Z=4040 electrons40Zr 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d2.pdf

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Z=40 40 electrons 40Zr: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d2 Solution Z=40 40 electrons 40Zr: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d2.

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The act had a profound effect on corporate governance in the United States. The Sarbanes-Oxley Act requires public companies to strengthen audit committees, perform internal controls tests, set personal liability of directors and officers for accuracy of financial statements, and strengthen disclosure. The Sarbanes-Oxley Act also establishes stricter criminal penalties for securities fraud and changes how public accounting firms operate their businesses. One direct effect of the Sarbanes-Oxley Act on corporate governance is the strengthening of audit committees at public companies. The audit committee receives wide leverage in overseeing the company\'s top management accounting decisions. The audit committee members must be independent of the top management and gain new responsibilities such as approving numerous audit and non-audit services, selecting and overseeing external auditors, and handling complaints regarding the management\'s accounting practices. The costliest part of the Sarbanes-Oxley Act is Section 404, which requires public companies to perform extensive internal control tests and include an internal control report with their annual audits. Testing and documenting manual and automated controls in financial reporting requires enormous effort and involvement of not only external accountants, but also experienced IT personnel. The compliance cost is especially burdensome for companies that heavily rely on manual controls. The Sarbanes-Oxley Act encouraged companies to make their financial reporting more efficient, centralized and automated. The Sarbanes-Oxley Act changes management\'s responsibility for financial reporting significantly. The act requires that top managers personally certify the accuracy of financial reports. If a top manager knowingly or willfully makes a false certification, he can face 10 to 20 years in prison. If the company is forced to make a required accounting restatement due to management\'s misconduct, top managers can be forced to give up their bonuses or profits made from selling the company\'s stock. If the director or officer is convicted in securities law violation, he can be prohibited from serving in the same role at the public company. The Sarbanes-Oxley Act significantly strengthens the disclosure requirement. Public companies are required to disclose any material off-balance sheet arrangements, such as operating leases and special purposes entities. The company is also required to disclose any pro forma statements and how they would look under the generally accepted accounting principles (GAAP). Insiders must report their stock transactions to the Securities and Exchange Commission (SEC) within two business days as well. The Sarbanes-Oxley Act imposes harsher punishment for obstructing justice and securities fraud, mail fraud and wire fraud. The maximum sentence term for securities fraud increased to 25 years, and the maximum prison time for obstruction of justice increased to 20 years. The act.

The act had a profound effect on corporate governance in the United .pdf

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Statistical Distributions Every statistics book provides a listing of statistical distributions, with their properties, but browsing through these choices can be frustrating to anyone without a statistical background, for two reasons. First, the choices seem endless, with dozens of distributions competing for your attention, with little or no intuitive basis for differentiating between them. Second, the descriptions tend to be abstract and emphasize statistical properties such as the moments, characteristic functions and cumulative distributions. In this appendix, we will focus on the aspects of distributions that are most useful when analyzing raw data and trying to fit the right distribution to that data. Fitting the Distribution When confronted with data that needs to be characterized by a distribution, it is best to start with the raw data and answer four basic questions about the data that can help in the characterization. The first relates to whether the data can take on only discrete values or whether the data is continuous; whether a new pharmaceutical drug gets FDA approval or not is a discrete value but the revenues from the drug represent a continuous variable. The second looks at the symmetry of the data and if there is asymmetry, which direction it lies in; in other words, are positive and negative outliers equally likely or is one more likely than the other. The third question is whether there are upper or lower limits on the data;; there are some data items like revenues that cannot be lower than zero whereas there are others like operating margins that cannot exceed a value (100%). The final and related question relates to the likelihood of observing extreme values in the distribution; in some data, the extreme values occur very infrequently whereas in others, they occur more often. Is the data discrete or continuous? The first and most obvious categorization of data should be on whether the data is restricted to taking on only discrete values or if it is continuous. Consider the inputs into a typical project analysis at a firm. Most estimates that go into the analysis come from distributions that are continuous; market size, market share and profit margins, for instance, are all continuous variables. There are some important risk factors, though, that can take on only discrete forms, including regulatory actions and the threat of a terrorist attack; in the first case, the regulatory authority may dispense one of two or more decisions which are specified up front and in the latter, you are subjected to a terrorist attack or you are not. With discrete data, the entire distribution can either be developed from scratch or the data can be fitted to a pre-specified discrete distribution. With the former, there are two steps to building the distribution. The first is identifying the possible outcomes and the second is to estimate probabilities to each outcome. As we noted in the text, we can draw on historical data or experience as .

