance ‘x between mid points of current and potential electrodes
Is not zero.Hence resistivity can be calculated using the formula:

     π ( L2 − x 2 ) 2 ∆V
ρ=                       meters*Volts/Ampere
     2l ( L2 − x 2 ) I
Where
L=3.25m,
2l=0.2m,
I=0.002A,
x=L –Potential Electrode (LHS position)
To calculate the distance ‘x’ and resistivity we used spreadsheet file and
below is the table showing the results
                                               x'
  Position of                              Distatanc
 mid point of                               e from
   potential                              the centre
  electrodes                                   of
 from LHS of                              Electrode
     site.                  DVmeasured         s           Resistivity
     (m)                      (V)             (m)              Meter*V/A
      0.5                    0.14             2.75           545.987137
      1.0                    0.14             2.25          2128.743182
      1.5                    0.10             1.75          3242.469482
      2.0                    0.22             1.25          11542.92394
      2.5                    0.60             0.75          42358.55263
      3.0                    0.20             0.25          16299.32189
      3.5                    0.16            -0.25          13039.45751
      4.0                    0.10            -0.75          7059.758772
      4.5                    0.11            -1.25          5771.461968
      5.0                    0.16            -1.75          5187.951171
      5.5                    0.30            -2.25          4561.592533
      6.0                    1.10            -2.75          4289.898934
Table :Calculated Resistivity and distance x values from spreadsheet

The graph of the resistivity versus position is shown in figure 4.
                                         Resistivity Vs Distance 'x'

                                               45000
                                                               0.75, 42358.55263
                                               40000
                                               35000
                                               30000
    Resistivity




                                               25000
                                                                                           Series1
                                               20000
                                               15000
                                               10000
                                                5000
                                                   0
                  -4   -3        -2       -1           0       1        2          3   4
                                                Distance 'x'


                                Figure 1: Resistivity Vs Distance ‘x’
Results:
From the graph it is clear that between the region -0.25 to +1.25 there is a
change in the resistivity of the region and at distance around 0.75 m is a clear
indication of some changes in the layer composition.Actually electrical
resistivity of stones ,rocks and hydrocarbons are much higher than the
soil.Therefore between region of -0.25 to +1.25 there may be some valuable
archaeological objects hidden beneath the position.



Exercise 4:Vertical electrical sounding (VES)
Vertical electrical sounding or electrical drilling is a detailed method to find out
the information on the vertical succession of different conducting zones and
their individual thickness and true resistivity and the method is based on the
four point probe method.(Schlumberger array).(http://www.geo-
serv.de/geoelec_VES_water.html)
In order to achieve vertical electrical sounding the relative spacing between
the electrodes should be maintained same and the position of the electrodes
should be expanded over a central fixed point .
Actually by expanding the electrodes the electric field generated by the
injected current electrodes can be increased vertically or down the ground
and this method can be used to find the objects deeper inside the ground.The
technique can be describe by the following diagram.

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Tomography_Resistivity Measurement System using Four Point Probe

