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Please help me, write this in computer(Write your results and processes on computer) Include the solution of the problems with the whole procedure clear, complete and organized. Look for the tension in the rope C 2. Determine the acceleration and tension in string(rope) C, from the following figure, once the masses are released from rest. 1.2 kg 3.2 kg Copyrigh0 2008 Parson Education Ine Solution Here the acceleration in both block will be same because there is no change in length of the string during motion tension on block A(1.2Kg ) and tension on Block B( 3.2Kg ) will be same .. suppose tension is T then tension in string C will be T+T =2T suppose acceleration is \'a\' on block A in Upward direction then eq will be T- 1.2g =1.2a ........(1) same accelaration on block B but in downward direction eq will be 3.2g-T= 3.2a ............(2) add (1)+(2)... we get 3.2g - 1.2g = ( 1.2+3.2) a by solving it a= 4.45 m/s^2 now put a value in eq (1) ...T= 17.11 N and tension in C will ..= 2T= 34.22 N .

Please help me, write this in computer(Write your results and processes on computer)
Include the solution of the problems with the whole procedure clear, complete and organized.
Look for the tension in the rope C
2. Determine the acceleration and tension in string(rope) C, from the following figure, once the
masses are released from rest.
1.2 kg 3.2 kg Copyrigh0 2008 Parson Education Ine
Solution
Here the acceleration in both block will be same because there is no change in length of the
string during motion
tension on block A(1.2Kg ) and tension on Block B( 3.2Kg ) will be same ..
suppose tension is T then tension in string C will be T+T =2T
suppose acceleration is 'a' on block A in Upward direction then eq will be
T- 1.2g =1.2a ........(1)
same accelaration on block B but in downward direction eq will be
3.2g-T= 3.2a ............(2)
add (1)+(2)...
we get 3.2g - 1.2g = ( 1.2+3.2) a
by solving it a= 4.45 m/s^2
now put a value in eq (1) ...T= 17.11 N

and tension in C will ..= 2T= 34.22 N

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Wizards are very useful for creating a good user experience. In all businesses, interactive sessions are most beneficial. To improve the user experience, wizards in Odoo provide an interactive session. For creating wizards, we can use transient models or abstract models. This gives features of a model class except the data storing. Transient and abstract models have permanent database persistence. For them, database tables are made, and the records in such tables are kept until they are specifically erased.

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Klinik_ Apotek Onlin 085657271886 Solusi Menggugurkan Masalah Kehamilan Anda Jual Obat Aborsi Asli KLINIK ABORSI TERPEECAYA _ Jual Obat Aborsi Cytotec Misoprostol Asli 100% Ampuh Hanya 3 Jam Langsung Gugur || OBAT PENGGUGUR KANDUNGAN AMPUH MANJUR OBAT ABORSI OLINE" APOTIK Jual Obat Cytotec, Gastrul, Gynecoside Asli Ampuh. JUAL ” Obat Aborsi Tuntas | Obat Aborsi Manjur | Obat Aborsi Ampuh | Obat Penggugur Janin | Obat Pencegah Kehamilan | Obat Pelancar Haid | Obat terlambat Bulan | Ciri Obat Aborsi Asli | Obat Telat Bulan | Pil Aborsi Asli | Cara Menggugurkan Konten | Cara Aborsi Tuntas | Harga Obat Aborsi Asli | Pil Aborsi | Jual Obat Aborsi Cytotec | Cara Aborsi Sendiri | Cara Aborsi Usia 1 Bulan | Cara Aborsi Usia 2 Tahun | Cara Aborsi Usia 3 Bulan | Obat Aborsi Usia 4 Bulan | Cara Abrasi Usia 5 Bulan | Cara Menggugurkan Konten | Kandungan Obat Penggugur | Cara Menghitung Usia Konten | Cara Mengatasi Terlambat Bulan | Penjual Obat Aborsi Asli | Obat Aborsi Garansi | Kandungan Obat Peluntur | Obat Telat Datang Bulan | Obat Telat Haid | Obat Aborsi Paling Murah | Klinik Jual Obat Aborsi | Jual Pil Cytotec | Apotik Jual Obat Aborsi | Kandungan Dokter Abrasi | Cara Aborsi Cepat | Jual Obat Aborsi Bergaransi | Jual Obat Cytotec Asli | Obat Aborsi Aman Manjur | Obat Misoprostol Cytotec Asli. "APA ITU ABORSI" “Aborsi Adalah dengan membendung hormon yang di perlukan untuk mempertahankan kehamilan yaitu hormon progesteron, karena hormon ini dibendung, maka jalur kehamilan mulai membuka dan leher rahim menjadi melunak,sehingga mengeluarkan darah yang merupakan tanda bahwa obat telah bekerja || maksimal 1 jam obat diminum || PENJELASAN OBAT ABORSI USIA 1 _7 BULAN Pada usia kandungan ini, pasien akan merasakan sakit yang sedikit tidak berlebihan || sekitar 1 jam ||. namun hanya akan terjadi pada saatdarah keluar merupakan pertanda menstruasi. Hal ini dikarenakan pada usiakandungan 3 bulan,janin sudah terbentuk sebesar kepalan tangan orang dewasa. Cara kerja obat aborsi : JUAL OBAT ABORSI AMPUH dosis 3 bulan secara umum sama dengan cara kerja || DOSIS OBAT ABORSI 2 bulan”, hanya berbedanya selain mengisolasijanin juga menghancurkan janin dengan formula methotrexate dikandungdidalamnya. Formula methotrexate ini sangat ampuh untuk menghancurkan janinmenjadi serpihan-serpihan kecil akan sangat berguna pada saat dikeluarkan nanti. APA ALASAN WANITA MELAKUKAN ABORSI? Aborsi di lakukan wanita hamil baik yang sudah menikah maupun belum menikah dengan berbagai alasan , akan tetapi alasan yang utama adalah alasan-alasan non medis (termasuk aborsi sendiri / di sengaja/ buatan] MELAYANI PEMESANAN OBAT ABORSI SETIAP HARI, SIAP KIRIM KESELURUH KOTA BESAR DI INDONESIA DAN LUAR NEGERI. HUBUNGI PEMESANAN LEBIH NYAMAN VIA WA/: 085657271886

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1. Please help me, write this in computer(Write your results and processes on computer) Include the solution of the problems with the whole procedure clear, complete and organized. Look for the tension in the rope C 2. Determine the acceleration and tension in string(rope) C, from the following figure, once the masses are released from rest. 1.2 kg 3.2 kg Copyrigh0 2008 Parson Education Ine Solution Here the acceleration in both block will be same because there is no change in length of the string during motion tension on block A(1.2Kg ) and tension on Block B( 3.2Kg ) will be same .. suppose tension is T then tension in string C will be T+T =2T suppose acceleration is 'a' on block A in Upward direction then eq will be T- 1.2g =1.2a ........(1) same accelaration on block B but in downward direction eq will be 3.2g-T= 3.2a ............(2) add (1)+(2)... we get 3.2g - 1.2g = ( 1.2+3.2) a by solving it a= 4.45 m/s^2 now put a value in eq (1) ...T= 17.11 N

2. and tension in C will ..= 2T= 34.22 N