Statistical DistributionsEvery statistics book provides a list.pdf

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second student expressed in better formhe made z independant, and .pdf

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AnswerProperties area.) Enthalpy, c.) Mass, e.) DensitySolu.pdf

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in He2 there are total of four electrons which can be placed on both bonding and antibonding orbital. So both the bonding and the antibonding orbital have two electrons each. so bond order for He2 = [no. e in bonding - no.e in antibonding ]/2 = (4-4)/2 = 0 for He 2+ = there are thre electrons among which two are in the bonding Molecular orbital and one in antibonding mo so bond order = 2-1/2 = 0.5 for He2- two bonding and two antibonding another one is in next 2sigmag bonding molecular orbital . so b.o = 5-2/2= 1.5 so He2 _ has the highest bond order. Solution in He2 there are total of four electrons which can be placed on both bonding and antibonding orbital. So both the bonding and the antibonding orbital have two electrons each. so bond order for He2 = [no. e in bonding - no.e in antibonding ]/2 = (4-4)/2 = 0 for He 2+ = there are thre electrons among which two are in the bonding Molecular orbital and one in antibonding mo so bond order = 2-1/2 = 0.5 for He2- two bonding and two antibonding another one is in next 2sigmag bonding molecular orbital . so b.o = 5-2/2= 1.5 so He2 _ has the highest bond order..

in He2 there are total of four electrons which can be placed on both.pdf

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I think that 24SolutionI think that 24.pdf

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For n=1,2,3 ;SolutionFor n=1,2,3 ;.pdf

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Egg polarity is the orientation of the egg. In developmental biology, all animal eggs have 2 poles one is anterior animal pole and the other is posterior vegetal pole, these poles are connected by the axis of the egg. The plane that bisects the main axis at right angle is the equitorial plane. Cytoplasmic determinants are molecules essential during oocyte matuaration in the ovary of female and may control gene expression. These are present in the region of egg\'s cytoplasm whcih results in included in the blastomeres. Dorso-ventral and Antero-posterior axis are established in egg and embryo by maternal effect genes (egg-polarity genes). In the early embroyonic development, cytoplasmic determinants already present in unfertilised egg encoded by mother\'s egg-polarity genes and these genes encode proteins that are existing in the egg while still in the mother\'s ovary. Solution Egg polarity is the orientation of the egg. In developmental biology, all animal eggs have 2 poles one is anterior animal pole and the other is posterior vegetal pole, these poles are connected by the axis of the egg. The plane that bisects the main axis at right angle is the equitorial plane. Cytoplasmic determinants are molecules essential during oocyte matuaration in the ovary of female and may control gene expression. These are present in the region of egg\'s cytoplasm whcih results in included in the blastomeres. Dorso-ventral and Antero-posterior axis are established in egg and embryo by maternal effect genes (egg-polarity genes). In the early embroyonic development, cytoplasmic determinants already present in unfertilised egg encoded by mother\'s egg-polarity genes and these genes encode proteins that are existing in the egg while still in the mother\'s ovary..

