1. Section 3.4
Derivatives of Trigonometric Functions
Math 1a
February 25, 2008
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2. Two important trigonometric limits
Theorem
The following two limits hold:
sin θ
lim =1
θ→0 θ
cos θ − 1
lim =0
θ→0 θ
3. Proof of the Sine Limit
Proof.
Notice
sin θ ≤ θ ≤ tan θ
Divide by sin θ:
θ 1
1≤ ≤
sin θ cos θ
Take reciprocals:
sin θ θ tan θ
θ sin θ
1≥ ≥ cos θ
cos θ 1 θ
As θ → 0, the left and right
sides tend to 1. So, then,
must the middle
expression.
4. Now
1 − cos θ 1 − cos θ 1 + cos θ 1 − cos2 θ
= · =
θ θ 1 + cos θ θ(1 + cos θ)
2
sin θ sin θ cos θ
= = ·
θ(1 + cos θ) θ 1 + cos θ
So
1 − cos θ sin θ cos θ
lim = lim · lim
θ→0 θ θ→0 θ θ→0 1 + cos θ
= 1 · 0 = 0.
5. Derivatives of Sine and Cosine
Theorem
d
sin x = cos x.
dx
Proof.
From the definition:
6. Derivatives of Sine and Cosine
Theorem
d
sin x = cos x.
dx
Proof.
From the definition:
d sin(x + h) − sin x
sin x = lim
dx h→0 h
7. Derivatives of Sine and Cosine
Theorem
d
sin x = cos x.
dx
Proof.
From the definition:
d sin(x + h) − sin x
sin x = lim
dx h→0 h
(sin x cos h + cos x sin h) − sin x
= lim
h→0 h
8. Derivatives of Sine and Cosine
Theorem
d
sin x = cos x.
dx
Proof.
From the definition:
d sin(x + h) − sin x
sin x = lim
dx h→0 h
(sin x cos h + cos x sin h) − sin x
= lim
h→0 h
cos h − 1 sin h
= sin x · lim + cos x · lim
h→0 h h→0 h
9. Derivatives of Sine and Cosine
Theorem
d
sin x = cos x.
dx
Proof.
From the definition:
d sin(x + h) − sin x
sin x = lim
dx h→0 h
(sin x cos h + cos x sin h) − sin x
= lim
h→0 h
cos h − 1 sin h
= sin x · lim + cos x · lim
h→0 h h→0 h
= sin x · 0 + cos x · 1 = cos x
12. Derivatives of Sine and Cosine
Theorem
d
sin x = cos x.
dx
d
cos x = − sin x.
dx
13. Derivatives of tangent and secant
Fill in the table:
y y
sin x cos x
cos x − sin x
tan x
cot x
sec x
csc x
14. Derivatives of tangent and secant
Fill in the table:
y y
sin x cos x
cos x − sin x
tan x sec2 x
cot x
sec x
csc x
15. Derivatives of tangent and secant
Fill in the table:
y y
sin x cos x
cos x − sin x
tan x sec2 x
cot x − csc2 x
sec x
csc x
16. Derivatives of tangent and secant
Fill in the table:
y y
sin x cos x
cos x − sin x
tan x sec2 x
cot x − csc2 x
sec x sec x tan x
csc x
17. Derivatives of tangent and secant
Fill in the table:
y y
sin x cos x
cos x − sin x
tan x sec2 x
cot x − csc2 x
sec x sec x tan x
csc x − csc x cot x
19. Example
Find
sin 2θ
lim
θ→0 θ
Solution (i)
Use a trig identity:
sin 2θ 2 sin θ cos θ sin θ
lim = lim = 2 · lim · lim cos θ = 2 · 1 · 1 = 1
θ→0 θ θ→0 θ θ→0 θ θ→0
20. Example
Find
sin 2θ
lim
θ→0 θ
Solution (i)
Use a trig identity:
sin 2θ 2 sin θ cos θ sin θ
lim = lim = 2 · lim · lim cos θ = 2 · 1 · 1 = 1
θ→0 θ θ→0 θ θ→0 θ θ→0
Solution (ii)
Use a change of variable. Let ϕ = 2θ. Then
sin 2θ sin 2θ sin ϕ
lim = 2 lim = 2 lim =1
θ→0 θ θ→0 2θ ϕ→0 ϕ