  • 1. Exercise 1: The resistivity measurement system that used was based on the four point probe Schlumberger configuration and it is shown in figure 1 Figure 1 :The Measurement System The circuit diagram of a constant current source is shown in figure 2.If we apply input voltage Vin ,this circuit produces the same output current irrespective the changes in load resistor Rload .Since the output current Io equals the current through R on the resistor R,hence the the circuit shown here has a nearly infinite load resistance. For Vin=0.6V and R=3000 ohms ……{given} current Io can be calculated as follows Io= Vin/R Io= 0.6/3000 = 0.0002A or 0.2 mA Actually by changing the load resistance Rload the opamp output changes its voltage to keep the current Io remain constant. Vin = 0.6V Vload R=3KOhm Figure 2 : Constant current generator
  • 2. Below is the table showing the values of Vload for different values of Rload for the resistivity measurement system used i.e,Vin=0.6 V. Rload(Ohms) V load (Volts) Io load(A) 1000 0.2 0.0002 2000 0.4 0.0002 3000 0.6 0.0002 4000 0.8 0.0002 5000 1 0.0002 6000 1.2 0.0002 Table showing results of Vload at Different Rload Plotting graph between Vload and Rload we have got Vload Vs Rload 1.4 1.2 y = 0.0002x 1 Vload (Vlots) 0.8 Series1 0.6 Linear (Series1) 0.4 0.2 0 0 5000 10000 Rload (ohms) Graph between Vload Vs Rload From the above graph between Vload and Rload the equation of line is given by Y=0.0002x Where Gradient=Vload/Rload=Io Therefore Io=0.0002 A Results: From the graph we can see that the gradient remains the same for all values of Rload. Hence we can say that in this constant current source the output current Io is independent of the changes in Rload and therefore the circuit has nearly infinite load resistance within the compliance range.
  • 3. . Exercise 2:Measurement Strategies Figure 1:Resistivity Measurement strategy used in archaeology site The measuring system used in a archaeology site (as shown by figure 1) for measuring electrical resistivity or conductivity of any material was based on the four point probe method.This is a simple and low cost method which is first proposed by Thomson in 1861 and first used by Schlumberger in 1920 to measure the resistivity of Earth. Principle The basic principle of four point probe method is illustrated in the figure below Ground Four Point Probe Method “By applying constant current to the outer electrodes ,Potential Difference can be measured by the inner electrodes at different positions on the surface of the material .The current remains constant in the circuit irrespective to the
  • 4. changes in resistances and the output voltage is totally dependent on the resistance changes.” The four point method offers advantages over Direct or two probes method which offer very poor performance due to polarization and electrode contact issues. By using constant current source the current flowing through the material will largely independent to the probe/contact impedances as current remains constant as resistance changes.For verification below is the experimental results showing that the current remains same for different values of load resistances and only the output voltage will be changed with resistance.this experiment was performed with 1 mA current source with different values of resistances.and the output voltage of 15 V as opamp maximum i/p was 15 V and the opamp saturated at 13 volts approximately. R Vout I ohms (volts) (amperes) 1000 1.02 0.00102 2000 2 0.001 3000 3.05 0.001017 4000 4.07 0.001018 5000 5.08 0.001016 6000 6.1 0.001017 7000 7.12 0.001017 8000 8.15 0.001019 9000 9.165 0.001018 10000 10.18 0.001018 11000 11.18 0.001016 12000 12.19 0.001016 13000 13.21 0.001016 Results from Laborator experiment for verification of constant current source The graph between different Voltage and resistances values is shown below .
  • 5. V vs R(Linear Range) 14 y = 0.0010x - 0.0050 12 10 8 Vo (V) Linear 6 Linear (Linear) 4 2 0 0 5000 10000 15000 R(ohm) Also to ensure that virtually no current will flow through the voltage measuring electrodes an instrumentational amplifier is used as shown in the figure. In designing the voltage measuring electrodes should be as near to resistance as possible to minimize contact resistance and loading effects. The current follows the path according to the distribution of resistivity within the region.Thereore the potential difference between the two inner probes contains the information about the distribution of electrical resistivity. For measuring resistivity of the ground currents are injected into the ground and the resulting potential differences are measured at the surface.The in situ measurement of resistivity is impractical as it is the resistance measured between the faces of a unit cube of material.Therefore the common method is to measure the resistance on the surface of a material and then calculate the apparent resistivity values using the current and voltage measurements and the electrode configuration used Mostly low frequency alternating sources are applied to the ground for avoiding the polarization effect. In practice the frequency of the alternating current required to penetrate in the ground decreases with the increase in depth. F a.c. α 1/depth In general a frequency of 100 Hz is required to penetrate in 10m depth whereas 10 Hz for 100m. The resistivity for a conducting cylinder of resistance ∆R,length ∆L and cross sectional area ∆A is given by: =∆R ∆A/∆L ………eq(1)