Egg polarity is the orientation of the egg. In developmental biology.pdf

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Every network and system has some loop holes and weaknesses so the intruders tries to get in to that network and hack the system. Network has so many weaknesses some of them are Operating system weakness, configuration weakness, technology weakness. - Coming to the vulnerabilities factors the intrudors or hacklers tries to find the weak spot in the network or device and tries to get in to that system. There are operating systems like UNIX, LINUX, Windows all these operating systems have some loop holes, these loop holes must be rectified. Passwords must be very typical that they would not have a chance of guessing that one. Every networks runs with some protocols. some of them are http, ftp, icmp. These are less insecure so these protocols must be secured properly. - Coming to the threats these are nothing but hackers and crackers that try to get in to that network and change the data. There atr several trypes of threats like hackers, crackers, phisher etc., The hackers try to get in to the network through a unauthorizes access and get the system in his control and the cracker gets in to the network through by sending some different viruses and gets the access over the network o0r system. Pischer in the sense they send so many mails which is not useful to us when we open to them we might effect with the viruses and this is one type of threat to the system. Solution Every network and system has some loop holes and weaknesses so the intruders tries to get in to that network and hack the system. Network has so many weaknesses some of them are Operating system weakness, configuration weakness, technology weakness. - Coming to the vulnerabilities factors the intrudors or hacklers tries to find the weak spot in the network or device and tries to get in to that system. There are operating systems like UNIX, LINUX, Windows all these operating systems have some loop holes, these loop holes must be rectified. Passwords must be very typical that they would not have a chance of guessing that one. Every networks runs with some protocols. some of them are http, ftp, icmp. These are less insecure so these protocols must be secured properly. - Coming to the threats these are nothing but hackers and crackers that try to get in to that network and change the data. There atr several trypes of threats like hackers, crackers, phisher etc., The hackers try to get in to the network through a unauthorizes access and get the system in his control and the cracker gets in to the network through by sending some different viruses and gets the access over the network o0r system. Pischer in the sense they send so many mails which is not useful to us when we open to them we might effect with the viruses and this is one type of threat to the system..

Every network and system has some loop holes and weaknesses so the i.pdf

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COOH and NH2SolutionCOOH and NH2.pdf

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confounding -- they are both caused by something else - wealth.pdf

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a. Journal entry fro revaluation of assetb. Journal entry for admi.pdf

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a) 2n-1 =12-1=11it was turners syndrome so the person has one sex .pdf

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2, Steven O’Brien’s suggested that the survivors of Plague during the 1600’s pandemic had some sort of genetic changes which led to increased survival. To test this hypothesis he decided to analyse the DNA sample of Plague survivor. For testing this he selected an isolated town called Eyam. The population here is known to have survived from Plague epidemic. Everyone here must have exposed to plague bacterium and those who survived must have the genetic mutation in their genes. He also suggested that the survivors who have the genetic mutation in their DNA would have transferred their mutation to succeeding generations. Eyam was keeping a parish registry from which he was able to trace the descendants of plague survivors. He collected blood samples and tested for delta 32 mutation in white blood cells . He was able to get 14% positive cases from whole population tested; to emphasis on his findings he need to prove that this 14% is a significant number. Further he collected blood samples from all over the world and tested for delta 32 mutation in them, the result was 0% for the population who never had a exposure to Plague before. Thus he proved his hypothesis. The Plague survivor has mutation name delta32 in CCR5 gene which may have prevented the plague from entering the host cells. During the global study in search for delta32 mutation he found out that there are people with delta32 mutation in other part of Europe as well which had been affected by plague earlier. Also Plague survivors and their descendants from Europe who has settled in America also showed this mutation in their genes. Solution 2, Steven O’Brien’s suggested that the survivors of Plague during the 1600’s pandemic had some sort of genetic changes which led to increased survival. To test this hypothesis he decided to analyse the DNA sample of Plague survivor. For testing this he selected an isolated town called Eyam. The population here is known to have survived from Plague epidemic. Everyone here must have exposed to plague bacterium and those who survived must have the genetic mutation in their genes. He also suggested that the survivors who have the genetic mutation in their DNA would have transferred their mutation to succeeding generations. Eyam was keeping a parish registry from which he was able to trace the descendants of plague survivors. He collected blood samples and tested for delta 32 mutation in white blood cells . He was able to get 14% positive cases from whole population tested; to emphasis on his findings he need to prove that this 14% is a significant number. Further he collected blood samples from all over the world and tested for delta 32 mutation in them, the result was 0% for the population who never had a exposure to Plague before. Thus he proved his hypothesis. The Plague survivor has mutation name delta32 in CCR5 gene which may have prevented the plague from entering the host cells. During the global study in search for delta32 mutation he found out t.

