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Today:
 Prep for Final
 Classwork, Alt.Khan
 Notebooks prepared for Thursday
submission
 Bring Calculator Tomorrow... Phones
cannot be used
Warm-Up Section of Notebook
June 10, 2014
Simplify:
Simplify:
Final Exam Review:
Final Exam Review:
Simplify:
Final Exam Review:
What was the price of each type of ticket?
3(6y + a = $17.50)
- 3y + 3a = $22.50
y = $2.00; a = $5.50
Final Exam Review:
Sadly, we have reached the end, the last warm-up
question of the year..........
5x  1  3x 5  2.
Set up the equation
so that there will be
only one radical on
each side of the equal sign.
Square both sides
of the equation.
Simplify.
Simplify by dividing
by a common factor of 2.
Square both sides of the
equation.
5x 1 2
 2  3x  5 2
5x 1
5x 1 3x 1 4 3x  5
2x  2  4 3x  5
x 1 2 3x  5
x 1 2
 2 3x  5 2
x2
 2x 1  4(3x  5) Use Foil.
5x 1  2 3x  5
Use Foil. 4  4 3x  5  (3x  5)
Solve
Solving Radical Equations
x2
 2x 1  4(3x  5) Distribute the 4.
x2
 2x 112x  20 Simplify.
x2
10x  21 0 Factor the quadratic.
(x  3)(x  7)  0 Solve for x.
x - 3 = 0 or x - 7 = 0
x = 3 or x = 7 Verify both solutions.
5x 1  3x  5 2
5(3)  1  3(3)  5
4  2
2
5x 1  3x  5 2
5(7)  1  3(7)  5
6  4
2
Solving Radical Equations
L.S. R.S. L.S. R.S.
June 10, 2014

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June 10, 2014

  • 1. Today:  Prep for Final  Classwork, Alt.Khan  Notebooks prepared for Thursday submission  Bring Calculator Tomorrow... Phones cannot be used Warm-Up Section of Notebook June 10, 2014
  • 5. Final Exam Review: What was the price of each type of ticket? 3(6y + a = $17.50) - 3y + 3a = $22.50 y = $2.00; a = $5.50
  • 7. Sadly, we have reached the end, the last warm-up question of the year..........
  • 8. 5x  1  3x 5  2. Set up the equation so that there will be only one radical on each side of the equal sign. Square both sides of the equation. Simplify. Simplify by dividing by a common factor of 2. Square both sides of the equation. 5x 1 2  2  3x  5 2 5x 1 5x 1 3x 1 4 3x  5 2x  2  4 3x  5 x 1 2 3x  5 x 1 2  2 3x  5 2 x2  2x 1  4(3x  5) Use Foil. 5x 1  2 3x  5 Use Foil. 4  4 3x  5  (3x  5) Solve Solving Radical Equations
  • 9. x2  2x 1  4(3x  5) Distribute the 4. x2  2x 112x  20 Simplify. x2 10x  21 0 Factor the quadratic. (x  3)(x  7)  0 Solve for x. x - 3 = 0 or x - 7 = 0 x = 3 or x = 7 Verify both solutions. 5x 1  3x  5 2 5(3)  1  3(3)  5 4  2 2 5x 1  3x  5 2 5(7)  1  3(7)  5 6  4 2 Solving Radical Equations L.S. R.S. L.S. R.S.