  • 6. Current Flow in the ground: Consider a homogeneous material,when current I will flow through it it will follow the radial pattern from the electrode and create hemispherical equipotential surfaces. From Ohms’s Law and substituting values in eq 1 we know that ∆V/∆L = I/∆A = - i …………………..eq(2) The potential gradient ∆V/∆L is dependent on the current density I and the resistivity of the material. If the electrode is at distance r the surface area is 2πr² and hence current density I is given by i=I/2πr² Now the potential gradient is given by Equation (3) Now the potential Vr at a distance r can be found by integerating above equation (3) The potential can be calculated at any point on or below the surface of a homogeneous surface or ground by using above equation. If the sink electrode is at a finite distance from the source as illustrated in the figure below
  • 7. The potential at any point is the sum of the potential contributions from each current conducting electrode. Absolute potential are difficult to measure hence normally the potential difference ∆V between any two voltage sensing electrodes is measured and is given by By using the above equation the electric resistivity can be calculated for any electrode configuration . The resistivity should be independent of the both electrode spacing and geometery and same for a uniform material but if the material is non uniform the electric resistivity will vary with the electrode position. Actually the apparent resistivity does not represent the average resistivity of the material and hence negative values can be possible. It does however provide a means of scanning a region for resistivity variations and hence offers the possibility of tomographic imaging. The depth of penetration of the current increases as the separation of the current electrodes is increased and hence it is possible to probe the material to different depths. In general the depth of penetration is limited to about half the electrode separation with features close to the surface having a greater influence on the current path (MC Phillipson et. All) Lock in Amplifier: By using the lock-in amplifier the effects of noise can be subsequently reduced and therefore it improves the signal to noise ratio. The main advantages are that it responds to the frequency of interest, and the reference frequency can be chosen to minimize the effect of 1/f and to avoid strong interfering noise signals.Actually, the lock-in amplifier is a phase sensitive detector which performs the following additional functions: o Phase shifting of input signal with respect to reference signal o Amplification and filtering of input signal. o Narrow bandwidth detection
  • 8. Exercise 3: To calculate the apparent resistivity and by plotting the graph between resistivity and position find out if there is any archaeological objects hidden inside the ground. Solution: It is given that Array (current injection probes) separation 2L =6.5 m Voltage probes separation 2l=0.2 m Injected current =0.0002 A The provided data are illustrated in columns 1,2 of the following table. Position of mid point of potential electrodes from LHS of site. DVmeasured (m) (V) 0.5 0.14 1.0 0.14 1.5 0.10 2.0 0.22 2.5 0.60 3.0 0.20 3.5 0.16 4.0 0.10 4.5 0.11 5.0 0.16 5.5 0.30 6.0 1.10 Since the distance ‘x between mid points of current and potential electrodes Is not zero.Hence resistivity can be calculated using the formula: π ( L2 − x 2 ) 2 ∆V ρ= meters*Volts/Ampere 2l ( L2 − x 2 ) I Where L=3.25m, 2l=0.2m, I=0.002A, x=L –Potential Electrode (LHS position)
  • 9. To calculate the distance ‘x’ and resistivity we used spreadsheet file and below is the table showing the results x' Position of Distatanc mid point of e from potential the centre electrodes of from LHS of Electrode site. DVmeasured s Resistivity (m) (V) (m) Meter*V/A 0.5 0.14 2.75 545.987137 1.0 0.14 2.25 2128.743182 1.5 0.10 1.75 3242.469482 2.0 0.22 1.25 11542.92394 2.5 0.60 0.75 42358.55263 3.0 0.20 0.25 16299.32189 3.5 0.16 -0.25 13039.45751 4.0 0.10 -0.75 7059.758772 4.5 0.11 -1.25 5771.461968 5.0 0.16 -1.75 5187.951171 5.5 0.30 -2.25 4561.592533 6.0 1.10 -2.75 4289.898934 Table :Calculated Resistivity and distance x values from spreadsheet The graph of the resistivity versus position is shown in figure 4. Resistivity Vs Distance 'x' 45000 0.75, 42358.55263 40000 35000 30000 Resistivity 25000 Series1 20000 15000 10000 5000 0 -4 -3 -2 -1 0 1 2 3 4 Distance 'x' Figure 1: Resistivity Vs Distance ‘x’ Results: From the graph it is clear that between the region -0.25 to +1.25 there is a change in the resistivity of the region and at distance around 0.75 m is a clear indication of some changes in the layer composition.Actually electrical
  • 10. resistivity of stones ,rocks and hydrocarbons are much higher than the soil.Therefore between region of -0.25 to +1.25 there may be some valuable archaeological objects hidden beneath the position. Exercise 4:Vertical electrical sounding (VES) Vertical electrical sounding or electrical drilling is a detailed method to find out the information on the vertical succession of different conducting zones and their individual thickness and true resistivity and the method is based on the four point probe method.(Schlumberger array).(http://www.geo- serv.de/geoelec_VES_water.html) In order to achieve vertical electrical sounding the relative spacing between the electrodes should be maintained same and the position of the electrodes should be expanded over a central fixed point . Actually by expanding the electrodes the electric field generated by the injected current electrodes can be increased vertically or down the ground and this method can be used to find the objects deeper inside the ground.The technique can be describe by the following diagram.