Determine the values of n in each equations that 1 root is triple the other root 3x^2-4x+n=0 Solution 3x^2 - 4x + n = 0 Let x1 and x2 be the roots; ==> x2= 3x1 .......(1) Let us use viete\'s rule: we know that: x1+ x2= -b/a = 4/3 ==> x1+ 3x1 = 4/3 ==> 4x1 = 4/3 ==> x1= 1/3 ==> x2= 3*1/3 = 1 Also, x1*x2= c/a = n/3 ==> 1*1/3= n/3 ==> n= 1.