the table shows the distance and costs of flights for a given air line with the same starting destination and a differant ending destination.
distance (miles) 1281 2796 790 150 3211 7810 812 210 7742 3578 1346 3214
cost (dollars) 473 683 508 301 1115 3619 587 n540 3013 1647 882 817
(a) find the equation of the median-median line for the data.
(b) predict the cost of a flight that travels a distance of 1950 miles. show how you figure the problems in full
Solution
Quite a bit of work to be done. You have already ordered the data. Now divide them into 3 equal parts. For each part, create a summary point by using the median x-value and the median y-value, and combining them to create an ordered pair. You are down to just three points. Now use the two outer summary points to determine the equation of the line between them Move that line 1/3 of the way towards the middle summary point. Find its equation. That\'s the equation of the median-median line. The answer to (a). [ See the example at the source for greater clarity] For the answer to (b) just substitute x = 1950 in the median-median line equation to get y which is the predicted cost
.
the table shows the distance and costs of flights for a given air line.docx
1. the table shows the distance and costs of flights for a given air line with the same starting
destination and a differant ending destination.
distance (miles) 1281 2796 790 150 3211 7810 812 210 7742 3578 1346 3214
cost (dollars) 473 683 508 301 1115 3619 587 n540 3013 1647 882 817
(a) find the equation of the median-median line for the data.
(b) predict the cost of a flight that travels a distance of 1950 miles. show how you figure the
problems in full
Solution
Quite a bit of work to be done. You have already ordered the data. Now divide them into 3 equal
parts. For each part, create a summary point by using the median x-value and the median y-
value, and combining them to create an ordered pair. You are down to just three points. Now use
the two outer summary points to determine the equation of the line between them Move that line
1/3 of the way towards the middle summary point. Find its equation. That's the equation of the
median-median line. The answer to (a). [ See the example at the source for greater clarity] For
the answer to (b) just substitute x = 1950 in the median-median line equation to get y which is
the predicted cost
![the table shows the distance and costs of flights for a given air line with the same starting
destination and a differant ending destination.
distance (miles) 1281 2796 790 150 3211 7810 812 210 7742 3578 1346 3214
cost (dollars) 473 683 508 301 1115 3619 587 n540 3013 1647 882 817
(a) find the equation of the median-median line for the data.
(b) predict the cost of a flight that travels a distance of 1950 miles. show how you figure the
problems in full
Solution
Quite a bit of work to be done. You have already ordered the data. Now divide them into 3 equal
parts. For each part, create a summary point by using the median x-value and the median y-
value, and combining them to create an ordered pair. You are down to just three points. Now use
the two outer summary points to determine the equation of the line between them Move that line
1/3 of the way towards the middle summary point. Find its equation. That's the equation of the
median-median line. The answer to (a). [ See the example at the source for greater clarity] For
the answer to (b) just substitute x = 1950 in the median-median line equation to get y which is
the predicted cost](https://image.slidesharecdn.com/thetableshowsthedistanceandcostsofflightsforagivenairline-230203023534-74c55a0b/85/the-table-shows-the-distance-and-costs-of-flights-for-a-given-air-line-docx-1-320.jpg)