2, Steven O’Brien’s suggested that the survivors of Plague during th.pdf

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1-2sin^2xSolution1-2sin^2x.pdf

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1). e. Lycophyta (club mosses).The lycophytes are the oldest plant.pdf

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A because conjugation of double bonds occur getti.pdf

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/** * The java program TwelveDays that prompts user to enter * last day number then prints the verse of christmas song * to console. * */ //TwelveDays.java import java.util.Scanner; public class TwelveDays { public static void main(String[] args) { final int MAX = 12; int lastDay = 0; //last day for the song, user will update //create a scanner class object Scanner scanner = new Scanner(System.in); //Get the last day and use input validation do { //prompt for lastDay value System.out.println(\"Enter last day number [1-12]\"); lastDay=Integer.parseInt(scanner.nextLine()); }while(lastDay<1 || lastDay>12); //set lastDay to day int day = lastDay; System.out.print(\"On the \"); //first switch case switch(day) { case 1: System.out.print(\"first \"); break; case 2: System.out.print(\"second\"); break; case 3: System.out.print(\"third\"); break; case 4: System.out.print(\"fourth\"); break; case 5: System.out.print(\"fifth\"); break; case 6: System.out.print(\"sixth\"); break; case 7: System.out.print(\"seventh\"); break; case 8: System.out.print(\"eighth\"); break; case 9: System.out.print(\"ninth\"); break; case 10: System.out.print(\"tenth\"); break; case 11: System.out.print(\"eleventh\"); break; case 12: System.out.print(\"twelfth\"); break; } System.out.println(\" day of Christmas, my true love sent to me:\"); //second switch case to select gift of day switch(day) { case 12: System.out.println(\"Twelve Drummers Drumming\"); case 11: System.out.println(\"Eleven Pipers Piping\"); case 10: System.out.println(\"Ten Lords a Leaping\"); case 9: System.out.println(\"Nine Ladies Dancing\"); case 8: System.out.println(\"Eight Maids a Milking\"); case 7: System.out.println(\"Seven Swans a Swimming\"); case 6: System.out.println(\"Six Geese a Laying\"); case 5: System.out.println(\"Five Golden Rings\"); case 4: System.out.println(\"Four Calling Birds\"); case 3: System.out.println(\"Three French Hens\"); case 2: System.out.print(\"Two Turtle Doves\"); case 1: if(day>1){ System.out.println(\",and \"); } System.out.println(\"A Partridge in a Pear Tree.\"); break; } } }//end of the class ------------------------------------------------------------------------------------------------------ Sample output: Enter last day number [1-12] 12 On the twelfth day of Christmas, my true love sent to me: Twelve Drummers Drumming Eleven Pipers Piping Ten Lords a Leaping Nine Ladies Dancing Eight Maids a Milking Seven Swans a Swimming Six Geese a Laying Five Golden Rings Four Calling Birds Three French Hens Two Turtle Doves,and A Partridge in a Pear Tree. sample run2\" Enter last day number [1-12] 11 On the eleventh day of Christmas, my true love sent to me: Eleven Pipers Piping Ten Lords a Leaping Nine Ladies Dancing Eight Maids a Milking Seven Swans a Swimming Six Geese a Laying Five Golden Rings Four Calling Birds Three French Hens Two Turtle Doves,and A Partridge in a Pear Tree. Solution /** * The java program TwelveDays that prompts user to enter * last day number then.

The java program TwelveDays that prompts user to enter l.pdf

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Nominal return 11.60 Inflation 2.6 Real rate of retur.pdf

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When the Maganese Dioxide was added to the Hydrog.pdf

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The act had a profound effect on corporate governance in the United .pdf

Statistical DistributionsEvery statistics book provides a list.pdf

second student expressed in better formhe made z independant, and .pdf

AnswerProperties area.) Enthalpy, c.) Mass, e.) DensitySolu.pdf

in He2 there are total of four electrons which can be placed on both.pdf

I think that 24SolutionI think that 24.pdf

For n=1,2,3 ;SolutionFor n=1,2,3 ;.pdf

Egg polarity is the orientation of the egg. In developmental biology.pdf

Every network and system has some loop holes and weaknesses so the i.pdf

COOH and NH2SolutionCOOH and NH2.pdf

confounding -- they are both caused by something else - wealth.pdf

a. Journal entry fro revaluation of assetb. Journal entry for admi.pdf

a) 2n-1 =12-1=11it was turners syndrome so the person has one sex .pdf

2, Steven O’Brien’s suggested that the survivors of Plague during th.pdf

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1). e. Lycophyta (club mosses).The lycophytes are the oldest plant.pdf

A because conjugation of double bonds occur getti.pdf

The java program TwelveDays that prompts user to enter l.pdf

Nominal return 11.60 Inflation 2.6 Real rate of retur.pdf

When the Maganese Dioxide was added to the Hydrog.pdf